C++ :: Read Two Positive Integers That Are 20 Or Fewer Digits In Length And Output Sum Of Two Numbers
Apr 30, 2013
so basically my project goes like this:
Write a C++ program that reads in two positive integers that are 20 or fewer digits in length and outputs the sum of the two numbers.
Your program will read the digits as values of type char so that the number 1234 is read as four characters '1', '2', '3' and '4'. After they are read into the program, the characters are changed to values of type int. The digits will be read into a partially filled array and you might find it useful to reverse the order of the elements in the array after array is filled with data from the keyboard.
Your program will perform the addition by implementing the usual pencil and paper addition algorithm. The result of the addition is stored in an array of size 20 and the result is written to screen. if the result of the addition is an integer with more than maximum number of digits(that is more than 20 digits) then your program should issue a message saying that it has encountered "integer overflow".
You should be able to change the maximum length of the integers by changing only one globally defined constant. Include the loop that allows the user to continue to do more additions until the user says the program should end. What I have so far is
#include <iostream>
#include <cstdlib>
using namespace std;
void reverseArr(int a[], int liu);
void addLargeInt(int a1[], int liu1, int a2[], int liu2, int sum[], int& liu_sum);
int main() {
cin.get(next);
Write a C++ program that reads in two positive integers that are 20 or fewer digits in length and outputs the sum of the two numbers.
Your program will read the digits as values of type char so that the number 1234 is read as four characters '1', '2', '3' and '4'. After they are read into the program, the characters are changed to values of type int. The digits will be read into a partially filled array and you might find it useful to reverse the order of the elements in the array after array is filled with data from the keyboard.
Your program will perform the addition by implementing the usual pencil and paper addition algorithm. The result of the addition is stored in an array of size 20 and the result is written to screen. if the result of the addition is an integer with more than maximum number of digits(that is more than 20 digits) then your program should issue a message saying that it has encountered "integer overflow".
You should be able to change the maximum length of the integers by changing only one globally defined constant. Include the loop that allows the user to continue to do more additions until the user says the program should end.
For some reason the sum won't add or output though, This is what i have so far:
#include <iostream> using namespace std; const int MAXIMUM_DIGITS = 20; void input_Large_Int (int a[], int& size_of_A); //input function for the two big integers void output_Large_Int(int a[], int size_of_A); //output function for the two big integers and the sum integer void add(int a[], int size_of_A, int b[], int size_of_B, int sum[], int & size_Sum); //add function for the big integers' sum
Write a function that raises an integer to a positive integer power. Call the function x_to_the_n taking two integer arguments x and n. Have the function return a long int, which represents the results of calculating x^n.Here's my code:
Code:
#include <stdio.h> long int x_to_the_n(int x, int n) { int i; long int acc = 1;
for(i = 1; i <= n; ++i) acc *= x; }
[code]...
It compiles OK, but when I run it the program stops after entering the number (x) and power (n).
My problem needs to prompt the user to input an integer and then outputs both the individual digits of the number and the sum of the digits. An example would be entering 8030 and it spits out 8 0 3 0 as well as 8+0+3+0=11 and it needs to work with negative numbers.
Code: #include <iostream> #include <iomanip> using namespace std; int main() { int base;
[Code] ....
Now I don't know if any of this is right a hint my professor gave us is that to get the fourth digit you would do base mod 10 and to get the first digit you do base divided 1000...
Code:
{ int power; int counter=0; int value=1; cout << "Enter the power of 10 you want: ";
Write a program which reads a stream of numbers from a file, and writes only the positive numbers to a second file. The user should be prompted to enter the names of both the input file and output file in main(), and then main() will open both files. Another function named process() must then be called to read all the numbers from the input file and write the positive numbers to the output file. Note that you must pass the open stream variables for each file as arguments to the process() function, and that you need to (always) double check that the files opened successfully before using them.
This is what I have so far but its not working out!
