C :: Concatenate Array Elements More Than Specified Range
Apr 19, 2013
I m concatenating specific range of digits that are same from an array "element" . I have problem with range. As in my case the range is col_elem[ii]=4, but it will continue reading the next element if it is the same. My code is:
Code:
int element[8]={0,1,3,3,3,0,1,2};
col_elem[ii]=4;
for (rr=0; rr<col_elem[ii];rr++){
join_tmp[qq]=rr;
while ((element[ii]== element[ii+1]) ) {
Actually i found some mistakes in my post. So here is the modified version. I want to concatenate the indexes of elements of array that has the same value for specific range.In my case the range is 4
Code:
int element[8]={2,2,0,3,3,0,1,2}; col=4; int rr; int qq=0; for (rr=0; rr<col;rr++){ join_tmp[qq]=rr; while ((element[rr]== element[rr+1]) ) { join_tmp[qq]= concatenate(rr+1, join_tmp[qq]); printf("%d ",join_tmp[qq]); rr++; } qq++; }
Code:
//FUNCTION TO CONCATENATE INTEGER VALUES OF SAME GROUP IN A COLUMN unsigned concatenate(unsigned x, unsigned y) { unsigned pow = 10; while(y >= pow) pow *= 10; return x * pow + y; }
Code: I want input like 10 2 3 Instead i get 10 2 34
how can i fix it so it will only iterate to the specific range?
I am trying to concatenate two words from a file together. ex: "joe" "bob" into "joe bob". I have provided my function(s) below. I am somehow obtaining the terminal readout below. I have initialized my memory (I have to use dynamic, dont suggest fixing that). I have set up my char arrays (I HAVE TO USE CHAR ARRAYS (c-style string) DONT SUGGEST STRINGS) I know this is a weird way to do this, but it is academic. I am currently stuck. My file will read in to my tempfName and templName and will concatenate correctly into my tempName, but I am unable to correctly get into my (*playerPtr).name.
/* this is my terminal readout joe bob <- nothing is put into (*playerPtr).name, why not? joe bob joe bob seg fault*/ /****************************************************************/ //This is here to show my struct/playerInit
How can I concatenate two 2-dimensional int arrays into one larger 3-dimensional array. This question is also valid for the 3-dimensional vectors. I know the command for the one dimensional vector as:
I've been getting this expression of "subscript being out of range" for my program but i'm not sure how exactly. I'm fiddling around with code, i'm trying to make a two dimensional array of random numbers, here is my code, it compiles just fine:
I want to make an array with a range of number from 1-9 only. So if the user entered more than or less than the number indicated it will be error and ask the user to reinput the data. So far my code can be used to do so that if the user enter the number one by one... But if the user entered all the number in one shot the reentered value will be prompt to the back automatically for some reason...Let say 10,2,3,4 which was suppose to be 1,2,3,4 became 2,3,4,1 instead... here is the code:
#include<stdio.h> void main() { int num[4][4]; int row,col,x,y; for(row=0;row<4;row++)
How would i go about loading an array with random numbers with in a range. For example, loading an array of 500 elements with random numbers in the range of 50-100.
i have tried like that int arr[1000000] to initialize but it crashed my programm.but if i do int arr[100000] it works fine..why is that and what is the maximum range of integer array initialization??
This is a test program that takes a number of arguments from the command prompt and concatenates them into a string object. I was looking into the possibility of using the range-based for loop for this purpose. Can it be done with pointer based arrays? I am mainly doing this because I want to have a firm understanding of range-based for, but also would like to do this with least amount of code possible.
This is my working program:
#include <string> #include <iostream> int main(int argc, char *argv[]) { if (argc > 1) { std::string concatenatedArgs;
[Code] ....
Can I somehow replace my while-loop with a range-based for? I tried the following but the compiler points out that begin and end were not declared in the scope of the range-based for loop.
#include <string> #include <iostream> int main(int argc, char *argv[]) { if (argc > 1) { std::string concatenatedArgs;
Write a program using user-defined function which accepts an integer array and its size as arguments and assign the elements into a two dimensional array of integers in the following format: If the array is 1,2,3,4,5,6, the resultant 2D array is
All structures are vector<char>. when i do the above my characters form Query and Subject are copied in my new vector called StrJoin but the size of that vector is twice the size then it should be.
How i can concatenate two integers into one integer. I have code that concatenate two integers but if the 2nd integer is zero it won't work. How can i modify it so that it can cater the case of y=0 too.
Code:
int concatenate(int x, int y) { int pow = 10; while(y >= pow) pow *= 10; return x * pow + y; }
The objective of the project is to become familiar with linked lists by writing a series of basic functions that allow us to manipulate a set of linked lists. I've completed all of the functions except for one.
The function I am stuck on is supposed to do the following:
concatenates list1 and list2 to form a new list, and returns a pointer to this new list;
Note: new list contains copies of all nodes in list1 and list2 */
I am having problem in writing the code for the problem "To assign the elements of 1-D integer array into 2-D array of integers such as if the array is 1,2,3,4,5,6 The resultant 2-D array should be like :
I have two std::string data items that contain binary data (so it may have the null character!). What is the proper way to concatenate them to preserve all of the data? I am guess a simple:
string string3 = string1 + string2;
Will not work, as it will terminate string3 on the first NULL character it encounters.
84484-37.96-Castor, Kathy 39050-69.68-Chandler, Ben 26183-70.84-Costello, Jerry
I have successfully read each element the id, grade and name into 3 separate array. Now i need to add a new student with an id and grade
How do i do this?
This is what I have.
int addStudent( int Iarray[], double dArray[], string sArray[], int newID, double newGrade, string newName, int size ) { char ready; int index; cout << endl; cout << "Enter new student ID number : ";
I have a question regarding the elements of an array. Suppose I have a 3 by 3 string array (char x[3][4] ) , and I initialize all the elements to x's , the array would then look like this :
xxx xxx xxx
I'm curious if there will be a value if I try to access and element outside the array. As I have to write a code to determine if I have reached the end of an array. The only way I can think of is to border the entire array with o's , making it look like this :
Write the definition of a function reverse , whose first parameter is an array of integers and whose second parameter is the number of elements in thearray . The function reverses the elements of the array . The function does not return a value .
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This is supposed to be the answer but I'm not quite sure why this is. I understand everything up until the actual loop. For one, shouldn't "int i" be declared outside the loop (I thought perhaps this was an error in the solutions)?
The main thing that I do not understand is the conditional statement.
Code: i<=num/2;
I don't understand why the "num/2" is necessary here. Also I can't really remember but is there a command that actually reverses an array?
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In my program, the function 'myreverse' is not getting invoked and the original array is being displayed as it is.
#include <iostream> using namespace std; void myreverse(int arr[],int n) { int *p=&arr[n-1]; int temp; for(int i=0;i<n;++i)
