This is my current code. The code is to remove the element in the list "head" that is "e". The code works if there is only one element in the list but if there are more than 1 element in the list, it doesn't work. The function should return true if there is an element that equals "e" and then it removes it and false if no element equals "e".
bool StringLinkedList::remove(const std::string& e){
StringNode* current = head;
int i = 0;
if (current == NULL)
return false;
This code is from a example in Jumping Into C++ and I understand the example. But it is a practice problem that is to write a program to remove an element from a linked list; the remove function should take just the element to be removed.
Code: #include <iostream> using namespace std; struct EnemySpaceShip { int x_coordinate; int y_coordinate;
[Code]...
If I got this right I will create a pointer that points to the first SHIP (getNewEnemy) and the other one will not be printed out.
How can I remove an element in a list when I have only an iterator that points to the object I want to remove. Is there a build in command? remove() takes an object reference as its argument. Is it possible to convert the iterator into a pointer type so it can be deferenced and passed to remove?
This is the code I am working on:
//player.cpp void Player::CheckCollectableCollisions(std::list<Collectable>& c) { std::list<Collectable>::iterator i = c.begin(); while(i != c.end()) { if (Collider::CheckCollision(pNodes_.front().getLocation(), i->getLocation()))
So I have linked list and function which deletes element if next element is bigger, so my code is working but its not working with first element, in the comment I have wrote code which I would code for checking that first element, but when ever I check it is blowing up all program.
#include <iostream> using namespace std; struct llist { int x; llist *next;
I am getting an error with my while loop(feels dumb) when running this code that I am allowed to modify. It is to remove all instances of an element within the list.
// Write a function called insertEntry() to insert a new entry into a linked list.
Have the procedure take as arguments a pointer to the list entry to be inserted (of type struct entry as defined in this chapter), and a pointer to an element in the list after which the new entry is to be inserted.
// The function dveloped in exercise 2 only inserts an element after an existing element in the list, thereby prenting you from inserting a new entry at the front of the list.
(Hint: Think about setting up a special structure to point to the beginning of the list.)
This is a working version of the exercise, but I don't think I'm doing what's asked. I was able to add an element to the beginning of the list using an if statement, not creating a special structure that points to the beginning of the list. How would I go about creating a special structure that points to the beginning of the list to add a new element at the beginning of the list?
class List; List *deletezeroendlist(List* L); class List { public: intdigit; List*nextDigit; public: List():digit(0), nextDigit(NULL){} List(int d, List *next):digit(d), nextDigit(next){}
I have tried many different ways but it is still not the answer / perform the function List *deletezeroendlist(List* L)
How to remove node from linked list. I am trying to implement this in a file record to remove data from struct..I dont know how addressing in linked list work for structs;
I've got this program that I'm working on. Most of the code is from a video tutorial, but I was editing it to be able to search for an element by name. That's working fine, but suddenly the part of the program that prints out all the elements starts in an infinite loop after I input two elements, and search for one.
I'm trying to calculate the total price of books contained in a linked list. I've tried getTotal() function in linked list but error: no match for 'operator+=' in 'total += ptr->Node<Book>::info'| occurred. How can I access the price in the node and then calculate the total price.
Here is part of my code :
Book class class Book { protected : int id; string title; double price; string bookStatus;
I have been trying to implement a way to remove a post from a list of posts implemented with a template doubly linked list. I have thought that the best way to do this might by operator overloading, but I have digressed. I have just thought of using a isEqual that checks equality, but when trying to implement i'm getting weird errors.
This is within my class wall, which is a linked list of wall posts, getPostInfo is within the class WallPost.
bool isEqual(WallPost const & a, WallPost const & b) { if(a.getPostInfo() == b.getPostInfo()) return true; else return false; }
I have several instances of the error "void illegal with all types" on line 3. It also is complaining about a not being a arithmetic, unscoped enum, or pointer type. I am assuming that it is because my getPostInfo function is a void.
I am trying to write a function to return the first element of a link list queue. I am not real sure how to implement this. I have include a copy of the struct for my Node & queue.
