How do i print another shape near the one i did. I have this code but how i can put another shape near it like this
Code:
#include <stdio.h>
int main() {
int i;
for (i = 0; i < 5; i++)
switch (i) {
case 0:
printf(" *
[Code] .....
Here is a simplified version of my Menu class, where submenus can be inserted arbitrarily deep. I need to add a new functionality "go back to previous menu", which I would like to be activated by entering 0 (universal command for all Menu instances). I considered the Memento Pattern, but that doesn't seem to quite fit. add that functionality to my Menu class.
#include <iostream>
#include <cstring>
using namespace std;
const int END = -1, NO_SUBMENU = 0;
[code]....
Say a user installs and uses the software for awhile. Then they uninstall it. Client wants the database containing client data to remain behind, in case they ever re-install the software. Which is fine.
So then.. they re-install the software. Client wants them to have the choice to either use the existing database, or to create a new one. When the software fires up, it always checks for the database, and creates one if it's not there. So how can I determine if the instance is a new install, or a current install, given that the database will be there no matter what?
I am in the process of creating a game that has two players machine and person. The player is selected randomly each round. So if the player is selected, he needs to choose a number from 1-9. Then the machine needs to choose another new number either in the same row or colunm.(i figured out how to check against col.and row). Then keep going until someone reaches 31.
I'm stuck on how to add the numbers from previous rounds and have them reflect in the new rounds. While at the same time using the last entered number(last numbers) as a reference has to whether or not the new number is valid.
Ok I created a while loop as suggested. But it is not adding each round like it should. So the question is: What is wrong with the code after the while loop?
while ((x != 0) && (suma < Meta)){
cout << "SUM =" << x + last number << endl;
if (player == Person) {
x = machinerandomnDigit(last number);
sum = sum + x;
player = Person;
last number = x;
[Code]...
decTotalAmountOwed = decAmountOwed + decAmountOwed;
This is what i've tried so far. The numbers are supposed to be added together once placed in listbox.
I have a condition and I would like to instead change the condition so that it would execute the previous statements after else statement.
It seems hard to explain but I'll try my best to illustrate anyway
if (condition)
<statement1>
else
<statement2>
So I would like to change the condition so that
if (condition)
<statement2>
else
<statement1>
And the condition is
Code:
if(!lightStateAtNextLink || !bIsLightEnAtConnection && nLinkNext.IndexToAttachedNode() != pVeh->_.stAutopilot.m_dwNextNode || bIsLightEnAtConnection && nLinkNext.IndexToAttachedNode() == pVeh->_.stAutopilot.m_dwNextNode)
And I have changed that to this. Is this correct?
Code: if(lightStateAtNextLink && bIsLightEnAtConnection || nLinkNext.IndexToAttachedNode() == pVeh->_.stAutopilot.m_dwNextNode && !bIsLightEnAtConnection || nLinkNext.IndexToAttachedNode() != pVeh->_.stAutopilot.m_dwNextNode)
For my assignment I have to have an array with only zeros.
Code:
int a[20] = { 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0 }; Then I need to send it into a function that makes the array like this
Code: int a[20] = {0,1,2,3,4,5,6, ... , 19}
Which I have done here
Code:
int initialize(int a[], int n) {
int m = 0;
int i;
printf("
[Code] ....
Now I need to do the following with the array. I need to take whatever value is in each position and add that value to all of the previous values. like this.
Code:
a[3] = a[3] + a[2] + a[1] + a[0]
only for every a[i] I know that I can code this the long way, but I just can't see to be able to find out how to do this a better way.
I am making a product and in which i use a timer. I want when the product is being start the timer will run and when the product is off the timer will stop. If i again start the product the timer will start from its previous value.
I have problem that the timer start from its initial when i start my product.
//#include "stdafx.h"
#include<iostream>
#include<cmath>
using namespace std;
//class declaration
class dayType{
public: int presday;
[Code] ....
So everything works perfectly, well not everything lol. Code compiles successfully without any errors but previous day does not calculate. In a sense that when it asks for number of previous days it returns a blank statement.
For example: Previous number day is: shows nothing
Below is the sample of the code :
int summation = 0;
for (it= s.begin(); it!= s.end(); ++it) {
summation += std::atoi( ((*it).substr( 8 )).c_str() );
}
Nos after the first 8 characters are the ones I need to perform addition on.
do the summation of these nos.
