I was going through the exercises in one C programming ebook.There is this question which asks me to print a float variable in fixed decimal notation, field size of 6, right-justified, no digits after decimal point.I got printf("%6f", x );
x = float variable.
But the above code prints numbers after the decimal point, so I changed it to %d. But %d doesn't work with float variables..
What would be the best way to remove the decimal point from a float number? For instance if I have a float number .2546 I would like to be able to remove the dot and use just the number (int) 2546 for some calculations.
Maybe, convert to string than remove the first character from the string than convert the string back to an int?
Question: A computer uses 10 bits to store integers with 1 bit for a sign. It stores an approximation of real numbers in 10 bits. The first bit of the first five is the sign of the mantissa and the other four bits are the mantissa. The first bit of the second five is the sign of the exponent and the other four the exponent.
1)What is the range of integers?
2)what is the range of real numbers(Float Type)
The first question was simple. I just found the smallest 10 digit binary number 1000000000 = -512 and then found the largest 10 digit binary number which would have to be 0111111111 = 511, therefore the range of integers is from -512 to 511.
For the second question - I am either making this harder than it is, or it really is a challenging question. So I followed the steps and first I was thinking I would take the number 1000000000 and convert this to a decimal (assuming its a 10 bit float)...But, can you even do this with a 10 bit float??
I ended up getting 1000000000 (after denormalizing) = .000100000 = 0.625.. would that be the minimum range? If so, then I know what I need to do to find the maximum , but if not - then I am really lost.
My Process was:
1.00000 X 2^(-4) = my final result of 0.625 after converting.
I am trying to find out when using float in a calculation how to set the number of decimal places. For example my code below
Code:
#include stdio.h>
int main()
{
float x=123.0;
[Code]....
This returns an answer 8487.0000 I would like it not to show all the decimal places. However if the sum has decimal places I would like to select the number of decimal places shown.
how can I check if the number is float point number without converting the number to string and then find '.'?
For example, this number (5.0) should not be integer. I found the following way in Python but it didn't work in C++
abs(n - (int)n) < 0.000001
I have a program that runs fine but outputs garbage and skips processes when I input a decimal. It compiles fine and has no errors.
Code:
#include <iostream>
#include <float.h>
using namespace std;
int main() {
int x;
int y;
[Code] ....
How to return the value after the decimal point. For example:if two integer numbers are 3, 4 then (3+4)/2 is 3.5 the 5 after the decimal point is to be returned. if suppose it is 34.456 i have to return 456.
View 11 Replies View RelatedI have a simple input output problem using float point numbers and after the first input the program skips the other cin functions is there something that I did wrong? It compiles fine also.
Code:
#include <iostream>
#include <float.h>
using namespace std;
int main() {
int x;
int y;
int z;
[Code] .....
I have a program that printf a float that is returned by a function like this:
Code:
printf("%3.1f
", myfloat());
...
float myfloat(void) {
code....
}
In w32 my program has been running ok, but when run in a w64, it crash at the printf. If I change the definition of the function to return double it runs ok. in printf format string - Wikipedia, the free encyclopedia , in the "type" section I see there is no definition to print a float, but %f is for double in fixed point.So the question is what is the correct way to printf a float? must I cast? or is it better to return double? if so, does it have a performance penalty?
write a c++ program that reads an unknown number of integer values and then print count, sum and average of odd values, even values, positive values, negative values!!
View 1 Replies View RelatedI have tried everything and i still can't access pixel RGB values in float format.
I tried vec3b which produces strange characters which i can't covert to float as it says no suitable function exists.
I tried vector<float> RGB;
with RGB = image.at<vector<float>>(row,col);
I get a unhandled exception error.
So whatever i do, if it is syntax correct i get unhandled exception error. If it should work i get this stupid error. I need it for chroma keying.
I am trying to make a program that will convert a list of binary numbers from a file into decimal and print the decimal to the screen. I have no problem doing the conversion, the problem comes up when our teacher wants the input file in a format as such:
3
10110101
11111111
10101010
The first number is supposed to tell the program how many different 8bit strings it is going to have to convert, and then the following lines are those binary numbers.
I am not very experienced with file inputs, and I know how to open files and read lines in.. The problem is, how to say "ok the first line says 3, so now I have to convert the next 3 lines" . I am assuming it is just a simple loop that I am missing....
I have the main() - which has entries like
Code:
main() {
int ss, ret, z;
float yy;
ret = function1(&yy, &ss, &z);
//int function1(flat *cc, int *dd, int *k) - is it correct?