I tried to modify staff name with an assignment value of other string but couldn't work it out. I managed to modify it by key in cin >>.
The purpose is that I want to assign string value from other different class to Staff class. An error : no match for 'operator=' in '* updateName = newStaffName' and note: no known conversion for argument 1 from 'std::string {aka std::basic_string<char>}' to 'const Staff&' occurred.
#include <iostream> using namespace std; class Staff { friend ostream& operator << (ostream& os, Staff& m) { os << "[" << m.ID << ", " << m.fName << "]";
I'm currently trying to remove the first element in an int array using objects in C#. I have just coded how to add an element to that start of the array and though it was just a case of changing a few things.
Here's the code for the addFirst() but i can't for the life of me figure out removeFirst()
public void addFirst(int value) { if (isFull()) { throw new Exception("List full");
I want to sequentially remove one element at a time starting with the first. When the second element is removed, the first element needs to go back in. The sequence would look like
Code: // original vector, row_numbers.size()=9 row_numbers{1,2,3,4,5,6,7,8,9}; // trimmed vector, row_numbers_trim.size()=8
[Code] .......
I have been working under the assumption that the best method would be to have row_numbers remain untouched and work on a copy. For each step in the sequence, you would create row_numbers_trim as a copy of row_numbers, and then remove an element from row_numbers_trim.
Code: // position being removed int counter = 0; // copy original vector row_numbers_trim = row_numbers; // remove the first element from the copy row_numbers_trim(row_numbers_trim.begin()+counter);
All you would have to do here is to increment counter in a loop. is there a better way?
I have a global list that contains smaller lists of char arrays. I have an issue where when I'm reading back the inner lists the last element of one list seems to point to first element of the next.
So my data looks like the below (values separated by commas with the pairs separated by tabs. The last pair in a line is the same as the first). When I read the first list back instead of seeing "456.678,678.98" as the last element in the list. I see "435.67,234.98" twice: at the end of the first list and start of the other. I have debugged when the list is populated and can see the correct values going in so I can't figure what's happening.
obstacle_list = op_prg_list_create(); while (fgets(line, sizeof(line), obstaclePositions_traj_file) ) { token = strtok(line, " "); //Pull the string apart into tokens using the
I have an std list of type double.. and the list is always guaranteed to have just 2 elements. I need to get the value of element 2 minus element 1. What is the least amount of code to accomplish that?
I tried this:
Code: list<double> dList; dList.push_back(1.0); dList.push_back(2.0); list<double>::iterator iter = dList.begin(); list<double>::iterator iter2 = dList.end(); double result = *iter2 - *iter;
I'm trying to write a function that takes two linked lists and creates a third one with only the common elements.
It assumes the first list (the caller) has no dups, but it doesn't seem to be working. The program doesn't crash, it just hangs when it is supposed to display L3 (the third list)..everything else runs and is displayed fine.
I have a linked list comprised of chars like so...
Code:
node1 - "p" node2 - "o" node3 - "p"
I need a function that will take in three perameters...node *replaceChar(node *head, char key, char *str)Stipulations of this function. head is the head of the list, 'key' and 'str' are guaranteed to contain alphanumeric characters only (A-Z, a-z, and 0-9). str can range from 1 to 1023 characters (inclusively). So if I call this function with these perameters..
Code:
node *head == /*the head of the list to be examined*/ char key == "p"char *str == "dog"The new list will look like this... node1 - 'd' node2 - 'o' node3 - 'g' node4 - 'o' node5 - 'd' node6 - 'o' node7 - 'g'
All instances of 'p' were replaced with 'dog' I have a toString function which takes in a string and converts it to a linked list and returns the head. So assume that you can call the function on str = "dog" so...
Code:
toString(str) == /*this will return the head to the list made from the str*/
If it's unclear what my question is...I am stumped on how to write the replaceChar function the one that takes in three perameters..
This function should delete each element in the list which is the same as this one typed by user. There are no errors, but function doesn't work. It deletes something, but not this element which should.
