C++ :: Compound Interest Formula
Jun 21, 2013
Equation for compound interest. The interest is supposed to be $43.34 according to the book, I am ending up with around $35. The actual equation is amount = principal * (1 + rate/t)^t where t = number of times compounded per year. I still have to go through and clean up all the code I just want the formula working first.
#include <iostream>
#include <iomanip>
#include <cmath>
using namespace std;
int main () {
float princ, rate, comp, savings, interest, rates, year;
[Code] .....
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Sep 24, 2014
Im having problems coding this
A = P(1 + r/n)nt
//Declared test cases
float principal = 200000.00, annualInt = 0.03;
float years = 10.0;
float calcInterest1(float principal, float years, float annualInt) {
float interest1;
float nt = annualInt*12;
float A = principal+annualInt;//Accrued Amount
interest1 = (A = (principal*(1+years/100))pow(nt));// A = P(1 + r/n)nt
return interest1;
}
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Jun 7, 2013
I am making this program for a class and it works fine except for the daily interest rate for the checking account is off. The daily interest for the savings computes perfectly. The monthly interest rate for savings is 6% and for checking 3%.
Account.h
#ifndef ACCOUNT_H
#define ACCOUNT_H
#include <iostream>
#include <string>
using namespace std;
const int DAYS_PER_MONTH = 30;
[Code] ....
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Jan 17, 2013
I was trying to make a program of calculating simple intrest using functions. I don't know whats wrong with the program but it always shows a wrong output.
#include<iostream.h>
#include<conio.h>
float si(int p,int r,int t) {
return ((p*t*r)/100.0);
[Code] ....
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Feb 11, 2014
math part.
The equation I need to use is: payment = [(rate * (1 + rate)^number payments ) / ((1 + rate)^number of payments -1)] * loan
Also, the value of rate in the above equation is (interest/12)/100. So 12% annual interest would be 1% monthly interest.
heres my code:
#include<iostream>
#include<cstdio>
#include<cmath>
using namespace std;
[Code].....
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Sep 27, 2013
Here is my code:
int main (int argc, char* argv[]) {
int x = atoi (argv[1]);
int y = atoi (argv[2]);
int z = atoi (argv[3]);
if (strcmp(argv[4], "Simple") == 0){
[Code ....
I need to convert the output of simple interest to float which is $5184.90 instead of $5180. how to go about it?
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Oct 21, 2014
This exercise should familiarise you with loops, if-then-else statements, and recursion. You will have to design and implement a program that calculates the interest earned on a bank-account. Deadline is the end of Tuesday in week 4.
Interests are compounded; that is, you earn interest on interest. Given a yearly interest rate of say, 6%, you can calculate the total sum available when an initial sum of 4000 pounds is put away for 13 years as follows:
4000 * ( (1 + [6/100])^13 ) = 8531.71 pounds
where the caret symbol denotes 'to the power of'. One way to calculate the power is by repeatedly mulitplying. Ie, you can mulitply 1.06 with 1.06 12 times to calculate 1.06^13.
PART 1
Design and implement a function that raises X to the power Y for a real number X and a positive integer Y. The function must use a while loop.
Design and implement a main program that calculates the sum availble when 1000 pounds has been put away for 25 years with 5 percent interest.
Change the while-loop in the function to a for-loop.
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Feb 4, 2013
For each quarter, calculate and display the beginning principal balance, the interest earned, and the final principal balance for the quarter.For example: The user entered 1000.00 for the beginning principal balance, 5.25 for the interest rate, and 8 for the number of quarters. The output from this part of the program should be similar to the following:
Q| Beginning Principle| Interest Earned| End Principle
1| $1,000.00 | $13.13 | $1,013.13
2| $1,013.13 | $13.30 | $1,026.42
3| $1,026.42 | $13.47 | $1,039.89
etc
Here is the code I have so far, and I just am not quite sure where to go next.
Code:
{
cout << "Quarters" << " " << "Beginning Principles" << " " <<"Interest Earned" << " " <<"End Principal" << endl;
endprin = balance + (quarter * interest);
interest = quarter * interest;
cout << endprin << endl;
}
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Apr 7, 2014
I have a problem requiring me to :
enter loan amount:
Enter interest rate:
Enter length of loan (years)
It wants me to input the minimum amount for the loan, and the minimum interest rate. and then output a table that has 5 loan amounts across the top in $10000 increments and 4 interest rates along the side in .25% increments.
