C++ :: Input Integer Then Output Both Individual Digits Of The Number And Sum Of Digits
Oct 11, 2014
My problem needs to prompt the user to input an integer and then outputs both the individual digits of the number and the sum of the digits. An example would be entering 8030 and it spits out 8 0 3 0 as well as 8+0+3+0=11 and it needs to work with negative numbers.
Code:
#include <iostream>
#include <iomanip>
using namespace std;
int main() {
int base;
[Code] ....
Now I don't know if any of this is right a hint my professor gave us is that to get the fourth digit you would do base mod 10 and to get the first digit you do base divided 1000...
Code:
{
int power;
int counter=0;
int value=1;
cout << "Enter the power of 10 you want: ";
Write a full C++ program that inputs three-digit integer, separates the integer into its individual digits and prints the digits separated from one another. For example, if the user types 549, the program should print;
"Every number has at most 500 digits" under input. 500? How am I supposed to store that? And what if someone multiplies 999 ...(500 times) * 999 ... (500 times) ? I seriously doubt that my computer can store that! Is that just some huge value used to scare people off or is there some sneaky trick that I am unaware of?
I am done with the program, but won't post it, Lets not ruin the fum for ohers...Does that 500 limit also applies to result of operation?So max length of an input number is ~22 digits ? But still, how do I store 500 digits? Array would be a lot of wastage of memory (though I do have 256MB available).
Just wanted to share a program I made. It was the answer to one of the end chapter exercises in the C programming book I'm using, asking the reader to create a program that adds all the digits of an integer.
Code:
/* Program to calculate the sum of the digits in an integer */ #include <stdio.h> int main () { int number, right_digit, sum = 0;
A problem that lets the user enter any positive integer, but you do not have to check for this, and then calculates the sum of the digits and displays this to user. For example, if user enters 14503, the outputted sum of the digits would be 13. You need turn in an algorithm, C++ source code and output.
how do i even go about making 1 add to 4? and so on. I'm lost.
In my homework, x is unknown. but don't worry, I wont ask for the full code. I just need the part where you change the int into a string/array of char.
I have an integer that the user enters. I need each digit of the integer to be set as an element of an array. the integer could also be entered as an array, but I need the user not to have to enter each element and press ENTER.
I have a char *pch that points to an integer digit 1 or 2 or ... 9. To get the character that's 1 less, instead of converting to int, minus 1, then converting back to char, I tried (*pch -1) and that seemed to work. I suppose that's because the particular character encoding on my system is such that the digits are encoded in the same order and spacing as the integers they represent. So the question is does this "convenience" feature hold true for all character encoding systems?
Write a C++ program that reads in two positive integers that are 20 or fewer digits in length and outputs the sum of the two numbers.
Your program will read the digits as values of type char so that the number 1234 is read as four characters '1', '2', '3' and '4'. After they are read into the program, the characters are changed to values of type int. The digits will be read into a partially filled array and you might find it useful to reverse the order of the elements in the array after array is filled with data from the keyboard.
Your program will perform the addition by implementing the usual pencil and paper addition algorithm. The result of the addition is stored in an array of size 20 and the result is written to screen. if the result of the addition is an integer with more than maximum number of digits(that is more than 20 digits) then your program should issue a message saying that it has encountered "integer overflow".
You should be able to change the maximum length of the integers by changing only one globally defined constant. Include the loop that allows the user to continue to do more additions until the user says the program should end.
For some reason the sum won't add or output though, This is what i have so far:
#include <iostream> using namespace std; const int MAXIMUM_DIGITS = 20; void input_Large_Int (int a[], int& size_of_A); //input function for the two big integers void output_Large_Int(int a[], int size_of_A); //output function for the two big integers and the sum integer void add(int a[], int size_of_A, int b[], int size_of_B, int sum[], int & size_Sum); //add function for the big integers' sum
I know how to remove digits in number from right to left.For example: the number 319. If I do (number /= 10), I get 31.how can I remove digits in number from left to right.For example: the number 319. If I will do something, I will get the number 19.
Write a C++ program that reads in two positive integers that are 20 or fewer digits in length and outputs the sum of the two numbers.
Your program will read the digits as values of type char so that the number 1234 is read as four characters '1', '2', '3' and '4'. After they are read into the program, the characters are changed to values of type int. The digits will be read into a partially filled array and you might find it useful to reverse the order of the elements in the array after array is filled with data from the keyboard.
