Display the remainder of the square of numbers from 100 to 10. This square of numbers must be divisible by the numbers from 100 to 10 respectively. what i need to in this
View 3 RepliesI have to build a program that calculates the remainder of the expression
(2^10)!/((2^10-500)! * 500!)
when divided by 10^9+7
where x^y = x*x*x*x...*x (y times)
and x! = x*(x-1)...*1
How can I do that? I know how to calculate the remainder of x! and the remainder of y!, but I do not know how t calculate the remainder of x!/y!. I can´t even store this in a variable because x! is very large.
if i have two integers, say number1 and number2, stored in arrays where each index is a digit of the number (i.e. if my numbers are 321 and 158, then number1 = {3,2,1} and number2 = {1,5,8}), can i find the remainder of number1/number2? assume number1 > number2.
View 1 Replies View RelatedSay I wanted to overload the modulus operator to return the remainder of a division between two floating point numbers. Why isn't a custom double operator%(double, double) allowed even though that function isn't available in the standard anyway?
View 5 Replies View RelatedWrite a function which takes two parameter of integer type and both parameters are positive integer. These number should be provided by the user of your program. The first parameter is lower than the second parameter. You function should be able to calculate the sum of the square of each of the numbers between the two inputs and should display that. Please write a main function to display the working of your function. Call the function at least three times by using some loop in the main function.
This is what I came up with but it is not correct:
#include <iostream>
using namespace std;
void sumsquares(int number1, int number2) {
int sum = 0;
for(int i = number1; i<number2; i++)
sum =sum+ i*i;
cout<<"The Result is: "<<sum<<endl;
[Code] .....
I'm currently trying to write a program that takes an integer input from the user and displays that number of square-free numbers. I've gotten most of the program to work, but I encounter an error during the noSquare function that causes it to print incorrectly.
A square-free number is a number that is not evenly divisible by the square of any prime number. It's hard to see the bold in the code area, but it begins after the "//I think below is where the problem is"
#include <iostream>
#include <vector>
using namespace std;
[Code]........
I'm currently trying to write a program that takes an integer input from the user and displays that number of square-free numbers. I've gotten most of the program to work, but I encounter an error during the noSquare function that causes it to print incorrectly. I have bolded the area where I believe the problem is what I am doing wrong.
The problem with the program is that it prints ALL numbers from 1 to the input number instead of just the square-free.
A square-free number is a number that is not evenly divisible by the square of any prime number ....
#include <iostream>
#include <vector>
using namespace std;
bool noSquare (int num); //Function to determine if the number is square-free
vector<int> getPrimes(int num); //Function to get a vector of all primes below num
bool isPrime (int number); //Function to determine if individual numbers are prime
int main()
[Code]...
By the way, the in the middle of the code was me trying to bold a section, not an actual part of the code. I can't seem to find where to edit my original post.
I want to make program to square the numbers from 1 to 20. i have written this program, it's running but not giving the required answer.i think it is giving a garbage value...
void main(void)
{int a;
int b;
b=a*a;
for (a=1; a<21; a++)
{printf("%d",b);
printf("the square is%d=b");
}
getche();}
this is what i have so far
#include <iostream>
#include <cmath>
using namespace std;
int main () {
int v;
[Code] ....
im trying to get the program to print this as an example if the user enters 5 (the rounding of the decimal is optional).
1 1.41 1.73 2 2.24
1 1.41 1.73 2
1 1.41 1.73
1 1.41
1
why its not reading my for loop for rows its only doing columns ...
I tried to check the rational or irrational numbers after we take the square root. i dont get the formula. for eg. squareroot of 64 is 8 and it is rational. square root of 2 is irrational. how to check it in c++..
View 10 Replies View RelatedI have tried writing a code which takes two numbers from the user and calculates their square root then the roots are added up to return the sum. The program is coming out with loads of errors.
#include<iostream>
#include<cmath>
float main(){
using namespace std;
float m1,m2,m3,m4,m5;
[Code] ....
I am able to display a filled and hollow square by themselves, but I can't seem to be able to get them side by side.
So this is my code so far:
[/
#include <iostream>
using namespace std;
int main()
[Code]....
I can get the hollow square to show up, but the first square just shows up as a single line instead of a square. It seems that it ignores the first if statement in the second loop. I've tried not using an if statement in the second loop but it didn't seem to work either.
I know how to draw a square hollow or filled but i need to draw an alternating pattern ....
ex
iPatternHeight = 1
X
iPatternHeight = 3
OOO
OXO
OOO
[Code] .....
I want to find the remainder of the division between a and b, but without using the reminder operator a%b.I thought to subtract b from a as long as a>b, that will give the remainder, but I don't know how to write it in code.
View 11 Replies View RelatedI know how to draw a square hollow or filled but I need to draw an alternating pattern
ex
iPatternHeight = 1
X
iPatternHeight = 3
OOO
OXO
OOO
[Code] ......
i want to to apply a validation for an field which is Vehicle number in that the last four should be digits for ex:
AP1234 something like this it and it shldnt have 0000 at the last ...
Assume you want to make sure that the user enters a positive number that is divisible by 10 with no remainder. Write the condition you would use in the following do-while loop.
do {
cout << “Enter a positive number that is divisible by 10 with no remainder” << endl;
cin >> number;
}
while ( ____________________________________________________________);
float put;
put = 6/120;
cout << put;
This outputs 0. Why is it so and how can I make it output 6/120 in a more precise way?
Using for loop .....
View 15 Replies View Relatedwhere are operators defined in C/C++? in headers or compiled code?
looking for the definition of how % modulus is calulated
I have a file with numbers and want to display it on the screen.
View 15 Replies View RelatedThis is a program that display prime numbers from 1 to 100. it has problem linking when i run the program.
#include <iostream>
class Prime {
public:
int PrimeNo();
int Display();
};
// class Prime number
int Prime::PrimeNo()
[Code] ....
Write a program that displays the first 40 Fibonacci numbers. A Fibonacci number is created by add the previous two, with the first two always being 0 and 1. A partial sequence is as follows:
0, 1, 1, 2, 3, 5, 8, 13, 21,….
Your table must display 6 numbers per row and use a spacing of 10 for each number. Don’t forget to include the header file “iomanip” at the top and use “setw()”. You will need to turn in an algorithm, source code and output.
Here is what i have but i get errors!
#include <iostream>
using namespace std; {
int FirstNumber = 0;
int SecondNumber = 1;
int NumberOfNumbers = 2;
int NewNumber;
[Code] .....
My display is producing:
Enter the first number:234
Enter the second number:2
Enter the Third number:3
The largest number is 3
#include <iostream>
using namespace std;
double larger(double n1, double n2, double n3);
int main() {
[Code] ....
We were asked to make a program which displays the prime numbers within the range you inputted... like for example i entered 20 as the upper limit and 1 as the lower, then the program must display all prime numbers within 20 and 1..
and so my problem is, i get to display the prime numbers, but 2, 3, 5, and 7 can't because it think it's with the if statement i made within the loop? (Code below)
#include<iostream.h>
#include<conio.h>
void prime (int up, int low);
main() {
clrscr();
int Upper, Lower, i;
[Code] .....
Create a program that will display all the composite numbers from 0 to 1000 and has a maximum column of 5 . A composite number is a positive integer that has at least one positive divisor other than one or itself. In other words a composite number is any positive integer greater than one that is not a prime number.
SAMPLE OUTPUT:
4 6 8 9 10
12 14 15 16 18
20 21 22 24 25
26 27 28 30 32
....and so on.