How to return the value after the decimal point. For example:if two integer numbers are 3, 4 then (3+4)/2 is 3.5 the 5 after the decimal point is to be returned. if suppose it is 34.456 i have to return 456.
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What would be the best way to remove the decimal point from a float number? For instance if I have a float number .2546 I would like to be able to remove the dot and use just the number (int) 2546 for some calculations.
Maybe, convert to string than remove the first character from the string than convert the string back to an int?
My problem needs to prompt the user to input an integer and then outputs both the individual digits of the number and the sum of the digits. An example would be entering 8030 and it spits out 8 0 3 0 as well as 8+0+3+0=11 and it needs to work with negative numbers.
Code:
#include <iostream>
#include <iomanip>
using namespace std;
int main() {
int base;
[Code] ....
Now I don't know if any of this is right a hint my professor gave us is that to get the fourth digit you would do base mod 10 and to get the first digit you do base divided 1000...
Code:
{
int power;
int counter=0;
int value=1;
cout << "Enter the power of 10 you want: ";
[Code] ....
I was going through the exercises in one C programming ebook.There is this question which asks me to print a float variable in fixed decimal notation, field size of 6, right-justified, no digits after decimal point.I got printf("%6f", x );
x = float variable.
But the above code prints numbers after the decimal point, so I changed it to %d. But %d doesn't work with float variables..
In the c pgm to find number of digits , if I am giving 001 as the input number ,why I am not getting the no. of digits as 3?
View 2 Replies View RelatedCalculate the Euclidean distance to the origin for each point in parallel on GPU.Assume that for each point i, its coordinate is X[i],Y[i] and given 1000000 points on 2d plane
[//
#include <iostream>
#include <stdio.h>
#include <cuda.h>
#include <assert.h>
[Code].....
I need to write a code in c++ , to input decimal number and the output to be number in Scientific notation with 32 bits .
View 1 Replies View RelatedCode: Complete the program below which converts a binary number into a decimal number. Sample outputs are shown belowComplete the program below which converts a binary number into a decimal number. Sample outputs are shown below.
Sample Output 1:
8-bit Binary Number => 11111111
Decimal Number = 255
Sample Output 2:
8-bit Binary Number => 10101010
Decimal Number = 170
Sample Output 3:
8-bit Binary Number => 101010102
Number entered is not a binary number
#include <iostream>
using namespace std;
int main()
{
int num;
[code]....
I know how to remove digits in number from right to left.For example: the number 319. If I do (number /= 10), I get 31.how can I remove digits in number from left to right.For example: the number 319. If I will do something, I will get the number 19.
View 15 Replies View Related//Program to reverse 5 digit number
#include <stdio.h>
void main() {
int num, i = 0;
char rev[5];
printf("Enter any 5 digit number
[Code] ....
WHILE DISPLAYING i am not getting correct output. whats wrong in rev[] array.
"Every number has at most 500 digits" under input. 500? How am I supposed to store that? And what if someone multiplies 999 ...(500 times) * 999 ... (500 times) ? I seriously doubt that my computer can store that! Is that just some huge value used to scare people off or is there some sneaky trick that I am unaware of?
I am done with the program, but won't post it, Lets not ruin the fum for ohers...Does that 500 limit also applies to result of operation?So max length of an input number is ~22 digits ? But still, how do I store 500 digits? Array would be a lot of wastage of memory (though I do have 256MB available).
How to get all the possible combinations for 4 digits from a 5 digit number. I need a pair that has both 5 digits and four digits. their sum must be equal to a five digit user input. i.e.
user input : 14690
output:
14690 has pairs 12345 + 2345
2345 came from 12345
lets say that x = 12345 and y =2345
besides y == x%10000
other formula can i have since if i use % and / i will have a lot of declarations....
I have been trying to write a recursive function to print the permutations of a n-digit number. This is the logic that i am trying to use.
1.call the permutation function,
2.keep the first digit in the first place and send the remaining 2 digits back to the permutation function recursively.
3.keep one of the two digits received and send the remaining digit to the permute function.
4. keep doing this till only one digit remains. this is the smallest solution so return it.
The aim is : If i have a natural number [max 5 digits] (say) n=13579. Then a[4]=1, a[3]=3, a[2]=5. a[1]=7. a[0]=9.
I start with a[4]= n/10000 .. then n= n - a[4]*10000;
then a[3]= n/1000. .. n= n - a[3]*1000;
i.e a[i]= n/10^i .... n= n - a[i]*10^i;
To reduce code size i used a for loop. The code is free from any syntax errors.
Its the "output" that is weird. I enter 13579 and what the program process is:
a[4]=1 a[3]=3 a[2]=5 a[1]=8 a[0]=5
Same goes for other numbers too.. leaving the most significant digit , the rest digits are just out of the logic!!
I am using CodeBlocks 12.11 and compiler is GNU GCC compiler.
Here is the output window: [URL] ....
