C++ :: Finding The Root Of Equation Using Secant Method
Feb 8, 2014
I want to find the root of an equation f(x) by using the secant method [URL] .....
#include <math.h>
#include <iostream>
using namespace std;
//Define function f(x)
double f(double x, double a, double b) {
return sin((a*x)/(1+x*x))*atan(b*x)+atan(x);
[Code] ....
1) Do I have to keep the function f and RootFinderSMNew in different cpp files?
I've been trying for more than one month to access a method found in a library called libcocosnas_static.a. I'm using Cocos2d-X version 2.0.4. The library has been used many times by my company to make games using cocos2d-1.0.1-x-0.12.0 without any problem.
This is what I've done: 1- I added the include paths of the library to both eclipse and Android.mk 2- Included the .h file using #include "NASPlatformUtil.h" 3- Added the libcocosnas_static.a file to the proj.androidobjlocalarmeabi folder 4- Added "LOCAL_WHOLE_STATIC_LIBRARIES += cocosnas_static" to the Android.mk file 5- Called the function using: NASPlatformUtil:: openUrl("http://xxx.xxx.com/");
I can right click on the function, click Open Declaration and get it without any problem, but the compiler keeps on giving me that dreaded error...
how to take two variables with values such as a 1; and b 2;. Now you take cout << a + b; and you will get 3, but I want to somehow have a 1; b 2; and c num; then have a + b = c. So what ever I have the user input is for a and be added together will become the value of the c variable.
I have a question similar to the one here: [URL] .....
The main difference is I would like to pass a method of derived class as a parameter to some other method in its template base class.
template <typename BaseType> class Base { public: typedef void (Base::*Callback)(int A);
[Code] .....
The above is an example which does not compile. My compiler complains that the two BaseMethod() calls in DerivedMethod() are invalid uses of non-static member function.
Is this not possible to do, or is my syntax simply wrong? All I want is to be able to pass as an an argument to a method in the base class from the derived class some callback as a variable for the base class to invoke later.
Code: #include <math.h> #include <stdio.h> int main(void) { float a,b,c,root_1,root_2; printf("Please enter value a from the quadratic equation
[Code] ......
And I keep getting this error:
Code: /tmp/ccgtUIun.o: In function `main': assign345.c:(.text+0xc7): undefined reference to `sqrt' assign345.c:(.text+0xef): undefined reference to `sqrt' collect2: ld returned 1 exit status
I have a small project for school due today but i cant get my head around programming
Ive to create a program where ive to get the values from the user and add them to an equation. I have also to add a selection statement where it will ask for the material being tested which will have its value set in the program.
Write a program that creates the output shown in the Output Layout section below. The program should create 2 points with x and y coordinates as integers, prompt the user to input the x and y values for one of the points and randomly set the other (-99 to 99 range) and output the length of the radius line segment and the area of the circle that radius defines. The program should then end. Include an SDM for the program and any other appropriate documentation.
Special Calculations: Distance between 2 points equation: √((p0x – p1x)2 + (p0y – p1y)2) (This requires use of the math library)
Output Layout: (bold text represents user input)
Please enter the location of your first point. Enter a value from -99 to 99 for your x coordinate: -2 Enter a value from -99 to 99 for your y coordinate: 17
The location of your second randomly set point. Your x coordinate: 45 Your y coordinate: -89
The length of the radius line segment from point one to point two is 115. The area of the circle with a radius of 115 is 41546.33.
I am creating a program that solves the quadratic equation ax^2 + bx +c.
I have this program almost complete except the output of the equation in the function called display_quadratic. I need the program to display the variables a,b,c in the equation ax^2 + bx + c but I am having 2 problems. My first problem is that I cannot get the right addition and subtraction signs for the equation.
For instance, if the program had the values for a,b,c as 2,2,3
it will display 2x^2 2x 3
How can I get it to display 2x^2 + 2x + 3? or if it was negative like 2x^2 - 2x - 3?
My next question is how do I get to not display the coefficients that are 1?
I had an if-else statement but no matter what I created it would overlap with another statement and print out twice. Here is the code:
I am having trouble understanding how this loops would work. Give the function (x*x*x*x) - (10*x*x*x) + (35*x*x) - (50*x) + 24 Write a program that will use bisection method to find the roots of this function. Define lower limit and upper limit (e.g. -1.05 and 6.05) Starting at the lower limit step along the X axis at intervals of 0.1 for H calculating the function values f(x) and f(x +h), then f(x+h) and f(x+2h) until the upper limit is exceeded. If sign of the function value changes this indicates a root between ranges. Apply bi sectional method to this range until root has been found with an epsilon of 0.000001, then continue on until upper limit has been exceeded and all 4 roots found. If the function is within 0.000001 of zero then root has been found therefore no need for bi sectional method.
Code:
#include "stdafx.h" #include "math.h" #define H 0.1 #define epsilon 0.000001 double F(double x); int main(void)
[code]....
So we have a function and a range. Program requires to work along the X axis at 0.1 increments until it reaches a point where the value changes from positive to negative or negative to positive. Then apply bisection method within that range to a given accuracy then print that root. Then continue on X axis until the next change of sign is found.
This is my code for the quadratic equation. It keeps telling me that my else is illegal since no matching if statement and my else statement is missing a statement
#include <iostream> #include <cmath> #include <string> #include <iomanip> using namespace std; int main() { string Name;
I've written a program that finds the maximum of a function. I now want to change it a little so that instead of evaluating the function y=x^2-7x-18, the program will ask the user to input an equation and then evaluate that equation. I'm really not sure of how to do so.
#include <iostream> #include <cmath> #include <cstdlib> using namespace std; int main() { int a, b, delta, x, y; double max= -1.8 * pow(10, 308);
So, I successfully made a program that will perform the quadratic equation on three numbers, imaginary or real. however, i am now trying to simplify the result, as to get rid of the "/2a" on the bottom. Hence the simplify() function. I just started to create the simplification function, and am attempting to divide the imaginary part of the solution as well as the real part of the solution by 2a. Somehow, it gives the error, "error:invalid operands of types 'int' and 'double *' to binary 'operator*'" on lines 105 and 106. I suspect it has to do with the pointers and references that i am passing as parameters. Also, just an aside, I have never actually seen "/=" be used. It can be, right? I know "+=" can be.
#include <iostream> #include <string> #include <cmath> #include <cstdlib>//simplify the answer using namespace std; int count=0; //prototyping double ans_1(double,double,double);
i have written a function that gives me the square root of a number. Yes i know there is already a function in <cmath> that gives square roots but i thought it would be pretty challenging (and therefore fun) to try writing one on my own. I wrote my code while i was in school, listening to my Irish teacher ramble on and on about useless shit, so it's probably not the best possible way of finding the square root of a number.
Lets say for example I have a BST that is sorted by char names, using strcmp. IF greater than 0 go right else go left.
I.E (this is just an example, they are not inserted correctly)
cat / dog buffalo / / fish mouse zebra snake
I wanted to make a copy of this BST IF the length of the nodes are greater than the root, how would I approach this? I kinda started on this but I'm not sure if I'm making this more difficult than it should be.
void BST::copygreater(node * root, node *& dest, int & holder) { if(!root) { dest = NULL; return; }
holder = strlen(root->name) + 1; //Don't know about this? If we do a recursive call then the value would change every call?
I am using matlab R2o11 in which the programming medium is c++. I am having these variables=
T=373 t0 376 V=0.09 to 1 P=T/V
I just need a result showing ... First it should take T=373 and solve the equation using all volume values. Then it takes another temperature and do the same.