Im trying to do a small program that will create multiples of the previous line *2, and spit out the anwser in seperate lines (as many times as the user wants)
Example if i wrote it in a bad way
2
4
8
16
32
etc.
At this time my code looks likes this, now im planing to get my hands on the IF statment
using System;
using System.Collections.Generic;
using System.Linq;
[Code].....
I have started making a text adventure game.
if (Choice == 2) {
cout << "" << endl << "You follow the light to the end of the hallway, you find your self in a room" << endl
<< "with natural light coming from a hole in the ceiling." << endl << "" << endl << "You hear the door you just came through, slam behind you!" << endl << "" << endl
<< "There are three possible directions." << endl << "" << endl << "Do you:" << endl << "" << endl << "1) Go forward" << endl << "" << endl << "2) Go left" << endl
[Code] .....
Ignore the if (Choice == 2) at the beginning, that's linked to some previous code.
I want to make the player go back to the first bit of text but i'm not sure how to do this if they keep choosing to go back and forth from one location.
I first thought of doing it by just putting the text back in after they have chosen the option, but I can't do this infinite times.
I have begun switching from WinForms to WPF and I'm having a hard time understanding the new concepts. In WinForms, I had a few User Controls, custom drawn using shapes (rectangles, ellipses, etc). They had some unique properties, like "Flashing" (setting this property to True and setting the "Flash Interval" property to 500 would have resulted in the control changing its background color to white and back again, every 0.5 seconds), "Beeping", etc.
I have tried to replicate these controls in WPF/XAML and so far managed to draw the shape. However, when it came to implementing a custom property that would redraw the background color of the rectangle every interval set by user in another property, i got stuck. The property is being set, but it doesn't change the background color. Alternatively, i have tried this method, with the same results (i got it to show in the "Properties" window in Visual Studio, i can set it, it is being stored in XAML, but it doesn't affect the background.
C# code behind:
public struct LCARSColors
{
public static Brush DarkBlue = (Brush)(new BrushConverter().ConvertFrom("#FF3366CC"));
public static Brush LightBlue = (Brush)(new BrushConverter().ConvertFrom("#FF99CCFF"));
public static Brush Pink = (Brush)(new BrushConverter().ConvertFrom("#FFCC99CC"));
[Code] ....
If i use this line (commented in this code sample):
<!--<SolidColorBrush x:Name="MySolidColorBrush" Color="{DynamicResource DarkBlue}" />-->
The background is colored in DarkBlue (as defined). But if i use this line:
<SolidColorBrush x:Name="MySolidColorBrush" Color="{Binding BackgroundColor, UpdateSourceTrigger=PropertyChanged, Mode=TwoWay}" />
Nothing happens, the rectangle disappears entirely. If i add this to the above line:
FallbackValue=LightYellow
The rectangle is colored in LightYellow, meaning that the property is not accepted and the fallback value is used. Why?
I'm doing a project and I need to draw a square into a pgm image if certain conditions are met, but I'm not sure how to draw the square into the image.
View 2 Replies View RelatedI'm building a pretty basic calculator program that calculates the area of generic shapes (triangles, rectangles, and squares); for some reason though, my program is having troubles as soon as it hits the if/else code in the int main section. When I enter triangle, rectangle, or square, it just spits back out the "That's not one of the options. Please re-enter and try again." error line I created. When I isolate and run just the stuff inside the if/else statements it works great, but why it won't just understand my if (shape == triangle).... .
Code:
#include <iostream>
using namespace std;
class figure {
protected:
double x, y;
[Code] ....
I know how to define a shape and attach it to a window as follows:
#include <Simple_window.h>
void cir() { Circle c(Point(100,100),50); }
int main() {
Simple_window win(Point(100,100),600,400, "test");
Rectangle r(Point(100,100),Point(300,200));
win.attach(r);
win.wait_for_botton();
}
But how to define a shape (say a circle by that cir() function which is) outside of the main() function? And how to attach it to be visible on window win?
have a problem with my code (I wish for answer with code). The conditions I have to grant:
- **Only** a pointer to an object must be saved in a **standard** class vector (e.g vector<ShapePtr>)
- Base class must be a polymorphic class (I call this class ShapePtr)
- I **must** have a deep copy process
- Constructor is **not** suppose to do a deep copy
- **clone()** is suppose to do the deep copy
Here is the code **provided** to me:
main.cpp
int main() {
typedef shared_ptr<Shape> ShapePtr;
vector<ShapePtr> shapevec;
[Code].....
