C++ :: Why Are Arithmetic Operations Like Division And Multiplication Invalid On Pointers
Feb 15, 2013why are the arithmetic operations like division(p/q) and multiplication(p*q) invalid on pointers?.here p and q both are pointers .
View 6 Replieswhy are the arithmetic operations like division(p/q) and multiplication(p*q) invalid on pointers?.here p and q both are pointers .
View 6 RepliesC++ only allow addition and subtraction operation with pointer .why multiplication and division is not allowed? Then how to perform multiplication and division with pointer
View 3 Replies View Related how to use template parameters to perform arithmetic operations on objects.
I feel that it would best to demonstrate my issue rather than try and explain it.
Sample:
// Fundamental object structure
template<int T> struct myInt
{
myInt() { value = T; };
[Code]....
What I don't know is how to get a hold of the T variable to add them through the 'add' structure. Also, might any of this have to do with sequence wrappers?
seq_c<T,c1,c2,... cn> is essentially what I'm thinking of. Where T in this case is the type and c to the nth c are the values.
At one point in my C++, non-CLR program, the following code:
Code:
unsigned int size = 3;
float maxX = (float)(int(size-1))/2.0f;
std::cout << maxX;
outputs 107. Is it something about a conversion from unsigned int to float?
I heard that the speed of floating point multiplication is much faster than division. Is it still the case today?
View 14 Replies View RelatedWhile executing this code i was getting a error Invalid lvalue in assignment. Can any one tell how to correct this.
dataItem* d=(dataItam*)malloc(10*sizeof(dataItem));
dataItem* temp;
temp=(d+6);
(d+6)=(d+8);//error line
(d+8)=temp;//error line
Code:
#include<stdio.h>
#include<conio.h>
void main()
[Code] .....
This program on running returns an error of "ILLEGAL USE OF POINTER".
Code:
#include<stdio.h> Code: #include<conio.h>
void main() {
int *a[2][2],*b[2][2],*c[2][2],i,j,k;
Printf("
ENTER a MATRIX ELEMENTS
[Code] .....
I have the following details
double x= 1.5
double y= -1.5
int m= 20
int n= 4
my question is 5 * x - n / 5 at which what would n / 5 equal to, I think its zero since its integer division? or would the 5 be considered a real number?
what I do I cannot get a division to work:
Code:
//END RANGE INPUT
long double End;
printf("
Please enter the start of the range (Lower Bound):
");
[Code]...
No matter what I input for the values of 'Start', 'End' and 'Interval', the value of 'SizeL' always seems to be -2.
I want to find the remainder of the division between a and b, but without using the reminder operator a%b.I thought to subtract b from a as long as a>b, that will give the remainder, but I don't know how to write it in code.
View 11 Replies View RelatedHow do i get this with decimal part?:
for(i=1;i<=4;i++){
printf("%d
",m);
s = s + m/i
m = m + 2;
}
m/i?
I have to build a program that calculates the remainder of the expression
(2^10)!/((2^10-500)! * 500!)
when divided by 10^9+7
where x^y = x*x*x*x...*x (y times)
and x! = x*(x-1)...*1
How can I do that? I know how to calculate the remainder of x! and the remainder of y!, but I do not know how t calculate the remainder of x!/y!. I can´t even store this in a variable because x! is very large.
Question about instead of using the division operator to display the output of user"s input....
View 4 Replies View RelatedSo I am using Visual Studio 2012 Professional, this is C++ code. I am just trying to get the remainder from a very simple division. Nothing difficult, heres the code:
double getProbability(){
int rd = random();
int max = numeric_limits<int>::max();
double result = rd % max;
cout << "Probability: " << result << "
";
return result;
}
When I look at the values in debug I get:
max 2147483647
rd 1804289383
result 1804289383.0000000
That is completely wrong. The answer should be 0.840188. What is going on here?
random() just returns a number from a vector that was prepopulated with "random" integers. Not really random, but that isn't all that important. What is important is why on earth is a % operation returning such a huge number. I assigned the values to variables so I could look at them in the debugger. I know I am going to probably get a thousand different ways that I could do this "better" but again, that isn't what I am looking for. I would just like to know why the % operation is doing what it is doing?
This code works very oddly.
Code:
#include <algorithm>
#include <cstdlib>
#include <iostream>
[Code].....
One thing that I was not able to fully understand even though I read through the section on it a few times, is the for loop. I mean, I understand the premise of (statement, condition, update statement). However, I do not quite understand how a math problem is affected by this.
How this works using multiplication and division? And lastly, why would you use a do.. while loop?
For class I need to write a program that inputs a file (the dividend), performs binary division on the file (using 0x12 as the divisor), and outputs the remainder(checksum).
I have researched binary division algorithms and I get the general gist, but I'm still unsure where to start. How would I store the dividend and divisor? As two arrays of bits?
Then, I need to figure out how to perform shifts and XORs on the the binary numbers. Maybe I should use bitwise operations?
I've got this string: Code: char * string = "2+2"; I want to get an integer value = 4 from this. How would I go about doing this.
View 1 Replies View RelatedI am a c++ leaner, I am trying to create a BST tree for this expression: 2346*+/8+, and do inorder and postorder to get the in-fix version, and postfix version of the expression. I am having difficulty to create the binary tree for the expression. Here is my peso code:
Tree:
Stack:
inorder fn{}
postorder fn{}
main{
input the file;
while(expression){
[Code] ....
The tree I want to create is like this
+
/
(/) 8
/
+ 2
/
* 3
/
4 6
My problem for this code is that after create (4*6) tree, I cant link (+3) with (4*6).
I made a program that prints out arithmetic sequence.. but problem is that,
when I enter a(first term) =5, d(differnce)=2.4 and n=3 the program prints out only first two terms not three.. for all the other numbers it works correctly..
Say I wanted to overload the modulus operator to return the remainder of a division between two floating point numbers. Why isn't a custom double operator%(double, double) allowed even though that function isn't available in the standard anyway?
View 5 Replies View RelatedI was required to write a program that takes a baseball players statistics and displays there averages. I was required to make 3 function in the file to perform this tasks. my problem I am having a division problem in the SLG function. My compiler does not require the system ("PAUSE"); command.
OUTPUT
The player's batting average is: 0.347
The player's on-base percentage is: 0.375
The player's slugging percentage is:
(test)AB = 101
(test)Tot Base = 58
0.000
Code:
/* Batting Average Program
file: batavg1CPP.cpp
Glossary of abbreviations:
BA = batting average
PA = plate appearances
H = hits
BB = bases on balls (walks)
[Code] ....
I want to create an unsigned arithmetic type that can hold a maximum size of 360. Without having to create a method.
It should be in such a manner that:
Code:
typedef uint8_t radius;
radius rotation = 0;
radius foo (radius rotation)
{ return --rotation;
}
returns 359, instead of 255, or 65535 or whatever max value the type I base my type on can hold.
#include <iostream>
#include <string>
using namespace std;
[Code]....
How to find the arithmetic mean of each column of the matrix and find the sum of all elements of this matrix?
Given integer matrix A of size NxM. Find the arithmetic average of each column and the sum of all matrix elements of the matrix.