Lets say for example I have a BST that is sorted by char names, using strcmp. IF greater than 0 go right else go left.
I.E (this is just an example, they are not inserted correctly)
cat
/
dog buffalo
/ /
fish mouse zebra snake
I wanted to make a copy of this BST IF the length of the nodes are greater than the root, how would I approach this? I kinda started on this but I'm not sure if I'm making this more difficult than it should be.
void BST::copygreater(node * root, node *& dest, int & holder) {
if(!root) {
dest = NULL;
return;
}
holder = strlen(root->name) + 1; //Don't know about this? If we do a recursive call then the value would change every call?
i have written a function that gives me the square root of a number. Yes i know there is already a function in <cmath> that gives square roots but i thought it would be pretty challenging (and therefore fun) to try writing one on my own. I wrote my code while i was in school, listening to my Irish teacher ramble on and on about useless shit, so it's probably not the best possible way of finding the square root of a number.
I got problem in binary tree code. below is my code. When i select pre, post or inorder, the .exe is not responding.. Since in my binary tree theres no roots yet.. who do i solve it? It need condition or what?
I'm trying to parse the root directory of FAT32 in order to get a dir list in the root folder.
So I need to go over all the directory entries in the root directory and parse them.
My problem is that I don't know when to stop the iteration - How to get the size of the root directory?
I noticed that there is a byte in the boot sector - the number of the entries in the root - but in FAT32 the value is always 0, So how can i get the size of the directory?
I am writing a program to find the square root of a number. I am using the Newton-Raphson method..Just to clarify a bit of the code.. fabs(1/(x+1)) < 0.001 is to check for relative error..
EXAMPLE: for user entry of 100 if the iteration process ends in 10.055 the answer will return as 10 which is correct. But it isn't doing that.
It compiles I then proceed to run it..prompts me "Enter a number to find the square root of: I type 100 then hit enter...
"The square root of 100 is -1077834936"
My first time writing a program from complete scratch.
And I know there is a sqrt() function...just wanted to write my own.
Code:
#include <stdio.h> #include <math.h> double mysqrt(double a); int main() { double a, result; printf("Enter a number to find the square root of: ");
I am trying to computed the time it takes for a projectile to hit the ground. The problem is that i need to square the input of velocity before i do the calculation. the question I have is that if it's possible to have multiple arguments inside the brackets after main.
#include <stdio.h> #include <math.h> double distance (double a, double v, double g); int square(int y); double height(double v, double a, double g); double time (double v, double a, double g); double sqrt(double num);
I want to find the root of an equation f(x) by using the secant method [URL] .....
#include <math.h> #include <iostream> using namespace std; //Define function f(x) double f(double x, double a, double b) { return sin((a*x)/(1+x*x))*atan(b*x)+atan(x);
[Code] ....
1) Do I have to keep the function f and RootFinderSMNew in different cpp files?
I got a mesh which has an edge with a specific transformation (translation + orientation). When this configuration / transformation is changed, its neighbours are to be updated. This structure is kept inside a tree so that when a root "frame" is passed to a method like UpdateHierachy, the mesh will recursively update itself.
If, I don't pass this method the root element, which is in my case, how do I change the rest of the structure? The reason to do this is because I want to say move the door, the windows and furniture will move along with it.
Add a square root function to the rational class. Have your program print the square root of any rational number. I want to find the square root for numerator and denominator separatetly. divide the answer to get decimals and convert the decimal to fractions. i got till geting the decimal but i want to convert it back to a simplified fraction
// finding greatest common factor int gcd(int a, int b) { if (b == 0) return a; else return gcd(b, a % b); }
I have an application which is used for calibration for electrical components. Here I want to set a rootpath for this application. I did some research and I found out that I can get the rootpath of the application (that is where the exe is stored) But what I am really looking for is once I start the application the root path should be what I assign. For instance currently the root path is "C:UsersPublicDocumentsABC.ToolsProjects" but I would like the root path to be "E:New ABC" Is this possible? I wrote some code where I call the exe of the application and it opens the file in a folder that I specify :
However, if one uses this code over and over, one quickly becomes tired of threading one's way all the way from root directory C:. There is undoubtedly some way to designate a starting directory. The most obvious candidate to set such a target is the:
Code: bi.pidlRoot = NULL;
But attempting to set bi.pidlRoot to a CString (directory address) errors because 'no suiitable conversion from CString to LPCITEMIDLIST exists'
How can I set the code to open at a designated address in the directory tree?
I'm working on a c program that generates approximations of square roots based on newton raphson method. I worked out the approximations with another method I learnt and I know this program does fine. But I don't get the concept of epsilon. Below is the code for the program
Code:
#include<stdio.h> // function to compute absolute value float absoluteValue(float x) { if(x < 0) x = -x;
[code]....
The text I worked this code from uses the epsilon value arbitrarily. how is the epsilon value selected? I tried using this formula to derive the square root of 45. On paper I can go as far as 6.8 something. But once this value is reached it's still bigger than epsilon, so shouldn't the code keep running? The program generates 1.41 for 2, but since it could go further why does the while loop in squareRoot function terminate?
I tried to check the rational or irrational numbers after we take the square root. i dont get the formula. for eg. squareroot of 64 is 8 and it is rational. square root of 2 is irrational. how to check it in c++..
I have tried writing a code which takes two numbers from the user and calculates their square root then the roots are added up to return the sum. The program is coming out with loads of errors.
#include<iostream> #include<cmath> float main(){ using namespace std; float m1,m2,m3,m4,m5;
I'm writing some functions pertaining to binary trees. I've used recursion once before while learning quicksort but am still quite new and unfamiliar with it. And this is my first time touching a binary tree. So my question: In my addnode function, will the return root statement at the end ever return a value other than the value passed to the function?
I'm a novice with C programming and i have to solve an error in the following code. The code works like you enter a password called "uoc" and it shows as OK. But surprisely when you entered another password as "Cambridge" it works fine too.
I think that the problem is in the array declaration but i'm checking resources and no success!
double x=1.00,y=2,z=4; if (y/z||++x) x+=y/z; printf("%f ",x); So (y/z||++x)
is true if at least one expression is true, that is either (y/z)!=0 or (++x)!=0 or both. I wonder how the comparison is done? Is (y/z) be truncated to integer or 0 be promoted to double?
I am trying to make a game where you have a secret code that is coded with colors like ROYG (red,orange,yellow,green) and I am having trouble when it tells you when you have a right color in the right spot or a right color in the wrong spot when you guess a color. How can I change my code under the function int comparearray where it will compare pointers to pointers and not integers and give me the correct number of "almost" and "correct".