The code that I have does not work.
Code:
#include <iostream>
#include <iomanip>
#include <sstream>
int main() {
std::string str3 = "99W8";
[Code] ....
I am having a problem with the output of a file. My function does everything it needs to do with the exception of one line. I have a .dat file with the following:
Code:
joe clint james brint howard
jimmy
alexander
*
me
When I run the function my output is as such:
Code:
file opened
word: joe
digit: 3
word: clint
digit: 5
word: james
[Code] .....
ERROR non alphanumeric digit on line 4!
File closed "Howard" is only six digits in length. Also it seems to skips a line in the output which could be the extra character but I am not sure. What I find very interesting is the other names, (jimmy & alexander) on separate lines do not have that problem.
Here is my function:
Code:
#include "main.h"
#include "fileCheck.h"
int fileCheck(FILE *fp){
int line_count = 0;
int ret_val = 0;
int digit_count = 0;
char file[BUFF];
[Code] .....
How I can correct this? I am aware of sscanf to parse the line but I do not know the format of the file. All I know is the file will be alphanumeric and if there is a non-alphanumeric, I must print out an error with the line it occurred on such as the above output.
How would I make the program still display zeros in front of a number?
Like say for example:
cout << "Enter any number";
cin >> number;
cout << number;
Let's say I entered 0003 as my input. How would I make it to where it will display the three zeros in front of the 3 instead of just displaying 3?
For my assignment I have to have an array with only zeros.
Code:
int a[20] = { 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0 }; Then I need to send it into a function that makes the array like this
Code: int a[20] = {0,1,2,3,4,5,6, ... , 19}
Which I have done here
Code:
int initialize(int a[], int n) {
int m = 0;
int i;
printf("
[Code] ....
Now I need to do the following with the array. I need to take whatever value is in each position and add that value to all of the previous values. like this.
Code:
a[3] = a[3] + a[2] + a[1] + a[0]
only for every a[i] I know that I can code this the long way, but I just can't see to be able to find out how to do this a better way.
I am trying to remove the leading zeros of the number user enters so 000002 will turn into 2. However, I am getting an error saying Segmentation fault (core dumped)
#include <stdio.h>
#include <string.h>
int main(){
char *str;
scanf("%c", *str);
[Code] ....
With the loop below, is there a way to display the actual number without the leading zeros (scientific notation) or will it just display 0 since there are so many leading zeros?
num = 1;
while (num > 0){
num /= 2;
}
cout << num;
If I have number of arrays (its 3 for instance) with fixed size (15), it consist of zeros and non-zeros
eg:array1[15]={5,5,0,0,4,4,4,0,0,0,1,0,0,0,3}
array2[15]={1,0,0,0,0,7,7,0,0,3,0,0,0,0,2}
array3[15]={6,6,6,0,8,8,8,0,0,0,3,3,0,0,4}
...........
sample output for the above arrays:
Index Nim_of_zeros
3 1
7 2
12 2
How can I count the common zero sequences and there indexes of arrays?
If I have number of arrays(is 3 for instance and may vary) with fixed size (15), it consist of zeros and non-zeros
eg:array1[15]={5,5,0,0,4,4,4,0,0,0,1,0,0,0,3}
array2[15]={1,0,0,0,0,7,7,0,0,3,0,0,0,0,2}
array3[15]={6,6,6,0,8,8,8,0,0,0,3,3,0,0,4}
...........
How can I count the common zero sequences and there indexes for all arrays?
sample output for the above arrays:
Index Nim_of_zeros
3 1
7 2
12 2
If I have number of arrays(its 3 for instance and may vary) with fixed size (15), it consist of zeros and non-zeros
How to write a program to count the common zero sequences and there indexes of arrays?
eg:array1[15]={5,5,0,0,4,4,4,0,0,0,1,0,0,0,3}
array2[15]={1,0,0,0,0,7,7,0,0,3,0,0,0,0,2}
array3[15]={6,6,6,0,8,8,8,0,0,0,3,3,0,0,4}
...........
sample output for the above arrays:
Index==> Nim_of_zeros
3==> 1
7==> 2
12==> 2
I'm new to C programming and in my first computer science class. Our assignment was to write a program that displays each digit of an integer in English. I wrote the following but cannot figure out why it won't display zeros. When I execute and type in the number 1,000, I get "zero."
Code:
#include <stdio.h>
int main (void)
{
int x, y = 0;
printf ("This program displays each digit of an integer in English.
[Code] ....
It is given an integer "p". I have to find a number "n" for which "n factorial" has "p" numbers of zero at the end. Here is the solution i thought, but i am not sure if it is a solution for this problem. Do i have to make a function to calculate the factorial and another function to get the zeros?
int p;
int count5=0;
int i;
int copy_i;
printf("Enter p: ");
scanf("%d",&p);
for(i=1; ;i++) {
[Code] .....
What is the efficiency of the two assignments (line 1 and 2), i.e. (function calls, number of copies made, etc), also the Big O notation. I know there are function calls for retrieving the size of each string in order to produce a new buffer for the concatenated string...any difference between line 1 and 2 in terms of efficiency?
String s("Hello");
String t("There");
1. s = s + t;
2. s += t;
Ok, so I'm writing this code and when I build it keeps saying cannot implicitely convert type int to string even though I declared my variables as string. Why is it giving me this error?
private static string Repair()
{
string result="";
string beep;
string spin;
Console.WriteLine("Does your computer beep on startup?:(y,n)");
[Code]...
I would like to understand a function on strings. Below is a code that I took from my teacher where the user inputs a string and prints out the length of the string.
