Create a program that keeps on reading positive numbers until user enters a zero value, and then outputs the last positive number entered.
I do not know how to output the 'last positive number' and I do not even know am I doing things correctly so far....
Code:
#include <stdio.h>
int main() {
double num;
for(;;) {
printf("Enter a positive number: ");
scanf("%lf",&num);
[Code] ....
I am trying to find the max number entered by the user, and it should terminate when a negative number is entered. For my code, it will just end when the user inputs a lower number than the previous. i.e.- 10 20 15 "The highest number is 20" when it should be "10 20 5 40 15 -1" "The highest number is 40". No arrays or do/while loops either.
#include <iostream>
using namespace std;
int Max(int x);
int main() {
int x;
[Code] ....
Write a program to enter the number till 100 till the user want and at the end it should display the count of positive and negative and zero entered.
View 8 Replies View RelatedI have written a function that takes in a positive decimal and returns its Binary equivalent; however, the output always adds an additional zero to the binary. What could I do to get rid of it?
If the number is 7, it outputs 0111 instead of 111.
Code:
#include <stdio.h>
void Dec(int n) {
if(n > 0)
Dec(n/2);
printf("%i", n%2);
[Code] ....
A problem that lets the user enter any positive integer, but you do not have to check for this, and then calculates the sum of the digits and displays this to user. For example, if user enters 14503, the outputted sum of the digits would be 13. You need turn in an algorithm, C++ source code and output.
how do i even go about making 1 add to 4? and so on. I'm lost.
Write a C++ program that reads in two positive integers that are 20 or fewer digits in length and outputs the sum of the two numbers.
Your program will read the digits as values of type char so that the number 1234 is read as four characters '1', '2', '3' and '4'. After they are read into the program, the characters are changed to values of type int. The digits will be read into a partially filled array and you might find it useful to reverse the order of the elements in the array after array is filled with data from the keyboard.
Your program will perform the addition by implementing the usual pencil and paper addition algorithm. The result of the addition is stored in an array of size 20 and the result is written to screen. if the result of the addition is an integer with more than maximum number of digits(that is more than 20 digits) then your program should issue a message saying that it has encountered "integer overflow".
You should be able to change the maximum length of the integers by changing only one globally defined constant. Include the loop that allows the user to continue to do more additions until the user says the program should end.
For some reason the sum won't add or output though, This is what i have so far:
#include <iostream>
using namespace std;
const int MAXIMUM_DIGITS = 20;
void input_Large_Int (int a[], int& size_of_A); //input function for the two big integers
void output_Large_Int(int a[], int size_of_A); //output function for the two big integers and the sum integer
void add(int a[], int size_of_A, int b[], int size_of_B, int sum[], int & size_Sum); //add function for the big integers' sum
[Code] .....
so basically my project goes like this:
Write a C++ program that reads in two positive integers that are 20 or fewer digits in length and outputs the sum of the two numbers.
Your program will read the digits as values of type char so that the number 1234 is read as four characters '1', '2', '3' and '4'. After they are read into the program, the characters are changed to values of type int. The digits will be read into a partially filled array and you might find it useful to reverse the order of the elements in the array after array is filled with data from the keyboard.
Your program will perform the addition by implementing the usual pencil and paper addition algorithm. The result of the addition is stored in an array of size 20 and the result is written to screen. if the result of the addition is an integer with more than maximum number of digits(that is more than 20 digits) then your program should issue a message saying that it has encountered "integer overflow".
You should be able to change the maximum length of the integers by changing only one globally defined constant. Include the loop that allows the user to continue to do more additions until the user says the program should end. What I have so far is
#include <iostream>
#include <cstdlib>
using namespace std;
void reverseArr(int a[], int liu);
void addLargeInt(int a1[], int liu1, int a2[], int liu2, int sum[], int& liu_sum);
int main() {
cin.get(next);
[Code]...
I am trying to find a way to put a getSmallest function in here so that it will output smallest integer entered. If it is just an arbitrary amount of #'s and I don't know what will be entered I am confused. Both on how to do it and how to link my function to my loop.
Code:
/* Prompts user and gets integer numbers from keyboard, one number at a time. Ends program when 99999 entered. and displays various results.
Written by:
Date: 10/20/14
*/
#include <stdio.h>
#include <stdlib.h>
[Code] .....
Could I take this and just replace all variables a, b, and c with getNumber, where would I link/declare smallest?
Code:
/* ==================== smallest ======================
This function returns the smallest of 3 integers.
Pre given 3 integers
Post the smallest integer returned
*/
int smallest (int a, int b, int c) {
[Code] ......
I was going through the following statement in a c book:
"interpreting -1 as unsigned int leads to a big +ve number"
-1 is already unsigned .... then what does the above statement mean ??
Assume you want to make sure that the user enters a positive number that is divisible by 10 with no remainder. Write the condition you would use in the following do-while loop.
do {
cout << “Enter a positive number that is divisible by 10 with no remainder” << endl;
cin >> number;
}
while ( ____________________________________________________________);
My program uses a while loop to eventually get to an error of zero and a root of sqrt(3). I'm not understand why after the third iteration the program fails to compute a new x value. I'm using Visual Studio 2013. The code tag instructions were dubious.
