C++ :: How Does Clock Return Same Value Every 72 Minutes
Apr 19, 2014
I am reading up on the clock() function: URL....It states: "On a 32bit system where CLOCKS_PER_SEC equals 1000000 this function will return the same value approximately every 72 minutes."
How could this return the same value, if clock is the number of clock ticks elapsed since program execution. Wouldn't the number of clock ticks continue to grow, and as such, when we divide by 1000000, the return value should continue to grow. So how does this function return same value every 72 minutes?
The system clock starts once the system is executed. But how can I update the clock value to certain other value? Let say, for example. If a=10, then, immediately the clock is set to 10 seconds after the current clock time. Is it possible?
So I am making a game and I want to push performance to the limit. That's why I really want to know how many clock cycles every operation, cast, memory allocation - EVERYTHING takes. Or approximate time consumption ratio, anything like that.
I tried doing it myself: I created a timer based on clock cycle counting, measured time of an empty loop and the same loop with various operations inside, but the results were extremely inconsistent and confusing: empty loop would take more time that the same loop with an addition, the time would vary greatly,... I guess it's because of background operations using up some of the CPU...
Since I didn't manage to find anything on the internet I guess there might be something I'm missing: maybe it depends on the processor?
Make an "analog clock" that is, a clock with hands that move. You get the time of day from the operating system through a library call. A major part of this exercise is to find the functions that give you the time of day and a way of waiting for a short period of time (e.g., a second for a clock tick) and to learn to use them based on the documentation you found. Hint: clock(), sleep().
OK, I wrote below code. It is in its primary stages and has not been completed yet.
#include <GUI.h> #include <time.h> #include <iostream> using namespace Graph_lib;
[Code] .....
I expect the system in void clock_hands() (line 38) attaches hour1 (line 41) then waits for 1000 ms (using Sleep(1000)) then detaches hour1 and attaches hour2 this time. But it doesn't occur in practice. When the system reaches Sleep(1000); it seems to go into a comma! It doesn't show the hour1 so seeing the movement of clock ticks by the clock's hands will not be possible.
I am currently working on a lab for my intro to programming class and the lab is asking for a long distance call calculator. Based on the times that you start your rate will change. If the call starts from 00:00 to 07:59, Rate = $0.07. If the call starts from 08:00 to 18.59, Rate = $0.12. Lastly if the call starts from 19:00 to 23:59, your rate is $0.28.
Then on the output you must show the start time, end time, rate, and total cost of the call.
My confusion is on the end part of the code (the output).
I know you have to use the % operator to convert minutes to hours, but I don't completely understand it which is why I am here. How does the modulus do that? And how will it go over to the next hour if the call starts at 1:35 and ends after 30 minutes (2:05)?
Here is what I have so far.
#include <iostream> #include <string> using namespace std; int main() { float callStart, minutes; double cost; char choice('Y'); string rate;
The question says: Make an "analog clock" that is, a clock with hands that move. You get the time of day from the operating system through a library call. A major part of this exercise is to find the functions that give you the time of day and a way of waiting for a short period of time (e.g., a second for a clock tick) and to learn to use them based on the documentation you found. Hint: clock(), sleep().
OK, I wrote below code. It is in its primary stages and has not been completed yet.
Code: #include <GUI.h> #include <time.h> #include <iostream> using namespace Graph_lib; //--------------------------------- class Dynamic_clock : public Window {
[Code] .....
I expect the system in void clock_hands() (line 38) attaches hour1 (line 41) then waits for 1000 ms (using Sleep(1000)) then detaches hour1 and attaches hour2 this time. But it doesn't occur in practice. When the system reaches Sleep(1000); it seems to go into a comma! It doesn't show the hour1 so seeing the movement of clock ticks by the clock's hands will not be possible.
I have a function which sometime takes more than 24 hours to run. So I want a code which will check the time and exit the function if the function executin is not successful and return to main function.
Program should continually have user enter a positive integer, and quits on zero entered. This entered number represents the total number of seconds and after each number is entered a function is called that displays the time in hours, minutes and seconds. Sample output is as follows:
Enter Total Seconds --> 3605 1:00:05
The function needs only one value parameter and should return nothing back to main. If the minutes or seconds are a one digit number then make sure to display a leading zero as the example above shows.