[Code]...
I understand most of program below. Essentially, we have strings that we want to convert from hex values to decimal equivalents. We check if first two characters of string are 0x or 0X, which signifies hex format. If our hex string consists of solely digits like 0x25, then the processing is simple. We take the digit assign it to answer variable, and for each additional position in the hex base-16 system, we multiply the digit by 16.
Now if the hex string is something like 0x2A, then for 'A', the hexalpha_to_int() function is called, since we are able to find 'A' in the hexalpha string, we take the value of 'A', which is ascii 65 divide it by 2 and add 10 to it: 65/2+10=42.5. This doesn't make sense. What is the purpose of this logic right here: 10 + (i / 2).
Code:
#include <stdio.h>
#include <stdlib.h>
int hexalpha_to_int(int c){
char hexalpha[] = "aAbBcCdDeEfF";
[Code] ....
i wanted to insert Decimal Values in MySQL database, but decimal values has precision and in C# there is not option to specify precision point, the last column is size which is integer.
MySqlParameter MySqlParameterCollection.Add(string parameter Name,MySqlDBTYPE dbType,int size);
Here my Code and i get error on last Line
MySqlCommand insert = new MySqlCommand("Insert into
Plan(Plan_ID,Plan_Title,Plan_rate,Plan_Length)
values(@p_id,@p_t,@p_r,@p_l);", con);
insert.Parameters.Add("@p_id", MySqlDbType.VarChar, 10).Value = p.p_id;
insert.Parameters.Add("@p_t", MySqlDbType.VarChar, 45).Value = p.p_title;
insert.Parameters.Add("@p_r", MySqlDbType.Decimal,10,2)=p.p_rate;
I am trying to read hex data from a file (not just hex values in text format). I was able to read it (02 EC) with "fread" into an char before but I need to change the Hex value into an integer in decimal.
I already read about strtol but I would prefer reading the hex Value into an integer.
Here is my code so far:
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
int main() {
int itrack1[1];
int itrack2[1];
[Code] ....
Write a function named "sum" that takes as its arguments the following:
(1) an array of floating point values.
(2) an integer that tells how many floating point values are in the array.
The function should return as its value the sum of the floating point values. For example, if the array that's passed to the function looks like this:
0 1 2 3 4
5.8|2.6|9.0|3.4|7.1
The function should return the value as 27.9 as its value...I know I need to declare and intialize the array in the main function. I don't how to write the sum function.
I want to learn ow to align an integer/decimal values on the Left inside devexpress gridview.
View 4 Replies View RelatedHow to reserved int number and print as float number ?
View 1 Replies View RelatedI have a problem with how to print out all the numbers that the user enters the code looks like this so far:
Code:
#include <iostream>
using namespace std;
int main()
[Code] ....
I want the program to print out all the numbers that the user has entered after the program have said the higest and lowest number is ?. But I do not know how to do this I thought it could be something like this:
Code:
cout << input[0];
//or
cout << input[i];
/*
Because i is the number of how many enters of numbers the user can do*/ But that was totally wrong tried to do another "for loop" in the first for loop but that was meaningless because it can't change anything in the first "for loop".
I want to print the current grid values while clicking the print option ..
View 7 Replies View RelatedGiven an array with integer values in the range [0, 100], print the values by popularity (number of time it appears in the array).
example: array: 60, 60, 70, 80, 80, 80, 80, 100;
output: 80 80 80 60 60 70 100.
complexity restriction: should be linear.cant use advance data structure like lists or hashmaps, only arrays. structs are not allowed.
my idea: to build counter array of buckets of size 101, and count each value.then i need to sort the counter array(its still linear), but how i can keep track that the value of 80 appeared 3 time?I mean i need to sort the values of the counter with the indexes as well.
I'm trying to print values from a vector of a struct and I don't really know how to do that. Here is a simple code that I have for now to test how to add data to the vector then attempt to print it out.
#include <iostream>
#include <vector>
#include <string>
#include <deque>
#include <fstream>
using namespace std;
struct Employee//employee data
[Code]...
I have one code that use MPI broadcast and I want to change it into Asynchronous Point to Point communication. I am newbie in Parallel programming. Looking for implementation of one simple same program in broadcast and P2P ?
View 6 Replies View RelatedI can do the folowing:
float var1 ;
var1 = 9.12345 ;
printf("%.2f",var1) ;
the output will be 9.12. What if I wanted to save that as another separate float with displaying it on screen?
#include <iostream>
#include <string.h>
#include <sstream>
[Code]....