Im trying to do a small program that will create multiples of the previous line *2, and spit out the anwser in seperate lines (as many times as the user wants)
Example if i wrote it in a bad way
2
4
8
16
32
etc.
At this time my code looks likes this, now im planing to get my hands on the IF statment
using System;
using System.Collections.Generic;
using System.Linq;
[Code].....
I've finished my series of tutorials and built a investment calculator with QT, now that's finished and I wanted to create a small radio that allows to retrieve audio from an URL. I wanted to use Juce but I'm clueless about it, I know how to program but I've never touched external libraries?
View 2 Replies View RelatedI'm just getting back into the swing of things after a long time of not programming. I'm trying to create a program which takes in command line arguments and prints the last one. My code is as follows:
#include <iostream>
#include <vector>
#include <string>
using namespace std;
int main() {
string x;
vector<string> arguments;
[Code]...
And the error message I receive, a simple but frustrating one, is as follows:
Enter arguments, enter STOP to stop: Segmentation fault...
I have been writing a program to generate pairs of RSA keys using small prime numbers. I have been using mpz_invert() to get a value for d for the private key. On small prime numbers it calculates the correct value, but on larger primes it calculates incorrect values.
I'm assuming there must be an upper limit to the values the mpz_invert() function can handle? If so, what is this limit to avoid erroneous values?
What I want it to do is have the user input a number: ex. 5 and then have the code give the sum for all the multiples of 5 less than 100, so it should be equal to 950 in this example.
Anyway, I have got so far to get it to list the numbers, but I need the sum of those numbers without all the text displayed every time.
I have chosen to use the FOR, but I am wondering if I should implement WHILE loop in my coding somewhere.
Code:
#include <iostream>
using namespace std;
int addMultiples() {
// Start
[Code] ....
I want the output like this:
What multiples are we adding? 5
The sum of the multiples of 5 less than 100 are: 950
I'm creating a program that is based on a menu system. Basically each menu is its own user-defined function. The problem is at each menu you can input 'b' to go to the previous menu. I just have it call the function of that menu.
However, do the functions need to complete themselves eventually? If I just keep calling functions will I just keep going further and further deeper into ever running functions?
If so how do I avoid this and yet keep the option to go back to a previous menu/function?
Write a c++ program to display a matrix of multiples of 4 from 1 upto 30 .....
View 1 Replies View RelatedI need to write a ANSI program to print out each command line argument on a separate line using a for-loop. also it need to print the name of the executable .so far I have
Code:
#include <stdio.h>
int main(int argc, char **argv) {
int i;
printf("")
[code]....
l need to write a program which writes out its command line arguments in reverse order one per line. The output from the program should look like this:
% a.out Two roads diverged in a yellow wood
wood
yellow
a
in
diverged
roads
Two
Okay, I'm hunting down Pythagorean triples. Both the natural ones, and the multiples.
What I would like, is to read in a value n, and then output every pythagorean triple for which the values <a,b,c> are less than or equal to n.
I have a working program. However, if you run this code and then compare it to the list here [URL] ....
You will notice that there are slight discrepancies. Not every multiple on that list, is found by my program. It's almost perfect, but I would like to at least understand why some are missing. My code is simple, so I will post it in its entirety.
#include <iostream>
#include <cmath>
using namespace std;
int main() {
int n;
cout << "a*a + b*b = c*c" << endl
<< "a,b,c are all integers" << endl
[Code] ....
It's really simple to say to a pointer to point to a sigle character or a single number.
Code: int *ptr;
int a = 5;
cout << *ptr << endl;
But I want for example a pointer to change a whole text line. My idea is that the user enters which language he speaks.
Code: cout << "English" << endl;
cout << "Swedish" << endl;
But I don't know how to this. I could have done this without pointers with if statments but I want to do it with pointers because it were a exercise to do.
I need to create a line chart that will be universal for every currency. As Y it will display value of currency, as X it will display time when that value was established.
For drawing I think of using Windows.UI.Xaml.Shapes.Line and Windows.UI.Xaml.Controls.Canvas
What I want to get is something like image below but it would have to draw correctly scaled chart for every currency which is the biggest problem(I think it is).
For every currency I will probably have to get minimal and maximal value which will be used to properly scale a chart(I will probably also have to get rendersize of canvas or something).
The user will choose the range of time and then the correct chart must be drawn (For example 04-11-2004 to 11-03-2007)
It is a windows store project.
Code:
char buffer1[10];
char buffer2[10] = "something";
sprintf(buffer1, "with %s", buffer2);
In a statement like the one above, is there a threat/leak or does it only truncate the string that is loaded into buffer1?
I am trying to add a small function to allow me to pause the game I am making. I measure the time elapsed using the following algorithm:
1. USE ""clock_t begin=clock();"" FOR SYSTEM TIME OF GAME BEGINNING.
2. USE ""cout<<(clock()-begin)/CLOCKS_PER_SEC;"" TO DISPLAY TIME ELAPSED IN SECONDS.
Now, if I want to pause, I would want to subtract the 'paused' time from the total time elapsed.Say,
clock_t pause, resume;
{
pause=clock();
.
.
.
resume=clock();
}
Then I would do cout<<(clock()-begin-(resume-pause))/CLOCKS_PER_SEC;
This, though is what I want, works only once(I can pause only once). I can use arrays of resume and pause, but it would still limit the number of times I can pause.
