C :: Cannot Enter Anything Else Than Name
Aug 10, 2013insert Code: #include<stdio.h>
#include<conio.h>
struct prod
{
char name[25];
[Code]....
insert Code: #include<stdio.h>
#include<conio.h>
struct prod
{
char name[25];
[Code]....
some where in main:
char value;
char* sname;
sname= new char[20];
for(int i=0;i!=19;i++)
{
cin>>value;
sname[i]=value;
}
I need a stopping case when user press enter array get closed and add '' at the end but how to do that?
I wrote a program that reads user input string using fgets() function. After this, program will ask if the user wants to save the string to file or does the user want to change the string or quit without saving. If user wants to change the string this must be made possible by asking for the string again. After this, menu will be printed again printing the choices available.
I had to flush stdin before getting changing input! However, problem is "Why do I have to hit return key 2 times, when I choose 2 and input string again." (I use code block 13.12 with windows 8.1 laptop) */
Code:
#include <stdio.h>
#include <string.h>
#define MAX 50
[Code]....
Currently I am working on a program where you enter in a date 14 03 2013 (Day, Month, Year) and you get the next day. I seem to be coming stuck with months with less than 31 days, and the whole leap year thing. Here is my code so far.
Code:
#include <stdio.h>
int day, month, year, next_day, next_month, next_year, calculation;
int main() {
printf("Enter a date in the form day/month/year: ");
scanf("%d %d %d", &day, &month, &year);
[Code] .....
The following 2 codes are almost identical, only that the switch statements are slightly different. The 2nd code has the issue of requiring an additional enter key to be pressed when I enter '3' as input to exit the program.
Working code :
Code:
#include <stdio.h>
#include <ctype.h>
#include <string.h>
void clearKeyboardBuffer() {
int ch;
while ((ch = getchar() != '
[code]....
I am trying to make a program that will allow a user to enter their name, from this point, three options should be present for the user to choose, then from that point, two more options should be present. I have if else statements in a switch case and I get the "undeclared" error for the a in the first " if(specificage == a) ".
NOTE: I use Code::Blocks.
Here is the code:
Code:
#include <stdio.h>
#include <string.h>
int main(){
char name[50];
char ageclass[50];
char specificage[50];
[Code] ....
getline is not readable after first time through loop. It skips that line and goes to Do you want stop entry? line.
#include<iostream>
#include<string>
#include<cstring>
#include<cctype>
using namespace std;
void upr(const string& str);
[Code] ....
about putting manually a path in my code.
This is what my code should looks like
#include <iostream>
#include <fstream>
#include <vector>
[Code]....
I'm trying to end my program when the user presses the enter/return key.
I'm trying to do this with a break statement.
I have two different situations, one when it is a string, and the other one when it is a char.
for (int i = 0; i < 80; ++i)
{
string s;
cin >> s;
if (s == "
")
break;
S.PushStack(s);
}
I'm doing the same thing for char just replacing string with char.
I'm not sure what I am doing wrong but pressing enter does not end the program.
i just want to break the loop when user hit ENTER.But after that programm is stil working, i don't know why, becouse i have a code just like in book, i spend a lot of time with it.
int getinfo(student pa[], int n){
cout << "START" << endl;
int i = 0;
for(i; i < n; i++) {
cout << "Studetn name";
char name[SLEN];
[code].....
I want to do simple program to capture some 5 surnames of people(employees) - using array and pointers. Well I understand a bit of arrays and I know how to loop through.
How can achieve this? This holds the key to my understanding how pointers work and can be used with char or strings.
I am working on a database project, which can store (initially) 10,000 marksheets with following capabilities
1) new entry
2) edit/modification of entry
3)delete entry
4) separate Departements ( BBA, BCS, M.Phil, Phd., etc.)
5) can store data on files ( initially, all data is stored in a single file)
Now, I want to create a menu, in which i can use arrow keys to navigate through the menu and use Enter key fo selection.
What should i use in it?? The project is only on C language.
Code:
struct lnode *ins_llist(char *data, struct llist *ll){
struct lnode *p, *q;
fprintf(stderr, "Data is %s when first entering ins_llist loop.
", data);
q = malloc(sizeof(struct lnode));
if ( q == NULL )
return(NULL);
}
[code]...