This is part of the program, What should i do if i want to total the number of times a shape was selected at the end?
#include<iostream>
#include<string>
#include<iomanip>
[Code]....
I know how to define a shape (here, a rectangle) and attach it to a window in C++ as follows:
#include <Simple_window.h>
void cir() { Circle c(Point(100,100),50); }
int main() {
Simple_window win(Point(100,100),600,400, "test");
Rectangle r(Point(100,100),Point(300,200));
win.attach(r);
win.wait_for_botton();
}
But how to define a shape (say a circle by that cir() function which is) outside of the main() function? And how to attach it on the window win to be visible?
I have cross sections in the form of rectangles in the XY plane formed from two point (top left, bottom right) as well as their Z position. I'd like finding some sort of API that can extrude a basic linear-average-approximated 3D shape (preferably eventually into STL format) from these points. I've tried googling but to no avail. The aim is to build a 3D shape from 2D wireframes.
View 2 Replies View Relateddynamically allocated arrays. int (*ttt)[2][10]; If I'm not mistaken this declares a pointer (that's all). This pointer has an intrinsic shape that makes it easier to access row, column without doing my own math to calculate the offset.
ttt = malloc(2 * 10 * sizeof(int));
So I should be able to access elements like this: ttt[i][j].
ttt[i][j] = 123;
But the compiler says: error C2440: '=' : cannot convert from 'int' to 'int [10]'...how to go about accessing a monolithic block of allocated memory using 2 or more dimensions, using some sort of casting to a known shaped array if possible. As opposed to doing i * cols + j type stuff.
I am trying to detect when my mouse is over a item. I can get it working if its a square shape an stuff.
(LOWORD(lParam) > 133) && (LOWORD(lParam) < 154) && (HIWORD(lParam) > 0) && (HIWORD(lParam) < 21)
but how would i detect if its over the white spot in this image? [URL] ....
i just drew a simple shape i need to detect from more edges but how to do it?.
And for some reason my program pauses (nothing displays, and my cursor changes to the little "loading" cursor thingy) when it hits line 139. That is where I added an additional piece of code that should change the shape of the triangle while the program is running.
#include <Windows.h>
#include <WindowsX.h>
#include <d3d9.h>
#define CUSTOMFVF (D3DFVF_XYZRHW | D3DFVF_DIFFUSE)
[Code].....
Having issues with program to create a shape area calculator with circle square and rectangle. the uml goes as follows:
Where the UML has shape as the abstract class with public area():double, getName():string,and getDimensions:string, rectangle derived from shape with protected height, and width, and a public rectangle(h:double, w:double), followed by a derived square from rectangle with just a public square(h:double), and finally a circle derived from shape with a private radius, and a public circle(r:double).
[URL]
Have linked my program and it is giving me the following compiler errors:
error: 'qdebug' was not declared in this scope line 15 of main
error: cannot declare variable 'shp' to be of abstract type 'shape' line 22 of main
error: expected primary-expression before ')' token lines 29 -31 of main
(note previously had qstring as a header file yet changed to string since I was getting error qstring was not declared in this scope.)
I know how to define a shape (here, a rectangle) and attach it to a window in C++ as follows:
Code:
#include <Simple_window.h>
void cir() { Circle c(Point(100,100),50); }
int main() {
Simple_window win(Point(100,100),600,400, "test");
[Code] ....
But how to define a shape (say a circle by that cir() function which is) outside of the main() function that is how to create a circle inside of the cir() function and it returns that circle when I called it in my main() function so that I can attach it on the window win to be visible?
Write a program to ask a user to input a symbol from the keyboard and to output that symbol in a n X n/2 sized V where n = the width of the V. You must use a loop to process the data
I am stuck at trying to figure out how to do the actual output formatting. This is where I am sitting currently.
string character = "";
int vheight = 0;
Console.WriteLine("Enter the character you wish to use for your V: ");
[Code]....
so Im really just a bit stumped on how to get the actual V shape to be formatted..