Your program will perform the addition by implementing the usual pencil and paper addition algorithm. The result of the addition is stored in an array of size 20 and the result is written to screen. if the result of the addition is an integer with more than maximum number of digits(that is more than 20 digits) then your program should issue a message saying that it has encountered "integer overflow".
You should be able to change the maximum length of the integers by changing only one globally defined constant. Include the loop that allows the user to continue to do more additions until the user says the program should end. What I have so far is
#include <iostream> #include <cstdlib> using namespace std; void reverseArr(int a[], int liu); void addLargeInt(int a1[], int liu1, int a2[], int liu2, int sum[], int& liu_sum); int main() { cin.get(next);
How to get all the possible combinations for 4 digits from a 5 digit number. I need a pair that has both 5 digits and four digits. their sum must be equal to a five digit user input. i.e.
user input : 14690 output: 14690 has pairs 12345 + 2345 2345 came from 12345 lets say that x = 12345 and y =2345 besides y == x%10000
other formula can i have since if i use % and / i will have a lot of declarations....
I use rand function to generate a number which consists of 3-5 digits(e.134,1435,73463..). The user decides whether he wants a 3 digit,4 digit or 5 digit number.After that,the user tries to guess the number.Its like mastermind game.The user will enter a number (with the same amount of digits) and the program will calculate how many digits from the secret number he has found and also how many digits he has found in the correct position(e.if the generatir produces the number 32541 and the user tries the number 49581 the program should tell him that he found 3 digits (5,1,4) and 2 digits in the correct position(5,1)) so that after some tries he finds the secret number.My problem is with the functions so that i can compare the digit of each number,find the amount of same digits and the amount of digits in same position.
I've been working on a program that displays the number of digits in each line of a file, but I feel stuck. Take for example a file that contains these characters:
6347aaa9 54j 811111 6a 709
And I'm trying to display a result like this
1 //that's the number of the line 5 //the number of digits 2 2 3 6 4 1 5 3
Here's what I've written so far:
Code: #include<stdio.h> int main() { char a=0; int number_of_digits=0, linescount=0, num, number_of_digits_per_line=0; FILE *inputFile; if(!(inputFile=fopen("C:TestTest.txt","r")))
[Code]..
I also thought of using fgets and strlen but I am not very good with them and couldn't get the program to work correctly. It did work but it displayed all characters, letters included, not only digits.
How to return the value after the decimal point. For example:if two integer numbers are 3, 4 then (3+4)/2 is 3.5 the 5 after the decimal point is to be returned. if suppose it is 34.456 i have to return 456.
Given an integer, find the sum of all the digits in the number until the sum becomes a single digit. E.g. sum of digits of 9264 = 21. Then sum of 21 = 3.
I have been trying to finish this code (function) for a while now, but am stuck on the last part. In this code, I prompt the user to select a number of integers and any number of digits and then find the smallest and largest value within these digits. On the next part, I am supposed to determine which of the given digits the smallest and largest are located such that the output should be:
Digit _ can be found in integer number(s): _, _
Here is what I have tried:
Code: int digitSizeLoca() { int userNumInteger; int* iPtr; int* iPtr2; int* iPtr3; int value;
[Code] ....
Seems to do the job, but it always outputs 1, 2...
So I have been given and as part of the solution I need to count the number of digits in a long long variable. To do this I use a while loop, but it is behaving strangely. Here is the code.
#include <stdio.h> #include <cs50.h> #include <math.h> int main (void) { printf("What is the card number?"); long long card = GetLongLong(); if(card <= 0)
[Code] .....
When I execute the program it asked for the number, but then nothing happens. Of course, my first instinct was that the program was caught in an infinite loop somehow, but could not figure out how. I commented out the while loop and the program completed (albeit returning the incorrect value), so I was further convinced that there was an infinite loop that I was not seeing. I ran the program throug gdb. Strangely, the program did not loop infinitely, instead it got to line 16 [while(card1 > 0] and then just stopped, it was not executing the next line of code at all.
I wrote a program with function my own function which count the digits of entered number. The problem is whatever i type it shows 0 digits.Why is that?
Code: #include <iostream> using namespace std; int cikCipari (int skaitlis, int cipars); int main()
