C :: Limit Action Within A Range Of Time
Mar 8, 2014My question is : can you limit an action to a certain time range?
For example, the user has to put character via getchar() within 3 seconds, otherwise the code will move on?
My question is : can you limit an action to a certain time range?
For example, the user has to put character via getchar() within 3 seconds, otherwise the code will move on?
consider this code:
Code:
private void DoIf(bool b, Action f)
{
if (b)
f();
}
int x = 0;
bool no = false;
DoIf(no, () => x = 10);
Does the compiler emit code to create a new action when the function is called or only when f() is actually called?
So I am have made this 2D ball game. But I want to set a time limit for each level. I want player to play that level for maximum 3 minutes. After 3 minutes the game level should end. I have used allegro 5.0.10 with c++ . How to achieve it?
View 2 Replies View RelatedI have made a complete solar system with key action for zoom in zoom out, moving along x, y, z axes on plus or minus and going up/down/right/left. I am now in a bit of a dilemma. I want to add a text window ( i have made my project in visual studio 2010 in win32 console application) where to put a text like a description of each planet to appear when i hit the left mouse button. E.g. When i click with the left mouse button the Venus planet I want a description to appear in my text window. However I don't know how to put make a text window and how to correctly define the picking methods... for now everywhere i hit the mouse button it appears in to the console that i hit the sun.
View 10 Replies View RelatedMy problem: I want to make an application that is going to block the action of some files (It is anticheat files actually).
how do I make code to block the application's action?
Maybe there is another way to do that? I need to use Cheat Engine in game, and anticheat blocks it, so I thought if I'll block the activity of the anticheat it couldn't detect the Cheat Engine...
This is a round robin execution. with gantt chart. arrival time and burst time. I think there is an error in my formula to get the right answer,i cant resolve it but my program is running. What is the code or the right formula??
#include<stdio.h>
int main(){
int i,j=0,n,time,remain,flag=0,ts;
int sum_wait=0,sum_turnaround=0,at[10],bt[10],rt[10];
int ganttP[50],ganttStartTime[50];
printf("Enter no of Processes : ");
scanf("%d",&n);
remain=n;
[Code] ....
Is there any way to set a "lock" on certain couts from system ("cls"). You can this with const to "lock" a variable to a certain value so I am wondering if that is true for couts from system ("cls"). This would make my program much simpler to write.
View 2 Replies View RelatedI want to set limit on cin for example
int i;
cout<<"Please enter 4 digits id: ";
cin>>i
If user enter more then 4 digits it must give an error
What's actually wrong with the program....I'm trying to print the primes in limit of L1 and L2 ;L1<L2.... */
Code:
#include<stdio.h>
#include<math.h>
void main(){
int L1,L2,n=0
printf("Enter Limits by a space:
}
[code]....
I have to find the sum of primes below limit. My program works fine when I try to find primes less than 10. However, when I run it for the sum of primes less than 100, I get 166337 when I am supposed to get 1060. My program works on modular arithmetic, where any prime greater than 3 can be expressed as 1 or 5 mod 6.
Here is my code:
#include <iostream>
using namespace std;
int main(){
unsigned long long prime, sum;
int limit = 100;
[Code] ....
OUTPUT:
SUM: 166337
I have created a new array and have wrote a code which will decrease || increase the value of the array element. I been trying to figure out how to set the value limit. For Example:
int[] stock = new int[] { 10, 10, 10, 10 };
How to set a limit on the elements that they will never go below to the negative integers and over 10?
Why is this code crashing ? and how do I put a limit of 100 questions to be outputted but not for the test to end ? Also this doesn't seem to be randomizing at all ?
#include <iostream>
#include <vector>
#include <cstdlib>
#include <ctime>
using namespace std;
int main() {
vector<string> questions;
vector<string> answers;
[Code] .....
Im working on a small code and am trying to limit the size of the mysql databse string its pulling.
It can only be 119 characters, or less if its more i would like to do nothing, but if its meets the requirements it runs the script.
Code:
int32 message_id;
string_t message ="Is requesting some one to respond.";<_______________TEMP SHOULD BE THE POSTERS MESSAGE
string_t username = "Guest";<_______________TEMP SHOULD BE THE POSTERS NAME
// char will not be logged in so get the id manually
[Code] ....
So here is where I'm heaving the problem
if(message is less then 119 characters run script )<<___________THIS IS THE CODE LINE IM TRYING TO LEARN
{
char buf[110];
sprintf(buf,"[Web Chat] %s %s",username.c_str(), message.c_str());
[code].....
Suppose you want to develop a program to play lottery. The program randomly generates a Lottery of a three-digit number( any number from 100 to 999), prompts the user to enter a three-digit number, and determines whether the user wins according to the following rule:
1. If the user matches the lottery in exact order , the awards is $100,000.
2. If the user input matches the lottery digits, the awards is $50,000.
3. If two digit in the user input matches a digit in the lottery, the awards is $30,000.
4. If one digit in the user input matches a digit in the lottery,
the awards is $10,000.
