I am trying to set a variable of type char equal to an element in an array of characters. For example:
char data[4] = "x+1";
char element;
element = data[2];
This seems like a logical progression from number arrays, but when I print both element and data[2], I get data[2] as expected, but element gives a different character every time (I assume a garbage value).
how to convert an element of int type of an array to char type?
View 2 Replies View RelatedI would like to convert a float or double variable into unsigned char variable and back.
float number_float = 23.453f;
unsigned char* number_char = (unsigned char*)malloc(sizeof(float));
number_char = reinterpret_cast<unsigned char*> (&number_float);
float* number_float_0 = reinterpret_cast<float*>(&number_char);
I am not getting the same value back.. why?
I have two char variables, m_GPSOffset[13] and m_FileName[100]. When m_GPSOffset has a value assigned to it, say for instance +11:25:30. The first entry of the value, in this case +, is always stored in m_FileName. I am clueless on why this is occurring.
View 15 Replies View RelatedI'm having some problems with changing an array of numbers of type char to type int. Every time i try to sum 2 array indexed values it returns some letter or symbol. Also, if i change the type of the array in the functions the compiler gives me an error message. I would also like to add that the problem requires that the first two arrays be char so each individual number gets assigned to a different value.
My current code is:
Code:
#include <iostream>
void input(char a[], char b[], int& size_a, int& size_b);
void convert(char a[], int size);
void reverse(char a[], int size);
void add(char a[], char b[], int c[], int size);
int main()
[Code]....
how can i compare an element of the char array and string with single chsracter also how to compare char array to cpp string
View 3 Replies View Relatedi would like to know how to replace a value with the variable that ii is equal, i mean like a=5 i want to be able to replace the number 5 by the letter a when needed in printf. ofc i want to use this for an actual purpuse and meaning what i gave was a mere example and thxx. BTW DONT jUst DROP a few lines of code that would make it work
View 5 Replies View RelatedBelow is an extracted portion of an example exercise from the C Programming Language book:
Code:
void escape(char * s, char * t) {
int i, j;
i = j = 0;
while ( t[i] ) {
switch( t[i] ) {
[Code] ....
Here's my problem with this. s is a pointer to a char array. That means each index stores 1 byte. A backslash character '' is one byte. In above example, we escape it with a second backslash character: ''. That means we have two bytes there. So why does it allow inserting two bytes into a one byte index?
How to change an enum type variable to a string type variable?
View 2 Replies View RelatedI have an array of char pointers:
Code: char *input_args[MAX_ARGS];
And I have this function:
Code: BOOL parseArgs(char **input_args[], input arg_num);
I am trying to pass a pointer to this char pointer array like this:
Code: parseArgs(&input_args, args_num);
But the compiler is complaining:
Code: warning: passing argument 1 of 'parseArgs' from incompatible pointer type ...
note: expected 'char ***' but argument is of type 'char * (*)[20]'
Tried a bunch of stuff but nothing works.
I am trying to convert a char buffer[1024] with raw data to int 16 buffer2[1024] which is supposed to have hex data (0x01, 0x02 kind of format).
Code:
char temp_buffer[1024];
block_size = sizeof(temp_buffer);
num_blocks = sizeof(char);
Status = mount(0, &myfsObject);
if(Status != DAVEApp_SUCCESS)
[Code] .....
I am verifying the data of resultant buffer by creating a new file and writing data to it. The result which i got is:
Code: H uy H uy H uy H uy H uy H uy H uy H uy
How to insert strings into an array of type char and also delete strings from that char array.
View 4 Replies View RelatedI am not getting any error below
--------
#include <iostream>
using namespace std;
void main()
{
char sqr[3];
sqr[0] = '1';
sqr[1] = '1';
cout << sqr[0] << sqr[1];
while (1);
}------------
but if I move my char type array before main , I get error l
----------------------------
#include <iostream>
using namespace std;
char sqr[3];
sqr[0] = '1';
sqr[1] = '1';
void main()
{
cout << sqr[0] << sqr[1];
while (1);
}
-------------------
I am writing a class Player which has several char arrays as private fields. I am trying to write a method which returns an array as a pointer, but doesn't alter the array in any way, thus the const.
