I want to do simple program to capture some 5 surnames of people(employees) - using array and pointers. Well I understand a bit of arrays and I know how to loop through.
How can achieve this? This holds the key to my understanding how pointers work and can be used with char or strings.
basically we were asked to make a program that will print everything before the user hits the enter button. we cannot use fgets and we have to use pointers here.
not sure what exactly to do. We were told not to use fgets cause it's so easy and we need to incorporate pointers in this project..
fprintf(stderr, "Data is %s when first entering ins_llist loop. ", data); q = malloc(sizeof(struct lnode)); if ( q == NULL ) return(NULL); }
[code]...
Trying to figure out a way to sort as i enter my data into the llist. What is in red and blue is what I've been messing around with to try and see if maybe i can get it to sort but it is not. When i flip sign, the order changes opposite, but i cant see how to sort each item as i go. Maybe i am too tired right now, lol, been working on this program for what feels like 30 of the past 24 hours haha.
I have a small program to calculate the value of salary. I want to user to be able to enter more than one user using array and finally calculates the average salary of all users.
Here is the code
Code: #include <iostream>#include <conio.h> using namespace std; int main() { const int months=3; double net_pay; string EmpName;
I've seen some threads that include the information about what data types one has to use usually to put a number of 12digit. But honestly speaking none of them works for me & it takes me a lot suffering about the data type. Even I've googled but I didn't get any specific result.
So, which data type I'd have to use to enter 12digit number.
I'm writing a code to find the largest prime factor of the number 600851475143
I'm trying to solve the ferry loading problem using two queues. My problem is I can't enter in data after the first set is scanned in, I'm assuming there is a problem with my loop, such that the scan function doesn't get called after one iteration. In the example I marked the data I can't enter. An example correct input would be:
correct input: 1 - can enter data20 4 - can enter data 380 left - can enter data 720 left - can't enter data 1340 right - can't enter data 1040 left - can't enter data
Okay, so my assignment for my C class is to generate a program that will allow the user to enter data for a stock and calculate the amount of stocks that ended up being positive, negative, and neutral.I tried to do this using one stock, here is my code;
how to correctly use pointers within relation to function parameters and main source file.
I noticed that char types, for example char myVariable[50]; which is an array, does not seem to require a pointer as if it already has one built in? as opposed to char *myVariable; which seems to need one - i assume this is because char has different ways to store memory in relation to pointers, because of there being multiple ways to store a string, and memory allocation as a part of that. - i stared C a few weeks ago and feel that it is difficult to progress without nailing down pointers. Also address operators provide confusion for me and written tutorials are not so clear because there are different ways to use these operators.
Assume the user has already put in the number of students (hence my variables numStuds, which will most likely be irrelevant to my problem).
So suppose I have this:
void inputStudentInfo(string *names, int *movies, const int numStuds) { for(int i =0; i < numStuds; i++) { cout << "Enter student name: "; getline(cin, names[i]); read_string(names[i]);
[Code] ....
Then I have my data type checking function:
//Data-Type Checking for strings string read_string(string Sname) { while(!cin.good())
[Code] ....
I am getting errors. I know the problem I think is that I am trying to data type check for a string made up of pointers* with just a string but I don't know how I am supposed to check this?
I am trying to use smart pointers to sort and re-link potentially large data elements. I have defined a class in my code for smart pointers, as listed below:
The object I'm trying to sort is a singly-linked list containing class objects with personal records (i.e., names, phone numbers, etc.). The singly-linked list class has an iterator class within it, as listed below.
The following is my function within my list class for "sorting" using the smart pointers.
template <typename T> void slist<T>::sort(){ vector< sptr<node> > Ap(N); // set up smart point array for list //slist<T>::iterator iter = begin(); node *ptrtemp = head->next;
[Code] .....
I must have a bad smart pointer assignment somewhere because this code compiles, but when I run it, std::bad_alloc happens along with a core dump. Where am I leaking memory?
I am a little confused while comparing char pointers to integer pointers. Here is the problem:
Consider the following statement; char *ptr = "Hello"; char cArr[] = "Hello";
When I do cout << ptr; it prints Hello, same is the case with the statement cout << cArr;
As ptr and cArr are pointers, they should print addresses rather than contents, but if I have an interger array i.e. int iArr[] = {1, 2, 3};
If I cout << iArr; it displays the expected result(i.e. prints address) but pointers to character array while outputting doesn't show the address but shows the contents, Why??
I'm trying to write a function that takes a 32bit address and a data to store at this address.
I'm wanting to take the 32 bit memory address eg 0x12345678 and split it into 4 x 2 bytes 12, 34, 56, 78
then each of the 4 entries is at most a 256 entry array.eg FF, FF, FF, FF
So in this example, 0x12 points to 0x34 in the second array, which points to 0x56 in the third array, which finally points to 0x78 in the last array. This last array holds the actual data.
After successfully doing 0x12345678, say I might get a read for 0x1234AABB. So, the first and second pointers already exist, but I then have to create and write to dynamically created arrays.
The arrays need to have all entries set to NULL so that i know whether to follow the pointers to overwrite a previously entered value or create new arrays and pointers.
It all looks good and simple in the pseudo code I've written up but I'm having trouble coding it. I'm currently trying to deal with the first entry case, ie all array elements are NULL, but I'm getting confused with the pointers and creation of new arrays.
void cpu::store(unsigned int mem_add,unsigned int mem_val) { int first = (mem_address&4278190080)>>24; int second = (mem_address&16711680)>>16; int third = (mem_address&65280)>>8; int fourth= (mem_address&255);
I wrote a program that reads user input string using fgets() function. After this, program will ask if the user wants to save the string to file or does the user want to change the string or quit without saving. If user wants to change the string this must be made possible by asking for the string again. After this, menu will be printed again printing the choices available.
I had to flush stdin before getting changing input! However, problem is "Why do I have to hit return key 2 times, when I choose 2 and input string again." (I use code block 13.12 with windows 8.1 laptop) */
Code: #include <stdio.h> #include <string.h> #define MAX 50
Currently I am working on a program where you enter in a date 14 03 2013 (Day, Month, Year) and you get the next day. I seem to be coming stuck with months with less than 31 days, and the whole leap year thing. Here is my code so far.
Code: #include <stdio.h> int day, month, year, next_day, next_month, next_year, calculation; int main() { printf("Enter a date in the form day/month/year: "); scanf("%d %d %d", &day, &month, &year);
The following 2 codes are almost identical, only that the switch statements are slightly different. The 2nd code has the issue of requiring an additional enter key to be pressed when I enter '3' as input to exit the program.
Working code :
Code:
#include <stdio.h> #include <ctype.h> #include <string.h> void clearKeyboardBuffer() { int ch; while ((ch = getchar() != '