A problem that lets the user enter any positive integer, but you do not have to check for this, and then calculates the sum of the digits and displays this to user. For example, if user enters 14503, the outputted sum of the digits would be 13. You need turn in an algorithm, C++ source code and output.
how do i even go about making 1 add to 4? and so on. I'm lost.
My problem needs to prompt the user to input an integer and then outputs both the individual digits of the number and the sum of the digits. An example would be entering 8030 and it spits out 8 0 3 0 as well as 8+0+3+0=11 and it needs to work with negative numbers.
Code:
#include <iostream>
#include <iomanip>
using namespace std;
int main() {
int base;
[Code] ....
Now I don't know if any of this is right a hint my professor gave us is that to get the fourth digit you would do base mod 10 and to get the first digit you do base divided 1000...
Code:
{
int power;
int counter=0;
int value=1;
cout << "Enter the power of 10 you want: ";
[Code] ....
I wrote a program with function my own function which count the digits of entered number. The problem is whatever i type it shows 0 digits.Why is that?
Code:
#include <iostream>
using namespace std;
int cikCipari (int skaitlis, int cipars);
int main()
[Code] .....
Write a C++ program that reads in two positive integers that are 20 or fewer digits in length and outputs the sum of the two numbers.
Your program will read the digits as values of type char so that the number 1234 is read as four characters '1', '2', '3' and '4'. After they are read into the program, the characters are changed to values of type int. The digits will be read into a partially filled array and you might find it useful to reverse the order of the elements in the array after array is filled with data from the keyboard.
Your program will perform the addition by implementing the usual pencil and paper addition algorithm. The result of the addition is stored in an array of size 20 and the result is written to screen. if the result of the addition is an integer with more than maximum number of digits(that is more than 20 digits) then your program should issue a message saying that it has encountered "integer overflow".
You should be able to change the maximum length of the integers by changing only one globally defined constant. Include the loop that allows the user to continue to do more additions until the user says the program should end.
For some reason the sum won't add or output though, This is what i have so far:
#include <iostream>
using namespace std;
const int MAXIMUM_DIGITS = 20;
void input_Large_Int (int a[], int& size_of_A); //input function for the two big integers
void output_Large_Int(int a[], int size_of_A); //output function for the two big integers and the sum integer
void add(int a[], int size_of_A, int b[], int size_of_B, int sum[], int & size_Sum); //add function for the big integers' sum
[Code] .....
Create a program that keeps on reading positive numbers until user enters a zero value, and then outputs the last positive number entered.
I do not know how to output the 'last positive number' and I do not even know am I doing things correctly so far....
Code:
#include <stdio.h>
int main() {
double num;
for(;;) {
printf("Enter a positive number: ");
scanf("%lf",&num);
[Code] ....
so basically my project goes like this:
Write a C++ program that reads in two positive integers that are 20 or fewer digits in length and outputs the sum of the two numbers.
Your program will read the digits as values of type char so that the number 1234 is read as four characters '1', '2', '3' and '4'. After they are read into the program, the characters are changed to values of type int. The digits will be read into a partially filled array and you might find it useful to reverse the order of the elements in the array after array is filled with data from the keyboard.
Your program will perform the addition by implementing the usual pencil and paper addition algorithm. The result of the addition is stored in an array of size 20 and the result is written to screen. if the result of the addition is an integer with more than maximum number of digits(that is more than 20 digits) then your program should issue a message saying that it has encountered "integer overflow".
You should be able to change the maximum length of the integers by changing only one globally defined constant. Include the loop that allows the user to continue to do more additions until the user says the program should end. What I have so far is
#include <iostream>
#include <cstdlib>
using namespace std;
void reverseArr(int a[], int liu);
void addLargeInt(int a1[], int liu1, int a2[], int liu2, int sum[], int& liu_sum);
int main() {
cin.get(next);
[Code]...
I am trying to find a way to put a getSmallest function in here so that it will output smallest integer entered. If it is just an arbitrary amount of #'s and I don't know what will be entered I am confused. Both on how to do it and how to link my function to my loop.
Code:
/* Prompts user and gets integer numbers from keyboard, one number at a time. Ends program when 99999 entered. and displays various results.
Written by:
Date: 10/20/14
*/
#include <stdio.h>
#include <stdlib.h>
[Code] .....
