I am trying to remove the leading zeros of the number user enters so 000002 will turn into 2. However, I am getting an error saying Segmentation fault (core dumped)
#include <stdio.h>
#include <string.h>
int main(){
char *str;
scanf("%c", *str);
With the loop below, is there a way to display the actual number without the leading zeros (scientific notation) or will it just display 0 since there are so many leading zeros?
num = 1; while (num > 0){ num /= 2; } cout << num;
QuoteWrite a program that reads in ten numbers and displays distinct numbers. If a number appears multiple times, it is displayed only once.For example: if user enters 1,1,2,3,4,4,5,1,0,9. You should output: 1,2,3,4,5,0,9. Order doesn't matter.
Steps:
a. Create an int[] to hold all the integers of user input and another int[] to store the distinct numbers.
b. Make a nested for-loops which the outer loop goes though the first array and inner loop to check if the value is already inside. Store the value to the second array if new number,otherwise do nothing.
c. Make a for loop to print out the elements of the second array
I've always been bothered when people say "don't name your variables with a leading underscore, it is reserved by the implementation", so I decided to ask this once and for all.
The actual standard says:
17.6.4.3.2 Global names [global.names]
1 Certain sets of names and function signatures are always reserved to the implementation:
- Each name that contains a double underscore _ _ or begins with an underscore followed by an uppercase letter (2.12) is reserved to the implementation for any use. - Each name that begins with an underscore is reserved to the implementation for use as a name in the global namespace.
Unless I'm mistaken I read this as:
Words like "__foo" or "_BAR" are strictly off limits, as the implementation may have used it as a macro.Words like "_foo", when used for things such a member variables, or scoped variables on the stack are fine. The implementation only gets to use those as global functions inside mainspace.
So my question is this: While using leading underscores is generally frowned upon, is it, strictly according to the standard, wrong?
For my assignment I have to have an array with only zeros.
Code: int a[20] = { 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0 }; Then I need to send it into a function that makes the array like this
Code: int a[20] = {0,1,2,3,4,5,6, ... , 19}
Which I have done here
Code: int initialize(int a[], int n) { int m = 0; int i; printf("
[Code] ....
Now I need to do the following with the array. I need to take whatever value is in each position and add that value to all of the previous values. like this.
Code: a[3] = a[3] + a[2] + a[1] + a[0]
only for every a[i] I know that I can code this the long way, but I just can't see to be able to find out how to do this a better way.
I'm new to C programming and in my first computer science class. Our assignment was to write a program that displays each digit of an integer in English. I wrote the following but cannot figure out why it won't display zeros. When I execute and type in the number 1,000, I get "zero."
Code: #include <stdio.h> int main (void) { int x, y = 0; printf ("This program displays each digit of an integer in English.
It is given an integer "p". I have to find a number "n" for which "n factorial" has "p" numbers of zero at the end. Here is the solution i thought, but i am not sure if it is a solution for this problem. Do i have to make a function to calculate the factorial and another function to get the zeros?
int p; int count5=0; int i; int copy_i; printf("Enter p: "); scanf("%d",&p); for(i=1; ;i++) {
I have a program that I'm making and I want to have the completion of one function lead to another function. So once one equation is done, I want for another equation in a different function to be completed. For example, in my program, I did this:
void Function1() { int a ; a = 4 + 2 ; //For example //now, go to another function, with the value of variable a
[Code] ....
Why doesn't this work, and, what will? When I compile it in Code::Blocks, the error message given is:
Code: /* generals is the first array. Max 10 elements. numGenerals is the element count of generals.
genBuff is the second array; it is to be checked/pruned. genCount is the element count of genBuff. genBuff will be a max of 171, but be pruned to no more than 10, and no more than the complement of the element count of generals. */
[Code] ....
(I do have comments in the actual source, different from above).
I have two int arrays. They hold values from 0 to 170. The first one will never be more than 10. The second will be at most 171, but will be whittled down to at most 10, usually less. 171 is worst case, most users of this particular program will probably be reasonable and not try to add all 171 (max is 10 anyway). The first array is the original array. The second array is a temporary array. Any value in the second array that is also found in the first array, is removed from the second array, since all values in the first one must be unique. After this pruning process, both arrays will collectively contain no more than 10 unique elements; the elements from the second will be added to the first.
So right now I have three nested loops. I figured with the miniscule array sizes it wouldn't be a big deal. I can think of a way to remove one or two of them, but I want to be sure that I'm still writing clean, legible, good-practice code. The first loop walks through the first array. For each element in the first array, there is a second loop to walk through the second array to check for duplicates. If a duplicate is found, the third loop walks through the second array to overwrite the duplicate while preserving the second loop's position (j).
Is this dumb? I know that the big O gets worse and worse the deeper you go with nested loops. Even though the arrays are really tiny, is this still a thing to avoid?
The following 2 codes are almost identical, only that the switch statements are slightly different. The 2nd code has the issue of requiring an additional enter key to be pressed when I enter '3' as input to exit the program.
Working code :
Code:
#include <stdio.h> #include <ctype.h> #include <string.h> void clearKeyboardBuffer() { int ch; while ((ch = getchar() != '
I know how to remove digits in number from right to left.For example: the number 319. If I do (number /= 10), I get 31.how can I remove digits in number from left to right.For example: the number 319. If I will do something, I will get the number 19.
class List; List *deletezeroendlist(List* L); class List { public: intdigit; List*nextDigit; public: List():digit(0), nextDigit(NULL){} List(int d, List *next):digit(d), nextDigit(next){}
I have tried many different ways but it is still not the answer / perform the function List *deletezeroendlist(List* L)
Below is my .h file and the code below that is my function that I'm having troubles with. Its suppose to take in a users topic and see if that topic exists, if it does exist then find the keyword, commentcompare will find where that keyword is and delete the comment. However its not deleting anything and its returning temp is NULL.
class comment //adds a comment { public: comment(char * create_comment);