Here is my program. my question is how do i make the numbers appear like this? 1:00:05
#include <iostream> #include <iomanip> using namespace std;
Understanding Fork() calls. I have to write a C program in UNIX machine, and make two Fork Calls Inside it and have these two instances run every five minutes all round the clock. How to achieve this.
I want to add a count down timer to my testing software 1hr and 30min
Its a 32bit console application, I want the countdown timer outputted above each question on the right side, timer only needs to output the time left at the top of each question so a live outputted timer is not important.
Questions are not random generated.
Also how to output "out of time" if the timer reaches 0 and for the test to end, I think branching is involved not too sure.
I already have, std::srand( std::time(0) ) ; at the start of the test to randomly generate the answer order.
I am looking for a function or any example that shows elapsed time in seconds and minutes. I didn't find any solution for both OS Win and Linux. I am looking for example that works for both - win and linux.
Design, implement, and test a class that represents an amount of time in minutes and seconds. The class should provide a constructor that sets the time to a specified number of minutes and seconds. The default constructor should create an object for a time of zero minutes and zero seconds. The class should provide observers that return the minutes and the seconds separately, and an observer that returns the total time in seconds (minutes x 60 + seconds). Boolean comparison observers should be provided that test whether two times are equal, one time is greater than the other, or one time is less than the other. (You may use RelationType and function ComparedTo if you choose). A function should be provided that adds one time to another, and another function that subtracts one time from another. The class should not allow negative times (subtraction of more time than is currently stored should result in a time of 0:00). This class should be immutable.
this is one of my main errors: Error1error C2653: 'Time' : is not a class or namespace namec:userskdesktop oane statecisp 1610visual studioschapter 12 assignmentchapter 12 assignmentchapter 12 assignment.cpp131Chapter 12 Assignment
The problem is that I need to figure out the user's birthday in months, days, hours, and minutes from today's date.
Here's what I have so far.
#include<iostream> #include<cmath> #include<ctime> using namespace std; int main() { int todayDay, todayMonth, todayYear; int birthDay, birthMonth, birthYear;
[Code] ....
I haven't initialized all the variables, yet. And it's very unfinished. I need to figure out how to convert years from the age into months only. And I need to figure out how to calculate the hours, seconds, and minutes.
I'm writing some functions pertaining to binary trees. I've used recursion once before while learning quicksort but am still quite new and unfamiliar with it. And this is my first time touching a binary tree. So my question: In my addnode function, will the return root statement at the end ever return a value other than the value passed to the function?
#include <iostream> using namespace std; int n; int& test();
[Code] ....
Explanation
In program above, the return type of function test() is int&. Hence this function returns by reference. The return statement is return n; but unlike return by value. This statement doesn't return value of n, instead it returns variable n itself.
Then the variable n is assigned to the left side of code test() = 5; and value of n is displayed.
I don't quite understand the bold sentence. Shouldn't value of n and variable n be the same?
I want to convert seconds into hours, min and seconds. I was able to test it with a small equation turning seconds into hours but now it returns zeros for every entry.
Code: #include <stdio.h> void secCount(int *seconds, int *hours, int *min, int *sec); int main(int argc, const char * argv[]) { int sec=0, hours=0, min=0, seconds =0;
In my program below, in the getage and get level functions, if an incorrect input is entered, then the correct one is entered after, it still returns the bad input back to main.
myClass is a class I have. Now, in the class, I have a function what_value and I need to get the classes.at(0) from the pointer to it in another function. But the problem is, how can I do it? I'm completely stumped, here's what I thought of:
newClass.*myclass.what_value();
And it I get an error from the compiler. Basically, how can I do this in another function with a pointer:
I'm going to write a program that takes string until end of file(eof). An condition must be considered and that is it must also terminate by a new line. For example when it's prompting me to enter a string if I press enter it must terminate and exit the program. How is it possible? I tried saving carriage return("") as a string then I compared it with the entered string but it didn't work.
