C++ :: Finding Mode - Number That Occurs Most Often In A Sequence Of Numbers
Dec 9, 2014
I was doing a side project from my textbook about finding the mode, which is the number that occurs most often in a sequence of numbers. I racked my brain on this for an embarrassing amount of time and finally came up with this, which I think works but for some reason I still feel like I'm not done.
#include "stdafx.h"
#include <iostream>
using namespace std;
void mode(int *, int);
void main() {
const int NUMBERS = 15;
int list[NUMBERS] = {99,73,56,14,28,42,93,64,51,26,56,16,38,81,98};
mode(list,NUMBERS);
[Code] ....
Console Output:
Final Mode 56
Press any key to continue . . .
There it is, I would have commented more but I couldnt think of the right words to explain everything.
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Sep 9, 2013
I have to use numbers in my .txt file that are stored in an array. So i have to write a function to find the mode of the numbers in my array.
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Sep 16, 2013
I have to write a program to find the nth number of the Ulam numbers.
It's a bit complicated to explain what an Ulam number is but Wolfram explains it very well here: [URL]
I have to find the nth Ulam number but I don't know what I have to do to get that. My program gives me all the Ulam numbers from a range of 0 to n.
What I want the program to do is tell me that the 49th Ulam number is 243.
/*
C++ Program to find nth Ulam Number
*/
#include <stdio.h>
#include <iostream>
#include <vector>
using namespace std;
int main() {
int num = 0;
vector<int> v;
[code]....
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Feb 20, 2015
Write a program that prompts the user to enter a number larger than 2. The program should use the Number class to determine the prime numbers between 2 and the number entered, and display them in the console window.I've been stuck for a while now and just lost in implementing classes and contstructors.
#include <iostream>
using namespace std;
int main(int argc, char * argv[])
{
cout << "Enter a number larger than 2: " << endl;
int n;
cin >> n;
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Sep 15, 2013
I have a very large number in word ~6million digits long
I wish to make a program to check if it is prime.
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Mar 20, 2014
I've been trying for over an hour to think of the logic to find the mode of an array.I left out code for initializing the arrays, but all the values in the array are between 0-9. Check out my code below.
Code:
int mode( int array[], int size ) {
int i;
int count;
int max = 0;
int num = 0;
int mode;
[code]....
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Jul 21, 2013
I'm currently working with linear VRAM (a buffer with 256KB memory, divided into four 64k planes, so plane 0 at 0x00000, plane 1 at 0x10000, plane 2 at 0x20000, plane 3 at 0x30000). Just add the index of the plane to that for the full address in VRAM.
I'm still wondering how to get a specific pixel from VRAM (x,y coordinate) when doing graphic modes (none color modes work, only the black/white pixels (1-bit) graphic mode works).
how I can get specific pixels from the VGA VRAM (having linear access described above) using Shift Register Interleave mode (VGA modes 4&5), 16-bit planar mode (Most VGA modes) etc.
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Sep 26, 2013
I'm trying to make an array that takes a group of numbers and finds the largest number into a template class.
template<class TYPE>
void Integers(TYPE data) {
int integers[] = {4, 25, 32, 85, 150, 12, 98, 200};
int i = 0;
int Max=integers[0];
for (i=1; i < 8; i++) {
[Code] ....
I'm sure I'm going about it all wrong, but I'm not sure as to get it so that it will accept the arrays input.
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Aug 24, 2014
I'm a new coder for C++, and I've recently learned java before starting this programming language. I'm attempting to find all prime numbers up to the number a user enters (i.e. User enters 10, System shows "1,2,3,5,7"),
#include <iostream>
#include <cstdlib>
using namespace std;
int main(int argc, char** argv) {
int num;
cout << "Enter a positive number." << endl;
[Code] ....
I've been looking at my forloop, and I can't seem to pinpoint the problem with it.
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Feb 17, 2014
Write a C program that calculates the sum and average of a sequence of numbers. Assume the first number specifies the number of values remaining to be entered. If the first number is less than 1, then the program should display an "Invalid Entry ... Please enter a positive number." message.
THIS IS HOW IT SHOULD COME OUT...
Enter the number of values to process 0
Invalid Entry ... Please enter a positive number.
Enter the number of values to process 3
Enter 3 numbers:
1
2
3
Sum: 6
Avg: 2
THIS IS THE CODE I HAVE SO FAR...
#include <stdio.h>
int main(void) {
int total=0;
int howmany;
int i;
int value;
[Code] ....
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Apr 24, 2013
I am trying to write a program that checks whether the number is in sequence(as in if the numbers are in order it is a sequence). Ex: If the numbers are {1,2,3,6,7,8,9,10,11,13,15,17,20,21}, then, the underlined parts are a sequence. Now i want to find
1) the no of sequence in the array(in the above it is 3 )
2) the longest sequence (7to 11 which is 5).
