I have to make a function that can add two numbers of any size. So far I have:
#include <iostream>
#include <string>
struct number {
[Code]....
why I'm getting a segmentation fault? It's really dense because of all the conversions I had to do.
Exmaple:
112121276783621784678236478236478623784672364782367846237846782364782367846238 + 783627846782364786237846782364782367846237846782364782367846237846237864782367846238
It should be efficient and fast. It is useful to calculate the Factorial 100000, and then I calculate the number of the module.
Example:
132142344564378657834657834657863785634786578346578346785634785678653478 % 124623874
In C++, the largest int value is 2147483647. So, an integer larger than this cannot be stored and processed as an integer. Similarly, if the sum or product of two positive integers is greater than 2147483647, the result will be incorrect. One way to store and manipulate large integers is to store each individual digit of the number in an array. Write a program that inputs two positive integers of, at most, 20 digits and outputs the sum of the numbers. If the sum of the numbers has more than 20 digits, output the sum with an appropriate message. Your program must, at least, contain a function to read and store a number into an array and another function to output the sum of the numbers. (Hint: Read numbers as strings and store the digits of the number in the reverse order.)
View 7 Replies View RelatedI have designed a code and still i dont get the desired output ....
#include <iostream>
using namespace std;
int fact(int,int);
int arr[200]={1};
int main() {
int n,t,len=0,i=0,j,a;
cin>>t;
[Code] ....
My code handles smaller numbers well enough, but I need the program to be able at least factor 100!.
#include <stdio.h>
void factorialOutput(unsigned int &n, int fac[]);
unsigned long long factorial(int n);
int main(int argc, const char * argv[]) {
unsigned int t = 0;
int n[101];
[Code] ......
I have a very large number in word ~6million digits long
I wish to make a program to check if it is prime.
If i m writing a code for a program to solve factorials, what is the best approach if i have large numbers in mind?
If i use int, i can only go upto 4bytes and if i use double i can go upto 8bytes. so should i create new type or is there any other way to get this done.
I have to write a program, that multplicates very large numbers (out of range of long int). It's said that i need to use arrays and read the numbers as strings. My problem is to end function called "mnoz:, because i don't know how to sum the multiplicated values of arrays a and b.
Code:
#include<stdio.h>
#include<math.h>
#include<stdlib.h>
#include "winbgi2.h"
#include<string.h>
#define roz 10000
char lan(char a[])
[Code] ......
Why this class doesn't work for Subtraction, Division and Square Root. When I try to get results for Subtraction, it output right answer, but with any trash. And When I try to get answer for Division and Square Root, it just brakes and don't output anything. For Addition and Multiplication class work correctly.
Its the link to this class [URL]
I'm programming an app that deals with large numbers. I have a do-while loop that I want to execute. I can not get it to work. The "while(d!=1)" part is the problem and I can not find a way around.
Code:
#include "stdafx.h"
#include <stdio.h>
#include <gmp.h>
#pragma comment(lib, "gmp.lib")
int main (int argc, char *argv[]) {
mpz_t d;
[Code] ....
I get errors:
1.error C2446: '!=' : no conversion from 'const int' to '__mpz_struct *'
Conversion from integral type to pointer type requires reinterpret_cast, C-style cast or function-style cast
2. '!=' : '__mpz_struct [1]' differs in levels of indirection from 'const int'
I tried to sort a large numbers of vector of random integers with std::sort(), but when the number increases over 10M, std::sort returns all zero in values. Does std::sort have a limitation of input numbers?
View 1 Replies View RelatedI am working on a program which creates a large pointer array of numbers and then performs several iterations of operations in them.
Code:
int * u = new int[N];
double * nu = new double[N];
int * nud = new int[N];
for (int i=0;i<M;i++){
for (int i=0;i<N;i++){
u[i]=0;
nu[i]=0;
[Code]...
If M is small enough then there are no problems in the program. However once M is large enough I get the "unhanded exception":
std::bad_alloc at memory location 0x0026f728..
Since I am just reusing the same arrays, and since I am able to make it through a few iterations, I didn't think it could be a memory issue. If it is, is there a way I can clear the data completely after each iteration?
What I'm trying to do is make a calculator that takes two large numbers in a linked list then ask the user if they wish to add them or subtract them.
#include<iostream>
#include<string>
using namespace std;
class Node {
public:
int value;
Node * next;
[Code] ....
int sum=82;
for(int i; i < sum.length; i++)
{
final=sum[i]+final;
}
I need getting the sum and adding the numbers together. for example 82 would be 8+2. I keep getting an error on this piece of code....
I was trying to solve a problem that required to add one hundred 50 digit numbers. Since there is no way to hold such a huge number. I read that storing them in strings is the way to go. I was caught midway while trying to do the same.
