I have created a new array and have wrote a code which will decrease || increase the value of the array element. I been trying to figure out how to set the value limit. For Example:
int[] stock = new int[] { 10, 10, 10, 10 };
How to set a limit on the elements that they will never go below to the negative integers and over 10?
how do I tell the if statement to output this error message 'exceeded the maximum amount of characters' that has its characters stored in an array using c-style string?
[INPUT] The cat caught the mouse!
[OUTPUT] Exceeded the maximum amount of characters (max 10)
#include<iostream>
#include<string>
[Code]....
If I have 2 arrays, say array1 = {2, 2, 4, 5, 6} which has sorted array elements and array2 = {4, 2, 6, 2, 5} that has same elements as array1 but not in sorted condition. How can I compare that both arrays have same elements. I have written the following code which works in all conditions except when array1 has two same elements and array2 has all different elements.
counter=0;
for (i=0; i<5; i++) {
for (int j=0; j<5; j++)
if (array2[i] == array1[j]) {
counter++;
array1[j]=0;
[Code] ....
I'm confused about accessing elements from arrays. Supposed I have an array of pointers to char:
char *names = { "John", "Rose", "Steven" };
To access one of the strings, should I use names[ 0 ][ i ], where i is an index in the set ( 0, 1, 2 ), or should I use names[ i ]? I would think it would be the first option, because this array has 1 dimension that contains others arrays, right?
So I'm trying to make two arrays, then the third array that will include common elements of those two arrays. I did make a code for that, but the problem is I don't know how to include that the elements do not repeat.
For example, if there are two arrays,
Elements of the first one: 2, 3
Elements of the second one: 2, 3, 2
The third array is going to be: 2 2
While I want it to be only 2.
#include <iostream>
using namespace std;
int* intersection(int* n1, int d1, int* n2, int d2, int& d3) {
d3=0;
for (int i=0; i<d1; i++) {
[Code] ....
int result = 1;
for (int j=0;j<N;j++) {
bool found = false;
for (int i=0;i<N && !found;i++) {
if (a[j] == b[i]) found = true;
}
if (!found) return 0;
}
I need to create a code that compares two in arrays without sorting them. They have to be the same length and contain the same elements in any order.
every integer in a[] is also in b[]
every integer in b[] is also in a[]
all such common values appear exactly the same number of times in both a[] and b[]
EX: a = {1, 2, 3}, b = {2, 3, 4} return 0 a = {1, 2, 3}; b = {2, 3, 1} return 1 a = {1, 2, 2}; b = {2, 2, 1} return 1 a = {1, 2, 2}; b = {2, 1, 1} return 0 a = {1, 1, 2, 2, 2}; b = {2, 1, 2, 1, 2} return 1
This is all i have...
Supposing you have a 3 or more overlapping arrays (arrays having elements in common), and you wish to select 2 or more of the arrays with the maximum number of elements but less overlap as compared to the rest of the overlapping arrays.
Eg. A[4],B[6],C[5]. A+B contains 10 elements but say the overlapping element is 3, meaning it has 7 unique element.
Also B+C=11 elements , but supposing it has 5 overlaps, it would mean it has only 6 unique elements. A+B+C=15. Supposing the overlaps are 11 then it means the unique elements are 4. Ect. So per the example, the best array options with most unique element would be A+B .
I have a matrix that contains zero and nonzero elements. I want to do a function that return 3 arrays.
The first one is for nonzero elements the second array contains the corresponding row numbers of each nonzero element the third array contains the corresponding column numbers of each nonzero element.
I have a txt file that looks like this:
Student ID:97707; Grades: 87.73, 90.41, 91.74, 95.04, 99.13; Name:Davis, Artur
Student ID:23628; Grades: 58.09, 65.18, 68.62, 68.62, 98.05; Name:Davis, Susan
Student ID:49024; Grades: 18.37, 66.06, 68.07, 80.91, 96.47; Name:DeGette, Diana
-I need to read the id, grades and names;
-The id to a separate array
-The grades to a 2-d array
-And the names to a c style string.
Where do I start, im having trouble read the dummy to start
int main() {
char filename[15] = "ex.txt";
string names[MAX_NAMES];
double grades[MAX_ROWS][MAX_COLS];
int id[MAX_IDS];
int index = 0;
ifstream fin;
[Code] .....
Is there any way to set a "lock" on certain couts from system ("cls"). You can this with const to "lock" a variable to a certain value so I am wondering if that is true for couts from system ("cls"). This would make my program much simpler to write.
View 2 Replies View RelatedI want to set limit on cin for example
int i;
cout<<"Please enter 4 digits id: ";
cin>>i
If user enter more then 4 digits it must give an error
What's actually wrong with the program....I'm trying to print the primes in limit of L1 and L2 ;L1<L2.... */
Code:
#include<stdio.h>
#include<math.h>
void main(){
int L1,L2,n=0
printf("Enter Limits by a space:
}
[code]....
I have to find the sum of primes below limit. My program works fine when I try to find primes less than 10. However, when I run it for the sum of primes less than 100, I get 166337 when I am supposed to get 1060. My program works on modular arithmetic, where any prime greater than 3 can be expressed as 1 or 5 mod 6.
