C++ :: Why If Statements Will Not Recognize Characters Inputted For Char
Oct 4, 2013
/*Write a program that mimics a calculator. The program should take as input two integers and the operation to be performed. It should then output the numbers, the operator, and the result.(For division, if the denominator is zero, output and appropriate message.) Some sample outputs follow:
I'm currently doing the exercises for the fifth chapter (Loops) and I've done all of them, but I wanted to go the extra mile on the last program I'm supposed to design. The program is a poll and all the input from the user will be with numbers. However when a letter is pressed then of course you get wrong behaviour from the program, it keeps looping endlessly.
Here is a fragment of what I think is the way of doing it - but of course it's not working
Code: int p = 0 char anyLetter[]={"abcde"};//Initializing char variable char a = anyLetter[p]; else if (userAnswer[n] == a)//if statement where char needs to be used. { cout << "Pressing a letter maybe? It's only with numbers. Try again." << endl; continue; }
Below is an extracted portion of an example exercise from the C Programming Language book:
Code: void escape(char * s, char * t) { int i, j; i = j = 0;
while ( t[i] ) { switch( t[i] ) {
[Code] ....
Here's my problem with this. s is a pointer to a char array. That means each index stores 1 byte. A backslash character '' is one byte. In above example, we escape it with a second backslash character: ''. That means we have two bytes there. So why does it allow inserting two bytes into a one byte index?
I am trying to set a variable of type char equal to an element in an array of characters. For example:
char data[4] = "x+1"; char element; element = data[2];
This seems like a logical progression from number arrays, but when I print both element and data[2], I get data[2] as expected, but element gives a different character every time (I assume a garbage value).
How can I display my inputted values here without overwriting the other earlier inputted values. It should be displayed like this [URL].... but mine shows this [URL].... I've been stucked here for hours in thinking for an algorithm. Everything is working fine except the PDISPLAY part
#include "stdafx.h" #include <iostream> #include <string> using namespace std;
int x; string favword;
[Code] ....
I want this program to be able to recognize if a user types in any word ex. (apple, tree, house etc..) and print "system error" if a word is recognized not to be a number. The bold section of code is my failed attempt to try this. Basically I need to know what to make
(x = ?(every word)) in order to finish my console program.
I need to develop an application in VC++ that will take .WAV files as an input and identify if there is a Gun shot in that wave file. WAVE file with gunshot must be having certain paramaters like frequency, bit rate etc which I don't know right now. But is there a way in VC++ to develop a program that can recognize gunshots by comparing that .WAV file with certain parameters?
I'm trying to write a function which can recognize whether a word is a palindrome. if it's the case , it must return 1 on screen, otherwise 0. This is the code which return 0 even in case of a palindrome...
Code: int IsPalindrom(char String[]){ int i,l; int counter=0; for(i=0;;i++){ //counts the number of array elements
I need to write a c program that can receive signals and recognize a certain pattern (SIGUSR1, SIGUSR2, SIGUSR1, SIGUSR2). once the pattern is caught the program terminates itself.
I am able to send the signals to the program from a different process, but I am unsure on how to get the signal handler to recognize the pattern. here is what i have so far:
My use case is this: I have a C# Console application. I would like to run it via the Windows Task Scheduler, and would like it to attempt to run until it succeeds. My problem is that I can't achieve this. How does the Windows Task Scheduler recognize that a program has failed? I tried returning 1 or 32 instead of 0 but that didn't work. One possibility is to have the rerun logic in the C# console application but it feels like there must be a better way.
so my question is i want to print characters,no string just an array of characters,i do this but it s not working,maybe i have to put the '' at the end?
Code:
int main() { int i; char ch[5]; for(i = 0; i < 5; i++) { scanf("%c",&ch[i]);
Im supposed to find the common characters between two string characters, assuming that the user wont input duplicate letters like ddog. When I run my code I get an output of a question mark upside down. Here is my code with comments on what each part is supposed to do