I am trying to create a code and cannot get the following part to work :
for (int n = 0; n = timesteps; n++)
{
n = n + 0.1 ;
cout<< "timesteps"<< n << endl ; //print time step value =0.1
for (int j = 0; j < nodesinx; j++)
{
T[j][n+1] = T[j][n] + 0.16 * (T[j][n] - 1[n] - 2[T[j][n] + T[j] + 1[n] ; //equation
n= n + 0.1 ;
cout<< "temperature" << T[j][n+1] << endl;
T[j][n+1] = 0.0 ;
}
}
My code is below:
Total Interest ends up as my last Monthly Payment amount instead of adding up all Interest Paid - What am I doing wrong?
Total Paid isn't calculating correcly either - What am I doing wrong?
I suspect both are very similar problems. I've tried several different calculations, but cannot figure this out.
#include <iostream>
#include <cmath>
using namespace std;
double GetMonthlyIntrest (double OpenBalance,double rate);
bool ContinuePgm();
int main () {
double StartingBalance,rate,amount,OpenBalance,IntPmt,TotalInt=0.0,GrandTotal=0.0;
[code]...
I need starting a do-while loop in my program that runs up to 10 time that asks the user to enter up to 10 scores, which include the slope and rating for the course, and calculates the handicap for each score.
Here's what I have so far:
Code:
{
//This program calculates a golfers handicap.
#include <iostream>
#include <string>
using namespace std;
[Code] ....
I am creating a binary search program that lets the user input up to 10 integers and then the program displays the array and sorts it. When the user is prompted to select an integer, if the integer is in the array, the program responds with the array subscript part. I can get the loop to work once and maximum twice, but then it wont search for the array or say value not found even though the number in in the array. I tried making the values NULL but that only lets me go through it one more time.
Here is my code:
#include <iostream>
using namespace std;
//Functions
void printArray(int);
void selection(int);
int binarySearch(int,int,int);
[code]....
I'm having trouble figuring out how to calculate the sum of two lines in the array(for loop)? And the next part, I can return the values to the main program however, how do I do it with c pointers?
(1) Write a C function that takes an integer array argument. The array argument has two rows and NDATA columns where NDATA is a symbolic constant. For each column in the array argument, the function calculates the sum of the values in the first and second row. The function returns to its calling program (using a second argument and call by reference as implemented with C pointers) the maximum of these sums. Additionally the function returns the column subscript where this maximum first occurs. This subscript value is returned the usual way (using a return statement). etc...
Here is the start of the array program
Code:
#include<stdio.h>
#include<stdlib.h>
#define NDATA 5 /* define number of data per row */
int row; /* count rows */
int column; /* count columns */
[Code] ....
From the example given below, I would like to Generate a matrix who stores a generated array for each iteration. I have an understanding of inputting single elements to a matrix but how can I input an array to a matrix. let's say I would like to input and array of 4 elements that should be stored as a single row of the generated matrix and do this for an infinite while{true} loop.
#include <iostream>
#include <unistd.h>
#include <cstdio>
#include <cmath>
#include <ctime>
#include <stdlib.h>
#include <stdio.h>
#include <vector>
void printArray(int arr[], int size) {
[Code] ....
I am attempting to create multiple labels in a for each loop for each tag text (using htmlagility pack). My current code only creates one and doesn't change the first value (Which is AAE). I am using the labels to later input all the label.text into a database after the initial loop has finished (not shown).
foreach (var tag in tdTags) {
MessageBox.Show(tag.InnerHtml);
Label label = new Label();
label.Name = "contentName" + tag.InnerHtml;
label.Text = tag.InnerHtml;
[Code] ....
I have this if block that is supposed to be creating a pipe then forking and I would like to combine the while loop below it with it. How would I do that?
p = pipe(pipe1);
if (p < 0) {
printf("pipe error");
exit(0);
} else {
printf("successful pipe1 = %d",p);
[Code].....
I have trying to read this documentation but don't understand it. [URL] ....
I have been working on a program to calculate the factorial of numbers. Part of my code is copied and modified from the FAQ about validating numbers in user input.
I have encountered a problem with the for loop that I am using near the end of my code. No matter what I do, it seems that my loop only does the multiplication of b = a*(a-1) and then prints. For example, inputting 5 will result in a print of 20, but the factorial is 120.
