C++ :: What Is The Maximum Range Of Integer Array For Initialization
May 22, 2014
i have tried like that int arr[1000000] to initialize but it crashed my programm.but if i do int arr[100000] it works fine..why is that and what is the maximum range of integer array initialization??
Any way to determine the highest value of an array I created with random numbers. I am confused because the array needs to be initialized in the main, but populated in a function. I was able to populate it using a pointer variable and my results came out good for the initial array values and elements.
In order to figure out the max, I think I would need the results of the populated array. How do I do this when the populated array is stored in a pointer variable? Would I need to create a pointer to the first pointer I created? I tried creating another pointer to the initial array and printing that, but my results were not good.
It doesn't make sense to me why this is working. The way my mind is thinking about this is that vertices is an array of type VertexPos, so then why can it be initialized with objects of type XMFLOAT3?
The following is something I am not clear about. Multi dimensional char arrays and the displaying of them.
Code: #include <iostream> using namespace std; main() { //char test[5][5]
[Code] .....
The commented out expression didn't run at all but the double quotation mark one did, unfortunately, it gives me a hexadecimal display. How can I get it to display like this:
I'm having trouble declaring and initializing a two-dimensional array using the C++11 standard conventions. I would like to know how to do it in C++11 style as know how to use the old style.
the exception im getting is:
c++11_array_exp.cpp:37:3: error: too many initializers for ‘std::array<std::array<std::basic_string<char>, 6ul>, 22ul>’
I am trying to assign the integer value to unsigned char array. But it is not storing the integer values. It prints the ascii values. Here the code snippet
The values which are stored in uc[] is ascii values.I need the integer values to be stored in uc[]. I tried to do it with sprintf. but the output is not as expected. if I print the uc[i] it should diplay the value as 0,1,2....99.
I was given some practice problems in my programming class, to prepare for the final and I don't quite understand what this one is asking for exactly:
Write the remainder of the program to find the maximum value for the middle row of the array data. Print the max after finding it. Your code should work for any 2D array of ints with three rows and four columns, so don't hard-code your program to these specific values.
How will you code a program that displays the maximum value in a two dimensional array of integers. the program will ask the user to input the 4x5 array?
i know how to code it. but i dont know what to do to find the maximum value. :( how to find the maximum?
Here's the code that returns maximum sum of a subsequence from a given array. This is according to "Programming Pearls" by Jon Bentley. I have come up with an example for which this program won't work. And here's that example:
{ -10, 11, 10, -10, 2, 3, -6, 1 }
Max subsequence sum above is 21. 2nd and 3rd elements.
But the program returns 16. It sums 2nd through 6th elements and returns. Why would the writer explain something with such depth, only to give a program that doesn't work in all instances?
int MaxSum(int lo, int hi, int* arr) { if (lo > hi) { return 0; } if (lo == hi)
I've been getting this expression of "subscript being out of range" for my program but i'm not sure how exactly. I'm fiddling around with code, i'm trying to make a two dimensional array of random numbers, here is my code, it compiles just fine:
I m concatenating specific range of digits that are same from an array "element" . I have problem with range. As in my case the range is col_elem[ii]=4, but it will continue reading the next element if it is the same. My code is:
Code:
int element[8]={0,1,3,3,3,0,1,2}; col_elem[ii]=4; for (rr=0; rr<col_elem[ii];rr++){ join_tmp[qq]=rr; while ((element[ii]== element[ii+1]) ) {
I want to make an array with a range of number from 1-9 only. So if the user entered more than or less than the number indicated it will be error and ask the user to reinput the data. So far my code can be used to do so that if the user enter the number one by one... But if the user entered all the number in one shot the reentered value will be prompt to the back automatically for some reason...Let say 10,2,3,4 which was suppose to be 1,2,3,4 became 2,3,4,1 instead... here is the code:
#include<stdio.h> void main() { int num[4][4]; int row,col,x,y; for(row=0;row<4;row++)
Actually i found some mistakes in my post. So here is the modified version. I want to concatenate the indexes of elements of array that has the same value for specific range.In my case the range is 4
Code:
int element[8]={2,2,0,3,3,0,1,2}; col=4; int rr; int qq=0; for (rr=0; rr<col;rr++){ join_tmp[qq]=rr; while ((element[rr]== element[rr+1]) ) { join_tmp[qq]= concatenate(rr+1, join_tmp[qq]); printf("%d ",join_tmp[qq]); rr++; } qq++; }
Code:
//FUNCTION TO CONCATENATE INTEGER VALUES OF SAME GROUP IN A COLUMN unsigned concatenate(unsigned x, unsigned y) { unsigned pow = 10; while(y >= pow) pow *= 10; return x * pow + y; }
Code: I want input like 10 2 3 Instead i get 10 2 34
how can i fix it so it will only iterate to the specific range?
How would i go about loading an array with random numbers with in a range. For example, loading an array of 500 elements with random numbers in the range of 50-100.
This is a test program that takes a number of arguments from the command prompt and concatenates them into a string object. I was looking into the possibility of using the range-based for loop for this purpose. Can it be done with pointer based arrays? I am mainly doing this because I want to have a firm understanding of range-based for, but also would like to do this with least amount of code possible.
This is my working program:
#include <string> #include <iostream> int main(int argc, char *argv[]) { if (argc > 1) { std::string concatenatedArgs;
[Code] ....
Can I somehow replace my while-loop with a range-based for? I tried the following but the compiler points out that begin and end were not declared in the scope of the range-based for loop.
#include <string> #include <iostream> int main(int argc, char *argv[]) { if (argc > 1) { std::string concatenatedArgs;
Write a program using user-defined function which accepts an integer array and its size as arguments and assign the elements into a two dimensional array of integers in the following format: If the array is 1,2,3,4,5,6, the resultant 2D array is
I am having problem in writing the code for the problem "To assign the elements of 1-D integer array into 2-D array of integers such as if the array is 1,2,3,4,5,6 The resultant 2-D array should be like :