#include <iostream> #include <fstream> #include <stdlib.h> using namespace std; int process(ifstream &inf, ofstream &outf);
My C programming class wants us to write a program to read integers into an array, sort the numbers and print out the occurrence of each number. I've tried everything that I can think of but the core dump is still occurring.
void countValues ( FILE *inf, int list[], int size ); /* Function prototypes. */ void printFrequencies( const int list[], int size ); int main (void) { int status = EXIT_SUCCESS; /* defaulting status to success. */ FILE *inf = fopen( "numbers.txt", "r" ); /* input data file */
I got an assignment which asked me to create a program that asks user to input 10 numbers (positive and negative) integer. The program would be using loop to compute sum and average of all positive integers, the sum and average of negative numbers and the sum and average of all the number entered. But, the new problem is after I've entered all the number, the answer that the program gave me wasn't the answer that the program supposed to give. I don't know how to describe it, I would attach a picture and the code below:
#include <iostream> #include <cstdlib> using namespace std; int main() { //Declaration int x, value, sum, average, SumPositive, SumNegative, Positive, Negative; float AveragePositive, AverageNegative;
I'm trying to get my C program to compile but it's not working at all. I've programmed a little in C++ before but I'm not used to C. Here's my program so far:
Code: int main(void){ // Establishes variables int num1, num2, product; float quotient;
[Code] .....
It keeps giving me an error message as follows:
"/usr/bin/ldrelabwk2: file format not recognized; treating as linker script /usr/bin/ldrelabwk2:1: syntax error collect2: ld returned 1 exit status"
Consider a new data type, the mikesint, which can hold 9 bits.
(a) What is the largest integer that an unsigned mikesint can hold? (b) What is the largest positive integer that a signed mikesint can hold? (c) What is the largest negative integer that a signed mikesint can hold?
I'm basically trying to make a simple program that reads integers out of a text file and only adds the positive ones and not the negatives.
All is well except it won't take the last integer (the last line, I presume.) I took the negative out, nothing to do with that. I put more numbers in and I made the txt file less, no answer. No matter what the last number is, the program won't read it. I've been researching online and I've been seeing that it might be an issue with "while "!inFile.eof())".
Anyway here's the program:
#include <iostream> #include <fstream> using namespace std; int main() { ifstream inFile; ofstream outFile;
#include <iostream> #include <fstream> #include <cstdlib> #include <ctime> using namespace std; int main () { ofstream fout("datain.txt",ios::out); int array[6][6];
A problem that lets the user enter any positive integer, but you do not have to check for this, and then calculates the sum of the digits and displays this to user. For example, if user enters 14503, the outputted sum of the digits would be 13. You need turn in an algorithm, C++ source code and output.
how do i even go about making 1 add to 4? and so on. I'm lost.
I'm a beginner at c++ and I need to write a program that reads a set of integers and then finds and prints the sum of the even and odd integers. The program cannot tell the user how many integers to enter. I need to have separate totals for the even and odd numbers. what would I need to use so that I can read whatever number of values the user inputs and get the sum of even and odd?
I have written a function that takes in a positive decimal and returns its Binary equivalent; however, the output always adds an additional zero to the binary. What could I do to get rid of it?
If the number is 7, it outputs 0111 instead of 111.
I want to read a string of unknown length from stdin. I tried to follow the approach from this link.
[URL]....
My code is like this:
Code:
#include <iostream> #include <string> using namespace std; int n; cin >> n; cout << "The value of n is " << n << endl; string str; getline(cin, str); cout << "The entereed string is " << str << endl;
What I have noticed is that if I take integer input from cin (cin >> n in the above code before getline, the control does not stop on getline to take str as input from the console. If I don't do (cin >> n) before getline then the control stops on getline and takes the string as input.
What is the best way to read from console multiple strings of unknown length in combination with the integers?
I am having an error at line 21. Specifically the code where it says "list[num]=x"
How am I able to fix this code to do what I want? The purpose of my program is to enter in positive numbers in an array (and having it end when 0 is typed) My program also accepts negative values but will ignore them when it is outputted. I believe I have all the code right except for line 21.
#include<iostream> using namespace std; const int ARRAY_SIZE(25); void read_list(const int list[],const int ARRAY_SIZE); int main() { int list[ARRAY_SIZE]; read_list(list, ARRAY_SIZE);
I'm sure this is pretty simple, but any way to do this. Essentially if I have an array with P collumns and V^P rows, how can I fill in all the combinations, that is, essentially, all possible numbers in base V of P digits.
For example, for P=3 and V=2
000 001 010 011 100 101 110 111
Keep in mind that this is an 2 dimensional array, not an array of ints.
For P=4 and V=3.
0000 0001 0002 0010 0011 0012 ....
Having this array generated, the rest of work for what I'm trying to develop is trivial
This is a code I've written that should do the trick, but for some reason it gives this error on compiling:
"main.cpp:65: error: invalid types `double[3][9][double]' for array subscript"
