Why my pointer skips over the colour addresses, it jumps to the next size address when I use Pointer++. I have tried changing the the char array to 4 bytes instead of 32 and whatnot but it doesn't work.
If I set the Pointer = the first colour address, it skips over the size addresses and only get the colour addresses. I know using 2 arrays would easily solve everything, but sadly I must use only 1.
I've got a problem with a piece of code that it doesn't seem to work anymore.
Code: #include <stdio.h> #include <conio.h> main () {
[Code] ..... i
I chose a to be 5 and it displays the following:
"Type a value for a: 5 5 in octal is: 5 5 in hexadecimal is: 5
Process returned 23 <0x17> execution time : 1.031 s".I first saw this when trying to display the address of a pointer. Am i missing something? I used to run this code on dev-c++ successfully but after a day or so of practice, it's not working anymore. I switched from dev-c++ to code blocks.
The StackElement class contains pointers to some dynamic arrays. When I use the assignment, StackElementArray[0] = iStackElement;, it doesn't copy the complete contents and I have to define an 'assignment operator' function to copy all the contents. I am wondering if there is a way I can assign StackElementArray[0] the pointer to the StackElement object. In that case, I will not need to copy the contents of iStackElement into StackElementArray[0] and will just copy the address.
#include <iostream> using namespace std; void myfunc(int* ); // what do i put in these parameters to accept a mem loc of a pointer int main () { int x = 5;
[Code] .....
SOLUTION:
#include <iostream> using namespace std; //Purpose to create a function that returns a pointer to a pointer int** myfunc(int**); int main () { int x = 5;
I need to initialize a pointer variable with a knowing address. See code below, ptr is the final destination and value of ptr_address contains the address value, so I need to do something like ptr = *ptr_address.
Code:
int *ptr; int *ptr_address; int address; address = 0x10000005; ptr_address = &(address); ptr = *ptr_address;
The problem is that compiler gives the following warning message:
warning: assignment makes pointer from integer without a cast [enabled by default]
Is my code wrong or there is any other way to do it without receiving this compiler warning?
Is there such thing as passing a winforms label by reference? For example, can I create a pointer label and pass the address to a function? I've looked online but couldn't find anything. Perhaps that's a sign?
if possible i want avoid the '&' when i assign the variable address.(variant2 f=varname;//like you see i don't use the '&') for the moment i just need put the address to Variant pointer. but i receive several errors .
Sem is a pointer to semantic which is a struct type variable. I pass the sem into function yylex so i can fill the semantic.i and semantic.s(s points to an array). The problem is that when sem->i = a; is used inside yylex function, sem->s stops showing to the array.
#include <stdio.h> #include <stdlib.h> #include <string.h> #include <ctype.h> #include <iostream> using namespace std; union SEMANTIC_INFO
I'm having an issue coming up with an if() statement to check if a word match the one in the value of a pointer's address. So far the best I've come up with only matches the first letter of the words, you'll find it in the code below.
#include"Header.h" int Colour(struct MyStruct *ArrayPointer, int ArraySize) //ArraySize = 3 for this run. { int ColourCount = 0; for (int i = 0; i < ArraySize; i++) {
[Code] ....
An example run you can see in attached pic.
I want to have an if statement that only accepts "Red" and not the occasional "Ravaged_Anus".
I'm using MVS Express 2013, .c source files, and the C++ compiler.
I wrote a program for class. It did its job, but I want to make it better. The program finds all of the Pythagorean triples between 1 and 100.
As you can see, the program will repeat the same Pythagorean triples but in different orders.
What I want to do is have the program repeat each Pythagorean triple once, regardless of whether the ordering is different. I have tried, but only came up with the solution to solving repetition that is consecutive. But the repetition for Pythagorean triples jump around.
I got stuck on how to eliminate jumping repetitions. I only know how to make it not repeat on consecutive entries.
I wrote a program that finds the Pythagorean triples for class. It did its job, but I want to make it better. The program below finds all of the Pythagorean triples between 1 and 100.
As you can see, the program will repeat the same Pythagorean triples but in different orders.
