I'm having trouble declaring and initializing a two-dimensional array using the C++11 standard conventions. I would like to know how to do it in C++11 style as know how to use the old style.
the exception im getting is:
c++11_array_exp.cpp:37:3: error: too many initializers for ‘std::array<std::array<std::basic_string<char>, 6ul>, 22ul>’
you can find my code here:
[URL]
How can I concatenate two 2-dimensional int arrays into one larger 3-dimensional array. This question is also valid for the 3-dimensional vectors. I know the command for the one dimensional vector as:
std::vector<int> results;
results.reserve(arr1.size() + arr2.size());
results.insert(results.end(), arr1.begin(), arr1.end());
results.insert(results.end(), arr2.begin(), arr2.end());
and for the one dimensional array as:
int * result = new int[size1 + size2];
copy(arr1, arr1 + size1, result);
copy(arr2, arr2 + size2, result + size1);
But I do not know how to make a 3-dimensional array or vector.
I had a hard question in my C++ final exam and I'm trying to solve it for the last 3 days. I haven't succeded yet! Here is the question: You have a one-dimensional array A[20]={1,2,3,4,...,20} and B[5][4] you have to assign the A array's elements to the B array but there is an order which is: B[5][4] = { { 12, 9, 11, 10 }, { 14, 7, 13, 8 }, { 16, 5, 15, 6 }, { 18, 3, 17, 4 }, { 20, 1, 19, 2 } } and there is a restriction: you can only use ONE for statement, nothing else!
#include <iostream>
#include <iomanip>
using namespace std;
int main(){
int A[20] = { 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15,
16, 17, 18, 19, 20 }; // define A array's elements.
int B[5][4] = { 0 }, k = 1; // define B array and k counter.
[code]....
I can't narrow the statements to one,This program works perfectly but it shouldn't be that long, we need ONLY ONE FOR statement, not two!
is it allowed to to like this:
char a[10] = "Lizard";
char b[2][5];
b[0][0] = a[0];
b[0][1] = a[1]; etc?
I have a 3D array that contains 200 strings. I'm trying to copy all these strings into a 2D array. How can this be done? This is what I have so far but it isn't working correctly.
Code:
for(int i = 0; i < row; i++) {
for (int j = 0; j < col; j++)
{
dest[i][j] = source[0][i][j];
} }
The finished product would be with 100 rows, 2 columns.
convert an one dimensional array into a two dimensional array and print like a matrix.
input: 34 50 2 4 90 33 7 80 9
output: A is a 3x3 matrix
34 50 2
4 90 33
7 80 9
Trying to get code to look like
Row 1: ^^^
Row 2: ^^^
Row 3: ^^^
const int siz = 3;
for (int t=0; t<siz;t++) {
cout << "Row" << t+1 << ":";
cout << endl;
[Code] ....
Also was wondering if i wanted to separately ask the user to choose a location to add a char who would i do that ?
( im thinking * cin << arry[][]; ? not sure but ask for them separately
array []1
array []2
= array [][]
In a book I'm reading, the author has the following struct:
struct VertexPos {
XMFLOAT3 pos;
};
Where XMFLOAT3 is a structure with x,y,z floating point values within. He declares and initializes an array as the following.
VertexPos vertices[] =
{
XMFLOAT3(0.5f, 0.5f, 0.5f),
XMFLOAT3(3.3f, 5.6f, 3.6f),
XMFLOAT3(-4.5f, 2.2f, 6.4f)
};
It doesn't make sense to me why this is working. The way my mind is thinking about this is that vertices is an array of type VertexPos, so then why can it be initialized with objects of type XMFLOAT3?
The following is something I am not clear about. Multi dimensional char arrays and the displaying of them.
Code:
#include <iostream>
using namespace std;
main() {
//char test[5][5]
[Code] .....
The commented out expression didn't run at all but the double quotation mark one did, unfortunately, it gives me a hexadecimal display. How can I get it to display like this:
*****
*****
*****
*****
*****
i'm currently working on a research project and i've been given some specifications
Is there a way i can access/use the array initialisation list i.e
{value,value,value}; .
For my own class? Like this
myclass foo={value,value,value};
How do you set all the entries in an array to 0 or a particular number...
View 3 Replies View Relatedi have tried like that int arr[1000000] to initialize but it crashed my programm.but if i do int arr[100000] it works fine..why is that and what is the maximum range of integer array initialization??
View 5 Replies View RelatedI have to initialize two arrays with values given alternately from console. But the array takes only the last entered values.
[URL] ....
#include <iostream>
using namespace std;
int main(){
int n,t,i;
cin>>n;
cin>>t;
int a[n];
for(i=0;i<n;i++)
[Code] ....
I would like to know the difference between the following two forms of array declaration:
(1)double myArray[3] = {1.0, 2.0, 3.0};
(2)array<double,3> myArray = {1.0, 2.0, 3.0};
If I say the second one allows to use different functions like .begin(), am I right? Is there any other difference between these two declaration?
I am attempting to write a program that converts binary to base10, and vice versa.
