C/C++ :: Quadratic Formula - If Statement Being Ignored
Jan 28, 2014
We are suppose to build a program to do the quadratic formula, which isnt really a issue. my issue is i have a if else loop and my if is being ignored.
what i want it to do is is state that if the (b * /> - 4(a)© is a negative, then it prints out stating it cant do this.
note: i know that i can use the i number system but we have been asked to not too and to do this instead.
here is my code
#include <stdio.h>
#include <math.h>
int main() {
float a, b, c, d, e, f, g, h, i; /* i would love to figure out a way to do this without so many variables*/
[code]....
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Feb 16, 2015
write codes that could solve a quadratic formula, and my codes are like this:
#include <bjarne/std_lib_facilities.h>
int main()
{
cout << "Enter the coefficients of a quadratic polynomial a*x**2 + b*x +c:
";
cout << " a? ";
double a;
cin >> a;
cout << " b? ";
[code]....
Which runs perfectly, but I have 2 questions:
1. How to simplify these code? On the assignment sheet the professor wrote about using void solve_linear(double b, double c); and void solve_ quadratic (double a, double b, double c);which I currently dont understand how these works. He asked us to write a well-encapsulated (as short as possible) program.
2. These are for extra points: the precision problem of floating numbers: professor asked us to find a way to get the precise answer of it, like this: Enter the coefficients of a quadratic polynomial a*x**2 + b*x +c:
a? 1
b? -20000
c? 1.5e-9
Trying to solve the quadratic equation 1*x*x + -20000*x + 1.5e-09 == 0
Using classical formula: Two roots, x = 20000 and x = 0
Using stable formula: Two roots, x = 20000 and x = 7.5e-14
My guess is that
A. Using code like if(x1*x2=a/c) to check if numbers were approximated.
B. Somehow determine the larger one in x1 and x2.
C. Somehow use that larger one to do something
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Oct 7, 2013
This is my code for the quadratic equation. It keeps telling me that my else is illegal since no matching if statement and my else statement is missing a statement
#include <iostream>
#include <cmath>
#include <string>
#include <iomanip>
using namespace std;
int main() {
string Name;
[Code] .....
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Oct 18, 2013
This is my code:
Code:
#include <math.h>
#include <stdio.h>
int main(void) {
float a,b,c,root_1,root_2;
printf("Please enter value a from the quadratic equation
[Code] ......
And I keep getting this error:
Code:
/tmp/ccgtUIun.o: In function `main':
assign345.c:(.text+0xc7): undefined reference to `sqrt'
assign345.c:(.text+0xef): undefined reference to `sqrt'
collect2: ld returned 1 exit status
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Jul 4, 2014
soo quadratic equation solver. output is "x=nan x=nan".
#include <iostream>
#include <string>
#include <cmath>
using namespace std;
//prototyping
double ans_1(double,double,double)
[code].....
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Oct 22, 2014
I have a task to find errors in this long line of code in order to correctly calculate the solutions of quadratic equations.
Code:
int main(int argc, char *argv[]) {
int validInput, solution_type;
double a, b, c, root_1, root_2, q;
/***********************
* Input / Validation
***********************/
/* Check numbers of arguments, and read input */
validInput = (argc = 4);
[Code] ....
Is a section of the code (the first section). And as you can probably guess, it goes on to calculate for a > 0 etc...
I dont really understand what the validinput section is saying? And a, b and c are never defined so Xcode is just saying a,b,c,root1,root2 are uninitialized and I also dont know what means. Do I need to define these values?
Code:
int main(int argc, char *argv[]) {
int validInput, solution_type;
double a, b, c, root_1, root_2, q;
[Code] ......
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Feb 3, 2013
I am creating a program that solves the quadratic equation ax^2 + bx +c.
I have this program almost complete except the output of the equation in the function called display_quadratic. I need the program to display the variables a,b,c in the equation ax^2 + bx + c but I am having 2 problems. My first problem is that I cannot get the right addition and subtraction signs for the equation.
For instance, if the program had the values for a,b,c as 2,2,3
it will display 2x^2 2x 3
How can I get it to display 2x^2 + 2x + 3? or if it was negative like 2x^2 - 2x - 3?