Code:
#include <stdio.h>
#include <string.h>
int main() {
char str[100];
int i = 0;
[Code] ....
Now I understand that it returns the count in "int" so my question is:
Let's say i declared
Code: int count = 0;
at the beginning of the code and then made
Code: count = strlen(str);
why wouldn't i have the same result? Is there a way to do it also?
I have this string d ="3 J JD, K" and i want to split the string to individual string. I have this code which eliminates the comma but doesn't split the string into individual string.
#include <iostream>
#include <string>
#include <sstream>
using namespace std;
int main() {
string str = "3 J JD,K";
stringstream ss(str);
[Code] ....
Output of the code is
3 J JD
k
but I want
3
J
JD
K
Also after I split the string is there any way to put the split string into individual string variables.
Very new to programming, and I know that there must be another way on inputting a string into each array cells not by just inputting it one by one, but as a whole. My code at the meantime is: [URL]
View 1 Replies View RelatedI have problem with string compare. I want to compare the string user input with a string in binary. And I don't know how to do it. Problem in function login();Here is the code: And you also can download file in attachment too..
Code:
#include<conio.h>#include<dos.h>
#include<stdio.h>
#include<process.h>
#include<string.h>
char nsb=1;
char ch, password[20], passlogin[20], inputpass[20], checked[20];
FILE *fp;
}
[code]....
In this code, i declared a string constant and trying to print the length of string. I know that if i write char a1[7] or char a1[] than it runs and give aggregate output, but in this case it is giving double length of string.
Code:
#include<stdio.h>
#include<conio.h>
#include<string.h>
void main()
}
[code]....
I wrote a program that reads a list from a file and stores it in a string type vector. Now, I want the user to input a word so that the program can search the vector to see if that word already exists. I have used every possible way of reading input from the console and storing it in order to compare with the vector but it never results in a match. When I print the input string and the vector string they are exactly the same thing (or at least print to the console as if they were). I've tried using getline; using cin direct to a string var; using cin to a char array and then casting to string using string str(arr); I even added a newline at the end just in case and STILL I cannot get a match.
vector <string> currentSet; //read a list in from a file and has 9 items in it
cin.ignore();
string line;
getline(cin, line);
if(line == vector[0]){//if printed to console line is HEAT and vector[0] is HEAT
cout<<"match"<<endl;
}
write a program that prompts the user to input a string and outputs the string in uppercase letters. (Use a character array to store the string.) Does this follow the criteria? This program is very similar to one I found on these forums but I have one problem, it outputs everything backwards! EX: dogs will output to SGOD. What I need to do to make it output correctly, I think it may have to do with getline?
#include <iostream>
#include <cctype>
#include <cstring>
using namespace std;
int main() {
char let[100];
cout << "Enter what you would like to be UPPERCASE: ";
[Code] ....
I just i would like to know how to record a string from a label to an array string ?
string[] stringArray = labelone.Text
I made a simple little program that takes text from the clipboard, and spits out all the lines I've copied one at a time (so my program can analyze it).
everything works perfectly, except, it spits it own in the wrong order, I want it to spit out from bottom to top. but currently it spits out the data from top to bottom. here is my code :
Code:
#include <iostream>
#include <Windows.h>
#include <string>
#include <sstream>
using namespace std;
int main() {
HANDLE clip; // assigns the var. clip to hold a handle ID.
[Code] .....
I want this loop to run backwards! Like it say's what I want to work backwards. Where as I know how to flip a while loop like this: while(x < 5), how to flip a loop like the one I'm using. how I can do this?
I have the codes for such a problem where, to create a program that counts how many times the second string appears on the first string. Yes it counts if you put 1 letter only, but if you put 2, it is an error. As an example. If the first string is Harry Partear, and the second string is ar, it must count as 3. Here's the code:
Code:
#include <iostream>
#include <conio.h>
using namespace std;
int main ()
[Code] ....
I am stuck in this program, Be given a string of chars, where each single char belongs to the following alphabet: a..zA..Z0..9 (So, in the string there are only lowercases, uppercases and digits. No blank, no comma, ...). For every char of the given alphabet, count how many times in the string
1-- the char belong to a sequence of identical chars whose length is at least three (i.e.: in the string cc74uyrpfccc348fhsjcccc3848djccccc484jd for three times the character 'c' satisfies this condition)
Code:
#include<stdio.h>
#include<conio.h>
#include<string.h>
[Code]...
2-what is the longest substring of characters strictly rising interm of ASCII code(the following is greater (>) of the previous)
3- what is the longest substring of successive characters interm of given string rannge (i.e.: fhkjshdfruytyzABCDEfglsj => 7)
/*assume array is already initialized and declared and is of array type string.*/
int i = 2;
int j = 1;
string newvalue;
cout<<"Current value at array[i][j] is "<<array[i][j]<<endl;
cout<<"Enter new value "<<endl;
cin>>newvalue;
array[i][j]= newvalue; //PROBLEM IS IN THIS LINE.
cout<<endl;
cout<<array[i][j]<<endl;
I'm having lots of trouble with storing a cin string text into a string array. It just seem that after I cin newvalue, the program crashes. Is this way of storing it considered illegal? I'm just a beginner with 5 months of coding experience in C++.
heres the function:
string ToString ( const char * format, ... )
{
char buffer[256];
[Code]....
these function do the same of the sprintf() function. but instead we use a variable for add the result, i want to return the result. when i use it:
string f;
f=ToString("hello world");
gives me several errors:
"error: crosses initialization of 'std::string f'"
"error: jump to case label [-fpermissive]"