I'm going to write a program that takes string until end of file(eof). An condition must be considered and that is it must also terminate by a new line. For example when it's prompting me to enter a string if I press enter it must terminate and exit the program. How is it possible? I tried saving carriage return("") as a string then I compared it with the entered string but it didn't work.
View 5 RepliesI am using C++ to write data into a (.ini)file. However, when I try to print the value '0A' I am getting '0D 0A'. (this is what I see when I copy the output to HexEdit). From what I can figure out, '0A' is the ascii for 'new line' so write function automatically adds the '0D' which is 'carriage return'. What I want is to print 0A alone. how can I do this?
Note: Windows it is working fine, but linux it is not working...
unsigned char arrRes[4];
int N = 10;
memcpy(arrRes,&N,4);
std::ofstream Output(LUT_OUTPUT_FILE_BINARY,std::ios_base::binary | std::ios_base::out);
Output.write((const char*)arrRes, 4);
here 10 means 0x0a but it is printing 0d,0a...
I'm writing some functions pertaining to binary trees. I've used recursion once before while learning quicksort but am still quite new and unfamiliar with it. And this is my first time touching a binary tree. So my question: In my addnode function, will the return root statement at the end ever return a value other than the value passed to the function?
Code:
#include <stdlib.h>
struct tnode
{
int data;
struct tnode * left;
struct tnode * right;
}
[code]....
From the page: [URL] ....
#include <iostream>
using namespace std;
int n;
int& test();
[Code] ....
Explanation
In program above, the return type of function test() is int&. Hence this function returns by reference. The return statement is return n; but unlike return by value. This statement doesn't return value of n, instead it returns variable n itself.
Then the variable n is assigned to the left side of code test() = 5; and value of n is displayed.
I don't quite understand the bold sentence. Shouldn't value of n and variable n be the same?
difference between return 0 and return -1 .and exit(0) and exit(1)
View 1 Replies View RelatedIn my program below, in the getage and get level functions, if an incorrect input is entered, then the correct one is entered after, it still returns the bad input back to main.
#include "stdafx.h"
#include <cstdlib>
#include <iostream>
#include <string>
#include <cstring>
#include <cmath>
[Code] ....
Here is what's up:
struct Square {int number, myClass* myclass};
int main() {
vector<myClass> classes;
myClass unrelated;
classes.push_back(unrelated);
Square newClass = {3, &classes.at(0)};
.
.
.
myClass is a class I have. Now, in the class, I have a function what_value and I need to get the classes.at(0) from the pointer to it in another function. But the problem is, how can I do it? I'm completely stumped, here's what I thought of:
newClass.*myclass.what_value();
And it I get an error from the compiler. Basically, how can I do this in another function with a pointer:
classes.at(0).what_value();
Is it possible to have more than 1 return value from a subprogram?
View 5 Replies View RelatedWhy my function will not return this int. It does make it into the if(... prints "test 32" but will not return the given value(123456789).
#include <iostream>
using namespace std;
int lastZero(int x[]);
int main(){
int myArray[] = {1,1,1};
lastZero(myArray);
[Code] ...
#include <iostream.h>
#include <conio.h>
int main ()
{
cout << "Hello World";
getch();
return 0;
}
In the above code, why is it necessary to write getch() and return 0? What is their purpose?
How can I return other object's value in a function(see code and comments)?
Person.h
Code:
#include <iostream>
#include <string>
using namespace std;
class Person{
public:
Person();
Person(string pname, int page);
[Code] ....
So the task is to find the node with minimum value of a binary tree (not binary search tree). the input is the pointer to the root of the tree. and i cannot make recursion work when i do if conditions. here is what i have Code: /*function 3-takses as input the pointer to the root of the tree and returns a pointer to the node with the minimum value*/
CPPtr minimumvalue(CPPtr SP){
CPPtr min = NULL; //node of minimum value
if(SP== NULL){ // if there is a node, begin comparing
return NULL;
}
else{
if(SP->data<SP->left->data){ //if the node has smaller value than its left child
min = SP; //update node of minimum value
[code].....
no matter where i call my function i get errors like unhandled exception at some memory. how to use recursion in this?
