I have to build a program that calculates the remainder of the expression
(2^10)!/((2^10-500)! * 500!)
when divided by 10^9+7
where x^y = x*x*x*x...*x (y times)
and x! = x*(x-1)...*1
How can I do that? I know how to calculate the remainder of x! and the remainder of y!, but I do not know how t calculate the remainder of x!/y!. I can´t even store this in a variable because x! is very large.
Say I wanted to overload the modulus operator to return the remainder of a division between two floating point numbers. Why isn't a custom double operator%(double, double) allowed even though that function isn't available in the standard anyway?
View 5 Replies View RelatedI want to find the remainder of the division between a and b, but without using the reminder operator a%b.I thought to subtract b from a as long as a>b, that will give the remainder, but I don't know how to write it in code.
View 11 Replies View RelatedSo I am using Visual Studio 2012 Professional, this is C++ code. I am just trying to get the remainder from a very simple division. Nothing difficult, heres the code:
double getProbability(){
int rd = random();
int max = numeric_limits<int>::max();
double result = rd % max;
cout << "Probability: " << result << "
";
return result;
}
When I look at the values in debug I get:
max 2147483647
rd 1804289383
result 1804289383.0000000
That is completely wrong. The answer should be 0.840188. What is going on here?
random() just returns a number from a vector that was prepopulated with "random" integers. Not really random, but that isn't all that important. What is important is why on earth is a % operation returning such a huge number. I assigned the values to variables so I could look at them in the debugger. I know I am going to probably get a thousand different ways that I could do this "better" but again, that isn't what I am looking for. I would just like to know why the % operation is doing what it is doing?
For class I need to write a program that inputs a file (the dividend), performs binary division on the file (using 0x12 as the divisor), and outputs the remainder(checksum).
I have researched binary division algorithms and I get the general gist, but I'm still unsure where to start. How would I store the dividend and divisor? As two arrays of bits?
Then, I need to figure out how to perform shifts and XORs on the the binary numbers. Maybe I should use bitwise operations?
C++ only allow addition and subtraction operation with pointer .why multiplication and division is not allowed? Then how to perform multiplication and division with pointer
View 3 Replies View RelatedDisplay the remainder of the square of numbers from 100 to 10. This square of numbers must be divisible by the numbers from 100 to 10 respectively. what i need to in this
View 3 Replies View Relatedif i have two integers, say number1 and number2, stored in arrays where each index is a digit of the number (i.e. if my numbers are 321 and 158, then number1 = {3,2,1} and number2 = {1,5,8}), can i find the remainder of number1/number2? assume number1 > number2.
View 1 Replies View RelatedI have the following details
double x= 1.5
double y= -1.5
int m= 20
int n= 4
my question is 5 * x - n / 5 at which what would n / 5 equal to, I think its zero since its integer division? or would the 5 be considered a real number?
Assume you want to make sure that the user enters a positive number that is divisible by 10 with no remainder. Write the condition you would use in the following do-while loop.
do {
cout << “Enter a positive number that is divisible by 10 with no remainder” << endl;
cin >> number;
}
while ( ____________________________________________________________);
where are operators defined in C/C++? in headers or compiled code?
looking for the definition of how % modulus is calulated
what I do I cannot get a division to work:
Code:
//END RANGE INPUT
long double End;
printf("
Please enter the start of the range (Lower Bound):
");
[Code]...
No matter what I input for the values of 'Start', 'End' and 'Interval', the value of 'SizeL' always seems to be -2.
How do i get this with decimal part?:
for(i=1;i<=4;i++){
printf("%d
",m);
s = s + m/i
m = m + 2;
}
m/i?
Question about instead of using the division operator to display the output of user"s input....
View 4 Replies View RelatedAt one point in my C++, non-CLR program, the following code:
Code:
unsigned int size = 3;
float maxX = (float)(int(size-1))/2.0f;
std::cout << maxX;
outputs 107. Is it something about a conversion from unsigned int to float?
I heard that the speed of floating point multiplication is much faster than division. Is it still the case today?
View 14 Replies View Relatedwhy are the arithmetic operations like division(p/q) and multiplication(p*q) invalid on pointers?.here p and q both are pointers .
View 6 Replies View RelatedThis code works very oddly.
Code:
#include <algorithm>
#include <cstdlib>
#include <iostream>
[Code].....
I was required to write a program that takes a baseball players statistics and displays there averages. I was required to make 3 function in the file to perform this tasks. my problem I am having a division problem in the SLG function. My compiler does not require the system ("PAUSE"); command.
OUTPUT
The player's batting average is: 0.347
The player's on-base percentage is: 0.375
The player's slugging percentage is:
(test)AB = 101
(test)Tot Base = 58
0.000
Code:
/* Batting Average Program
file: batavg1CPP.cpp
Glossary of abbreviations:
BA = batting average
PA = plate appearances
H = hits
BB = bases on balls (walks)
[Code] ....
I am just trying to get a code going for a mock test and to get use to the getline and IF operations, but it seems I have ran into an issue[URL] is a link to the code I have written, and I can use getline to give a value to my variable, but it seems like it gets lost once I try to use the IF function. Am I not using the right variable type?
View 14 Replies View RelatedCode:
int i=5,j;
j=++i + ++i + ++i;
printf("%d",j); //22
i=5;
j=i++ + i++ + i++;
printf("%d",j); //19 Shall not it give 21 and 18 respectively?????
I need to run some operation if a key from keyboard is pressed. so I go with
Code: c=getchar();
to get it read. yet the user could press a key anytime; so I'd need some if-loop. no plans on how it'd look like though...I suppose something like this below wouldn't work right?
Code:
if(getchar()==1){
..
}
How do I do the operation of two integers that gives you the results?
I'm supposed to write a program that:
Asks the user for an integer
Asks the user for one of '+', '-', '*', or '/' (as a character)
Asks the user for another integer
Performs the given operation on the two integers, and prints out the result of
Please enter an integer: 4
Please enter an operation (+, - , *, /): *
Please enter another integer: 5
4 * 5 = 20
Code:
#include <iostream>
using namespace std;
int main() {
int x;
int c;
int d;
char e;
[Code] ....
#include<iostream.h>
#include<conio.h>
class date {
int dd,yy,day,*incr;
char *mon; //first latter
public:
void setptr(date *m);
[Code] ....
I have union of pointer.
union {
short *two_int;
int *four_int;
double *eight_real;
char *one_ascii;
// void *v;
};
We have write function which write into file.
fwrite (r.one_ascii, 1, i, outstr);
I found one thing,When we write function, we fill only four int in following way.
r.four_int[0] = x + xoff;
r.four_int[1] = y + yoff;
So my question,we fill four_int but write one_ascii only.As is it union of pointer. So it does not matter. I am using 64bit machine and do not have any issue in 32 bit machine.
For more information: [URL] ....
So I am making a game and I want to push performance to the limit. That's why I really want to know how many clock cycles every operation, cast, memory allocation - EVERYTHING takes. Or approximate time consumption ratio, anything like that.
I tried doing it myself: I created a timer based on clock cycle counting, measured time of an empty loop and the same loop with various operations inside, but the results were extremely inconsistent and confusing: empty loop would take more time that the same loop with an addition, the time would vary greatly,... I guess it's because of background operations using up some of the CPU...
Since I didn't manage to find anything on the internet I guess there might be something I'm missing: maybe it depends on the processor?