I am having trouble understanding how this loops would work. Give the function (x*x*x*x) - (10*x*x*x) + (35*x*x) - (50*x) + 24 Write a program that will use bisection method to find the roots of this function. Define lower limit and upper limit (e.g. -1.05 and 6.05) Starting at the lower limit step along the X axis at intervals of 0.1 for H calculating the function values f(x) and f(x +h), then f(x+h) and f(x+2h) until the upper limit is exceeded. If sign of the function value changes this indicates a root between ranges. Apply bi sectional method to this range until root has been found with an epsilon of 0.000001, then continue on until upper limit has been exceeded and all 4 roots found. If the function is within 0.000001 of zero then root has been found therefore no need for bi sectional method.
Code:
#include "stdafx.h"
#include "math.h"
#define H 0.1
#define epsilon 0.000001
double F(double x);
int main(void)
[code]....
So we have a function and a range. Program requires to work along the X axis at 0.1 increments until it reaches a point where the value changes from positive to negative or negative to positive. Then apply bisection method within that range to a given accuracy then print that root. Then continue on X axis until the next change of sign is found.
I have been writing code to find the roots of a quartic (with coefficients input by the user) by the Newton Rapson method. The method fails if no real roots exist so I have been trying to implement an initial check to see whether the equation has real roots. I've been trying to use the intermediate value theorem but it only works for functions with a positive and negative tail. extend the bounds (fa and fb) to check over many ranges or any other mathematical method of better effect?
Atm I define fa<0<fb where fa=F(-10) and fb=F(10).
#include <stdio.h> #include <math.h> #include <conio.h> #include <stdlib.h> int a0, a1, a2, a3, a4; double F(double x) //Sets main function { return (a0+a1*x+a2*pow(x, 2)+a3*pow(x, 3)+a4*pow(x, 4));
I have tried writing a code which takes two numbers from the user and calculates their square root then the roots are added up to return the sum. The program is coming out with loads of errors.
#include<iostream> #include<cmath> float main(){ using namespace std; float m1,m2,m3,m4,m5;
how to take two variables with values such as a 1; and b 2;. Now you take cout << a + b; and you will get 3, but I want to somehow have a 1; b 2; and c num; then have a + b = c. So what ever I have the user input is for a and be added together will become the value of the c variable.
Code: #include <math.h> #include <stdio.h> int main(void) { float a,b,c,root_1,root_2; printf("Please enter value a from the quadratic equation
[Code] ......
And I keep getting this error:
Code: /tmp/ccgtUIun.o: In function `main': assign345.c:(.text+0xc7): undefined reference to `sqrt' assign345.c:(.text+0xef): undefined reference to `sqrt' collect2: ld returned 1 exit status
I have a small project for school due today but i cant get my head around programming
Ive to create a program where ive to get the values from the user and add them to an equation. I have also to add a selection statement where it will ask for the material being tested which will have its value set in the program.
Write a program that creates the output shown in the Output Layout section below. The program should create 2 points with x and y coordinates as integers, prompt the user to input the x and y values for one of the points and randomly set the other (-99 to 99 range) and output the length of the radius line segment and the area of the circle that radius defines. The program should then end. Include an SDM for the program and any other appropriate documentation.
Special Calculations: Distance between 2 points equation: √((p0x – p1x)2 + (p0y – p1y)2) (This requires use of the math library)
Output Layout: (bold text represents user input)
Please enter the location of your first point. Enter a value from -99 to 99 for your x coordinate: -2 Enter a value from -99 to 99 for your y coordinate: 17
The location of your second randomly set point. Your x coordinate: 45 Your y coordinate: -89
The length of the radius line segment from point one to point two is 115. The area of the circle with a radius of 115 is 41546.33.
I am creating a program that solves the quadratic equation ax^2 + bx +c.
I have this program almost complete except the output of the equation in the function called display_quadratic. I need the program to display the variables a,b,c in the equation ax^2 + bx + c but I am having 2 problems. My first problem is that I cannot get the right addition and subtraction signs for the equation.
For instance, if the program had the values for a,b,c as 2,2,3
it will display 2x^2 2x 3
How can I get it to display 2x^2 + 2x + 3? or if it was negative like 2x^2 - 2x - 3?
My next question is how do I get to not display the coefficients that are 1?
I had an if-else statement but no matter what I created it would overlap with another statement and print out twice. Here is the code:
This is my code for the quadratic equation. It keeps telling me that my else is illegal since no matching if statement and my else statement is missing a statement
#include <iostream> #include <cmath> #include <string> #include <iomanip> using namespace std; int main() { string Name;
I've written a program that finds the maximum of a function. I now want to change it a little so that instead of evaluating the function y=x^2-7x-18, the program will ask the user to input an equation and then evaluate that equation. I'm really not sure of how to do so.
#include <iostream> #include <cmath> #include <cstdlib> using namespace std; int main() { int a, b, delta, x, y; double max= -1.8 * pow(10, 308);
I want to find the root of an equation f(x) by using the secant method [URL] .....
#include <math.h> #include <iostream> using namespace std; //Define function f(x) double f(double x, double a, double b) { return sin((a*x)/(1+x*x))*atan(b*x)+atan(x);
[Code] ....
1) Do I have to keep the function f and RootFinderSMNew in different cpp files?
So, I successfully made a program that will perform the quadratic equation on three numbers, imaginary or real. however, i am now trying to simplify the result, as to get rid of the "/2a" on the bottom. Hence the simplify() function. I just started to create the simplification function, and am attempting to divide the imaginary part of the solution as well as the real part of the solution by 2a. Somehow, it gives the error, "error:invalid operands of types 'int' and 'double *' to binary 'operator*'" on lines 105 and 106. I suspect it has to do with the pointers and references that i am passing as parameters. Also, just an aside, I have never actually seen "/=" be used. It can be, right? I know "+=" can be.
#include <iostream> #include <string> #include <cmath> #include <cstdlib>//simplify the answer using namespace std; int count=0; //prototyping double ans_1(double,double,double);
I am using matlab R2o11 in which the programming medium is c++. I am having these variables=
T=373 t0 376 V=0.09 to 1 P=T/V
I just need a result showing ... First it should take T=373 and solve the equation using all volume values. Then it takes another temperature and do the same.
I need an equation that determines the lowest possible cost for laying power line.
The variables are as follows:
1. The width of a river 2. The distance a factory is downstream from a station on the other side of the river. 3. The cost for laying line underwater. 4. The cost for laying line on land.
All these variables will be user input each use of program.
I want to develop an application which can host multiple views of explorer (window), where as each window is totally separate from others. So that I can have multiple desktop views through my single explorer. Any built in feature in .NET ?
I've been working on a function that works like a pipeline of a shell but receives a directory, go over it an search for every file to send it to a filter, something like this in bash "cat dir/* | cmd_1 | cmd_2 | ... | cmd_N", The only problem i have with the code is the redirection of the pipe descriptors.
Code:
int main(int argc, char* argv[]){ char** cmd; int Number_cmd; cmd = &(argv[2]); /*list of cmds*/ Number_cmd = argc-2; /*number of cmds*/ }
[code]....
The code is seems to work fine except when i run it with more than one command in example ("./filter DIR wc rev") in this case it returns
wc: standard input: Bad file descriptor wc: -: Bad file descriptor 0 0 0