Code:
int main(void) {
char buf[BUFSIZ];
char *p;
long int a;
long int b;
long int i;
printf ("Enter a number to be factorialized: ");
[Code] ....
I need starting a do-while loop in my program that runs up to 10 time that asks the user to enter up to 10 scores, which include the slope and rating for the course, and calculates the handicap for each score. Here's what I have so far:
//This program calculates a golfers handicap.
#include <iostream>
#include <string>
using namespace std;
int main(){
int score, slope;
double rating, handicap;
[Code] ....
My address book will be simple, and the thing's that I'm expecting to use in it are :
Pointers, Linked Lists
Malloc
Structs
Typedefs
Makefile, header file
Putting functions into different program files
I have started the program trying to create a struct, and getting it working with a couple of entries before going onto user input and splitting it up.
Code:
#include <stdio.h>
#include <stdlib.h>
int main(void) {
// Struct type address book. Just a name, a number and a pointer
[Code] .....
I'm a bit lost at this point... My knee jerk thought is to create a for loop, and cycle through the list.
I'm not sure how this would apply to this though? Without using the familiar type of print loop such as :
Code:
for (i = 0; ;i++) {
printf("%i
", array[i];
}
I'm thinking that I need to create a temporary struct that can be used to assign the value of the next struct in the list, and then somehow print from that....
I'll try and write the logic out :
while temp != NULL (The last node value is assigned NULL to show us where the end of the list is)
create a temporary pointer that can be used to keep track of where we are in the list.
print out the current entry name and number
then assign the temp pointer value to the * next of the current struct. So if we are in entry1 the *next should be the address of entry 2.
Print out entry 2 name and number, assign entry 2 next to the temp value.
I'm writing a code that's suppose to do a payroll for my intro cs class. At first it was working fine until I had to add the part that made sure a user couldn't enter a wage value below $6.00 and now it stops the loop right after that part for some reason.
#include <iostream>
#include <iomanip>
using namespace std;
int main() {
int const HR = 7;
[Code] ....
I'm trying to create a program that will take input from a user and calculate it in a do-while loop. The program does the calculation but the answer is wrong. The loop also doesn't work. The purpose of the program is to see how much an item will cost after a discount is taken off and tax is added.
#include <iostream>
#include <cmath>
using namespace std;
double original_cost;
double discount;
double tax;
double total;
char answer;
[Code]...
I have this code that im stuck on what i need to do is Extend the code such that when it starts the user is asked to input values to specify each of the three ranges before moving on to accept and tally the main values how do i do that Using a for loop to input and output array values Also calculate the average
*/
#include <stdio.h>
int main(void)
{
/* Declare an array of integers */
int Grades[5];
int nCount;
int nTotal = 0; /* Declare and initialise the value */
float fAverage;
[Code]...
Write a program that calculates the average of a stream of positive numbers. The user can enter as many positive numbers as they want, and they will indicate that they are finished by entering a negative number. For this program, treat zero as a positive number, i.e., zero counts as a number that goes into the average. Of course, the negative number should not be part of the average. You must use a function to read in the numbers, keep track of the running sum and count, compute the average, and return the average to the main() function. Note that you must use a loop to do this, as you don't know how many numbers the user will enter ahead of time. I am having problem writing a loop program for it..
View 1 Replies View RelatedI am currently having problems creating a loop that will allow my user to choose to return to the beginning of the program or quit.
#include <iostream>
using namespace std;
int main() {
int j;
do {float a;
cout << "+----Welcome to Basic Operations----+
| Select Your Operation |
[Code] .....
I have not yet finished designing the interface for a couple of the operations, but right now i am hung up on trying to return to the beginning. I believe it is because the j was defined inside do and isn't carried out of the do statement for while.
I am trying to create a loop to call in the entries from the text file named Set. The entries of Set.txtare :
1 2 3
2 4 5
and so on .. (64 such combinations)[/CODE]
It basically means the first combination for testing is 1 2 3 and next has to be 2 4 5 and so i have 64 such entries defined in set
My test files are located in D://data// and are named tst_data1 to tst_data64.
I created a loop for test set but its incorrect
Code:
// loop for test samples
char basefilename[] = "D://data//";
char , testFilen[160], numiChar[10];
for (int i=1; i<=64; i++) {
strcpy(basefilenme, "D://data//");
strcat(testfilename, Set[]);
[Code] .....
