/*Write a program that mimics a calculator. The program should take as input two integers and the operation to be performed. It should then output the numbers, the operator, and the result.(For division, if the denominator is zero, output and appropriate message.) Some sample outputs follow:
3+4=7
13*5=65*/
#include <stdio.h>
int main()
{
[Code].....
I'm currently doing the exercises for the fifth chapter (Loops) and I've done all of them, but I wanted to go the extra mile on the last program I'm supposed to design. The program is a poll and all the input from the user will be with numbers. However when a letter is pressed then of course you get wrong behaviour from the program, it keeps looping endlessly.
Here is a fragment of what I think is the way of doing it - but of course it's not working
Code:
int p = 0
char anyLetter[]={"abcde"};//Initializing char variable
char a = anyLetter[p];
else if (userAnswer[n] == a)//if statement where char needs to be used.
{
cout << "Pressing a letter maybe? It's only with numbers. Try again." << endl;
continue;
}
Below is an extracted portion of an example exercise from the C Programming Language book:
Code:
void escape(char * s, char * t) {
int i, j;
i = j = 0;
while ( t[i] ) {
switch( t[i] ) {
[Code] ....
Here's my problem with this. s is a pointer to a char array. That means each index stores 1 byte. A backslash character '' is one byte. In above example, we escape it with a second backslash character: ''. That means we have two bytes there. So why does it allow inserting two bytes into a one byte index?
I am trying to set a variable of type char equal to an element in an array of characters. For example:
char data[4] = "x+1";
char element;
element = data[2];
This seems like a logical progression from number arrays, but when I print both element and data[2], I get data[2] as expected, but element gives a different character every time (I assume a garbage value).
How can I display my inputted values here without overwriting the other earlier inputted values. It should be displayed like this [URL].... but mine shows this [URL].... I've been stucked here for hours in thinking for an algorithm. Everything is working fine except the PDISPLAY part
#include<iostream>
#include<iostream>
#include<string>
#include<cctype>
#include<cstdlib>
#include <iomanip>
#include <windows.h>
#include<conio.h>
[Code]...
#include "stdafx.h"
#include <iostream>
#include <string>
using namespace std;
int x;
string favword;
[Code] ....
I want this program to be able to recognize if a user types in any word ex. (apple, tree, house etc..) and print "system error" if a word is recognized not to be a number. The bold section of code is my failed attempt to try this. Basically I need to know what to make
(x = ?(every word)) in order to finish my console program.
I need to develop an application in VC++ that will take .WAV files as an input and identify if there is a Gun shot in that wave file. WAVE file with gunshot must be having certain paramaters like frequency, bit rate etc which I don't know right now. But is there a way in VC++ to develop a program that can recognize gunshots by comparing that .WAV file with certain parameters?
View 3 Replies View RelatedI have my libraries in ../../lib location
and when i try to compile :
gcc -O9 -I ../../include/ -L ../../lib/ -o test test.c thr.o -lm -lthread
I get :
gcc: error: thr.o: No such file or directory
obviously the problem is the library path location but my obj is there
ls -al ../../lib/ | grep thr.o
-rw-rw-r-- 1 xxxxxx xxxxxx 23544 Aug 12 23:03 thr.o
????
I'm trying to write a function which can recognize whether a word is a palindrome. if it's the case , it must return 1 on screen, otherwise 0. This is the code which return 0 even in case of a palindrome...
Code:
int IsPalindrom(char String[]){
int i,l;
int counter=0;
for(i=0;;i++){ //counts the number of array elements
[Code] ....
How do I create a function that can understand trigonometric functions?
Examples:
if I am to input: x^2 + sin(x)
The program will understand the the value between parenthesis preceded by a string "sin" will be computed as the sine of x. of any function in case.
I have the program here.
#include <iostream>
#include <cstdlib>
#include <cctype>
#include <cstring>
using namespace std;
enum types { DELIMITER = 1, VARIABLE, NUMBER }; //DEL = 1; VAR = 2; NUM = 3.
class analyzer {
[Code] .....
In my little experiment i am trying to get the compiler to recognize 1 word with 2 parts from a list of names.
For example: if the user wanted to choose "candy bar", from a list of items which include: "candy bar", "cat", "dog"
My current code can recognize words without a space like cat and dog. But how can i recognize candy bar?
I tried using getline but its of no use.
I need to write a c program that can receive signals and recognize a certain pattern (SIGUSR1, SIGUSR2, SIGUSR1, SIGUSR2). once the pattern is caught the program terminates itself.