Trying to figure out a way to sort as i enter my data into the llist. What is in red and blue is what I've been messing around with to try and see if maybe i can get it to sort but it is not. When i flip sign, the order changes opposite, but i cant see how to sort each item as i go. Maybe i am too tired right now, lol, been working on this program for what feels like 30 of the past 24 hours haha.
I have task to make program.. To enter 10 positive numbers in an array. Find three numbers that stand near each other and that have the maximum sum.
I understand how to make array, enter 10 number i find only one biggest number from 10.. How to find three max number sum that stand near each other..
Consider below statements:
int x;
scanf("%d", &x);
After running, It's supposed to enter an integer for x. what will happen if I enter a char instead of integer? which value will be in &x and x itself? I have a script and I get strange result while entering a char instead of integer for x.
How to write a code that will let me input how many variables I want.
Write a program that will enable you to enter a certain amount of values
Eg. 4
And then add the corresponding integers. Ex.
Choice: 4 12 34 56 78
The sum of the integers is: 180.
Basically I'm having trouble reading more than one character.I want the user to input character traits(ie, w, a), if two traits are entered they get the job.
But I cannot get my program to read more than one character input.
This is what I have so far...
#include <iostream>
using namespace std;
int main(){
char input;
int count = 0;
[Code] .....
When the program is processing/sleeping, those char input at that time would not goes into the buffer until the next input request (such as calling istream::get). The program below shows this.
#include <iostream>
#include <streambuf>
#include <chrono>
#include <thread>
int main() {
std::cout << "Sleeping...
[Code] ....
I wonder if there is a way to distinguish between the input comes from the time that does not request it (i.e., during processing or sleeping) and those comes after the time does request it (in the example, after "Input something: ").
I need a program in c++ that will enter a limit of the loop. using nested for loop with a limit of 3 loops only.
like this !
for (){
for (){
for (){
cout
}
}
}
Sample output:
Enter a number : 3 [enter]
1 2 3
4 5 6
7 8 9
2 3 4
5 6 7
8 9 10
3 4 5
6 7 8
9 10 11
How can i jump from textBox to next texBox when i press enterKey in c# , what i the event for that .....
View 2 Replies View RelatedThis program with DLL that check number enter in textbox and use RGB for change color
example: if user enter 000 (000:black) changed color automatic textbox to black, and other 111 ....
using System;
using System.Collections.Generic;
using System.ComponentModel;
using System.Drawing;
[Code]....
Okay, I'm not entirely certain where my code is messed up, but when I run the console it asks if I want to add Employee information and then it just skips through everything when I say yes.
#include <iostream>
#include <iomanip>
#include <string>
[Code].....
How to use enter key? When am using two textbox then to enter the key automatically goto next form. This time am not using tab or mouse ??
View 1 Replies View RelatedI have a small program to calculate the value of salary. I want to user to be able to enter more than one user using array and finally calculates the average salary of all users.
Here is the code
Code:
#include <iostream>#include <conio.h>
using namespace std;
int main() {
const int months=3;
double net_pay;
string EmpName;
[Code].....
I am trying to write up something to have a user to enter a four digit number. Only four digits, Ex: 0001, 0116, or 9999. There is no getting around the selection 0001 or 0002. I understand if not done correctly, the first three 0's will be ignored.
I've been just playing around with what I have below but I just don't remember how to do it nor can I find a good example online to figure it out. I know it is not correct just typing to try to remember. I am aware that it is gibberish right now, this is just me brainstorming.
int number;
cout<<("Please enter the four digit number(Ex: 0001):
");
cin>> setw(2) >> number;
cout<<)"Please enter four digit date. Two digits for month and two digits for year:
");
cin>> date;
if (number< || number > 30)
cout << "Invalid choice. Try again." << endl;
cin.clear();
Currently I have to manually look up values on several different tables in different locations. I have 8 or 10 tables with 100 to 500 parts.
I would like to write a program so if I enter a value it will return the corresponding correct answers from the tables.
If I entered 2.5 for a value it would return the following three items from the tables since they all meet the requirement.
Table 2
Part min max
235 2.4 2.9
Table 6
Part min max
589 2.3 2.5
Table 7
Part min max
12 2.3 2.7
What would the best method be for setting up and accessing tables like this? Is C++ good at representing something like this or should I be looking at a different language?