How i can concatenate two integers into one integer. I have code that concatenate two integers but if the 2nd integer is zero it won't work. How can i modify it so that it can cater the case of y=0 too.
Code:
int concatenate(int x, int y) {
int pow = 10;
while(y >= pow)
pow *= 10;
return x * pow + y;
}
when i was finding a way to concatenate three integers in C, I came across a snippet like this
Code:
#include<stdio.h>
#define cat(a,b,c) a##b##c
int main()
{
int d;
d=cat(1,2,3);
return 0;
}
How the macro works here? I am unable to understand the function '#' plays in the macro.
Using a do-while loop, for loop, or while loop. This is what I have so far but i don't know what to do after that.
#include <iostream>
using namespace std;
int main() {
int num;
int min = 2;
int max = 256;
}
Also the results should be printed out with 10 integers per line, right justified in a 5 byte field.
So I have a simple calculator that does a few operations (+ - * / %) Pretty basic stuff
I declared int x, y for the numbers, char operation, and float result.
the code is based on switch(operation)
The program is running alright, but when I divide 8/7 it returns 1 as the result, I tried changing the x and y to float but that won't work because of the case '%'
I also tried making local float variables in the case'/' but it won't compile "E2126 Case bypasses initialization of a local variable"
How can I make the division work and return a float value?
Write a program that reads four integers from a file ‘input.txt’.
The program will then create a single integer number from the four integers. The output of the program will be the single number and single number + 600.
#include <iostream>
using namespace std;
int main () {
int number , a;
cout<<"enter en integer number";
cin>>number;
cout<<"add 600 to the number"
cin>>a=number+600;
return 0;
}
what I need is to get the first integer from a file and assign it to a variable and the others integers to an array. Example: Thats my file content 5 4 6 7 8 0 and that would be the code:
Code:
struct Array{
int n;
int *v;
}
[code]....
I got everything in this code running except for my remove function. What the project does is adds or removes an integer to a chain of integers created by the user. My add function works the first time but after that if I try to remove or add I believe it is pointing to the improper location and I don't know how to fix this....
Here is my code:
Header:
// adds "number" to the array pointed to by "arrayPtr" of "size".
// Note the size of the array is thus increased.
void addNumber(int *& arrayPtr, int number, int &size);
// removes a "number" from the "arrayPtr" of "size".
// if "number" is not there -- no action
[Code] .....
I am having problem in writing the code for the problem "To assign the elements of 1-D integer array into 2-D array of integers such as if the array is 1,2,3,4,5,6 The resultant 2-D array should be like :
1 0 0 0 0 0
1 2 0 0 0 0
1 2 3 0 0 0
1 2 3 4 0 0
1 2 3 4 5 0
1 2 3 4 5 6
"
I want to concatenate string+int so i make like that
Code:
for(int i=0;i<n;i++)
{
name="obstacle"+i;
cout<<name;
}
I get in the window
obstacle
obstacl
obstac
obsta
obst
...
..
o
but i want instruction that allow me to get
obstacle0
obstacle1
obstacle2
...
This seamed as a simple thing but i am getting something i did not expect: Example:
Code:
vector<char> StrJoin(SubjSeq.size()+ QuerySeq.size());
cout << StrJoin.size()<<"
"; // size x
StrJoin.insert( StrJoin.begin(), QuerySeq.begin(), QuerySeq.end() );
StrJoin.insert( StrJoin.begin(), SubjSeq.begin(), SubjSeq.end() );
cout << StrJoin.size()<<"
"; // x*2
All structures are vector<char>. when i do the above my characters form Query and Subject are copied in my new vector called StrJoin but the size of that vector is twice the size then it should be.
Trying to concatenate the 1st and 2nd element from an array of chars. Then this to be used as a hex value.
so for example
specs[0]='f'
specs[1]='4'
concatenate_value=0xf4
I m concatenating specific range of digits that are same from an array "element" . I have problem with range. As in my case the range is col_elem[ii]=4, but it will continue reading the next element if it is the same. My code is:
Code:
int element[8]={0,1,3,3,3,0,1,2};
col_elem[ii]=4;
for (rr=0; rr<col_elem[ii];rr++){
join_tmp[qq]=rr;
while ((element[ii]== element[ii+1]) ) {
[code]....
The objective of the project is to become familiar with linked lists by writing a series of basic functions that allow us to manipulate a set of linked lists. I've completed all of the functions except for one.
The function I am stuck on is supposed to do the following:
concatenates list1 and list2 to form a new list,
and returns a pointer to this new list;
Note: new list contains copies of all nodes in list1 and list2 */
I have a function that concatenate the strings in an array(2D)
Ex 1: Sean Connery Micheal King James Wood
Result: SeanConnery MichealKing JamesWood ...
The concatenation function working correctly and displays correctly in the function. But if I make another function to display it, it shows this
Ex 2: SeanConnery Sean MichealKing Micheal JamesWood James..
It adds to first name. Why?
Code:
void Concatenation( char dest[200][13] ) {
// loop through and concatenation the strings
for(int i=0;i<200;i+=2) {
myStrCat(dest[i],dest[i+1]); // mystrcat is equalto strcat()
[Code] .....
