C/C++ :: Comparing Two Arrays For Same Elements

Feb 17, 2015

int result = 1;
for (int j=0;j<N;j++) {
bool found = false;
for (int i=0;i<N && !found;i++) {
if (a[j] == b[i]) found = true;
}
if (!found) return 0;
}

I need to create a code that compares two in arrays without sorting them. They have to be the same length and contain the same elements in any order.

every integer in a[] is also in b[]
every integer in b[] is also in a[]
all such common values appear exactly the same number of times in both a[] and b[]

EX: a = {1, 2, 3}, b = {2, 3, 4} return 0 a = {1, 2, 3}; b = {2, 3, 1} return 1 a = {1, 2, 2}; b = {2, 2, 1} return 1 a = {1, 2, 2}; b = {2, 1, 1} return 0 a = {1, 1, 2, 2, 2}; b = {2, 1, 2, 1, 2} return 1

This is all i have...

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C++ :: Comparing Arrays To Have Same Elements

Sep 2, 2014

If I have 2 arrays, say array1 = {2, 2, 4, 5, 6} which has sorted array elements and array2 = {4, 2, 6, 2, 5} that has same elements as array1 but not in sorted condition. How can I compare that both arrays have same elements. I have written the following code which works in all conditions except when array1 has two same elements and array2 has all different elements.

counter=0;
for (i=0; i<5; i++) {
for (int j=0; j<5; j++)
if (array2[i] == array1[j]) {
counter++;
array1[j]=0;

[Code] ....

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Sep 14, 2013

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[code].....

This is what I get back.

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Oct 30, 2014

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