C :: How To Use Two Dimensional Array To Store Address
Apr 11, 2014
I am working on an assignment for class: Create a program that allows a user to enter up to 10 addresses of friends. Use a two dimensional array to store the address of friends. After each address is entered, the user should have the option to enter another address or print out a report that shows each addresses entered thus far. I have created a code that is coming up without errors, but i am not getting the desired results.
Code:
#include <stdio.h>
#include <string.h>
#include <stdlib.h>
int main ()
{
char name[10][10] = {0};
char address[10][10]= {100};
int choice;
[Code]....
My trouble is coming from the the output. I am able to fill the array but i am not able to print my desired results. Where am I losing it in the loop? Also after my first entry if i have space in the "address" input the program prints and ends.
I'm trying to design a C program that ask the users to type their full name (seperate by a space), and store this name in a two dimensional array. I just want to test if I did it correctly, so i just entered one name and give it a try.
char name[50][2]; printf("enter the neame"); scanf("%s%s",&name[0][0],&name[0][1]); printf("%s",name); return 0;
but the program will not print the expected result.
5. Four experiments are performed and each experiment produces four test results. The results are tabulated as shown below. Write a program to store these results in a two-dimensional array, A[4][5], then use a nested for-loop to compute the average of the test results for each experiment and store it in the 5th column of the array. Print the array.
6. Using the srand( ) and rand ( ) C++ library functions, fill an array of 1000 numbers with random numbers that have been scaled to the range of 1 to 100 inclusive. Then determine and display the number of random numbers having bvalues between 1 and 50 and the number having values greater than 50. What do you expect the output counts to be?
I'm using the SDL library and trying to match the C++11 standards... Anyway, I thought about a vector where I store all the addresses of game instances, so I can access them anytime... I tried with this function:
Where "Instance" is the 'parent' class of various child classes like the player. So, if I have to search the existing of a thing in my game, I should check if the address references to an instance of class. How can I do this?
I'm reading through a data structure textbook. I'm doing the part of Linked list. here's the code from the textbook:I'm not clear with pointer.what I'm confused is that the code created a pointer to the structure (*NodePtr)
Q1. Is NodePtr store the address of the structure?? Q2. Are top, np, last address of the structure?? Q3. here.....NodePtr makeNode(int);... does it returns an address of the structure which is np?? but following part np is used as a pointer??
How can I concatenate two 2-dimensional int arrays into one larger 3-dimensional array. This question is also valid for the 3-dimensional vectors. I know the command for the one dimensional vector as:
I want to store the address of a customer (with spaces) in a char variable (say cadd). First I tried to use "cin", as we know it reads until it sees any whitespace. So it reads only first word before a white space. So, I used "getline()" function, it will work. But when I used it, It did'nt wait for the I/P (it skipped it).
I had a hard question in my C++ final exam and I'm trying to solve it for the last 3 days. I haven't succeded yet! Here is the question: You have a one-dimensional array A[20]={1,2,3,4,...,20} and B[5][4] you have to assign the A array's elements to the B array but there is an order which is: B[5][4] = { { 12, 9, 11, 10 }, { 14, 7, 13, 8 }, { 16, 5, 15, 6 }, { 18, 3, 17, 4 }, { 20, 1, 19, 2 } } and there is a restriction: you can only use ONE for statement, nothing else!
#include <iostream> #include <iomanip> using namespace std; int main(){ int A[20] = { 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20 }; // define A array's elements. int B[5][4] = { 0 }, k = 1; // define B array and k counter.
[code]....
I can't narrow the statements to one,This program works perfectly but it shouldn't be that long, we need ONLY ONE FOR statement, not two!
I have a 3D array that contains 200 strings. I'm trying to copy all these strings into a 2D array. How can this be done? This is what I have so far but it isn't working correctly.
Code: for(int i = 0; i < row; i++) { for (int j = 0; j < col; j++) { dest[i][j] = source[0][i][j]; } }
The finished product would be with 100 rows, 2 columns.
Write a program using user-defined function which accepts an integer array and its size as arguments and assign the elements into a two dimensional array of integers in the following format: If the array is 1,2,3,4,5,6, the resultant 2D array is
charArr = new char[50]; cout << "put in value: "; cin.getline(charArr, 50); some_func(charArr);
[Code] ....
Let's say I enter a value: 101
It goes into the if statement but clearly I've enter 1s and 0s. When I debugged, at i = 0, the charArr[i] gives me a value of 49 when assigned to an int variable. But when I cout charArr[i] it gives me 1.
So I'm going to assume 49 is part of the address? How can I correctly check the if statement condition?
I want to make a program that asks the user for a message and then print out a large graphic of that message. For example, if the user types "he" I want to print out
H..................H EEEEEEEEE H..................H E H..................H E H..................H E HHHHHHHHHH EEEEEEEEE H..................H E H..................H E H..................H E H..................H EEEEEEEEE
(treat the periods as spaces. I only put them there because it wouldn't separate the H's correctly.)
I will loop this to continue until the user types quit.
1. How would I set this up to store the user input characters into an array?
2. How would I print out the stored data in the shape of the word?
Here is what I have, I have a 1D Array being added to a 2D Array and I need to Sort them by value value 3 in the 2D Array, while maintaining a specific amount. Here is what I have so far:
I am thinking bubble sorting but I remember reading about something faster. Unfortunately I can't find it on the web. The idea is that there will be always 10 Values and 4 Columns on the 2D Array. [The 11th Row being empty at the end of it.
I want to create 4 dimensional array, in that first three dimenstional are fixed size and the final index will be on 0 to N-numbers.
E.g., double array[500][25][10][<NOT FIXED>].. So I cant create statically, because the index size are more. Also I have tried 4 dimenstional vector, but its giving 2 problem.
(i) I am storing 4th dimenstion size is more than vector[0][0][0].max_size() (ii) Storing and Retrieving its more time in vector
So, any other solution to store large array which is 3 index is FIXED and final one is not FIXED?
i created a program which uses Sparse 2 dimensional array, but i am not sure if i did it in the right way .
this is the instruction i have:
Create a constructor and a destructor. The constructor should take as input the size of the array (consider only square NxN arrays, so only one dimension is needed) and the thickness of the ribbon. To make this precise, if supplied with a thickness parameter t, you may assume that the element [0,t] (i.e. the (t+1)-th element of the first row) is where the useless area begins on the right. Similarly, the element [t,0] is where the useless area begins on the left. The border of the useless areas moves diagonally down and to the right, i.e. it consists of [1,t+1],[2,t+2],... and [t+1,1],[t+2,2],... The above example has thickness 3.
The space for the 2-d array should be dynamically allocated and must be large enough to fit the useful data only.Create methods for random read and write access to the array as in the case of 1-d arrays.Overload the [] and << operators, as in the case of 1-d arrays. Think carefully about what the [] operator should return and how it should work. Ideally we would like this to behave in a manner similar to standard 2-d arrays (i.e. accessing elements in the normal way, like x[5][6]).
Why my pointer skips over the colour addresses, it jumps to the next size address when I use Pointer++. I have tried changing the the char array to 4 bytes instead of 32 and whatnot but it doesn't work.
If I set the Pointer = the first colour address, it skips over the size addresses and only get the colour addresses. I know using 2 arrays would easily solve everything, but sadly I must use only 1.
The program should store a character array in reverse order then display the reversed array. I have also included in the code that will display the actual characters into the array as it loops through. So I know the characters are being stored, but why doesn't it display the entire string when I call it?