Code:
#include <stdio.h>
#include <math.h>
main() {
/*This program uses the Newton-Raphson method to solve y = (x^3)-3 for it's roots.*/
printf("This program uses the Newton-Raphson method to solve y = (x^3)-3 for it's roots. Enter your estimate of the root.
");
float x,y,z;
int num;
num = 0;
[Code]...
#include <iostream>
using namespace std;
int main() {
int h;
double A[10][10];
[Code] .....
Write a C++ program that will input from the user a positive number n and find its factorial. Don’t forget to validate the input. The factorial of a positive integer n (denoted by n!) is defines as the product of the integers from 1 to n.
n! = 1* 2 * 3 * ... * (n - 1) * n
You should allow the user to continue working with your program for additional data sets.
Sample output:
Please enter a number: 5
5! = 120
Would you like to continue (Y/N)?Y
Please enter a number: 3
3! = 6
Would you like to continue (Y/N)?N
Good Bye!!
My code for what i think I'm doing is as follows:
#include <iostream>
using namespace std;
int main(){
int i=1;
int n;
[Code] ....
So I tried creating a test code for reading a negative number and positive number but whenever I enter a negative number it read it as being positive.
#include <stdio.h>
#include <iostream>
#include <iomanip>
[Code].....
PS: I am using char over int because the program that I am testing for requires me to use 8 bit variable.
I have to make a program and how to go with it. What is excepted of me is to have a entered number, become fragmented, and then resembled.
Ex. 1394--> 1 3 9 4 --> 1394
How to find the largest and smallest number entered by a user. So far I'm able to add, find the average and count how many numbers are entered.
I'm just having trouble with find the max and min. I tried if statements and it breaks the program will it wont let me exit the while loop or the program will do a force close after entering a value.
Code:
#include <stdio.h>
#include <stdlib.h>
int main(){
int maxNum=0, minNum=0, value, count=0, sum=0;
double average;
[Code] ....
I'm trying to calculate the number of distinct values entered into an array. If i enter the followings "3,4,5,6,7,7,6,e (anything that's not a number)" . I get a total of 7 but in reality it should be a 5.
Code:
#include <stdio.h>
//---------function to find the distinct values----
int find_distinct(int list[], int size)
{
int i, j,size2, distinct = 0;
for(i = 0; i < size; i++)
[Code]...
I wrote a program with function my own function which count the digits of entered number. The problem is whatever i type it shows 0 digits.Why is that?
Code:
#include <iostream>
using namespace std;
int cikCipari (int skaitlis, int cipars);
int main()
[Code] .....
I am trying to write code to find all the prime numbers before a user entered number. I started with a working program and when I tried to create a function, it got all messed up.
Code:
#include <stdio.h>
int is_prime( int num );
int get_positive_integer(void);
int main( ) {
int upper; /* upper limit to check */
int num; /* current number to check */
int isprime;
/* used to flag if number is prime or not */
[Code]...
It says the error is on line 23
I need to write a code in c++ , to input decimal number and the output to be number in Scientific notation with 32 bits .
View 1 Replies View RelatedI am attempting to write code that receives a number from the user and outputs the largest prime number underneath the user's number. There are no errors in my code, but no matter what number is imputed, the program says the largest prime number is 1. I cannot find where the issue is in the code. Here is the code I wrote:
#include <cstdlib>
#include <iostream>
#include <cmath>
using namespace std;
bool isPrime(int num);//function prototype
[Code] ....
i just started learning programming and i just wanna know how come when i try to print the last digit of a number the output always become 6?
View 4 Replies View RelatedI have this simple code here:
Code:
#include <iostream>
int multiply (double x, double y) {
double result = x*y;
return (result);
[Code] ....
I get the answer 5.94 (which is what I'm looking for). I can't work out why the first example is not outputting a decimal number. I have set the variables as a double so I just can't see why this is not working for me.
//using bloodshed dev c++ compiler
//How can I output the name and a two digit number next to it
//example would be Indiana Jones 20
#include<iostream>
#include<string>
using namespace std;
class Customer {
[Code] .....
Here is my code and everything works except i can not get the highest array number to be output. it always says 10.
My instructions are:
(1) Create a 10-integer array called data
(2) Set a pointer ptr to point to array data
(3) Output the elements in array data using pointer ptr
(4) Find the largest element in the array data using pointer ptr
#include <iostream>
#include <cstdlib>
using namespace std;
[Code].....
The problem that I am having is that , the program outputs numbers that are perfect numbers and im not sure where i can add a statement to make it so that if it isn't a perfect number it doesn't output...
#include<iostream>// allows user input/output
#include<conio.h>
#include<fstream>//data file / result file
#include<iomanip>
#include<cmath> // math function
#define in_file "data.txt"
#define out_file "result.txt"
[Code] ....