Could I take this and just replace all variables a, b, and c with getNumber, where would I link/declare smallest?
Code:
/* ==================== smallest ======================
This function returns the smallest of 3 integers.
Pre given 3 integers
Post the smallest integer returned
*/
int smallest (int a, int b, int c) {
[Code] ......
I am trying to find the max number entered by the user, and it should terminate when a negative number is entered. For my code, it will just end when the user inputs a lower number than the previous. i.e.- 10 20 15 "The highest number is 20" when it should be "10 20 5 40 15 -1" "The highest number is 40". No arrays or do/while loops either.
#include <iostream>
using namespace std;
int Max(int x);
int main() {
int x;
[Code] ....
Write the function itob(n,s,b) that converts the integer n into a base b character representation in the string s . In particular, itob(n,s,16) formats n as a hexadecimal integer in s .
Note that it says the result is formatted into a hexadecimal integer in the string s. Here is the example provided:
Code:
void itob(int n, char s[], int b) {
static char digits[] = "0123456789ABCDEFGHIJKLMNOPQRSTUVWXYZ";
int i, sign;
if ( b < 2 || b > 36 ) {
fprintf(stderr, "EX3_5: Cannot support base %d
[Code] ....
Why does digits array hold the full alphabet when the maximum digit for a hex number is f?
I know how to remove digits in number from right to left.For example: the number 319. If I do (number /= 10), I get 31.how can I remove digits in number from left to right.For example: the number 319. If I will do something, I will get the number 19.
View 15 Replies View Relatedconverting 8bit binary into 2 digit hex
how to do this?
im starting it now but going in the direction of using arrays
//Program to reverse 5 digit number
#include <stdio.h>
void main() {
int num, i = 0;
char rev[5];
printf("Enter any 5 digit number
[Code] ....
WHILE DISPLAYING i am not getting correct output. whats wrong in rev[] array.
Just wanted to share a program I made. It was the answer to one of the end chapter exercises in the C programming book I'm using, asking the reader to create a program that adds all the digits of an integer.
Code:
/* Program to calculate the sum of the digits in an integer */
#include <stdio.h>
int main () {
int number, right_digit, sum = 0;
[code]....
"Every number has at most 500 digits" under input. 500? How am I supposed to store that? And what if someone multiplies 999 ...(500 times) * 999 ... (500 times) ? I seriously doubt that my computer can store that! Is that just some huge value used to scare people off or is there some sneaky trick that I am unaware of?
I am done with the program, but won't post it, Lets not ruin the fum for ohers...Does that 500 limit also applies to result of operation?So max length of an input number is ~22 digits ? But still, how do I store 500 digits? Array would be a lot of wastage of memory (though I do have 256MB available).
How to get all the possible combinations for 4 digits from a 5 digit number. I need a pair that has both 5 digits and four digits. their sum must be equal to a five digit user input. i.e.
user input : 14690
output:
14690 has pairs 12345 + 2345
2345 came from 12345
lets say that x = 12345 and y =2345
besides y == x%10000
other formula can i have since if i use % and / i will have a lot of declarations....
I have been trying to write a recursive function to print the permutations of a n-digit number. This is the logic that i am trying to use.
1.call the permutation function,
2.keep the first digit in the first place and send the remaining 2 digits back to the permutation function recursively.
3.keep one of the two digits received and send the remaining digit to the permute function.
4. keep doing this till only one digit remains. this is the smallest solution so return it.
The aim is : If i have a natural number [max 5 digits] (say) n=13579. Then a[4]=1, a[3]=3, a[2]=5. a[1]=7. a[0]=9.
I start with a[4]= n/10000 .. then n= n - a[4]*10000;
then a[3]= n/1000. .. n= n - a[3]*1000;
i.e a[i]= n/10^i .... n= n - a[i]*10^i;
To reduce code size i used a for loop. The code is free from any syntax errors.
Its the "output" that is weird. I enter 13579 and what the program process is:
a[4]=1 a[3]=3 a[2]=5 a[1]=8 a[0]=5
Same goes for other numbers too.. leaving the most significant digit , the rest digits are just out of the logic!!
I am using CodeBlocks 12.11 and compiler is GNU GCC compiler.
Here is the output window: [URL] ....