My next question is how do I get to not display the coefficients that are 1?
I had an if-else statement but no matter what I created it would overlap with another statement and print out twice. Here is the code:
Code:
#include <stdio.h>
#include <stdlib.h>
#include <math.h>
void display_quadratic (float a, float b, float c);
float root1(float a, float b, float c);
[Code] ......
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May 23, 2013
I have given following exercise in my cpp book: Determine the roots of quadratic equations
ax^2 + bx + c = 0
using formula
x = -b +(plus-minus) (root)b^2 - 4ac/2a
i don't now how to write such code...
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Jul 6, 2014
So, I successfully made a program that will perform the quadratic equation on three numbers, imaginary or real. however, i am now trying to simplify the result, as to get rid of the "/2a" on the bottom. Hence the simplify() function. I just started to create the simplification function, and am attempting to divide the imaginary part of the solution as well as the real part of the solution by 2a. Somehow, it gives the error, "error:invalid operands of types 'int' and 'double *' to binary 'operator*'" on lines 105 and 106. I suspect it has to do with the pointers and references that i am passing as parameters. Also, just an aside, I have never actually seen "/=" be used. It can be, right? I know "+=" can be.
#include <iostream>
#include <string>
#include <cmath>
#include <cstdlib>//simplify the answer
using namespace std;
int count=0;
//prototyping
double ans_1(double,double,double);
[Code] ....
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Jun 21, 2013
Equation for compound interest. The interest is supposed to be $43.34 according to the book, I am ending up with around $35. The actual equation is amount = principal * (1 + rate/t)^t where t = number of times compounded per year. I still have to go through and clean up all the code I just want the formula working first.
#include <iostream>
#include <iomanip>
#include <cmath>
using namespace std;
int main () {
float princ, rate, comp, savings, interest, rates, year;
[Code] .....
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Sep 24, 2014
Im having problems coding this
A = P(1 + r/n)nt
//Declared test cases
float principal = 200000.00, annualInt = 0.03;
float years = 10.0;
float calcInterest1(float principal, float years, float annualInt) {
float interest1;
float nt = annualInt*12;
float A = principal+annualInt;//Accrued Amount
interest1 = (A = (principal*(1+years/100))pow(nt));// A = P(1 + r/n)nt
return interest1;
}
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Mar 21, 2014
I am trying to create a code and cannot get the following part to work :
for (int n = 0; n = timesteps; n++)
{
n = n + 0.1 ;
cout<< "timesteps"<< n << endl ; //print time step value =0.1
for (int j = 0; j < nodesinx; j++)
{
T[j][n+1] = T[j][n] + 0.16 * (T[j][n] - 1[n] - 2[T[j][n] + T[j] + 1[n] ; //equation
n= n + 0.1 ;
cout<< "temperature" << T[j][n+1] << endl;
T[j][n+1] = 0.0 ;
}
}
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Jul 27, 2014
It is possible to define the formula of prime numbers in C++ language?
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Sep 3, 2013
Its a basic math function using the exponential growth formula which is correct but the computer is not outputting the right numbers.
Code:
#include <stdio.h>
#include <math.h>
int main() {
int blanketsquares, num1, num2, blanket,remainder;
[Code] .....
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Nov 7, 2014
I need to calculate the area of a triangle using heron's formula. I wrote the code below and i need to modify it so that a user is required to keep entering the three side until he/she decides to stop. If the three sides entered make an invalid triangle, the user is required to re-enter the values until valid triangle is formed. Then the area is displayed.
#include <iostream>
#include <cmath>
using namespace std;
int main(){
double a,b,c=0;
double s,A=0;
[Code] .....
the screen output should like this:
Enter three sides of a triangle: 0 1 2 Error!
Re-enter three sides of a triangle: -1 1 2 Error!
Re-enter three sides of a triangle: 3 4 5 => 6
Continue (y/n)? y
Enter three sides of a triangle: 1 1 2 Error!
Re-enter three sides of a triangle: 6 8 10 => 24
Continue (y/n)? n
Done!
