int sum=82;
for(int i; i < sum.length; i++)
{
final=sum[i]+final;
}
I need getting the sum and adding the numbers together. for example 82 would be 8+2. I keep getting an error on this piece of code....
I was trying to solve a problem that required to add one hundred 50 digit numbers. Since there is no way to hold such a huge number. I read that storing them in strings is the way to go. I was caught midway while trying to do the same.
Here's the source code;
Code:
#include<stdio.h>
#include<string.h>
const char * addTwoStrings(char *number1,char *number2)
}
[code]...
And the text file is this. Code: 123465789 321654987 This isn't the exact huge number, but I wanted to try it out with lower number before trying out with the original huge ones.I am trying to store the numbers in a two-dimensional array. However when I and try to pass the single number as an parameter to the AddTwoStrings() method, It actually passes the entire number as such.
When I pass string[0],string[1] it should pass the first and second number from the files as the two numbers instead of the whole number as such.The function AddTwoStrings() doesn't do anything as of now, I encountered this error when I was testing the code till this part.
I am designing a math program for kids. I want the program to produce 2 random numbers and check the sum of these numbers against the user's guess. I have the generating random numbers portion complete. What's the coding procedure to compare the sum to the user's guess?
View 9 Replies View RelatedCalculate the reversed numbers from the input. Reversed number is a number written in arabic numerals but the order of digits is reversed (e.g. 543 reversed would be 345). You need to add two reversed numbers and output their reversed sum. Of course, the result is not unique because any particular number is a reversed form of several numbers (e.g. 21 could be 12, 120 or 1200 before reversing). Thus you must assume that no zeros were lost by reversing (e.g. assume that the original number was 12).
Input
The input consists of N cases (equal to about 10000). The first line of the input contains only positive integer N. Then follow the cases. Each case consists of exactly one line with two positive integers separated by space. These are the numbers you are to reverse and add together.
Output
For each case, print exactly one line containing only one integer - the reversed sum of two reversed numbers (Get the sum of the 2 integers that have been reverses, then reverse that sum also). Omit any leading zeros in the output.
Sample
#include <iostream>
#include <string>
#include <sstream>
#include <algorithm>
std::string convertInt(unsigned number) {
[Code] ....
Right now I'm thinking that it can't be done without converting the numbers to a string because I have been working on this for days and can't find a answer.
I have to make a function that can add two numbers of any size. So far I have:
#include <iostream>
#include <string>
struct number {
[Code]....
why I'm getting a segmentation fault? It's really dense because of all the conversions I had to do.
I need to make a small program with a function with this prototype: void f(char *a,char *b) that adds two numbers represented as strings without using conversion operators or other tricks.
View 8 Replies View RelatedHow to do the problem below using loop?
Using loop...
Output the total of the reciprocals of the numbers from 1 to 10:
1/1 + 1/2 + 1/3 + 1/4 ... + 1/10 = 2.928968
Exmaple:
112121276783621784678236478236478623784672364782367846237846782364782367846238 + 783627846782364786237846782364782367846237846782364782367846237846237864782367846238
It should be efficient and fast. It is useful to calculate the Factorial 100000, and then I calculate the number of the module.
Example:
132142344564378657834657834657863785634786578346578346785634785678653478 % 124623874
This code is suppose to display arithmetic sequence after it has to add all the numbers together without a formula.
for example: the starting number is 5, common difference is 3, the term is 9
the sequence would display as: 5, 8, 11, 14, 17, 20, 23, 26, 29
the sum is: 153
with my code I've managed to get 8,11
To get the sum, I am restricted to using a "for" loop. For sequence, I am using a while. I am trouble developing the while loop to display the sequence and getting the sum for the for loop.
#include <iostream>
#include <cmath>
#include <stdlib.h>
using namespace std;
int main() {
double a, d, n,i,sum,j;
[Code] ....
I'm stuck on the last part of my program. The directions are the following~
Expand the program to add an overloaded function to handle floating point numbers (i.e., doubles). Include output for one list of integers and one list of doubles. Use this function prototype: double avgx(double&, double&, int, ...);
Compile and run. You should have one function named avg, one named davg, and two functions named avgx
My code does not compile and I think I'm not declaring my function prototype correctly?
#include <iostream>
using std::cout;
using std::endl;
#include <cstdarg>
// function prototype(s)
int avg(int, ...);
[Code] ....
I'm writing a program to calculate a final grade by adding 4 numbers minus the lowest grade and dividing by 3. My knowledge in c is not extensive I thought that a simple assigment operator would do the job but I'm getting a strange large numbers in the execution.
Code:
#include <stdio.h>
#include <stdlib.h>
main(){
int eg, g1, g2, g3, g4, fg, s1, s2, sg;
[Code] ....
How to do the problem below using loop?
Input numbers until the user types a 0, then output the product of the non 0 numbers: e
E.g., if the user types 2 4 6 0, the program should output 48
User enters sentence "The Smiths have two daughters, three sons, two cats and one dog." (The numbers may change depending on what the user chooses to enter. He told us the range would be from zero to nine.) and we have to convert the written numbers within the sentence into actual decimal numbers and print out the new sentence. Ex. The Smiths have 2 daughters, 3 sons...etc.
I have written the following bit of code which reads the string and finds all the "written numbers" but I am not sure how to proceed from there. I am stuck on how to print out the new sentence with the converted numbers as my professor mentioned something about creating the new string using dynamic memory allocation.
Code:
#include <stdio.h>#include <string.h>
int main () {
char A[100];
int length = 0;
int i;
[Code] .....
