This is the delete function of binary search tree. However it won't enter the if-else statement that checks whether the node to be deleted is the left child or right child.
void DeleteNode(node* T, int number) { node* x = new node; node* current = new node; node* dele = new node; node* finder = new node; finder = root;
Below is my implementation of a Binary Search Tree, but there is a bug in the DeleteNode() function. It does not set the parent's pointer to NULL as I intended.
How would I remove the largest node in a Binary Search tree?
function prototype: boolean remove_largest(node *& root) { }
I know that if there's no right child, then the root node has to be deleted. If there is a right child, then traverse that path for the largest node. But how to make this in to code that works?
I got problem in binary tree code. below is my code. When i select pre, post or inorder, the .exe is not responding.. Since in my binary tree theres no roots yet.. who do i solve it? It need condition or what?
how can a breadth-first-search-tree include every node have ancestor list. every node have multiple ancestor list(because every node may be multiple parents)
I am having trouble with my deleteNode function, using recursion I am trying to delete a node from a binary tree. My tree is displayed as the following...
Tree: (node)->[left child, right child] (k)->[g,p] (g)->[c,h] (c)->[ ,e]
[Code]....
The result did show that it is erased but when I try to add the erase node "t" back into the tree it still exist. I am stumped on what to do when using recursion way of deleting node.
It has been a while since I built a binary tree from scratch so I decided to do it. Everything works fine but this one function. When I enter a number to search it just keeps running and allowing me to keep enter numbers.
Code: void tree::search(int key,Node* leaf) { if (leaf == NULL) { std::cout<<"The tree is empty
I don't know why, but my remove function doesn't seem to operate properly. The rest of my code is fine, so I am trying to pinpoint the exact location of my error. The else if statement remove(root->left, data) should've been called twice, but it only called once.
BST* smallestNode(BST* root) // precondition: T is not null // postcondition: return the node in the subtree rooted at T that
Traversal of binary search tree. In my header file there is a function setTraversal (public) and private print file. As I understood from teacher's explanation, my setTraversal function should call the recursive print function and print the list depending on selected order (pre,in or post-order). I still cannot get my head around what should be in setTraversal function definition. All resources I read last two days explain each order separately (preorder, inorder, postorder). How can I combine them? Here is my code:
#include "NodeTypeBST.h" #include <iostream> enum TravType {PRE, IN, POST}; template<class T> class BST
I'm working on a programming homework that asks us to implement all the functions of a Binary Search Tree using templated classes. I'm almost done with it but I'm sort of stuck with the last part which is the `search` function. For this part the homework asks for the following requirements
Quote
Node<T>* search(T value, Node<T>* subtree)
if the current node's value is the one we're search for, return a pointer to itif the current node's left and right subtree's are empty (both m_left and m_right are looking at nullptr) then return the nullptr to indicate we didn't find the valueif the value is less than the current node's value, return the search of the left subtreeif the value is greater than or equal to the current node's value, return the search of the right subtreeMake sure to only traverse a subtree if it's not null
Standard example. I have a large text file and I wish to lex it into words. I tell the program that all words are delimited by ' ' ';' ':' and ''.
When I run the program it seems to be outputting the occurances of the letters and not the words. Im gobsmacked, I dont know what the hell is going on. Heres the function that lexes letters and not words. I want words dammit words!!
First youll see I define root node and point it to null; This forms the base of the BST. Then keep munching one character at a time until EOF reached. If the character is not a delimiter, assign it to "word" string, character by character. If it is a delimiter, take the so-far-constructed "word" and chuck it in the BST, then clear the word string through .clear().
The code above is supposed to be a binary search tree. The main outcome for this program is to display the tree in C each time the user inserts or deletes a value.
Since I am a newbie in C programming, I first tried creating a code that would simply display the values in the tree after a user inserts and deletes, before I proceed to displaying the exact tree.
But when I run it the following output shows:
And when I try to insert another value, It won't display anything and won't respond to any keys pressed.
I'm trying to create a template binary search tree and I'm getting all these vague errors that I have no clue how to solve. I've narrowed it down to my findMax and findMin functions but i can't figure it out any further than that.
template<class T> class BinarySearchTree{ private: struct BinaryNode{ T data; BinaryNode *left; BinaryNode *right;
[Code] .....
and here is are the errors I'm getting from this header file.
1>------ Build started: Project: Programming Assignment 2, Configuration: Debug Win32 ------ 1> main.cpp : error C2143: syntax error : missing ';' before '*' : error C4430: missing type specifier - int assumed. Note: C++ does not support default-int : error C2065: 'T' : undeclared identifier
I'm writing the function as described in the title but it isn't quite working. It works as long as the value passed is less than the parent (going left) but when the value should be placed to the right, it doesn't actually insert the node.
Im working on a BST remove function. I think I'm on the right track but I'm not sure. From what I understand there are 3 possible cases. A Node with no children, one child, or 2 children(this being the most complex).