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Feb 16, 2014
The next code is right. I mean it works. It gives the sequence of fibonaci numbers ...
Code:
#include <iostream>
#include <iomanip>
using namespace std;
int fibo(int pos) {
if(!pos)return 0;
if(pos==1)return 1;
[Code] .....
But.... when I change the lines:
Code:
int r1=fibo(pos1);
int r2=fibo(pos2);
int r=r1+r2;
For the lines:
Code:
int r=fibo(pos1)+fibo(pos2);
It doesn't work right. Apparently it should work the same.
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Feb 23, 2014
I needed to compute average median and mode for numbers in a vector. Im having a few issues I have already figured out how to calculate average and median just not mode. Also the program crashes when 0 is entered instead of exiting nicely. Also i keep getting a error on line 47 saying primary expression expected before else.
#include <iostream>
#include <conio.h>
#include <math.h>
[Code]....
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Oct 7, 2013
This code is suppose to display arithmetic sequence after it has to add all the numbers together without a formula.
for example: the starting number is 5, common difference is 3, the term is 9
the sequence would display as: 5, 8, 11, 14, 17, 20, 23, 26, 29
the sum is: 153
with my code I've managed to get 8,11
To get the sum, I am restricted to using a "for" loop. For sequence, I am using a while. I am trouble developing the while loop to display the sequence and getting the sum for the for loop.
#include <iostream>
#include <cmath>
#include <stdlib.h>
using namespace std;
int main() {
double a, d, n,i,sum,j;
[Code] ....
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Nov 18, 2014
I'm saving the images in folder by using:
webClient.DownloadFile(href, sourcepath);
I don't want to give name as Current date and time..shown in given below code
string sub = @"Gadhada";
DirectoryInfo subFolder = dir1.CreateSubdirectory(sub);
Imagename = DateTime.Now.Year.ToString() + DateTime.Now.Month.ToString() +
[Code].....
I want to save my imagename as 1.jpg, 2.jpg, 3.jpg.
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Feb 28, 2013
I was trying to create a code to calculate the nth number in a Fibonacci sequence, when the nth number is entered interactively.
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Jun 19, 2013
I need to implement the fibonacci number sequence. Here is an example output of the program:
Server:Waiting for connection
Server:Receive connection from client
Client:10
Server:Print 10 Fibonacci
Server:1 1 2 3 5 8 13 21 34 54
Client:1 1 2 3 5 8 13 21 34 54
if Client send value of 5, the output would be 1 1 2 3 5
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Jun 20, 2013
User enters sentence "The Smiths have two daughters, three sons, two cats and one dog." (The numbers may change depending on what the user chooses to enter. He told us the range would be from zero to nine.) and we have to convert the written numbers within the sentence into actual decimal numbers and print out the new sentence. Ex. The Smiths have 2 daughters, 3 sons...etc.
I have written the following bit of code which reads the string and finds all the "written numbers" but I am not sure how to proceed from there. I am stuck on how to print out the new sentence with the converted numbers as my professor mentioned something about creating the new string using dynamic memory allocation.
Code:
#include <stdio.h>#include <string.h>
int main () {
char A[100];
int length = 0;
int i;
[Code] .....
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Sep 3, 2014
When ever I enter a value higher than 10, my out put looks like this
How many numbers are in the Fibonacci Series? 20
0 0 0 0 0 0
0 0 0 0 34 21
13 8 5 3 2 1
1 0
Press any key to continue . . .
This is what I got when I entered the value 20.
As you can see, it will only display up to the 10 term of the Fibonacci sequence
I'm trying to get the output to look like this:
4181 2584 1597 987 610 377
233 144 89 55 34 21
13 8 5 3 2 1
1 0
Here is my code:
#include <iostream>
#include <iomanip>
using namespace std;
#define SIZE 20
void Fibonacci( int );
int main( ) {
cout << "How many numbers are in the Fibonacci Series? ";
[code].....
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Oct 24, 2013
I am just starting out programming and have an assignment due in the near future. the problem is I cant seem to figure it out. I started it already but got stuck cant seem to figure it out. Here is the assignment.
Create a program that will generate a list of 200 random numbers (ranging from 1-1000) and determine the medium, mode, and average of the list of numbers. Have the program display the original list ant then display the list in ascending and descending order on the screen.
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Mar 27, 2014
I have to made a programme which will search for given number and it must work in O(log(n)). The problem is that this programme beside finding this number have to find how many times this given number is used in this sequence.