Please note that Continue (y/n)? only displayed after a valid triangle is formed. Otherwise, the user needs to re-enter sides until it's valid.
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Sep 19, 2014
My code is below:
Total Interest ends up as my last Monthly Payment amount instead of adding up all Interest Paid - What am I doing wrong?
Total Paid isn't calculating correcly either - What am I doing wrong?
I suspect both are very similar problems. I've tried several different calculations, but cannot figure this out.
#include <iostream>
#include <cmath>
using namespace std;
double GetMonthlyIntrest (double OpenBalance,double rate);
bool ContinuePgm();
int main () {
double StartingBalance,rate,amount,OpenBalance,IntPmt,TotalInt=0.0,GrandTotal=0.0;
[code]...
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Apr 17, 2013
How to write a formula for standard deviation but im having a hard time ?
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Nov 14, 2013
I'm currently writing a program and a portion of it needs to have a function that computes the result of a formula for two sets of inputs. It then has to calculate and display the difference between the two results.
I have code that takes the input from the user and converts it to the type that I need. In this case we are talking about latitudes and longitudes that will be converted to degrees, then to xyz coordinates.
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May 7, 2013
I did a function for lagrange interpolation formula. However i`m stuck on how do i substitute values into the power. Here is my code snippet :
for(int i=1;i<getSecretShare+1;i++) {
//calculateValue=getSecret+(10*p)+(2 * pow(p,2));
int storeThreshold=getThreshold;
calculateValue=getSecret+(10*i)+(2 * pow(i,2));
calculateFinalValue=calculateValue % 17 ;
cout<<"the calculated value is "<<calculateFinalValue<<endl;
}
The formula that i want to implement is that a + a1x^1 + a2x^2 + a(t-1) ^t-1
I have gotten the substitution of the x value out. However, i am stuck on how do i calculate the values according to the threshold which the user keys in. For example if the user keys in 3.
It will into account the no. of shares to generate which is for example 5 in this case, then it will then take into account the threshold keyed in , which is 3, i will then calculate using the formula using the no. of shares and also threshold.
if the threshold is 3 and the number of shares to generate is 5. I should have the following:
y(1) = 13 + a1(1)^1 +a2(1)^2
y(2) = 13 + a2(2)^1 +a2(2)^2
the power depends on the threshold which is t-1, 3-1 =2
So I will have to generate two a values based on that and also calculate them according to the power that is dependent on the threshold the first value being to the power of 1 and the 2nd being to the power of 2 if the threshold is 4.
Then I will generate 3 a values and then calculate them :
y(1) = 13 + a1(1)^1 + a2(1)^1 + a3(1)^3
and so on..
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Oct 26, 2013
I want to get the direct formula for calculating the range of double and float datatypes in c,if any.
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Feb 24, 2013
I was given a question in my programming class to create a program to find the factorial of any number greater than zero and to use Gosper's formula to approximate it.
Code:
#include <stdio.h>
#include <math.h>
#define PI 3.14159265
double equation(int n);
int
[Code] ....
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Apr 12, 2014
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3. Making an offset for ragged arrays which have different row lengths?
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This is not for an assignment but preparation for an exam. I don't know how to go about on finding these out.
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Sep 7, 2013
How to make if else code below into SWITCH STATEMENT?
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cin >> temp;
cout << "Enter the pressure: ";
cin >> pressure;
cout <<endl;
[Code]....
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Sep 22, 2013
This while statement is not cooperating and I am not really sure why. I tried to say while not equal to true and later false, but both produce a never ending loop. I know I posted this before and I got several comments back about different issues with this program. However this question is specific about the while statement.
Code:
#include <iostream>
#include <vector>
#include <string>
using namespace std;
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Apr 30, 2013
I'm having a really dumb moment and I cant seem to remember how an if statement works, with only the variable name as the condition..
Code:
if(var){
//then do something
}
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Oct 21, 2013
Well for some reason this doesn't work.
Code:
#include <stdio.h>#include <ctype.h>
int main(void)
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int lottoNums[150];
int num;
[Code]....
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