What I am looking for is a way to pause any number of times.
Suppose my file a.txt has "ABC" written in it. Now I want to write a small b before capital B in the file. How will I do it. I've tried to do it but i'm having problems.
1. When opened in app mode seekp doesn't work.
2. When opened normally previous written data is erased.
I am trying to find the best way to detect a small symbol such as :
Just for testing features I tried to load these into SURF example that comes with EMGU and it does not pick it up... And I think the technology used for SURF is better for objects with more details and color gradients...
I am having difficulty with arrays because of the limitation of the size of the arrays that I can declare. I need sizes that are very large and windows or C# does not allow me to create bigger than the following for example:
public static int[] gaPoints = new int[20000000000000000000 + 1];
I get an error message saying that "integral size is too large".
I need to be able to declare sizes that are even much larger than the abovementioned size.
How can I circumvent this problem?
Do I have to use something other than arrays?
I want to store a very small number - too small for even a long double. However, I don't need the number to be stored very precisely - in fact, all I really need is the order of magnitude of the number. For example, the number 5.205849034425 X 10^-381 can just be stored as an integer of -381 for my purposes. I don't really care about the precision of the 5.205849034425 part.
The reason I get this very small number, is because I am multiplying together thousands of numbers, all of which are around 0.0001 in value. So, one way to do this would be to store all these individual values as simply their order of magnitude (e.g. -4) and then instead of multiplying the numbers, I would just add up their orders of magnitude. However, I am wondering whether there is a way in C++ to do this without me having to change the way I store my data - I still would like to keep the original values if possible.
How do i print another shape near the one i did. I have this code but how i can put another shape near it like this
Code:
#include <stdio.h>
int main() {
int i;
for (i = 0; i < 5; i++)
switch (i) {
case 0:
printf(" *
[Code] .....
Here is a simplified version of my Menu class, where submenus can be inserted arbitrarily deep. I need to add a new functionality "go back to previous menu", which I would like to be activated by entering 0 (universal command for all Menu instances). I considered the Memento Pattern, but that doesn't seem to quite fit. add that functionality to my Menu class.
#include <iostream>
#include <cstring>
using namespace std;
const int END = -1, NO_SUBMENU = 0;
[code]....
Say a user installs and uses the software for awhile. Then they uninstall it. Client wants the database containing client data to remain behind, in case they ever re-install the software. Which is fine.
So then.. they re-install the software. Client wants them to have the choice to either use the existing database, or to create a new one. When the software fires up, it always checks for the database, and creates one if it's not there. So how can I determine if the instance is a new install, or a current install, given that the database will be there no matter what?
I am in the process of creating a game that has two players machine and person. The player is selected randomly each round. So if the player is selected, he needs to choose a number from 1-9. Then the machine needs to choose another new number either in the same row or colunm.(i figured out how to check against col.and row). Then keep going until someone reaches 31.
I'm stuck on how to add the numbers from previous rounds and have them reflect in the new rounds. While at the same time using the last entered number(last numbers) as a reference has to whether or not the new number is valid.
Ok I created a while loop as suggested. But it is not adding each round like it should. So the question is: What is wrong with the code after the while loop?
while ((x != 0) && (suma < Meta)){
cout << "SUM =" << x + last number << endl;
if (player == Person) {
x = machinerandomnDigit(last number);
sum = sum + x;
player = Person;
last number = x;
[Code]...
decTotalAmountOwed = decAmountOwed + decAmountOwed;
This is what i've tried so far. The numbers are supposed to be added together once placed in listbox.
Whenever I try to call merge sort on large numbers say n=10000000. It gives an error. It works fine for small numbers, even though I have declared my Lists on the heap.
The below code is just the divde part.
List<long>* Merge(List<long> *ParentList) {
if((ParentList)->Length==1) {
return ParentList;
[Code] .....
I have a condition and I would like to instead change the condition so that it would execute the previous statements after else statement.
It seems hard to explain but I'll try my best to illustrate anyway
if (condition)
<statement1>
else
<statement2>
So I would like to change the condition so that
if (condition)
<statement2>
else
<statement1>
And the condition is
Code:
if(!lightStateAtNextLink || !bIsLightEnAtConnection && nLinkNext.IndexToAttachedNode() != pVeh->_.stAutopilot.m_dwNextNode || bIsLightEnAtConnection && nLinkNext.IndexToAttachedNode() == pVeh->_.stAutopilot.m_dwNextNode)
And I have changed that to this. Is this correct?
Code: if(lightStateAtNextLink && bIsLightEnAtConnection || nLinkNext.IndexToAttachedNode() == pVeh->_.stAutopilot.m_dwNextNode && !bIsLightEnAtConnection || nLinkNext.IndexToAttachedNode() != pVeh->_.stAutopilot.m_dwNextNode)
For my assignment I have to have an array with only zeros.
Code:
int a[20] = { 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0 }; Then I need to send it into a function that makes the array like this
Code: int a[20] = {0,1,2,3,4,5,6, ... , 19}
Which I have done here
Code:
int initialize(int a[], int n) {
int m = 0;
int i;
printf("
[Code] ....
Now I need to do the following with the array. I need to take whatever value is in each position and add that value to all of the previous values. like this.
Code:
a[3] = a[3] + a[2] + a[1] + a[0]
only for every a[i] I know that I can code this the long way, but I just can't see to be able to find out how to do this a better way.