C++ :: Calculating Area Of A Triangle Using Heron Formula
Nov 7, 2014
I need to calculate the area of a triangle using heron's formula. I wrote the code below and i need to modify it so that a user is required to keep entering the three side until he/she decides to stop. If the three sides entered make an invalid triangle, the user is required to re-enter the values until valid triangle is formed. Then the area is displayed.
#include <iostream>
#include <cmath>
using namespace std;
int main(){
double a,b,c=0;
double s,A=0;
[Code] .....
the screen output should like this:
Enter three sides of a triangle: 0 1 2 Error!
Re-enter three sides of a triangle: -1 1 2 Error!
Re-enter three sides of a triangle: 3 4 5 => 6
Continue (y/n)? y
Enter three sides of a triangle: 1 1 2 Error!
Re-enter three sides of a triangle: 6 8 10 => 24
Continue (y/n)? n
Done!
Please note that Continue (y/n)? only displayed after a valid triangle is formed. Otherwise, the user needs to re-enter sides until it's valid.
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Oct 26, 2013
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Nov 16, 2014
I was asked to build a small program to calculate the are of a Triangle but my code must have some problem.. />
#include "stdafx.h"
void main()
{
int a,b;
[Code]....
I get this errors:
-warning C4996: 'scanf': This function or variable may be unsafe. Consider using scanf_s instead. To disable deprecation, use _CRT_SECURE_NO_WARNINGS.
-warning C4244: '=' : conversion from 'int' to 'float', possible loss of data
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Sep 28, 2014
I am having trouble with my C++ program. My program asks the user to enter any number greater than 0 and less than 20, and if the user enters any number(s) outside the acceptable range, the output should display:
input outside of exceptable range > 0 and < 20
length: 1 width: 1 area: 1 perimeter: 1
But in my program, this output displays no matter what the user types (even if the numbers are in the acceptable range, when it should be displaying the length and width the user enters and also displaying the calculated perimeter and area whenever the user enters number(s) in the acceptable range. Here is my code:
#include <iostream>
using namespace std;
float class_rectangle_area();
float class_rectangle_perimeter();
float class_rectangle_length();
float class_rectangle_width();
[Code] .....
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Jun 10, 2013
I am currently learning "if statements" while doing a program that calculates the area of a triangle. My problem is that the result is always "0". I am pretty sure the problem lies within my math, but how I have set it up wrong.
I am using Heron's Formula. Here it is for reference:
area=sqrt(s(s-a)(s-b)(s-c)) where s=(a+b+c)/2
Code:
#include <stdio.h>
#include <math.h>
int main () {
float area, sideA, sideB, sideC, halfP;
[Code] ....
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May 26, 2013
i have written a program to find area of triangle, but i meet some errors,
//******area of triangle******//
#include<iostream>
using namespace std;
[Code].....
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Jan 8, 2015
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I am beginning like this;
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#include <cmath>
using namespace std;
double area ( R2 *A,double *z)
[Code] .....
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#include <stdio.h>
#include<Windows.h>
#include<math.h>
double hypotenuse(double side1, double side2);
int main(void){
double side1, side2, hyp;
[Code] .....
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How to find triangle in an array of n triangles which has the largest area?
#include <stdio.h>
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#include<math.h>
typedef struct {
double x,y;
[Code] .....
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#include <iostream>
#include <iomanip>
#include <cmath>
using namespace std;
int main () {
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[Code] .....
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Jan 28, 2014
We are suppose to build a program to do the quadratic formula, which isnt really a issue. my issue is i have a if else loop and my if is being ignored.
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note: i know that i can use the i number system but we have been asked to not too and to do this instead.
here is my code
#include <stdio.h>
#include <math.h>
int main() {
float a, b, c, d, e, f, g, h, i; /* i would love to figure out a way to do this without so many variables*/
[code]....
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Sep 24, 2014
Im having problems coding this
A = P(1 + r/n)nt
//Declared test cases
float principal = 200000.00, annualInt = 0.03;
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float interest1;
float nt = annualInt*12;
float A = principal+annualInt;//Accrued Amount
interest1 = (A = (principal*(1+years/100))pow(nt));// A = P(1 + r/n)nt
return interest1;
}
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Mar 21, 2014
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for (int n = 0; n = timesteps; n++)
{
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{
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T[j][n+1] = 0.0 ;
}
}
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#include <math.h>
int main() {
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[Code] .....
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Feb 16, 2015
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int main()
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";
cout << " a? ";
double a;
cin >> a;
cout << " b? ";
[code]....
Which runs perfectly, but I have 2 questions:
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b? -20000
c? 1.5e-9
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C. Somehow use that larger one to do something
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#include <iostream>
#include <cmath>
using namespace std;
double GetMonthlyIntrest (double OpenBalance,double rate);
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[code]...
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The formula that i want to implement is that a + a1x^1 + a2x^2 + a(t-1) ^t-1
I have gotten the substitution of the x value out. However, i am stuck on how do i calculate the values according to the threshold which the user keys in. For example if the user keys in 3.
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if the threshold is 3 and the number of shares to generate is 5. I should have the following:
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y(2) = 13 + a2(2)^1 +a2(2)^2
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double equation(int n);
int
[Code] ....
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Code:
#include<iostream>
#include<cmath>
using namespace std;
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[Code] .....
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