So I am making a game and I want to push performance to the limit. That's why I really want to know how many clock cycles every operation, cast, memory allocation - EVERYTHING takes. Or approximate time consumption ratio, anything like that.
I tried doing it myself: I created a timer based on clock cycle counting, measured time of an empty loop and the same loop with various operations inside, but the results were extremely inconsistent and confusing: empty loop would take more time that the same loop with an addition, the time would vary greatly,... I guess it's because of background operations using up some of the CPU...
Since I didn't manage to find anything on the internet I guess there might be something I'm missing: maybe it depends on the processor?
The system clock starts once the system is executed. But how can I update the clock value to certain other value? Let say, for example. If a=10, then, immediately the clock is set to 10 seconds after the current clock time. Is it possible?
Program should continually have user enter a positive integer, and quits on zero entered. This entered number represents the total number of seconds and after each number is entered a function is called that displays the time in hours, minutes and seconds. Sample output is as follows:
Enter Total Seconds --> 3605 1:00:05
The function needs only one value parameter and should return nothing back to main. If the minutes or seconds are a one digit number then make sure to display a leading zero as the example above shows.
Here is my program. my question is how do i make the numbers appear like this? 1:00:05
#include <iostream> #include <iomanip> using namespace std;
I am reading up on the clock() function: URL....It states: "On a 32bit system where CLOCKS_PER_SEC equals 1000000 this function will return the same value approximately every 72 minutes."
How could this return the same value, if clock is the number of clock ticks elapsed since program execution. Wouldn't the number of clock ticks continue to grow, and as such, when we divide by 1000000, the return value should continue to grow. So how does this function return same value every 72 minutes?
Make an "analog clock" that is, a clock with hands that move. You get the time of day from the operating system through a library call. A major part of this exercise is to find the functions that give you the time of day and a way of waiting for a short period of time (e.g., a second for a clock tick) and to learn to use them based on the documentation you found. Hint: clock(), sleep().
OK, I wrote below code. It is in its primary stages and has not been completed yet.
#include <GUI.h> #include <time.h> #include <iostream> using namespace Graph_lib;
[Code] .....
I expect the system in void clock_hands() (line 38) attaches hour1 (line 41) then waits for 1000 ms (using Sleep(1000)) then detaches hour1 and attaches hour2 this time. But it doesn't occur in practice. When the system reaches Sleep(1000); it seems to go into a comma! It doesn't show the hour1 so seeing the movement of clock ticks by the clock's hands will not be possible.
The question says: Make an "analog clock" that is, a clock with hands that move. You get the time of day from the operating system through a library call. A major part of this exercise is to find the functions that give you the time of day and a way of waiting for a short period of time (e.g., a second for a clock tick) and to learn to use them based on the documentation you found. Hint: clock(), sleep().
OK, I wrote below code. It is in its primary stages and has not been completed yet.
Code: #include <GUI.h> #include <time.h> #include <iostream> using namespace Graph_lib; //--------------------------------- class Dynamic_clock : public Window {
[Code] .....
I expect the system in void clock_hands() (line 38) attaches hour1 (line 41) then waits for 1000 ms (using Sleep(1000)) then detaches hour1 and attaches hour2 this time. But it doesn't occur in practice. When the system reaches Sleep(1000); it seems to go into a comma! It doesn't show the hour1 so seeing the movement of clock ticks by the clock's hands will not be possible.
This is a round robin execution. with gantt chart. arrival time and burst time. I think there is an error in my formula to get the right answer,i cant resolve it but my program is running. What is the code or the right formula??
#include<stdio.h> int main(){ int i,j=0,n,time,remain,flag=0,ts; int sum_wait=0,sum_turnaround=0,at[10],bt[10],rt[10]; int ganttP[50],ganttStartTime[50]; printf("Enter no of Processes : "); scanf("%d",&n); remain=n;
I am just trying to get a code going for a mock test and to get use to the getline and IF operations, but it seems I have ran into an issue[URL] is a link to the code I have written, and I can use getline to give a value to my variable, but it seems like it gets lost once I try to use the IF function. Am I not using the right variable type?