Sequence is from lowest to highest only one possibility to use binary search algorithm
For example when we have squence
-1 -2 3 3 3 3 4 5 6 7 7 8 9 9 9 9 10
The numbers we need to search are
1 , 3 , 7 , 9 , 11 , 12
The answer is
0 , 4 , 2 , 4 , 0 , 0
So we need to find the sum of used number in sequence.
I have written algorithm Code: int start = 0;
int end = sequencelenght - 1;
int mid = 0;
/// Binary serach
while (start<=end) {
int mid=(start+end)/2;
if (sequence[mid]==givennumber) {
[Code] .....
As u see i search for given numer with binary with O(log(n)) but when i have to sum the duplicates the only good way i see is using loop to right and left but this have got log(n) specification (because when sequence would be for example 7 7 7 7 7 7 7 7 7 and given number to search will be 7 this will be O(n) loop).
How would look the most optimal algorithm look for this exercise? I mean O(log(n)) the fastest algorithm....
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Mar 24, 2014
write a program in c to read a sequence of N integers and print the number that appears the maximum number of times in the sequence.
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Jan 30, 2015
I want to find the value occurs most in an 8 integer array. Here is the code that I have. It does compile, but has not been tested.
Code:
int POLL (int *RANGE_ARRAY) {
int d = 0;
int e = 0;
int f = 0;
int g = 0;
int h = 0;
int j = 0;
intk;
[Code] .....
Does this look right or is there a better way of doing this?
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Apr 10, 2014
Try not to make too much fun of me for my logic, but I'm having trouble with this. I am trying to make it so the program takes a 1 dimensional array and a 2 dimensional array, and checks to see what row in the 2 dimensional array is the closest to the 1D array.
To compute the value of the 1D array you take the first row first element in the 2D array, and the first element in the 1D array, subtract and the absolute value.
Example: | 4 - 3 | = 1;
1Darray = 1.
Full 1 Dimensional Array:
3 1 6 9
Full 2 Dimensional Array:
4 9 1 5
6 1 7 3
0 8 2 6
To compute the value of the first row in the 2D array,
| 4 - 3 | + | 9 - 1 | + | 1 - 6 | + | 5 - 9 | = 18.
| 6 - 3 | + | 1 - 1 | + | 7 - 6 | + | 3 - 9 | = 10.
| 0 - 3 | + | 8 - 1 | + | 2 - 6 | + | 6 - 9 | = 17.
Thus row 1 being the closest row to the 1 dimensional array.
The code I've written so far seems to be going down the right path. Have a look below...
Code:
int i,j,tempRow,tempTotal = 0,firEle,cloRow;
firEle = abs( x[0][0] - y[0] );
for( i = 0; i < size; i++ ) {
tempRow = 0;
for( j = 0; j < size; j++ ) {
tempRow += abs( x[i][j] - y[j] );
[Code] ....
The whole temp part is kind of confusing myself. What I'm thinking is that I can add all row values up using
Code: tempRow += abs( x[i][j] - y[j] ); , then I need to compare that value to see if it is close to the "firEle" which is value I need to get closest to.
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Feb 16, 2013
My problem is to count the characters in a file and define how many times each one occurs.Characters who are not found must not be included in the table; The output must be a table - like that -
”| character | ASCII- DEC | ASCI – HEX | how many times it occurs |”
This my function:
Code:
int f2(FILE *p1)
{
FILE *g3;
int char_count[256]={0};
char ch;
int n=0;
if(!(g3=fopen("D:zz.txt", "w"))){
[Code] ....
It must look like this:
| D | 68 | 44 | 2 |
| 2 | 50 | 32 | 1 | and so on...
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Feb 14, 2014
I know how to write the GCD for one, two, three, four, and etc, numbers. But I cannot seem to find a way to write a code that does it for 'n' numbers.
That is, the user inputs a number 'n', which determines the size of a dynamic array. Then they are prompted to input the values for each of the elements in the array that will constitute the numbers the program is to find the GCD for.
This records the array:
for (int count = 0; count < n; count++) {
cout <<"Enter the numbers you wish to find the GCD for, for term" << count << ": ";
cin >> GCD_n[count];
}
Here is a code for finding GCD of three numbers:
cout << "This program finds the greatest common divisor of three numbers.
"
<< "Enter the first number:
";
cin >> a;
[Code] ....
How to proceed coding a program that finds the GCD of 'n' terms.
GCD_n[n] is the array that contains the numbers for which we need to determine the GCD for.
My main problem is with writing a code that tests the elements of the array containing the list of numbers in GCD_n[n], all at the same time, such that:
int n;
cout << "This program finds the greatest common divisor of n numbers.
"
<< "What is the total amount of numbers you want to find the GCD for?
[Code] .....
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