I am able to send the signals to the program from a different process, but I am unsure on how to get the signal handler to recognize the pattern. here is what i have so far:
Code:
#include <signal.h>
#include <stdio.h>
#include <string.h>
#include <sys/types.h>
#include <unistd.h>
#include <stdlib.h>
sig_atomic_t sigusr1_count = 0;
sig_atomic_t sigusr2_count = 0;
[Code] .....
I just need getting the program to be able to catch that specific pattern.
My use case is this: I have a C# Console application. I would like to run it via the Windows Task Scheduler, and would like it to attempt to run until it succeeds. My problem is that I can't achieve this. How does the Windows Task Scheduler recognize that a program has failed? I tried returning 1 or 32 instead of 0 but that didn't work. One possibility is to have the rerun logic in the C# console application but it feels like there must be a better way.
View 6 Replies View Relatedso my question is i want to print characters,no string just an array of characters,i do this but it s not working,maybe i have to put the '' at the end?
Code:
int main() {
int i;
char ch[5];
for(i = 0; i < 5; i++) {
scanf("%c",&ch[i]);
[Code]...
Im supposed to find the common characters between two string characters, assuming that the user wont input duplicate letters like ddog. When I run my code I get an output of a question mark upside down. Here is my code with comments on what each part is supposed to do
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
int main(){
char str1[20], str2[20],remp = ' ';
int size1,i,j,temp;
printf ("Input the first string");
[Code]...
how can my program read if a letter is inputted again it prompts "letter inputted already"? heres my code:
Code:
#include <stdio.h>
#include <string.h>
#include <conio.h>
[Code].....
I have been here for almost 3 months looking for answers in my C++ problems.here's some type of code for this.
cout << "Enter value of x: " << endl; //Let's say 5.
cin >> x;
cout << "Enter equation: "; //Let's say x+1
cin >> equation;
Then the program analyzes that this character "x" has an initial value of 5.I already have the parser for the equation functions (+,-,*,/)This is the only thing lacking. Is there some type of function that i missed?
Program works perfectly fine. I input in the length, width and height. But i want it to display those values for every individual prism when i output... along with the area and volume which i already have. Since i made a vector i won't let me cout it normally.
#include <iostream>
#include <vector>
using namespace std;
[Code].....
#include<stdio.h>
#include<conio.h>
#include<string.h>
char str1[20], str2[20]="kent";
main() {
printf("Enter your Username: ");
scanf("%s",str1);
[Code] ....
I need to allow the user to input an integer of any length and print out the word of each number in the integer. So the user would enter "324562" and then the output would be "three two four five six two". I'm struggling to understand the best way to do it in C. I know I need a loop that goes through the int but I don't know how to do it
View 7 Replies View RelatedI came up with this code to try to add each number from a zip code inputted by the user but I think I'm adding up the ascii values not the real values the user is inputting. How I can go from ascii to the real digit. This is my code so far
#include <iostream>
#include <iomanip>
#include <string>
#include <conio.h>
using namespace std;
int main() {
int total = 0;
char ch[5];
cout << "Please input your 5 digit zip code: ";
[Code] ....
I've been working on this program and I have it all pretty much down, but I just need one thing that I can't, for the life of me, think of! I need to find the reciprocal of a number that the user inputted (ex: if user input was 2 output would be 0.5 or if input was .6, out put would be 1.6 repeating). If theres a simple way, I can't think of it.
View 2 Replies View RelatedMy problem is that some of my conditions are not being triggered when the price level of a medium or large discount is smaller than the cost of the widget(defined as .40) An example being ,base price, $2 med discount 80%, and large discount 90%. My med discount is,1.6(80%) off of 2, so $.40, which is fine, but 90% off mean 1.8(90%) off of a base of $2, which is $.20 which is too low., and should trigger the 4th if statement, Nick you are discounting large purchases too much!. However when I run this in the program, I am triggering the first if statement.
#include <math.h>
#include <stdio.h>
#define widget_cost 0.40
int main (){
float sellprice;
float discount_med_price;
[Code] ....
I am trying to get this program to accept two inputs Student number and grade and validate them both
However the program skips over the student number
Code attached AssignmentProgram.c
I've written a program which takes a character string and then prints each character vertically so that for instance the string 123 can be written as
1
2
3
no what i need is for all the numbers from zero to the inputted number to print the numbers digits vertically but each number to be printed horizontally so that for instance an input of 11 prints
1 2 3 4 5 6 7 8 9 1 1
0 1
i've made it so that i can print all numbers up to the inputted number vertically; however, i am stuck with a method for making each number print horizontally as described above.
I have an array of characters. I am trying to find "houston". The only way I can think of to do this is to use a for loop and check each individual character. Is there an easier way to do this?
char string[] = "Fishing tourism miami atlanta dallas houston";