I need to run some operation if a key from keyboard is pressed. so I go with
Code: c=getchar();
to get it read. yet the user could press a key anytime; so I'd need some if-loop. no plans on how it'd look like though...I suppose something like this below wouldn't work right?
How do I do the operation of two integers that gives you the results?
I'm supposed to write a program that:
Asks the user for an integer Asks the user for one of '+', '-', '*', or '/' (as a character) Asks the user for another integer Performs the given operation on the two integers, and prints out the result of
Please enter an integer: 4 Please enter an operation (+, - , *, /): * Please enter another integer: 5
4 * 5 = 20
Code: #include <iostream> using namespace std; int main() { int x; int c; int d; char e;
union { short *two_int; int *four_int; double *eight_real; char *one_ascii; // void *v; };
We have write function which write into file.
fwrite (r.one_ascii, 1, i, outstr);
I found one thing,When we write function, we fill only four int in following way.
r.four_int[0] = x + xoff; r.four_int[1] = y + yoff;
So my question,we fill four_int but write one_ascii only.As is it union of pointer. So it does not matter. I am using 64bit machine and do not have any issue in 32 bit machine.
I have to build a program that calculates the remainder of the expression
(2^10)!/((2^10-500)! * 500!)
when divided by 10^9+7
where x^y = x*x*x*x...*x (y times) and x! = x*(x-1)...*1
How can I do that? I know how to calculate the remainder of x! and the remainder of y!, but I do not know how t calculate the remainder of x!/y!. I can´t even store this in a variable because x! is very large.
This program is meant to present users with a list of rooms they then press the 'Select' button and it starts the relevant program for that room. However when running the program on Windows 8 it is giving an error that 'The requested operation requires elevation.'
using System; using System.IO; using System.Collections.Generic; using System.ComponentModel; using System.Data;
[code]....
P.s. It runs the programs as local administrator so that the user does not get prompted for UAC permission, as this is something the users find very annoying!
I had created windows service .from that i just want to insert data into database . It is successfully installed but it is not started. It gives an error service could not started...
I am having some column say "Response" column in my Datatable.Now I want to fetch this particular column value and compare this value with the maximum response how to fetch and compare it in C#.net .. This is my code.
for (int i = 0; i < DataFilter.Rows.Count; i++) { DataRow dr = DataFilter.Rows[i]; DataView dv2 = new DataView(); dv2 = DataFilter.DefaultView;
I have a VC++ 6 dialog-based application. This application is intended for reading data from a USB device (this is a FTDI FT245R chip). I have a start button on the dialog. On clicking it, unsigned char data retrieved from the USB device is displayed on the dialog. The start button invokes a function which includes a while (1) loop inside which the USB device is read and the values displayed.
There are no break or continue statements inside the always operating while (1) loop. All this works fine. My problem is how do I exit the application as normally it would just run forever? I have put an exit button on the dialog with code added to call OnOK(). Normally this would nicely close the application but as I have an endless while loop in my application so this button doesn't seem to work. Nothing happens on clicking it and clicking it repeatedly just hangs the program.
error C2995: 'foo<l+r> operator *(const foo<s> &,const foo<r> &)' : function template has already been defined see declaration of 'operator *' see reference to class template instantiation 'foo<s>' being compiled with [ s=4 ]
If I change the operator to return a foo<s> it does compile (but that's not the behaviour I need).
if I move the operator to outside the class (removing the 'friend') it does compile and behaves how I need, but I can't access non-public members so I can't write the implementation correctly.
A process is writing data continuously to a file . I need to stop the write operation if the file size has reached 1GB. Is there any way to check file size when it is opened for the write operation.
I could do the same using scripts. Can this be done using C Programming ?
I trying to write a code for a calculator using stack is how to convert an operation from infix to postfix . Here is my attempt I created a header file.
#ifndef STACK_H #define STACK_H #include <iostream> using namespace std; template<class T> struct node { T item;