But in the function for converting Base10 to Binary, just as it reaches the line of code
int* binary = new int [a];
it skips straight to the int main()
All I'm attempting to do with that line of code is initialize the variable "a" into the elements of the array "binary".
[URL] ....
I want to understand the ways in which arrays can be declared and used. What each of the following do or what's the difference between them and what would be the length of each:-
1 - char ary1[50];
2 - char ary2[50] = {'H','e','l','l','o'};
3 - char ary3[50] = {'H','e','l','l','o',' '};
4 - char ary4[50] = {' '};
5 - char ary5[50] = {' ','H','e','l','l','o'};
6 - char ary6[50] = {' ','H','e','l','l','o',' '};
I have a little program that does some statistical processing on text files. The program has thrown a segmentation fault with an input file that is larger that I have used before. I didn't write this tool, so I went searching for the problem. Data from the input file is dumped into a 2D array and the program fails at the declaration of that array.
Code : double A[cont][Nr_col_split];
The vales for cont and Nr_col_split and determined from the input file and in this case, cont=807 and Nr_col_split=350. I assume that these values are just too large and not enough memory can be allocated, or something like that. Do I need to use reserve or similar to set aside enough memory? I will have input files that are quite a bit bigger than this one, so perhaps there needs to be a different solution for storing the input file data.
Write a program using user-defined function which accepts an integer array and its size as arguments and assign the elements into a two dimensional array of integers in the following format: If the array is 1,2,3,4,5,6, the resultant 2D array is
1 2 3 4 5 6
1 2 3 4 5 0
1 2 3 4 0 0
1 2 3 0 0 0
1 2 0 0 0 0
1 0 0 0 0 0
I was going through a code where i found the definition of int array[63] in one of the source files. But i also found the declaration as extern int array[66] in another source file. This is clearly wrong, but my doubt is how the compiler compiled it. It should have thrown error. In case if it compiles then what will be the behavior of the system? Will it be normal or some undefined behavior?
View 3 Replies View RelatedI have some files:
file1: 1000x500 array of numbers
file2: 2000x600
file3: 300x5000
...
I would like to automatically declare array variables of myarray1, myarray2, myarray3... that reads the numbers from files:
Code:
for (i1=0; i1<nrows; i1++)
{
for (i2=0; i2<ncolumns; i2++)
{
fscanf(filename, "%lf", &y);
myarrayX[i1][i2]=y;
}
}
nrows and ncolumns can be passed from a config file. Also I can cat all files into a single filename. However, the difficult part is:
How to declare different myarrayX automatically ? (A workaround is to declare a huge 3d array but I do not want to do this).
I am attempting to declare an array of pointers dynamically based on user input. I am not sure if A) I'm implementing the syntax of declaring a dynamic array correcntly and B) if my code is set up correctly to print otherwise.
int array_size;
cout << "Please enter the size of the array: " << endl;
cin >> array_size;
if(array_size >= 8) {
cout << "Invalid array size, please enter a valid integer size";
cin >> array_size;
[Code] .....
i am using c language to program PIC micro controllers, i am making a multi compilation unit project in order to organize my code better.
I want to create an array of functions and be able to call it from anyplace in the code
what i have done so far gplib.c
Code:
typedef void (*out)(int8);
void OUT_A(int8 weight){output_A(weight);}
void OUT_B(int8 weight){output_B(weight);}
void OUT_C(int8 weight){output_C(weight);}
void OUT_D(int8 weight){output_D(weight);}
void OUT_E(int8 weight){output_E(weight);}
out output_port[5+1] = {OUT_A, OUT_B, OUT_C, OUT_D, OUT_E};
how to declare them in gplib.h and how to call them anywhere in the code.
Here's my program: - Program which inputs a string from user, reverses it and displays it.
#include <iostream>
using namespace std;
void string_reverse (char [], const int);
int main() {
const int arraysize = 10;
char string[arraysize];
[Code] ....
In the string_reverse function, I have declared temp character type array but on line 38, the
compiler is throwing 3 errors: -
error C2057: expected constant expression
error C2466: cannot allocate an array of constant size 0
error C2133: 'temp' : unknown size
I have declared a constant integer arraysize in line 35. Now I have no clue why is this happening because I think as I have declared it as a constant integer variable, this should not happen.
I was able to get the max to work but I cant get the min. it returnning something like -125863456.
Code:
int maxx(int a[][10]);
int minn(int a[][10]);
int main(void){
int array[][10] = { { 2, 7, 6, 8, 4}, {3, 9, 1, 5, 6} };
int max1, min1;
[Code] .....
I want to make a program that asks the user for a message and then print out a large graphic of that message. For example, if the user types "he" I want to print out
H..................H EEEEEEEEE
H..................H E
H..................H E
H..................H E
HHHHHHHHHH EEEEEEEEE
H..................H E
H..................H E
H..................H E
H..................H EEEEEEEEE
(treat the periods as spaces. I only put them there because it wouldn't separate the H's correctly.)
I will loop this to continue until the user types quit.
1. How would I set this up to store the user input characters into an array?
2. How would I print out the stored data in the shape of the word?
Is it possible to create an 8 dimensional array in C? If no, then what can I do to improvise or let say bypass the limit?
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