#include <iostream>
#include <iomanip>
#include <cmath>
using namespace std;
int main () {
double loan, interest, length, payment,ti;
//Enter loan price
[Code] .....
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Jan 25, 2013
Your objective is to write a program that calculates the simple interest for a given loan amount and duration (in years).
Formula:
Simple interest = loan amount X interest rate X number of years
Assume interest rate is a constant 6% per year.
Specifically, your program will:
1. Output descriptive header
2. Prompt and read any customer’s first name, middle initial, and last name individually
3. Prompt and read the principal/loan amount
4. Prompt and read the duration of the loan in years
5. Calculate the interest
6. Output:
a. Customer full name
b. Principal/loan amount
c. Duration of loan
d. Interest rate
e. Interest on loan
f. Principal and interest due at end of term
OK SO THIS IS MY PROGRAM SO FAR. As you can see i got it all but i am so confused with as to for loan amount and duration of year, if i should use float or double to declare it?
i need to finish this assignment by calculating the simple interest and i dont know how or where to begin.
int main(){
system("color f0");
string firstName;
string middleInitial;
string lastName;
cout<<"Please enter your First Name: ";
[Code]...
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Jan 28, 2014
We are suppose to build a program to do the quadratic formula, which isnt really a issue. my issue is i have a if else loop and my if is being ignored.
what i want it to do is is state that if the (b * /> - 4(a)© is a negative, then it prints out stating it cant do this.
note: i know that i can use the i number system but we have been asked to not too and to do this instead.
here is my code
#include <stdio.h>
#include <math.h>
int main() {
float a, b, c, d, e, f, g, h, i; /* i would love to figure out a way to do this without so many variables*/
[code]....
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Mar 21, 2014
I am trying to create a code and cannot get the following part to work :
for (int n = 0; n = timesteps; n++)
{
n = n + 0.1 ;
cout<< "timesteps"<< n << endl ; //print time step value =0.1
for (int j = 0; j < nodesinx; j++)
{
T[j][n+1] = T[j][n] + 0.16 * (T[j][n] - 1[n] - 2[T[j][n] + T[j] + 1[n] ; //equation
n= n + 0.1 ;
cout<< "temperature" << T[j][n+1] << endl;
T[j][n+1] = 0.0 ;
}
}
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Jul 27, 2014
It is possible to define the formula of prime numbers in C++ language?
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Sep 3, 2013
Its a basic math function using the exponential growth formula which is correct but the computer is not outputting the right numbers.
Code:
#include <stdio.h>
#include <math.h>
int main() {
int blanketsquares, num1, num2, blanket,remainder;
[Code] .....
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Nov 7, 2014
I need to calculate the area of a triangle using heron's formula. I wrote the code below and i need to modify it so that a user is required to keep entering the three side until he/she decides to stop. If the three sides entered make an invalid triangle, the user is required to re-enter the values until valid triangle is formed. Then the area is displayed.
#include <iostream>
#include <cmath>
using namespace std;
int main(){
double a,b,c=0;
double s,A=0;
[Code] .....
the screen output should like this:
Enter three sides of a triangle: 0 1 2 Error!
Re-enter three sides of a triangle: -1 1 2 Error!
Re-enter three sides of a triangle: 3 4 5 => 6
Continue (y/n)? y
Enter three sides of a triangle: 1 1 2 Error!
Re-enter three sides of a triangle: 6 8 10 => 24
Continue (y/n)? n
Done!
Please note that Continue (y/n)? only displayed after a valid triangle is formed. Otherwise, the user needs to re-enter sides until it's valid.
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Feb 16, 2015
write codes that could solve a quadratic formula, and my codes are like this:
#include <bjarne/std_lib_facilities.h>
int main()
{
cout << "Enter the coefficients of a quadratic polynomial a*x**2 + b*x +c:
";
cout << " a? ";
double a;
cin >> a;
cout << " b? ";
[code]....
