C :: Array With Only Zeros - Add Value To All Of Previous Values
Apr 17, 2013
For my assignment I have to have an array with only zeros.
Code:
int a[20] = { 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0 }; Then I need to send it into a function that makes the array like this
Code: int a[20] = {0,1,2,3,4,5,6, ... , 19}
Which I have done here
Code:
int initialize(int a[], int n) {
int m = 0;
int i;
printf("
[Code] ....
Now I need to do the following with the array. I need to take whatever value is in each position and add that value to all of the previous values. like this.
Code:
a[3] = a[3] + a[2] + a[1] + a[0]
only for every a[i] I know that I can code this the long way, but I just can't see to be able to find out how to do this a better way.
Goal: Write a program that compares the values stored in the first array to the user inputted values in the second array.
In order to fix this error: [URL]...
I had to change my array initialization to one with a star in front of it:
char a1[]={"a","d","b","b","c","b","a","b","c","d","a","c","d","b","d","c","c","a","d","b"}; to: char *a1[]={"a","d","b","b","c","b","a","b","c","d","a","c","d","b","d","c","c","a","d","b"};
I also changed my 2nd array to one with a star in front of it: char *a2[20];
What does this mean exactly? Putting a star in front of an array?
Also, I am now getting an "unhandled exception" when I try to get input for my 2nd array:
I am trying to remove the leading zeros of the number user enters so 000002 will turn into 2. However, I am getting an error saying Segmentation fault (core dumped)
#include <stdio.h> #include <string.h> int main(){ char *str; scanf("%c", *str);
With the loop below, is there a way to display the actual number without the leading zeros (scientific notation) or will it just display 0 since there are so many leading zeros?
num = 1; while (num > 0){ num /= 2; } cout << num;
Here is a simplified version of my Menu class, where submenus can be inserted arbitrarily deep. I need to add a new functionality "go back to previous menu", which I would like to be activated by entering 0 (universal command for all Menu instances). I considered the Memento Pattern, but that doesn't seem to quite fit. add that functionality to my Menu class.
#include <iostream> #include <cstring> using namespace std; const int END = -1, NO_SUBMENU = 0;
Say a user installs and uses the software for awhile. Then they uninstall it. Client wants the database containing client data to remain behind, in case they ever re-install the software. Which is fine.
So then.. they re-install the software. Client wants them to have the choice to either use the existing database, or to create a new one. When the software fires up, it always checks for the database, and creates one if it's not there. So how can I determine if the instance is a new install, or a current install, given that the database will be there no matter what?
I am in the process of creating a game that has two players machine and person. The player is selected randomly each round. So if the player is selected, he needs to choose a number from 1-9. Then the machine needs to choose another new number either in the same row or colunm.(i figured out how to check against col.and row). Then keep going until someone reaches 31.
I'm stuck on how to add the numbers from previous rounds and have them reflect in the new rounds. While at the same time using the last entered number(last numbers) as a reference has to whether or not the new number is valid.
Ok I created a while loop as suggested. But it is not adding each round like it should. So the question is: What is wrong with the code after the while loop?
while ((x != 0) && (suma < Meta)){ cout << "SUM =" << x + last number << endl; if (player == Person) { x = machinerandomnDigit(last number); sum = sum + x; player = Person; last number = x;
I'm new to C programming and in my first computer science class. Our assignment was to write a program that displays each digit of an integer in English. I wrote the following but cannot figure out why it won't display zeros. When I execute and type in the number 1,000, I get "zero."
Code: #include <stdio.h> int main (void) { int x, y = 0; printf ("This program displays each digit of an integer in English.
I am making a product and in which i use a timer. I want when the product is being start the timer will run and when the product is off the timer will stop. If i again start the product the timer will start from its previous value.
I have problem that the timer start from its initial when i start my product.
using namespace std; //class declaration class dayType{ public: int presday;
[Code] ....
So everything works perfectly, well not everything lol. Code compiles successfully without any errors but previous day does not calculate. In a sense that when it asks for number of previous days it returns a blank statement.
For example: Previous number day is: shows nothing
Im trying to do a small program that will create multiples of the previous line *2, and spit out the anwser in seperate lines (as many times as the user wants)
Example if i wrote it in a bad way
2 4 8 16 32 etc.
At this time my code looks likes this, now im planing to get my hands on the IF statment
using System; using System.Collections.Generic; using System.Linq;
if (Choice == 2) { cout << "" << endl << "You follow the light to the end of the hallway, you find your self in a room" << endl << "with natural light coming from a hole in the ceiling." << endl << "" << endl << "You hear the door you just came through, slam behind you!" << endl << "" << endl << "There are three possible directions." << endl << "" << endl << "Do you:" << endl << "" << endl << "1) Go forward" << endl << "" << endl << "2) Go left" << endl
[Code] .....
Ignore the if (Choice == 2) at the beginning, that's linked to some previous code.
I want to make the player go back to the first bit of text but i'm not sure how to do this if they keep choosing to go back and forth from one location.
I first thought of doing it by just putting the text back in after they have chosen the option, but I can't do this infinite times.
I got this program to create an array of playing cards and assign the values and suits and shuffle the array. I'm at the point where I need to output the cards but I need to burn the first card by making it output "**" instead of the card. my cards[] is a constant so I can's assign the first card as such.
void showCards(const int cards[], int numCards, bool hideFirstCard) { if (cards[0]) { hideFirstCard=true; cards[0] = '**'; } for(int a = 0; a <= numCards; a++) { cout >> showCard(cards[a]); } }
I wanted to print the values of a array from a function by passing the array as well as the number of elements to be read. For a single dimensional array, this is how i have written it. It's pretty straight forward. I want to read 5 elements from the 5th element in the array.
Code: #include<stdio.h> void display(int array[],int size) { int i;
[Code]....
With this code I want to print the five elements from the element present in [0][4].
But shows an error that
Code: D:BennetCodeblocks CLearning CSingleDimentionalArray.c||In function 'main':| D:BennetCodeblocks CLearning CSingleDimentionalArray.c|18|warning: passing argument 1 of 'display' from incompatible pointer type [enabled by default]| D:BennetCodeblocks CLearning CSingleDimentionalArray.c|2|note: expected 'int (*)[10]' but argument is of type 'int *'| ||=== Build finished: 0 error(s), 1 warning(s) (0 minute(s), 0 second(s)) ===|
I know when you pass a array as an argument it gets decomposed into a pointer, but with a multi-dimensional array this is not the case. how this works for mult- dimensional array's?
My program takes the values from one array and searches for their index position in another array (linear search algorithm). This is an example of the issue im having(its not part of the actual code below)
a[]={1,2,3,4,5,6} Arr[]={1,2,2,3,4,5}
If it finds 1 in arr, it returns 0, which is fine but if it finds 2 in arr it return 1 and 1 instead of 1 and 2.
for (int q=0; q=size2;q++) { int rs=secfunc(array1;size1;array2[q]) if(rs>=0) { cout<<rs << "";
I'm creating a program that is based on a menu system. Basically each menu is its own user-defined function. The problem is at each menu you can input 'b' to go to the previous menu. I just have it call the function of that menu.
However, do the functions need to complete themselves eventually? If I just keep calling functions will I just keep going further and further deeper into ever running functions?
If so how do I avoid this and yet keep the option to go back to a previous menu/function?