Here is my code:
#include <iostream>
using namespace std;
int main(){
unsigned long long prime, sum;
int limit = 100;
[Code] ....
OUTPUT:
SUM: 166337
Why is this code crashing ? and how do I put a limit of 100 questions to be outputted but not for the test to end ? Also this doesn't seem to be randomizing at all ?
#include <iostream>
#include <vector>
#include <cstdlib>
#include <ctime>
using namespace std;
int main() {
vector<string> questions;
vector<string> answers;
[Code] .....
Im working on a small code and am trying to limit the size of the mysql databse string its pulling.
It can only be 119 characters, or less if its more i would like to do nothing, but if its meets the requirements it runs the script.
Code:
int32 message_id;
string_t message ="Is requesting some one to respond.";<_______________TEMP SHOULD BE THE POSTERS MESSAGE
string_t username = "Guest";<_______________TEMP SHOULD BE THE POSTERS NAME
// char will not be logged in so get the id manually
[Code] ....
So here is where I'm heaving the problem
if(message is less then 119 characters run script )<<___________THIS IS THE CODE LINE IM TRYING TO LEARN
{
char buf[110];
sprintf(buf,"[Web Chat] %s %s",username.c_str(), message.c_str());
[code].....
My question is : can you limit an action to a certain time range?
For example, the user has to put character via getchar() within 3 seconds, otherwise the code will move on?
Suppose you want to develop a program to play lottery. The program randomly generates a Lottery of a three-digit number( any number from 100 to 999), prompts the user to enter a three-digit number, and determines whether the user wins according to the following rule:
1. If the user matches the lottery in exact order , the awards is $100,000.
2. If the user input matches the lottery digits, the awards is $50,000.
3. If two digit in the user input matches a digit in the lottery, the awards is $30,000.
4. If one digit in the user input matches a digit in the lottery,
the awards is $10,000.
Sample:
The winning number is 865.
Your ticket is 865 then 100000
Your tickect is 686, or 568,.. all digits are right but not in order
You get 50000
Your ticket is 860, or 186 .. then 30000
Your ticket is 800, 706, 600.. just one digit much you get
10000
Else
0
Im using if/else statements. Which syntax would I use to figure out the limit between 100-99?
Is dere is any limit in number of objects of a class?
View 16 Replies View RelatedI need a program in c++ that will enter a limit of the loop. using nested for loop with a limit of 3 loops only.
like this !
for (){
for (){
for (){
cout
}
}
}
Sample output:
Enter a number : 3 [enter]
1 2 3
4 5 6
7 8 9
2 3 4
5 6 7
8 9 10
3 4 5
6 7 8
9 10 11
In my program, i have a function, example: bool open(string szString); this function i have known it's fix address, example: 0x12345678 Because of my computer which has low capability, if this function is called 1000 times per second it will be hanged, slow. So i want limit the number of function call down to 500 times per second. how will i do with C/C++?
View 2 Replies View RelatedIn my platform, Windows 7 Ultimate 64 bits with Service Pack 1 over a x86-64 AMD microprocessor, AMD Phenom II 1090T X6, with a total of 4 GBytes of RAM memory), one C++ program can only allocate up to 2 GBytes of dynamic memory (using operator new, so Heap memory).
In am using the IDE Microsoft Visual C++ 2010 Express Edition to compile my C++ program and generate the executable file (for Win32).
In my system, there are much more available memory than 2 GBytes (yet remain 1 GByte of RAM memory and the virtual memory), so, Why can't my C++ program allocate more than 2 GBytes of memory? Do I need to configure something in the IDE to allow more memory to the program?
I was wondering how to limit error message to one only.
For example
cin.getline(stringname,7);
for(int i=0;i<size;i++){
if(strcmp(stringname, "hello")=0)
cout<<"Found!"<<endl;
else
cout<<"not found"<<endl;
}
not found
not found
.......
I want to get only once not found
I wrote this code, but now need to apply a limit to the recursive depth. This is the format that I have to use. How would I pass a limit so that it stops after a given number? I'm just confused about where to apply it.
int compute_edit_distance(char *string1, char *string2, int i, int j, int limit) {
if (strlen(string1) == i) return strlen(string2) - j;
if (strlen(string2) == j) return strlen(string1) - i;
if (string1[i] == string2[j]) return compute_edit_distance(string1, string2, i + 1, j + 1, limit);
[Code] .....
I have managed to make text dynamically appear in a text-box while I enter text into another.
how ever I would like to know to to limit the amount of text that is dynamically entered(I'd say about 10 characters at most).
here's a sample of what I have done so far:
Random r = new Random();
int IDrandom = r.Next(0, 9);
Emp_ID.Text += IDrandom.ToString();
//Emp_ID.MaxLength = 10; does not work
I calculate two numbers "R1",R2"
when i make
cout<<R1;
cout<<R2
i get
R1=51,9151
R2=51,915
when i make
Code: if (R1>R2) cout<<"i am here" he print the message
but they are equal. how i made limit the number of flottant to get equal numbers?
So I am have made this 2D ball game. But I want to set a time limit for each level. I want player to play that level for maximum 3 minutes. After 3 minutes the game level should end. I have used allegro 5.0.10 with c++ . How to achieve it?
View 2 Replies View Related