Find all the prime numbers between a given pair of numbers. Numbers should be read in from an input file called "numbers.txt" and find all the prime numbers between them. Store the prime numbers in an array, then sort the array from greatest to least. Display the array before and after the sort.
I'm stuck on how to put the prime numbers into an array.
The input file has the numbers 1 & 100.
Here's what I have so far.
#include <iostream>
#include <fstream>
using namespace std;
int main() {
ifstream fin;
fin.open("numbers.txt");
[Code] .....
Question: How to find a duplicate numbers and numbers found once in array.
View 7 Replies View RelatedI'm working on this program that I have to design a class Numbers that can be used to translate whole numbers to the English description of the number.
Now this is what I got so far:
#include <iostream>
#include <string>
using namespace std;
class Numbers {
private:
int number;
static string ones[];
static string tens[];
[Code] ....
The program seems to work. However its not giving me the right number description,
Example:
Please enter the amount you would like translated into words: 5
six dollars
please enter another number: 10
eleven dollars
please enter another number: 20
thirty dollars
please enter another number: 30
forty dollars
please enter another number: 100
two hundred dollars
please enter another number: 150
two hundred sixty dollars
please enter another number: 500
six hundred dollars
please enter another number: 1000
two thousand dollars
please enter another number:
ignoring negative numbers when I am trying to add up only positive numbers.
SAMPLE:
if (num>=0) {
sum= sum + num;
}
else
how would the else in this case being a negative number not be included in the sum
I need a list generated of all possible subset combinations for the set 1,2,3,4,5,6,7,8,9,10,12. Select six. Numbers cannot repeat.
Example subset: 1,2,3,4,5,6 (six selected, no repeats).
Example of what I dont need: 1,1,2,2,3,3,4,4,5,5,12,12 or 1,1,1,1,1,6.
I will also need the opposites removed, meaning...if I have 1,3,5,7,9,11 then I need 2,4,6,8,10,12 eliminated from the final list.
This is for a game, where you must select all numbers right or no numbers right.
The code below will generate combinations of numbers from 1 to 25 in an 15 numbers array. The only filter I've applied is that the sum of all the numbers in the vectors divided by 15 needs to be between 13 and 14.
I would like to count how many consecutive numbers there are in one combination, so that later i can apply another filter.. for example:
1 3 4 5 6 8 10 13 14 16 17 18 19 20 25
3 + 4 = 1
4 + 5 = 1
5 + 6 = 1
13 + 14 = 1
16 + 17 = 1
17 + 18 = 1
18 + 19 = 1
19 + 20 = 1
_____________
Count = 8, in this case..
I think it's not very difficult to do, but i just can't see how to do it.
#include <iostream>
#include <vector>
#include <numeric>
[Code]....
I want to make a program to print the product of even numbers between 1 and 30 and sum of odd numbers between 1 and 30. But the answer of product is negative. The photo shows the output of the code.
#include <stdio.h>
#include <conio.h>
void main ()
{
int i, even_product=1, odd_sum=0;
for(i=1;i<=30;i++) // For loop starts here!
[Code]...
I tried to add 2 or more strings together but failed.
eg I would like to add "KK" & "LL" together by adding but it couldn't work.
string string_B = "KK";
string string_C = "LL";
string_A = string_B + string_C;
Every time I run if(color=="1") it's supposed to add 1 to redTotal. However, every time I run if(color=="1") if get 1 for redTotal every time.
(Write a program that provides the option of tallying up the results of a poll with 3 possible values. The first input to the program is the poll question; the next three inputs are the possible answers. The first answer is indicated by 1, the second by 2, the third by 3. The answers are tallied until a 0 is entered. The program should then show the results of the poll—try making a bar graph that shows the results properly scaled to fit on your screen no matter how many results were entered.)
Code:
#include <iostream>
#include <string>
using namespace std;
int main()
[Code]....
I am new to c and I have come across a problem when adding other functions to a programme and printing the values. The question I am attempting to solve is :
The following function computes ex by summing the Taylor series expansion to n terms. Write a program to print a table of ex using both this function and the exp() function from the math.h library, for x = 0 to 1 in steps of 0.1. The program should ask the user what value of n to use.
double taylor(double x, int n) {
int i;
double sum = 1.0;
double term = 1.0;
for (i=1; i<=n; i++) {
/*Or we could have written: */
term = term * x / i; /* term *= x / i; */
sum = sum + term; /* sum += term; */
}
return sum;
}
My code is
Code:
#include<stdio.h>
#include<stdlib.h>
#include<math.h>
/*Taylor series for e*/
[code]....
code prints out the values for exp, but it gets stuck in the Taylor function and I'm not sure how to solve it.
So here is what i need i need a way i can add 3 variables one after the other example:
int a = 1;
int b = 2;
int c = 3;
//Here comes my problem
int d = a + b + c;
When I write it like thet d = 6 ,
but I need it to be 123,
How would one add each value from an array? I'm working from a string but I was wondering if there was a way to loop through the string and add each value. This is what I have so far:
#include <iostream>
#include <cmath>
#include <string>
int main() {
std::string numbers;
int sum;
[Code] ....
I have the following code in sourceFile.cpp. functionA() is first called and inserted entires for key1, key2 and key3. Then functionB() gets called to use the vectors for the 3 keys. I want to free all memory after exiting functionC(). Among the three ways to put an entry into the map for the 3 keys, which is correct / better?
Class ClassA { ... }
ClassA *key1 = new ClassA();
ClassA *key2 = new ClassA();
ClassA *key3 = new ClassA();
[Code]....