Here is the code:
#include<iostream>
#include<math.h>
using namespace std;
int main() {
int n,a[5],i,t,dec,divisor; // n: storing number; t: copy of n,
[Code] .....
I wrote the following code to solve this problem:
Read, from the keyboard, an integer greater than or equal to 1 (store it in a variable of type int).
Convert the integer to its representation in string format isolate each digit of the integer, convert it to the corresponding character (char).
Present the resulting string on the screen.
#include <iostream>
#include <ctime>
#include <cstring>
#include <ctype.h>
#include <cmath>
using namespace std;
unsigned GetNumberOfDigits (unsigned i) {
return i > 0 ? (int) log10((int) i) + 1 : 1;
[Code] ....
Why is it answering like this?
INTEGER ? 1999
STRING : œ
I'm working on a class project, and I'm having a difficulty. Suppose I have: string a = "21" and string b = "30"; normally, a+b=2130 (i.e concatenation of the characters in the string) but suppose I want a+b=51 (i.e. numerical addition) how do I go about this?
View 1 Replies View RelatedC++ program to accept a value and split it digit by digit and display in name
E.g.: 123
>one two three
write a program that counts the number of digits in a file?
For example the file contains:
5 6 7 -8 9obvsefs
6 7 8i uhbnm
8 8
And the program returns: "The number of all digits is 10"
I'm sure this is pretty simple, but any way to do this. Essentially if I have an array with P collumns and V^P rows, how can I fill in all the combinations, that is, essentially, all possible numbers in base V of P digits.
For example, for P=3 and V=2
000
001
010
011
100
101
110
111
Keep in mind that this is an 2 dimensional array, not an array of ints.
For P=4 and V=3.
0000
0001
0002
0010
0011
0012
....
Having this array generated, the rest of work for what I'm trying to develop is trivial
This is a code I've written that should do the trick, but for some reason it gives this error on compiling:
"main.cpp:65: error: invalid types `double[3][9][double]' for array subscript"
Code:
for(i=0;i<P;i++) {
for(j=0;j<pow(V,i);j++) {
for(k=0;k<V;k++) {
for(l=0;l<pow(V,(P-i-1));l++) {
a[i][(j*V*pow(V,P-i-1) + l + k*pow(V,P-i-1))];
}
}
}
}
I'm fairly new to C++ and have been understanding until Ive hit this rock. Im trying to figure out how to indicate whether or not a first command line argument interpreted as an integer is a multiple of the sum of its own digits. I understand that logic as if you type 20 = 2(2+0) where 2 is a multiple and 3113 = 8 which is not a multiple but i feel hopeless trying to set it up. And here is my code.
Code:
#include <iostream>
using namespace std;
int main(int argc, char*argv[])
{
[Code] .....
I use rand function to generate a number which consists of 3-5 digits(e.134,1435,73463..). The user decides whether he wants a 3 digit,4 digit or 5 digit number.After that,the user tries to guess the number.Its like mastermind game.The user will enter a number (with the same amount of digits) and the program will calculate how many digits from the secret number he has found and also how many digits he has found in the correct position(e.if the generatir produces the number 32541 and the user tries the number 49581 the program should tell him that he found 3 digits (5,1,4) and 2 digits in the correct position(5,1)) so that after some tries he finds the secret number.My problem is with the functions so that i can compare the digit of each number,find the amount of same digits and the amount of digits in same position.
View 5 Replies View RelatedI've been working on a program that displays the number of digits in each line of a file, but I feel stuck. Take for example a file that contains these characters:
6347aaa9
54j
811111
6a
709
And I'm trying to display a result like this
1 //that's the number of the line 5 //the number of digits
2 2
3 6
4 1
5 3
Here's what I've written so far:
Code:
#include<stdio.h>
int main() {
char a=0;
int number_of_digits=0, linescount=0, num, number_of_digits_per_line=0;
FILE *inputFile;
if(!(inputFile=fopen("C:TestTest.txt","r")))
[Code]..
I also thought of using fgets and strlen but I am not very good with them and couldn't get the program to work correctly. It did work but it displayed all characters, letters included, not only digits.
How to return the value after the decimal point. For example:if two integer numbers are 3, 4 then (3+4)/2 is 3.5 the 5 after the decimal point is to be returned. if suppose it is 34.456 i have to return 456.
View 11 Replies View Related
