C++ :: Display Arithmetic Sequence After Adding All Numbers
Oct 7, 2013
This code is suppose to display arithmetic sequence after it has to add all the numbers together without a formula.
for example: the starting number is 5, common difference is 3, the term is 9
the sequence would display as: 5, 8, 11, 14, 17, 20, 23, 26, 29
the sum is: 153
with my code I've managed to get 8,11
To get the sum, I am restricted to using a "for" loop. For sequence, I am using a while. I am trouble developing the while loop to display the sequence and getting the sum for the for loop.
#include <iostream>
#include <cmath>
#include <stdlib.h>
using namespace std;
int main() {
double a, d, n,i,sum,j;
I made a program that prints out arithmetic sequence.. but problem is that,
when I enter a(first term) =5, d(differnce)=2.4 and n=3 the program prints out only first two terms not three.. for all the other numbers it works correctly..
I have to write a program for school that displays a random sequence of colored squares, each square is a different color. Then the squares disappear and the 5 more pop up at the bottom. The user has to guess which color was first, second, and so on. They click on the squares on the bottom that matches the first square on the top.
My question is how do you get the computer to say ok this square (that the user clicked on) matches this square here.
is there a command that says something like if this color matches this color?
Write a C program that calculates the sum and average of a sequence of numbers. Assume the first number specifies the number of values remaining to be entered. If the first number is less than 1, then the program should display an "Invalid Entry ... Please enter a positive number." message.
THIS IS HOW IT SHOULD COME OUT... Enter the number of values to process 0
Invalid Entry ... Please enter a positive number.
Enter the number of values to process 3 Enter 3 numbers: 1 2 3
Sum: 6 Avg: 2
THIS IS THE CODE I HAVE SO FAR...
#include <stdio.h> int main(void) { int total=0; int howmany; int i; int value;
I was doing a side project from my textbook about finding the mode, which is the number that occurs most often in a sequence of numbers. I racked my brain on this for an embarrassing amount of time and finally came up with this, which I think works but for some reason I still feel like I'm not done.
#include "stdafx.h" #include <iostream> using namespace std; void mode(int *, int); void main() { const int NUMBERS = 15; int list[NUMBERS] = {99,73,56,14,28,42,93,64,51,26,56,16,38,81,98}; mode(list,NUMBERS);
[Code] ....
Console Output:
Final Mode 56 Press any key to continue . . .
There it is, I would have commented more but I couldnt think of the right words to explain everything.
I have migrated my MFC application from Visual Studio 6 to VS2010. But the UI controls still looks the same as of old theme. How can i add the manifest file now to get the UI controls to be displayed as of the current OS theme. i.e. Win7 look if the application is run on windows 7.
I was trying to solve a problem that required to add one hundred 50 digit numbers. Since there is no way to hold such a huge number. I read that storing them in strings is the way to go. I was caught midway while trying to do the same.
And the text file is this. Code: 123465789 321654987 This isn't the exact huge number, but I wanted to try it out with lower number before trying out with the original huge ones.I am trying to store the numbers in a two-dimensional array. However when I and try to pass the single number as an parameter to the AddTwoStrings() method, It actually passes the entire number as such.
When I pass string[0],string[1] it should pass the first and second number from the files as the two numbers instead of the whole number as such.The function AddTwoStrings() doesn't do anything as of now, I encountered this error when I was testing the code till this part.
I am designing a math program for kids. I want the program to produce 2 random numbers and check the sum of these numbers against the user's guess. I have the generating random numbers portion complete. What's the coding procedure to compare the sum to the user's guess?
Calculate the reversed numbers from the input. Reversed number is a number written in arabic numerals but the order of digits is reversed (e.g. 543 reversed would be 345). You need to add two reversed numbers and output their reversed sum. Of course, the result is not unique because any particular number is a reversed form of several numbers (e.g. 21 could be 12, 120 or 1200 before reversing). Thus you must assume that no zeros were lost by reversing (e.g. assume that the original number was 12).
Input
The input consists of N cases (equal to about 10000). The first line of the input contains only positive integer N. Then follow the cases. Each case consists of exactly one line with two positive integers separated by space. These are the numbers you are to reverse and add together.
Output
For each case, print exactly one line containing only one integer - the reversed sum of two reversed numbers (Get the sum of the 2 integers that have been reverses, then reverse that sum also). Omit any leading zeros in the output.
Right now I'm thinking that it can't be done without converting the numbers to a string because I have been working on this for days and can't find a answer.
I need to make a small program with a function with this prototype: void f(char *a,char *b) that adds two numbers represented as strings without using conversion operators or other tricks.
I'm stuck on the last part of my program. The directions are the following~
Expand the program to add an overloaded function to handle floating point numbers (i.e., doubles). Include output for one list of integers and one list of doubles. Use this function prototype: double avgx(double&, double&, int, ...);
Compile and run. You should have one function named avg, one named davg, and two functions named avgx
My code does not compile and I think I'm not declaring my function prototype correctly?
#include <iostream> using std::cout; using std::endl; #include <cstdarg> // function prototype(s) int avg(int, ...);
Display the remainder of the square of numbers from 100 to 10. This square of numbers must be divisible by the numbers from 100 to 10 respectively. what i need to in this
Write a program that displays the first 40 Fibonacci numbers. A Fibonacci number is created by add the previous two, with the first two always being 0 and 1. A partial sequence is as follows:
0, 1, 1, 2, 3, 5, 8, 13, 21,….
Your table must display 6 numbers per row and use a spacing of 10 for each number. Don’t forget to include the header file “iomanip” at the top and use “setw()”. You will need to turn in an algorithm, source code and output.
Here is what i have but i get errors!
#include <iostream> using namespace std; { int FirstNumber = 0; int SecondNumber = 1; int NumberOfNumbers = 2; int NewNumber;
We were asked to make a program which displays the prime numbers within the range you inputted... like for example i entered 20 as the upper limit and 1 as the lower, then the program must display all prime numbers within 20 and 1..
and so my problem is, i get to display the prime numbers, but 2, 3, 5, and 7 can't because it think it's with the if statement i made within the loop? (Code below)
#include<iostream.h> #include<conio.h> void prime (int up, int low); main() { clrscr(); int Upper, Lower, i;
Create a program that will display all the composite numbers from 0 to 1000 and has a maximum column of 5 . A composite number is a positive integer that has at least one positive divisor other than one or itself. In other words a composite number is any positive integer greater than one that is not a prime number.
