C++ :: Converting Binary Digits To Hex?
Apr 16, 2013converting 8bit binary into 2 digit hex
how to do this?
im starting it now but going in the direction of using arrays
converting 8bit binary into 2 digit hex
how to do this?
im starting it now but going in the direction of using arrays
I wrote the following code to solve this problem:
Read, from the keyboard, an integer greater than or equal to 1 (store it in a variable of type int).
Convert the integer to its representation in string format isolate each digit of the integer, convert it to the corresponding character (char).
Present the resulting string on the screen.
#include <iostream>
#include <ctime>
#include <cstring>
#include <ctype.h>
#include <cmath>
using namespace std;
unsigned GetNumberOfDigits (unsigned i) {
return i > 0 ? (int) log10((int) i) + 1 : 1;
[Code] ....
Why is it answering like this?
INTEGER ? 1999
STRING : œ
I want to convert the integer into a string.
int x = 693;
char chararr[max];
In my homework, x is unknown. but don't worry, I wont ask for the full code. I just need the part where you change the int into a string/array of char.
I'm thinking in circles from where to start?
c++ program that reads in a sequence of binary digits (values 0 and 1) and stores them into a STL container. The input should terminate on any input that is not a 0 or 1. After finishing the read-process, apply a "bit-stuffing" algorithm to the container. In this case the bit stuffing should occur after four consecutive bits of the same value.i,e. four 0's or four 1's.. Also write the de-stuffing code to process the stuffed data to recreate the original data and verify that the original data is recovered correctly.
View 6 Replies View RelatedI have written a code but i tried to alter it a little in this manner. But it seemed to not recognise what hexStack.getsize() > 0) is..??
while(hexStack.getSize() > 0)
{
//buffer being a previously declared int
buffer = hexStack.pop();
[Code]....
My problem needs to prompt the user to input an integer and then outputs both the individual digits of the number and the sum of the digits. An example would be entering 8030 and it spits out 8 0 3 0 as well as 8+0+3+0=11 and it needs to work with negative numbers.
Code:
#include <iostream>
#include <iomanip>
using namespace std;
int main() {
int base;
[Code] ....
Now I don't know if any of this is right a hint my professor gave us is that to get the fourth digit you would do base mod 10 and to get the first digit you do base divided 1000...
Code:
{
int power;
int counter=0;
int value=1;
cout << "Enter the power of 10 you want: ";
[Code] ....
I'm not the best at C but I'm trying to write a C function that basically opens a text file with assembler language does a syntax error check on it and then converts the binary data into hex.
This is my code so far:
Code:
#include <stdio.h>
#include <string.h>
int main(void)
{
FILE*fname;
char prompt;
char filename[15];
char text[100];
printf( "Please enter the name of the file you wish to open: " );
[Code]...
I'm trying to write a program that converts a decimal number to a binary one. I have most of the program written, but I am having a little bit of trouble. Whenever I enter a decimal number, the program will convert it correctly to binary, however, the last number is not included in the conversion. EX: Converting 37 into binary (0100101) yields 010010 when entered into the program. BTW the program must utilize recursion to achieve this goal.
#include <iostream>
using namespace std;
void decToBinary(int num1);
int main() {
int num1;
[code]....
This is the question: [URL] .....
Now I have the binary numbers printed out in my code, but I don't know how I can covert them into to decimal.
#include <iostream>
#include <iomanip>
#include <string>
#include <cmath>
using namespace std;
int main() {
int numberOfDigits;
int numberOfRows;
char flag;
[Code] ....
I want to read a Bitmap file in C language and produce the binary equivalent of it in the form of 0's and 1's.
View 1 Replies View RelatedI'm fairly new to C++ and programming in general and I'm trying to get a program to check the parameters of a binary string before converting that string to dec values. I have the user input 'num' line 39 - 42, but I want to reuse that same value in the 'void bin_to_dec()' function. Is there anyway I can use the same variable between void functions?
13 #include <bitset>
14 #include <sstream>
15 using namespace std;
16
17 void dec_to_bin(){
18 string mess;
[Code] ....
The program is supposed to convert a two digit hexadecimal number to its binary representation. My code runs without any problems but I do not know how to limit the user's input to two digits only. For example the person can input "1ABC" and the program will give the binary representation and I need it to only accept two digit only like for example "1A".
#include<stdio.h>
#define MAX 1000
int main(){
char binaryNumber[MAX],hexaDecimal[MAX];
long int i=0;
printf("Enter a two digit hexadecimal number: ");
[Code] ....
Write a program in c++ to accept a number and convert this number into binary or hexa decimal or octal number according to the user choice using the concept of array.
View 6 Replies View RelatedWrite a C++ program that adds three binary numbers of 8-bit each. Every number is stored into an array of 8 elements.