Here's the source code;
Code:
#include<stdio.h>
#include<string.h>
const char * addTwoStrings(char *number1,char *number2)
}
[code]...
And the text file is this. Code: 123465789 321654987 This isn't the exact huge number, but I wanted to try it out with lower number before trying out with the original huge ones.I am trying to store the numbers in a two-dimensional array. However when I and try to pass the single number as an parameter to the AddTwoStrings() method, It actually passes the entire number as such.
When I pass string[0],string[1] it should pass the first and second number from the files as the two numbers instead of the whole number as such.The function AddTwoStrings() doesn't do anything as of now, I encountered this error when I was testing the code till this part.
I am designing a math program for kids. I want the program to produce 2 random numbers and check the sum of these numbers against the user's guess. I have the generating random numbers portion complete. What's the coding procedure to compare the sum to the user's guess?
View 9 Replies View RelatedCalculate the reversed numbers from the input. Reversed number is a number written in arabic numerals but the order of digits is reversed (e.g. 543 reversed would be 345). You need to add two reversed numbers and output their reversed sum. Of course, the result is not unique because any particular number is a reversed form of several numbers (e.g. 21 could be 12, 120 or 1200 before reversing). Thus you must assume that no zeros were lost by reversing (e.g. assume that the original number was 12).
Input
The input consists of N cases (equal to about 10000). The first line of the input contains only positive integer N. Then follow the cases. Each case consists of exactly one line with two positive integers separated by space. These are the numbers you are to reverse and add together.
Output
For each case, print exactly one line containing only one integer - the reversed sum of two reversed numbers (Get the sum of the 2 integers that have been reverses, then reverse that sum also). Omit any leading zeros in the output.
Sample
#include <iostream>
#include <string>
#include <sstream>
#include <algorithm>
std::string convertInt(unsigned number) {
[Code] ....
Right now I'm thinking that it can't be done without converting the numbers to a string because I have been working on this for days and can't find a answer.
I need to make a small program with a function with this prototype: void f(char *a,char *b) that adds two numbers represented as strings without using conversion operators or other tricks.
View 8 Replies View RelatedHow to do the problem below using loop?
Using loop...
Output the total of the reciprocals of the numbers from 1 to 10:
1/1 + 1/2 + 1/3 + 1/4 ... + 1/10 = 2.928968
This code is suppose to display arithmetic sequence after it has to add all the numbers together without a formula.
for example: the starting number is 5, common difference is 3, the term is 9
the sequence would display as: 5, 8, 11, 14, 17, 20, 23, 26, 29
the sum is: 153
with my code I've managed to get 8,11
To get the sum, I am restricted to using a "for" loop. For sequence, I am using a while. I am trouble developing the while loop to display the sequence and getting the sum for the for loop.
#include <iostream>
#include <cmath>
#include <stdlib.h>
using namespace std;
int main() {
double a, d, n,i,sum,j;
[Code] ....
I'm stuck on the last part of my program. The directions are the following~
Expand the program to add an overloaded function to handle floating point numbers (i.e., doubles). Include output for one list of integers and one list of doubles. Use this function prototype: double avgx(double&, double&, int, ...);
Compile and run. You should have one function named avg, one named davg, and two functions named avgx
My code does not compile and I think I'm not declaring my function prototype correctly?
#include <iostream>
using std::cout;
using std::endl;
#include <cstdarg>
// function prototype(s)
int avg(int, ...);
[Code] ....
I'm writing a program to calculate a final grade by adding 4 numbers minus the lowest grade and dividing by 3. My knowledge in c is not extensive I thought that a simple assigment operator would do the job but I'm getting a strange large numbers in the execution.
Code:
#include <stdio.h>
#include <stdlib.h>
main(){
int eg, g1, g2, g3, g4, fg, s1, s2, sg;
[Code] ....
How to get large fatorials in c++...in c++ i am getting the ouput upto maximum of 20!
View 4 Replies View RelatedWhat I want to create is a program that sorts through a huge list (millions of lines).
I want it to get rid of any line that contains a word that isn't in an English dictionary.
Example list:
00sdfdsf
ahdadsg
angel
ksjflsjdf
green
green000
carrot
and it would go through millions like that, giving me only:
angel
green
carrot
as my new list.
How could I go about this? What extra programs would I need?
My programs gives a segmentation fault for large n (n=9999999). It works fine for small n. Where n = total numbers to sort
List<long>* Merge(List<long> *ParentList)
{
if(ParentList->length()==1)
{
[Code]....
storing int=9000000000; gives me another number. how can i store the value?my bad int number=9000000000;
View 3 Replies View Related