Which runs perfectly, but I have 2 questions:
1. How to simplify these code? On the assignment sheet the professor wrote about using void solve_linear(double b, double c); and void solve_ quadratic (double a, double b, double c);which I currently dont understand how these works. He asked us to write a well-encapsulated (as short as possible) program.
2. These are for extra points: the precision problem of floating numbers: professor asked us to find a way to get the precise answer of it, like this: Enter the coefficients of a quadratic polynomial a*x**2 + b*x +c:
a? 1
b? -20000
c? 1.5e-9
Trying to solve the quadratic equation 1*x*x + -20000*x + 1.5e-09 == 0
Using classical formula: Two roots, x = 20000 and x = 0
Using stable formula: Two roots, x = 20000 and x = 7.5e-14
My guess is that
A. Using code like if(x1*x2=a/c) to check if numbers were approximated.
B. Somehow determine the larger one in x1 and x2.
C. Somehow use that larger one to do something
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Sep 19, 2014
My code is below:
Total Interest ends up as my last Monthly Payment amount instead of adding up all Interest Paid - What am I doing wrong?
Total Paid isn't calculating correcly either - What am I doing wrong?
I suspect both are very similar problems. I've tried several different calculations, but cannot figure this out.
#include <iostream>
#include <cmath>
using namespace std;
double GetMonthlyIntrest (double OpenBalance,double rate);
bool ContinuePgm();
int main () {
double StartingBalance,rate,amount,OpenBalance,IntPmt,TotalInt=0.0,GrandTotal=0.0;
[code]...
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Apr 17, 2013
How to write a formula for standard deviation but im having a hard time ?
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Nov 14, 2013
I'm currently writing a program and a portion of it needs to have a function that computes the result of a formula for two sets of inputs. It then has to calculate and display the difference between the two results.
I have code that takes the input from the user and converts it to the type that I need. In this case we are talking about latitudes and longitudes that will be converted to degrees, then to xyz coordinates.
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May 7, 2013
I did a function for lagrange interpolation formula. However i`m stuck on how do i substitute values into the power. Here is my code snippet :
for(int i=1;i<getSecretShare+1;i++) {
//calculateValue=getSecret+(10*p)+(2 * pow(p,2));
int storeThreshold=getThreshold;
calculateValue=getSecret+(10*i)+(2 * pow(i,2));
calculateFinalValue=calculateValue % 17 ;
cout<<"the calculated value is "<<calculateFinalValue<<endl;
}
The formula that i want to implement is that a + a1x^1 + a2x^2 + a(t-1) ^t-1
I have gotten the substitution of the x value out. However, i am stuck on how do i calculate the values according to the threshold which the user keys in. For example if the user keys in 3.
It will into account the no. of shares to generate which is for example 5 in this case, then it will then take into account the threshold keyed in , which is 3, i will then calculate using the formula using the no. of shares and also threshold.
if the threshold is 3 and the number of shares to generate is 5. I should have the following:
y(1) = 13 + a1(1)^1 +a2(1)^2
y(2) = 13 + a2(2)^1 +a2(2)^2
the power depends on the threshold which is t-1, 3-1 =2
So I will have to generate two a values based on that and also calculate them according to the power that is dependent on the threshold the first value being to the power of 1 and the 2nd being to the power of 2 if the threshold is 4.
Then I will generate 3 a values and then calculate them :
y(1) = 13 + a1(1)^1 + a2(1)^1 + a3(1)^3
and so on..
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Oct 26, 2013
I want to get the direct formula for calculating the range of double and float datatypes in c,if any.
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Feb 24, 2013
I was given a question in my programming class to create a program to find the factorial of any number greater than zero and to use Gosper's formula to approximate it.
Code:
#include <stdio.h>
#include <math.h>
#define PI 3.14159265
double equation(int n);
int
[Code] ....
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Apr 12, 2014
I know how to make offsets/addressing formula of a straight forward N Dimensional array but how to make an offset and a storage allocation space for something tricky like:
1. A lower and upper triangular matrix?
2. A band matrix?
3. Making an offset for ragged arrays which have different row lengths?
4.A upper/lower triangular matrix using ragged arrays?
This is not for an assignment but preparation for an exam. I don't know how to go about on finding these out.
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