How can i call the Set .txt and how to define it.
Equation for compound interest. The interest is supposed to be $43.34 according to the book, I am ending up with around $35. The actual equation is amount = principal * (1 + rate/t)^t where t = number of times compounded per year. I still have to go through and clean up all the code I just want the formula working first.
#include <iostream>
#include <iomanip>
#include <cmath>
using namespace std;
int main () {
float princ, rate, comp, savings, interest, rates, year;
[Code] .....
We are suppose to build a program to do the quadratic formula, which isnt really a issue. my issue is i have a if else loop and my if is being ignored.
what i want it to do is is state that if the (b * /> - 4(a)© is a negative, then it prints out stating it cant do this.
note: i know that i can use the i number system but we have been asked to not too and to do this instead.
here is my code
#include <stdio.h>
#include <math.h>
int main() {
float a, b, c, d, e, f, g, h, i; /* i would love to figure out a way to do this without so many variables*/
[code]....
Im having problems coding this
A = P(1 + r/n)nt
//Declared test cases
float principal = 200000.00, annualInt = 0.03;
float years = 10.0;
float calcInterest1(float principal, float years, float annualInt) {
float interest1;
float nt = annualInt*12;
float A = principal+annualInt;//Accrued Amount
interest1 = (A = (principal*(1+years/100))pow(nt));// A = P(1 + r/n)nt
return interest1;
}
It is possible to define the formula of prime numbers in C++ language?
View 1 Replies View RelatedIts a basic math function using the exponential growth formula which is correct but the computer is not outputting the right numbers.
Code:
#include <stdio.h>
#include <math.h>
int main() {
int blanketsquares, num1, num2, blanket,remainder;
[Code] .....
I need to calculate the area of a triangle using heron's formula. I wrote the code below and i need to modify it so that a user is required to keep entering the three side until he/she decides to stop. If the three sides entered make an invalid triangle, the user is required to re-enter the values until valid triangle is formed. Then the area is displayed.
#include <iostream>
#include <cmath>
using namespace std;
int main(){
double a,b,c=0;
double s,A=0;
[Code] .....
the screen output should like this:
Enter three sides of a triangle: 0 1 2 Error!
Re-enter three sides of a triangle: -1 1 2 Error!
Re-enter three sides of a triangle: 3 4 5 => 6
Continue (y/n)? y
Enter three sides of a triangle: 1 1 2 Error!
Re-enter three sides of a triangle: 6 8 10 => 24
Continue (y/n)? n
Done!
Please note that Continue (y/n)? only displayed after a valid triangle is formed. Otherwise, the user needs to re-enter sides until it's valid.
write codes that could solve a quadratic formula, and my codes are like this:
#include <bjarne/std_lib_facilities.h>
int main()
{
cout << "Enter the coefficients of a quadratic polynomial a*x**2 + b*x +c:
";
cout << " a? ";
double a;
cin >> a;
cout << " b? ";
[code]....
Which runs perfectly, but I have 2 questions:
1. How to simplify these code? On the assignment sheet the professor wrote about using void solve_linear(double b, double c); and void solve_ quadratic (double a, double b, double c);which I currently dont understand how these works. He asked us to write a well-encapsulated (as short as possible) program.
2. These are for extra points: the precision problem of floating numbers: professor asked us to find a way to get the precise answer of it, like this: Enter the coefficients of a quadratic polynomial a*x**2 + b*x +c:
a? 1
b? -20000
c? 1.5e-9
Trying to solve the quadratic equation 1*x*x + -20000*x + 1.5e-09 == 0
Using classical formula: Two roots, x = 20000 and x = 0
Using stable formula: Two roots, x = 20000 and x = 7.5e-14
My guess is that
A. Using code like if(x1*x2=a/c) to check if numbers were approximated.
B. Somehow determine the larger one in x1 and x2.
C. Somehow use that larger one to do something
How to write a formula for standard deviation but im having a hard time ?
View 2 Replies View RelatedI'm currently writing a program and a portion of it needs to have a function that computes the result of a formula for two sets of inputs. It then has to calculate and display the difference between the two results.
I have code that takes the input from the user and converts it to the type that I need. In this case we are talking about latitudes and longitudes that will be converted to degrees, then to xyz coordinates.