Sample:
The winning number is 865.
Your ticket is 865 then 100000
Your tickect is 686, or 568,.. all digits are right but not in order
You get 50000
Your ticket is 860, or 186 .. then 30000
Your ticket is 800, 706, 600.. just one digit much you get
10000
Else
0
Im using if/else statements. Which syntax would I use to figure out the limit between 100-99?
Is dere is any limit in number of objects of a class?
View 16 Replies View RelatedI need a program in c++ that will enter a limit of the loop. using nested for loop with a limit of 3 loops only.
like this !
for (){
for (){
for (){
cout
}
}
}
Sample output:
Enter a number : 3 [enter]
1 2 3
4 5 6
7 8 9
2 3 4
5 6 7
8 9 10
3 4 5
6 7 8
9 10 11
In my program, i have a function, example: bool open(string szString); this function i have known it's fix address, example: 0x12345678 Because of my computer which has low capability, if this function is called 1000 times per second it will be hanged, slow. So i want limit the number of function call down to 500 times per second. how will i do with C/C++?
View 2 Replies View RelatedIn my platform, Windows 7 Ultimate 64 bits with Service Pack 1 over a x86-64 AMD microprocessor, AMD Phenom II 1090T X6, with a total of 4 GBytes of RAM memory), one C++ program can only allocate up to 2 GBytes of dynamic memory (using operator new, so Heap memory).
In am using the IDE Microsoft Visual C++ 2010 Express Edition to compile my C++ program and generate the executable file (for Win32).
In my system, there are much more available memory than 2 GBytes (yet remain 1 GByte of RAM memory and the virtual memory), so, Why can't my C++ program allocate more than 2 GBytes of memory? Do I need to configure something in the IDE to allow more memory to the program?
I was wondering how to limit error message to one only.
For example
cin.getline(stringname,7);
for(int i=0;i<size;i++){
if(strcmp(stringname, "hello")=0)
cout<<"Found!"<<endl;
else
cout<<"not found"<<endl;
}
not found
not found
.......
I want to get only once not found
I wrote this code, but now need to apply a limit to the recursive depth. This is the format that I have to use. How would I pass a limit so that it stops after a given number? I'm just confused about where to apply it.
int compute_edit_distance(char *string1, char *string2, int i, int j, int limit) {
if (strlen(string1) == i) return strlen(string2) - j;
if (strlen(string2) == j) return strlen(string1) - i;
if (string1[i] == string2[j]) return compute_edit_distance(string1, string2, i + 1, j + 1, limit);
[Code] .....
I have managed to make text dynamically appear in a text-box while I enter text into another.
how ever I would like to know to to limit the amount of text that is dynamically entered(I'd say about 10 characters at most).
here's a sample of what I have done so far:
Random r = new Random();
int IDrandom = r.Next(0, 9);
Emp_ID.Text += IDrandom.ToString();
//Emp_ID.MaxLength = 10; does not work
I calculate two numbers "R1",R2"
when i make
cout<<R1;
cout<<R2
i get
R1=51,9151
R2=51,915
when i make
Code: if (R1>R2) cout<<"i am here" he print the message
but they are equal. how i made limit the number of flottant to get equal numbers?
I am trying to make a double array, but I keep getting an error Segmentation fault (core dumped) when I make more than 105 elements in the array. I need to make 114 elements.
I am building my array with myarray[999] and increasing the number doesn't seem to do anything.
How can I store more elements in my array?
Suppose I make a class, something like having the constructor being invoked first makes sense, I don't have a problem with that. But, how could I limit access to functions until certain functions are called? Perhaps this isn't built into the language so you can't. And maybe this problem never comes up. For example if you have a set() and get() functions, if they are both public functions, there doesn't seem to be a way for the compiler at least now if set() never gets called you shouldn't call get(). I just see this as error prone if you need to use libraries, you have to know not to do it from documentation instead of something the compiler can check.
View 11 Replies View RelatedIn my attempt to capture multiple files using CFileDialog I discovered that there is a limit on the number of characters in the file name buffer. [URL]
I have used this code to get the file names and it works fine up to the point where the buffer is full. NB: m_vcsPathnames and m_vcsFilenames are std::vector<CString> types.
Code:
// get a list of the files to process
wchar_t szFilters[]= _T("All Files (*.*)|*.*||");
// Create an Open dialog; the default file name extension "*.*"
CFileDialog fileDlg(TRUE, _T(""), _T("*.*"),
OFN_FILEMUSTEXIST| OFN_HIDEREADONLY | OFN_ALLOWMULTISELECT, szFilters, this);
m_vcsPathnames.resize(0);
[code]....
Is there any possible work around for this limitation, other than completely writing my own CFileDialogExx class ?
#include<iostream>
#include<conio.h>
using namespace std;
int main(void){
clrscr();
[Code] ....
I am trying to print ascii characters but problem is If i put a limit in for loop to 255 or more than 126 the output don't stop it keeps on going
I know there is another way to this program but what i want to know this why this happen in this logic....it doesn't happen if a<=125 or less then 125.