Here is a snippet:
Code: class Player
{
private:
char state[MAX_STATE_CHAR + ONE_VALUE];
int rating;
char last[MAX_NAME_CHAR + ONE_VALUE];
char first[MAX_NAME_CHAR + ONE_VALUE];
int groupNumber = NEG_ONE;
public:
char * GetFirst() const
{
return first;
}
Visual studio is saying that the return type doesn't match.
I have program where i have to check to see if file exist, if it does not then it needs to be created. SO I have a read file that works fine, if th efile exist it reads whats in it, if it does it says the file does not exist. Now Im trying to creata function that creates the file if it doesnt exist. so in my read function when the person enters the name of the file to be checked for..I pass that name to a variable called name..Hoping that I could then pass it into my create file function if it does not exist..and use that variable to pass the name they entered into the createfile array..called filename.. but I am having trouble because i get error when i try to pass from a string name to char array.. even when I change the varialbe name to char, or char [256] it will not work.. I try to fing a way to convert th string to a char using the strncopy function but still no dice..here the code i have for the createfile funciton
void CreateNew(ofstream & FileNew)//Create file
{
char filename[256];
string name;
[Code].....
How can i do this without having to ask the person to enter the file name twice..
How i can find two equal int in array with O(n) time complexityand O(1) place complexity?
View 8 Replies View RelatedHere is the code
#include <iostream>
using namespace std;
int main () {
char element;
cout << " Please enter a symbol. " << endl;
[Code] ....
let's say someone puts in h and Hydrogen comes up, and when someone puts in he, hydrogen also comes up, what am i doing wrong.
what is the function of ordering element(char)in a struct
View 1 Replies View RelatedI am programming a 2-D platformer video game. The stages are composed of an array (really a vector) of 16x16 px^2 tiles. I have defined a base class "Tile" and several derived classes, e.g., "Ramp", "Door", etc., which have their own attributes. The idea is that upon entering a room, the program will load all of the necessary tile data for that room into a vector. So, I have a vector that looks like: vector <Tile*> room_tiles, and resize it based on the total number of tiles in the room: room_tiles.resize(Tile_Count). I then want to read in certain info from the data file containing all of the tile information for that room. For example, if the data file says Tile 5 should be a ramp, I want to change the 5th element of the room_tiles vector to the derived ramp class. This is really where I'm having trouble. I've worked with vectors of base and derived classes before, but those were always of indeterminate size and I always used something like: (Vector).push_back(new DerivedClass()) to specify the derived class of that element. The problem is that that method only seems to work if you are appending elements to the end of a vector.
how I can do this?
Why I cannot do this to display each element of my char string? What is the proper way?
Code:
char str[SIZE];
int i;
for(i=0; i<SIZE; i++)
{
printf("%s", str[i]);
}
create a program that asks the user to input 10 integers of an array the program will add the numbers greater or equal to 10.
View 6 Replies View Relatedso my question is i want to print characters,no string just an array of characters,i do this but it s not working,maybe i have to put the '' at the end?
Code:
int main() {
int i;
char ch[5];
for(i = 0; i < 5; i++) {
scanf("%c",&ch[i]);
[Code]...
/*Write a program that mimics a calculator. The program should take as input two integers and the operation to be performed. It should then output the numbers, the operator, and the result.(For division, if the denominator is zero, output and appropriate message.) Some sample outputs follow:
3+4=7
13*5=65*/
#include <stdio.h>
int main()
{
[Code].....
I have an array of characters. I am trying to find "houston". The only way I can think of to do this is to use a for loop and check each individual character. Is there an easier way to do this?
char string[] = "Fishing tourism miami atlanta dallas houston";
I have this program.
Code:
int test_variable;
int main() {
test_variable = (int)0x12;
}
Now my doubt is what is the advantage of type casting 0x12 to int. suppose if the test_variable data type is "char" then should i type cast to "char"?
How can you convert int type to const char*
View 2 Replies View Related