I had ...
class List;
List *deletezeroendlist(List* L);
class List {
public:
intdigit;
List*nextDigit;
public:
List():digit(0), nextDigit(NULL){}
List(int d, List *next):digit(d), nextDigit(next){}
I have tried many different ways but it is still not the answer / perform the function List *deletezeroendlist(List* L)
EX
L=12345600 -> L=123456
or L=01203000 -> L=01203
remove the 0 at the end
This code is from a example in Jumping Into C++ and I understand the example. But it is a practice problem that is to write a program to remove an element from a linked list; the remove function should take just the element to be removed.
Code: #include <iostream>
using namespace std;
struct EnemySpaceShip {
int x_coordinate;
int y_coordinate;
[Code]...
If I got this right I will create a pointer that points to the first SHIP (getNewEnemy) and the other one will not be printed out.
This is my current code. The code is to remove the element in the list "head" that is "e". The code works if there is only one element in the list but if there are more than 1 element in the list, it doesn't work. The function should return true if there is an element that equals "e" and then it removes it and false if no element equals "e".
bool StringLinkedList::remove(const std::string& e){
StringNode* current = head;
int i = 0;
if (current == NULL)
return false;
[Code] ....
How to remove node from linked list. I am trying to implement this in a file record to remove data from struct..I dont know how addressing in linked list work for structs;
#include <iostream>
#include<fstream>
#include<cstring>
#include<cstdlib>
using namespace std;
struct node{
int val;
[Code] ....
segmentation fault
How can I remove an element in a list when I have only an iterator that points to the object I want to remove. Is there a build in command? remove() takes an object reference as its argument. Is it possible to convert the iterator into a pointer type so it can be deferenced and passed to remove?
This is the code I am working on:
//player.cpp
void Player::CheckCollectableCollisions(std::list<Collectable>& c) {
std::list<Collectable>::iterator i = c.begin();
while(i != c.end()) {
if (Collider::CheckCollision(pNodes_.front().getLocation(), i->getLocation()))
[Code] .....
I'm trying to write a function that takes two linked lists and creates a third one with only the common elements.
It assumes the first list (the caller) has no dups, but it doesn't seem to be working. The program doesn't crash, it just hangs when it is supposed to display L3 (the third list)..everything else runs and is displayed fine.
template <typename T>
LList <T> LList <T>:: common (LList <T> &B)//common fct
{
Node <T> *hunter1 = Head;
[Code]......
I have this structures:
Code:
typedef struct {{
GList *presets;
} Settings;
typedef struct Preset preset;
struct Preset
{gchar *name;
[Code]...
I want to remove duplicates items in list if them have same freq value.
Example output with duplicate freq:
PHP Code:
name freq unammed 87.80 Radio ZU 92.20 Napoca FM 104.50 unammed 92.20 Rock FM 102.20
Want output:
PHP Code: Europa FM 92.20 unammed 87.80 Radio ZU 92.20 Napoca FM 104.50 Rock FM 102.20
write code to remove duplicates.
I am getting an error with my while loop(feels dumb) when running this code that I am allowed to modify. It is to remove all instances of an element within the list.
The loop is whithin this function:
void arrayListType<elemType>::removeAll(int location)
I have attached both the header file and main function file in .txt format.
void arrayListType<elemType>::removeAll(int location)*
Attached File(s) :
header.txt (12.23K)
main function.txt (2.95K)
I have a linked list comprised of chars like so...
Code:
node1 - "p"
node2 - "o"
node3 - "p"
I need a function that will take in three perameters...node *replaceChar(node *head, char key, char *str)Stipulations of this function. head is the head of the list, 'key' and 'str' are guaranteed to contain alphanumeric characters only (A-Z, a-z, and 0-9). str can range from 1 to 1023 characters (inclusively). So if I call this function with these perameters..
Code:
node *head == /*the head of the list to be examined*/
char key == "p"char *str == "dog"The new list will look like this...
node1 - 'd'
node2 - 'o'
node3 - 'g'
node4 - 'o'
node5 - 'd'
node6 - 'o'
node7 - 'g'
All instances of 'p' were replaced with 'dog' I have a toString function which takes in a string and converts it to a linked list and returns the head. So assume that you can call the function on str = "dog" so...
Code:
toString(str) == /*this will return the head to the list made from the str*/
If it's unclear what my question is...I am stumped on how to write the replaceChar function the one that takes in three perameters..
Code:
// Write a function called insertEntry() to insert a new entry into a linked list.
Have the procedure take as arguments a pointer to the list entry to be inserted (of type struct entry as defined in this chapter), and a pointer to an element in the list after which the new entry is to be inserted.
// The function dveloped in exercise 2 only inserts an element after an existing element in the list, thereby prenting you from inserting a new entry at the front of the list.
(Hint: Think about setting up a special structure to point to the beginning of the list.)
#include <stdio.h
struct entry1 {
int value;
struct entry1 *next;
};
[code]...