Code:
returnType operatorOperatorSymbol (parameterList); // syntax for operator overloading
Class Fraction
public:
Fraction operator-(const Fraction& f1){
Fraction r;
return r;
}
Is this even syntactically correct? It gives me errors. Im just trying to compile it without errors. I think the function makes sense since its returning a type Class
I wanted to return a string I can do
Code:
string parseFilename(string fileName){
return fileName.subtr(/*blah*/);
}
Can I also use pointers/references here though? When would you use a pointer and when just a return statement?
I have a function that needs to return a "uint8_t" value. However before doing the processing I need to perform a test on the argument to check if it's between expected boundaries. Although this function works it gives (a logical) warning that not always a value is returned although expected. What is the normal way for functions like these where I normally should return e.g. -1 in case the test doesn't succeed and otherwise the uint8_t (t) value?
Code:
uint8_t myFunc(int a) {
if (a >= 0 && a <= 100) {
// Perform actions
uint8_t = ...
return t;
}
}
understand the below program.
Why I'm getting output y is 6.000000
Code:
#include <stdio.h>
int square(double a);
int main()
[Code].....
Here is the part of my code that I need to return two values. I am working on a roulette program and I need to return the choice and the number they are betting on. How can I use a pointer to achieve this?
Code:
int makeBet(char choice, int num){
printf("
What type of bet would you like to place? ");
printf("
Type n for number.
Type e for even/odd.
Type d for dozen.
[Code] ....
If i declare a function as a void function. But for testing purpose if i use a return statement in the function definition. i have tested and found that the function does not return and executes the entire function. How does the function not return even if a return statement is available? Does the compiler removes this return statement or how it is?
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View 5 Replies View RelatedI'm having a problem with the strcmp return value. My compiler returns the correct value based on my research, but I tried to compile the code below on those online compilers and the result was 1.
My compiler gave me 10, which I consider to be the correct result according to strcmp - C++ Reference. So strcmp is not very portable?
Code:
#include <stdio.h>
#include <string.h>
int main(void) {
printf("Return value: %d
", strcmp("Rocks", "Rockie"));
return 0;
}
How would I go about getting a loop to return to the start?
View 2 Replies View RelatedI am trying to return a pointer from a method. Below is a sample of my code.
CSubnode * CTest::GetSubNode() {
return m_psubnode;//this is declared in CTest as CSunbnode * m_psubnode
}
//in another class
m_subnode = m_ptest->GetSubNode(); //m_subnode is declared as a pointer
Is this the correct why to return a pointer?
I am reading up on the clock() function: URL....It states: "On a 32bit system where CLOCKS_PER_SEC equals 1000000 this function will return the same value approximately every 72 minutes."
How could this return the same value, if clock is the number of clock ticks elapsed since program execution. Wouldn't the number of clock ticks continue to grow, and as such, when we divide by 1000000, the return value should continue to grow. So how does this function return same value every 72 minutes?
How we can return a 3x3 matrix in c++ function.
My code is:
double *computeA() {
double *A = new double[2][2];
// some operations on A and then return
return A;
}
The error that I have in this case is:
error C2440: 'initializing' : cannot convert from 'double (*)[2]' to 'double *'
I am working through Binary IO with objects and am running into a curious error.
The program executes perfectly until it hits the very end. At "return 0", the program fails. The debugger picks up SIGABRT when executing "return 0". This seems to me to indicate a deconstructor problem of some kind. However, I can't seem to find any deconstructor problems (I am fairly new at programming though).
If I comment out the following two lines:
"binaryio.read(reinterpret_cast<char *>(&studentNew1), sizeof(Student));"
"binaryio.read(reinterpret_cast<char *>(&studentNew2), sizeof(Student));"
then the program finishes exiting without error . . . . but the whole point is to be able to read from the binary file. With those two lines in the code, the program successfully reads from the file and outputs the objects to the console ,but fails at "return 0";
Here is the code:
#include <iostream>
#include <fstream>
#include "Student.h"
using namespace std;
void displayStudent(Student student) {
cout << student.getFirstName() << " ";
[Code] .....
I need a function to return a string..i need to pass input as "a,b,c,a,c,d,e" function should return out put as "a,b,c,d,e".
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