What I want to do is have the program repeat each Pythagorean triple once, regardless of whether the ordering is different. I have tried, but only came up with the solution to solving repetition that is consecutive. But the repetition for Pythagorean triples jump around.
E.g., Pythagorean triple (6, 8, 10) appears. Then two Pythagorean triples later, (8, 6, 10) appears.
I got stuck on how to eliminate jumping repetitions. I only know how to make it not repeat on consecutive entries.
I nested one for loop, in another for loop that is nested in another for loop. One for loop for each of the values in the triple. The most nested loop is for the c value in a^2 + b^2 = c^2, and has an if statement: if( ((a*a)+(b*) == (c*c) ) , and then the program prints the numbers.
#include <iostream> #include <cmath> using namespace std; int main() { unsigned int a, b, c; char con; cout << "This program finds the pythagorean triples between 1 and 200.
I am working on an assignment for class: Create a program that allows a user to enter up to 10 addresses of friends. Use a two dimensional array to store the address of friends. After each address is entered, the user should have the option to enter another address or print out a report that shows each addresses entered thus far. I have created a code that is coming up without errors, but i am not getting the desired results.
Code:
#include <stdio.h> #include <string.h> #include <stdlib.h> int main () { char name[10][10] = {0}; char address[10][10]= {100}; int choice;
[Code]....
My trouble is coming from the the output. I am able to fill the array but i am not able to print my desired results. Where am I losing it in the loop? Also after my first entry if i have space in the "address" input the program prints and ends.
charArr = new char[50]; cout << "put in value: "; cin.getline(charArr, 50); some_func(charArr);
[Code] ....
Let's say I enter a value: 101
It goes into the if statement but clearly I've enter 1s and 0s. When I debugged, at i = 0, the charArr[i] gives me a value of 49 when assigned to an int variable. But when I cout charArr[i] it gives me 1.
So I'm going to assume 49 is part of the address? How can I correctly check the if statement condition?
When declaring char array[10], memory is allocated for 10 1-bit memory locations. Is extra memory allocated for storing the address of array[0]? In expressions, is array equivalent to a pointer constant or is it an identifier for a memory cell containing the address of array[0]? In other words, is array a variable or an alias for &array[0]?
i have been fiddling with pointers but I don't understand how the proper syntax is written when I want to acces an element of an array through a pointer to a pointer...The code is all mostly just random bs for learning purposes. I marked the problem "// THIS LINE"
This is a sample program that declares a Matrix as a structure with an array as a pointer to a pointer. The following program is supposed to store a matrix in the structure "_Matrix" and later print the matrix just entered but it fails giving me a "segmentation fault". The sample code is given below
Code: #include <stdio.h> #include <stdlib.h> struct _Matrix { int row_size; int col_size; int **mat;
I wish to know how to traverse or loop through a dynamic 2D array using pointer to pointer as returned by the code above. Like I would in a static T[20][20] 2D array.
In my refference book I have got a example with a part saying to access the a[4][0] element of the array (named a) with pointer this can be written:
*((int*)a+4)
I wonder if the cast is really required. The book says it is required so that the pointer arithmetic can be done properly. However I am not sure about it. When I work with pointers defined by myself I don't use casts similar to this one. Is there a difference between a self defined pointer and array name?
I have written this code, and at first glance it does what I want, however I am worried that
a) I am overwriting the array that is apssed from chord.getPattern() b) Im getting a memory leak that I want to get rid of, and c) is there generally a /what is the neater way to do it:
Code: uint8_t* ChordBuilder::invert(uint8_t count, Chord chord) { temp = chord.getPattern(); chord.invert(true); //TODO count is how many times to invert. Moves root aswell however
for (uint8_t i = 0; i < count; i++){
[Code] ....
temp is a member variable of ChordBuilder - and is expressed as: Code: uint8_t* temp; I dont want the pattern that chord stores, and passes with getPattern() to change - I fear it is at the moment?
I would rather not use the "new" but I cant think how to get rid of it, however Im not sure where I would need to put the "delete"?