This is a working version of the exercise, but I don't think I'm doing what's asked. I was able to add an element to the beginning of the list using an if statement, not creating a special structure that points to the beginning of the list. How would I go about creating a special structure that points to the beginning of the list to add a new element at the beginning of the list?
I'm working on a linked list and was wondering how this looks to everybody else for a deleteList function.
void deleteList(Node* head)
{
Node* iterator = head;
while (iterator != 0)
[code].....
I need to make the functions using these function prototypes. I am mainly having problems with GetFirst() and SwapData() but how to do it..
Header File with Prototypes
Code:
#ifndef LINKEDLIST_H
#define LINKEDLIST_H
/**
* @file
* This file provided a doubly-linked list implementation capable of storing any arbitrary data.
* The list implementation relies on a chain metaphor: a list is merely a sequence of links
* (ListItems) and there is no separate construct to represent the entire list, each ListItem in it
[Code]....
I read an article on linked list here: C Linked List Data Structure Explained with an Example C Program
Code:
struct test_struct* search_in_list(int val, struct test_struct **prev)
{
struct test_struct *ptr = head;
struct test_struct *tmp = NULL;
bool found = false;
}
[code].....
What is "if(prev)"? Wouldn't "prev" always have the same value? Secondly, if tmp is NULL (which will be the case when the loop if(ptr->val == val) finds a match the first time it is run), is *prev assigned a NULL?
I'm having a small issue here with my linked list.I built a linked list with strings and it worked perfectly.Now since i'm using strtok() to separate the string.for now here's what i've got:
Code:
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
typedef struct dict_word *word;
typedef struct node *Node;
typedef struct double_linked_list *DLL;
}
[code]....
I have the codes for the functions: "Given the functions that we have discussed and defined in the class and the code that we have created, create the code for the Delete Node function and the Search function. Create an application that will incorporate all the functions that we have discussed and the new ones that you need to create. The application should allow the linked list to be built initially from a text file. The application should then allow for the user select an operation to perform. The acceptable operations are
- to search for an item
- to delete an item
- to enter a new item
- to exit the application
After the initial build and loading of data from the textfile, the application should print a listing of each item in the list and the node that it is located in. after a delete or insert, the application should display an output of the list again showing each item in the list and the node that it resides in.
The data item for this problem will be the inventory structure that we created in class and the data is in the inventory file that you already have downloaded."
I am having difficulty getting my program to run. I have looked and looked many times trying to figure out what I am doing wrong. I have a hunch that it's my load function that's acting up, but from my perspective, my creation of my singly linked list looks good. From the creation of my singly linked list, does anything stand out as being abnormal?
Code:
typedef struct Node {
char word[LENGTH+1];
struct Node *Next;
} Node;
}
[code]....
I been ask to create a sorted linked list module, and to test each function with 1 unit, 2 +.so i wrote my addtofront function( we have to use the same as the teacher)
Code:
struct MyList{
char * name;
Sorted * AddmyChar;
struct MyList * next;
}
[code]....
but i cant seem to test it because it always display a seg fault.... i dont know what i did wrong....how do i call this function in main to display a string i want?
I decided to make a linked list program using classes and templates.I implemented my linked list and added some basic functions, everything worked just fine. Then I proceeded to add templates...First, the error list:
#pragma once
template<class T>
class Node {
private:
Node* next;
[code]....
To sum up: Something's wrong with the templates that I used in "List.cpp" and what it could be.
My program is almost done all that is left is entering big numbers, the program can add and subtract small numbers but not big numbers because it puts them all in one node, I need the program to store each number in a node.
#include<iostream>
#include<string>
using namespace std;
class Node {
public:
int value;
Node * next;
[Code] .....
When I am traversing a linked list ...i suppose we can do it only with pointers
like p is a head node pointer then
p
p->next
p->next->next
p-next->next->next
so on represents a link...
if i have to pass head node as struct variable itself...can i traverse a link using dot operator??
p and p.next and how to retrieve third and remaining links through this method if we can traverse like this???
I have created this program to merge two linked list into one ,but however everything is working fine but on execution it providing a segmentation fault error ( on calling merging function )
code :
#include<iostream>
#include<stdio.h>
using namespace std;
struct node{
int data;
node* link;
[code].....
I am unable to make any logical algorithm to access middle of stack. I am using stack implemented with linkedlists, I have following functions available for stack like push,pop,top.
View 6 Replies View RelatedCode is:
#include<stdio.h>
struct node {
int info;
struct node *next,*prev;
[Code] ....
How to reverse a linked list .....
How can you make a linked list without having to write
node *head = NULL;
head = new node ( "zildjian" );
head->next = new node ("sabian");
head->next->next = new node ("paiste" );
#include <iostream>
#include <string>
#include <iomanip>
[Code].....
while the prog. running compiler say " access violation .. "
this my code ...
solved :just forget to make r=NULL ; rf =NUll ; frontm=NUll; frontf=NULL ;
#include <iostream>
#include<conio>
struct stu{
int id;
float gba ;
char gender ;
stu *next ;
}*r ,*rf ;
stu read()
[code]....