C :: Display Address Of A Pointer

Jan 31, 2014

I've got a problem with a piece of code that it doesn't seem to work anymore.

Code:
#include <stdio.h>
#include <conio.h>
main () {

[Code] ..... i

I chose a to be 5 and it displays the following:

"Type a value for a:
5
5 in octal is: 5
5 in hexadecimal is: 5

Process returned 23 <0x17> execution time : 1.031 s".I first saw this when trying to display the address of a pointer. Am i missing something? I used to run this code on dev-c++ successfully but after a day or so of practice, it's not working anymore. I switched from dev-c++ to code blocks.

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I have the following code.

StackElement *StackElementArray;
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I want to assign one element of this array StackElementArray the address of another object. For example,

voidStackMem::push(StackElement &iStackElement) {
CurrentDepth++;
StackElementArray[0] = iStackElement;
}

The StackElement class contains pointers to some dynamic arrays. When I use the assignment, StackElementArray[0] = iStackElement;, it doesn't copy the complete contents and I have to define an 'assignment operator' function to copy all the contents. I am wondering if there is a way I can assign StackElementArray[0] the pointer to the StackElement object. In that case, I will not need to copy the contents of iStackElement into StackElementArray[0] and will just copy the address.

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Apr 29, 2013

What I'm trying to do is:

int *p;
someType memoryLocation;
cout<<"Enter your memory location: ";
cin >> memoryLocation;
p = memoryLocation;
cout << *p;

I was just messing around with some code, and was curious to if this was possible.

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C++ :: Pass Address Of Pointer To Function

Sep 25, 2014

#include <iostream>
using namespace std;
void myfunc(int* ); // what do i put in these parameters to accept a mem loc of a pointer
int main () {
int x = 5;

[Code] .....

SOLUTION:

#include <iostream>
using namespace std;
//Purpose to create a function that returns a pointer to a pointer
int** myfunc(int**);
int main () {
int x = 5;

[Code] ....

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Why my pointer skips over the colour addresses, it jumps to the next size address when I use Pointer++. I have tried changing the the char array to 4 bytes instead of 32 and whatnot but it doesn't work.

If I set the Pointer = the first colour address, it skips over the size addresses and only get the colour addresses. I know using 2 arrays would easily solve everything, but sadly I must use only 1.

I'll post whatever relevant code here:

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Dec 28, 2013

I need to initialize a pointer variable with a knowing address. See code below, ptr is the final destination and value of ptr_address contains the address value, so I need to do something like ptr = *ptr_address.

Code:

int *ptr;
int *ptr_address;
int address;
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The problem is that compiler gives the following warning message:

warning: assignment makes pointer from integer without a cast [enabled by default]

Is my code wrong or there is any other way to do it without receiving this compiler warning?

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I have an integer pointer and i want its address without allocating memory,

main() {
int *a;
cout<<a;
}

This is giving 00000000 and its but obvious. Now if i use address of a (&a) along with *a,

main() {
int *a;
cout<<a;
cout<<&a;
}

'cout<<a' gives me a constant address but 'cout<<&a' gives me different address.

what is the reason behind & and why behaviour of 'cout<<a' changes when using with &.

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class variant2 {
private:
void *Vvariant=NULL;
public:
template<typename b>
variant & operator = (b *adress)

[Code] ....

if possible i want avoid the '&' when i assign the variable address.(variant2 f=varname;//like you see i don't use the '&')
for the moment i just need put the address to Variant pointer. but i receive several errors .

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#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#include <ctype.h>
#include <iostream>
using namespace std;
union SEMANTIC_INFO

[Code] ...

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C/C++ :: If Statement To Check Matching Word To Pointer Address Value

Jan 3, 2015

I'm having an issue coming up with an if() statement to check if a word match the one in the value of a pointer's address. So far the best I've come up with only matches the first letter of the words, you'll find it in the code below.

#include"Header.h"
int Colour(struct MyStruct *ArrayPointer, int ArraySize) //ArraySize = 3 for this run. {
int ColourCount = 0;
for (int i = 0; i < ArraySize; i++) {

[Code] ....

An example run you can see in attached pic.

I want to have an if statement that only accepts "Red" and not the occasional "Ravaged_Anus".

I'm using MVS Express 2013, .c source files, and the C++ compiler.

Attached image(s)

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I wrote a code and I found a small problem with the display of the pointer

here is the code :

Code:

#include <stdio.h>#include <stdlib.h>
#include <string.h>
int main(int argc, char *argv[]) {

[Code]....

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Feb 12, 2013

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Code:
#include<stdio.h>
#include<conio.h>
int main() {
clrscr();

int arr[10][10],rows,cols;
int* ptr;

[Code] ....

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#include <sstream>
using namespace std;
const int SIZE=5;

[Code]....

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I was having problems changing the value of my head node I passed it as an argument as head which would be the address. The parameter was defined as struct node *head. like this

bool deleteNode(struct node *head, struct node *delptr)

I tried manipultaing pointer values to change head node value but it did not work. I saw some code online which used pointer to pointers(in code below) to change head node value it worked I dont fully understand why. Would like better understanding of why.

Would also like to know why the argument call needed &head instead of just head.

remove = deleteNode(&head,found); opposed to remove = deleteNode(head,found);

#include "stdafx.h"
#include<iostream>
struct node{

[Code].....

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I'll admit that I may not be explaining this 100% correct but I am trying to implement the code inside the main function below.

class MainObject;
class SecondaryObject;
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Code:
#include <stdio.h>
#include <stdlib.h>
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FILE *fp;
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[Code] ....

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EDIT: got rid of irrelevant code. Am I using the correct syntax to do this?

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[Code] ....

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const void insertStuff(const void *key, const int value){
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switch(value){
case 0:
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[Code] .....

But this causes an error of: "crosses initialization of int*intPtr"

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i have been fiddling with pointers but I don't understand how the proper syntax is written when I want to acces an element of an array through a pointer to a pointer...The code is all mostly just random bs for learning purposes. I marked the problem "// THIS LINE"

Code:

#include <stdio.h>
#include <stdarg.h>
#include <stdlib.h>
#include <string.h>
#define MAX_DATA 100
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[Code]...

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C :: How To Declare Two Dimensional Array Using A Pointer To A Pointer

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This is a sample program that declares a Matrix as a structure with an array as a pointer to a pointer. The following program is supposed to store a matrix in the structure "_Matrix" and later print the matrix just entered but it fails giving me a "segmentation fault". The sample code is given below

Code:
#include <stdio.h>
#include <stdlib.h>
struct _Matrix {
int row_size;
int col_size;
int **mat;

[Code] ......

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