Here is the code:
#include<iostream>
#include<math.h>
using namespace std;
int main() {
int n,a[5],i,t,dec,divisor; // n: storing number; t: copy of n,
[Code] .....
write a program that counts the number of digits in a file?
For example the file contains:
5 6 7 -8 9obvsefs
6 7 8i uhbnm
8 8
And the program returns: "The number of all digits is 10"
Here's the part of the codes where I tried to use boolean expression:
Code:
#include <iostream>
using namespace std;
int main() {
int num;
cout << "8-bit Binary Number=";
cin >> num;
[Code] .....
How can I get started with the body?
Here's the part of the codes where I tried to use boolean expression:
#include <iostream>
using namespace std;
int main()
[Code].....
May I know that how can I get started with the body?
I use rand function to generate a number which consists of 3-5 digits(e.134,1435,73463..). The user decides whether he wants a 3 digit,4 digit or 5 digit number.After that,the user tries to guess the number.Its like mastermind game.The user will enter a number (with the same amount of digits) and the program will calculate how many digits from the secret number he has found and also how many digits he has found in the correct position(e.if the generatir produces the number 32541 and the user tries the number 49581 the program should tell him that he found 3 digits (5,1,4) and 2 digits in the correct position(5,1)) so that after some tries he finds the secret number.My problem is with the functions so that i can compare the digit of each number,find the amount of same digits and the amount of digits in same position.
View 5 Replies View RelatedI've been working on a program that displays the number of digits in each line of a file, but I feel stuck. Take for example a file that contains these characters:
6347aaa9
54j
811111
6a
709
And I'm trying to display a result like this
1 //that's the number of the line 5 //the number of digits
2 2
3 6
4 1
5 3
Here's what I've written so far:
Code:
#include<stdio.h>
int main() {
char a=0;
int number_of_digits=0, linescount=0, num, number_of_digits_per_line=0;
FILE *inputFile;
if(!(inputFile=fopen("C:TestTest.txt","r")))
[Code]..
I also thought of using fgets and strlen but I am not very good with them and couldn't get the program to work correctly. It did work but it displayed all characters, letters included, not only digits.
I want to write a function which take an integer and return the number of digits in it i.e
int i = 123456
func(i) {
some code
}
output
the number of the digits are 6
Given an integer, find the sum of all the digits in the number until the sum becomes a single digit. E.g. sum of digits of 9264 = 21. Then sum of 21 = 3.
View 2 Replies View RelatedSo I have been given and as part of the solution I need to count the number of digits in a long long variable. To do this I use a while loop, but it is behaving strangely. Here is the code.
#include <stdio.h>
#include <cs50.h>
#include <math.h>
int main (void) {
printf("What is the card number?");
long long card = GetLongLong();
if(card <= 0)
[Code] .....
When I execute the program it asked for the number, but then nothing happens. Of course, my first instinct was that the program was caught in an infinite loop somehow, but could not figure out how. I commented out the while loop and the program completed (albeit returning the incorrect value), so I was further convinced that there was an infinite loop that I was not seeing. I ran the program throug gdb. Strangely, the program did not loop infinitely, instead it got to line 16 [while(card1 > 0] and then just stopped, it was not executing the next line of code at all.
I wrote a program with function my own function which count the digits of entered number. The problem is whatever i type it shows 0 digits.Why is that?
Code:
#include <iostream>
using namespace std;
int cikCipari (int skaitlis, int cipars);
int main()
[Code] .....
Code:
int exploder(int number,int array[]) {
int functi = 0;
int digit = number % 10;
while (number > 0) {
[Code] ....
How can I read a file that contains numbers only, but read it by three digits at a time? I have a long string of numbers and every three digits corresponds to a particular number in itself. i.e. a string of 064045154 would need to be read as '064' '045' and '154'. I need to then subtract one from each of these numbers and the new values I need to convert into their ASCII characters and place these in a new file. This is what I have (focusing on the 'Decrypt' function) but all it does is in the new file place a string of the same character repeated over and over a total number of times equal to the number of integers in the numbers file.
Code:
#include "stdio.h"
#include "stdlib.h"
#include "string.h"
#include "limits.h"
int Encrypt(char * FILENAME)
[Code]..
I have to code a simple program who determining the number of Characters (A character could be any alphabets, digits, punctuation marks, or special , Operators ( Operators are those symbols that are used in mathematica expression, such as,'+', '*', '/', '-', and so on.), Uppercase letters (Uppercase characters are those from A..Z) and Numerical digits ( A digit is any of the Hindu-Arabic numerals from 0..9). Why the output is wrong!
#include <iostream>
#include <string>
#include <fstream>
#include <cstdlib>
#include <iomanip>
using namespace std ;
int main() {
char text;
[Code] .....
This is my input file This is a possible factorial function in a programming language called LISP
(defun factorial (n)
(if (< n 2)
1
(* n (factorial (1- n)))))
This is my output:
The number of characters = 113
The number of operators = 3
The number of numerical digits = 3
Uppercase letters = 5
I think that "characters" is wrong, but I do not know why !