Example:
Array A
0 1 2 3 4 5 6 7
0 1 1 0 1 1 1 0
+
Array B
0 1 2 3 4 5 6 7
0 1 1 0 1 1 1 0
+
Array C
0 1 2 3 4 5 6 7
0 1 1 0 1 1 1 0
Store the result into an array D of 8 elements. Your program should show the decimal numbers for every binary number. Print screen of 6 answers. This means you should try your program six times with different numbers in every run and show the printed screen result.
Write the function itob(n,s,b) that converts the integer n into a base b character representation in the string s . In particular, itob(n,s,16) formats n as a hexadecimal integer in s .
Note that it says the result is formatted into a hexadecimal integer in the string s. Here is the example provided:
Code:
void itob(int n, char s[], int b) {
static char digits[] = "0123456789ABCDEFGHIJKLMNOPQRSTUVWXYZ";
int i, sign;
if ( b < 2 || b > 36 ) {
fprintf(stderr, "EX3_5: Cannot support base %d
[Code] ....
Why does digits array hold the full alphabet when the maximum digit for a hex number is f?
I know how to remove digits in number from right to left.For example: the number 319. If I do (number /= 10), I get 31.how can I remove digits in number from left to right.For example: the number 319. If I will do something, I will get the number 19.
View 15 Replies View RelatedA problem that lets the user enter any positive integer, but you do not have to check for this, and then calculates the sum of the digits and displays this to user. For example, if user enters 14503, the outputted sum of the digits would be 13. You need turn in an algorithm, C++ source code and output.
how do i even go about making 1 add to 4? and so on. I'm lost.
//Program to reverse 5 digit number
#include <stdio.h>
void main() {
int num, i = 0;
char rev[5];
printf("Enter any 5 digit number
[Code] ....
WHILE DISPLAYING i am not getting correct output. whats wrong in rev[] array.
Just wanted to share a program I made. It was the answer to one of the end chapter exercises in the C programming book I'm using, asking the reader to create a program that adds all the digits of an integer.
Code:
/* Program to calculate the sum of the digits in an integer */
#include <stdio.h>
int main () {
int number, right_digit, sum = 0;
[code]....
"Every number has at most 500 digits" under input. 500? How am I supposed to store that? And what if someone multiplies 999 ...(500 times) * 999 ... (500 times) ? I seriously doubt that my computer can store that! Is that just some huge value used to scare people off or is there some sneaky trick that I am unaware of?
I am done with the program, but won't post it, Lets not ruin the fum for ohers...Does that 500 limit also applies to result of operation?So max length of an input number is ~22 digits ? But still, how do I store 500 digits? Array would be a lot of wastage of memory (though I do have 256MB available).
How to get all the possible combinations for 4 digits from a 5 digit number. I need a pair that has both 5 digits and four digits. their sum must be equal to a five digit user input. i.e.
user input : 14690
output:
14690 has pairs 12345 + 2345
2345 came from 12345
lets say that x = 12345 and y =2345
besides y == x%10000
other formula can i have since if i use % and / i will have a lot of declarations....
I have been trying to write a recursive function to print the permutations of a n-digit number. This is the logic that i am trying to use.
1.call the permutation function,
2.keep the first digit in the first place and send the remaining 2 digits back to the permutation function recursively.
3.keep one of the two digits received and send the remaining digit to the permute function.
4. keep doing this till only one digit remains. this is the smallest solution so return it.
The aim is : If i have a natural number [max 5 digits] (say) n=13579. Then a[4]=1, a[3]=3, a[2]=5. a[1]=7. a[0]=9.
I start with a[4]= n/10000 .. then n= n - a[4]*10000;
then a[3]= n/1000. .. n= n - a[3]*1000;
i.e a[i]= n/10^i .... n= n - a[i]*10^i;
To reduce code size i used a for loop. The code is free from any syntax errors.
Its the "output" that is weird. I enter 13579 and what the program process is:
a[4]=1 a[3]=3 a[2]=5 a[1]=8 a[0]=5
Same goes for other numbers too.. leaving the most significant digit , the rest digits are just out of the logic!!
I am using CodeBlocks 12.11 and compiler is GNU GCC compiler.
Here is the output window: [URL] ....
Here is the code:
#include<iostream>
#include<math.h>
using namespace std;
int main() {
int n,a[5],i,t,dec,divisor; // n: storing number; t: copy of n,
[Code] .....
I'm working on a class project, and I'm having a difficulty. Suppose I have: string a = "21" and string b = "30"; normally, a+b=2130 (i.e concatenation of the characters in the string) but suppose I want a+b=51 (i.e. numerical addition) how do I go about this?
View 1 Replies View RelatedC++ program to accept a value and split it digit by digit and display in name
E.g.: 123
>one two three
write a program that counts the number of digits in a file?
For example the file contains:
5 6 7 -8 9obvsefs
6 7 8i uhbnm
8 8
And the program returns: "The number of all digits is 10"