Actually i found some mistakes in my post. So here is the modified version. I want to concatenate the indexes of elements of array that has the same value for specific range.In my case the range is 4
Code:
int element[8]={2,2,0,3,3,0,1,2};
col=4;
int rr;
int qq=0;
for (rr=0; rr<col;rr++){
join_tmp[qq]=rr;
while ((element[rr]== element[rr+1]) ) {
join_tmp[qq]= concatenate(rr+1, join_tmp[qq]);
printf("%d
",join_tmp[qq]);
rr++;
}
qq++;
}
Code:
//FUNCTION TO CONCATENATE INTEGER VALUES OF SAME GROUP IN A COLUMN
unsigned concatenate(unsigned x, unsigned y) {
unsigned pow = 10;
while(y >= pow)
pow *= 10;
return x * pow + y;
}
Code: I want input like
10
2
3
Instead i get
10
2
34
how can i fix it so it will only iterate to the specific range?
I have two std::string data items that contain binary data (so it may have the null character!). What is the proper way to concatenate them to preserve all of the data? I am guess a simple:
string string3 = string1 + string2;
Will not work, as it will terminate string3 on the first NULL character it encounters.
I'm a beginner at c++ and I need to write a program that reads a set of integers and then finds and prints the sum of the even and odd integers. The program cannot tell the user how many integers to enter. I need to have separate totals for the even and odd numbers. what would I need to use so that I can read whatever number of values the user inputs and get the sum of even and odd?
View 2 Replies View RelatedI am trying to concatenate two words from a file together. ex: "joe" "bob" into "joe bob". I have provided my function(s) below. I am somehow obtaining the terminal readout below. I have initialized my memory (I have to use dynamic, dont suggest fixing that). I have set up my char arrays (I HAVE TO USE CHAR ARRAYS (c-style string) DONT SUGGEST STRINGS) I know this is a weird way to do this, but it is academic. I am currently stuck. My file will read in to my tempfName and templName and will concatenate correctly into my tempName, but I am unable to correctly get into my (*playerPtr).name.
/* this is my terminal readout
joe bob
<- nothing is put into (*playerPtr).name, why not?
joe bob joe bob
seg fault*/
/****************************************************************/
//This is here to show my struct/playerInit
[Code]....
How can I concatenate two 2-dimensional int arrays into one larger 3-dimensional array. This question is also valid for the 3-dimensional vectors. I know the command for the one dimensional vector as:
std::vector<int> results;
results.reserve(arr1.size() + arr2.size());
results.insert(results.end(), arr1.begin(), arr1.end());
results.insert(results.end(), arr2.begin(), arr2.end());
and for the one dimensional array as:
int * result = new int[size1 + size2];
copy(arr1, arr1 + size1, result);
copy(arr2, arr2 + size2, result + size1);
But I do not know how to make a 3-dimensional array or vector.
I am trying to assign the integer value to unsigned char array. But it is not storing the integer values. It prints the ascii values. Here the code snippet
Code: uchar uc[100];
for(i=0;i<100;i++)
{
uc[i] = i;
}
The values which are stored in uc[] is ascii values.I need the integer values to be stored in uc[]. I tried to do it with sprintf. but the output is not as expected. if I print the uc[i] it should diplay the value as 0,1,2....99.
changing a 9 digit integer into a new 9 digit integer through simple mathematical operations. For example, I need to change 123456789 into the new digit 456123789. Sometimes I need to change a 9 digit integer into an 8 digit integer. An example is 789062456 into 62789456. I can ONLY use simple mathematical operations (addition, subtraction, multiplication, division and modulo).
View 4 Replies View RelatedComplete the function myitohex so that its converts 8-byte integer to string based hexadecimals.
Ex: printf("0x%s",myitohex(64,hex)); should printout "0x40" on the screen
char *myitohex(uint8_t i, char *result){
???
return result;
}
I wrote:
#include <stdio.h>
#include <stdint.h>
char *myitohex(uint8_t i, char *result){
*result = i + '0';
[Code] ....
0xp gets printed out which is wrong. I think *result = i + '0'; is wrong. What changes should i do on this row ?
Write a program, sumit.c, that reads an integer value n from the user and then sums the integers between 0 and n. Your program should be able to handle both positive and negative values of n and should write the sum to the output file sumitout.txt. Note that your sum should not actually include 0, since that doesn't affect the sum. Your program should open the file sumitout.txt for appending so that the file can record a series of runs.
For marking purposes run your program twice with values n = −10 and n = 5.
Here is a sample run:
Enter n: -4 The sum of integers from -1 to -4 is -1
#include<stdio.h>
int main(void) {
//declare your variables
int n, i, term, total = 0;
//promt user to enter and read a value of n
printf("Enter n: ");
scanf("%d", &n);
//calculate the sum
[Code] ....
i am relatively new to C programming so i run into problems on daily basis. But this time i have something i just cant figuer out and i was hoping you could point me towards the right track. I am trying to divide two integers.DevValue by KpTotal. for some reason my micro controller allways crashes.Y is a variable of a distance measuring sensor. i have a 4x4 keypad to enter a three digit number (e.i 123) so Kp1 = 1 Kp2 = 2 Kp3 =3.
Code:
int kp1, kp2, kp3, kpTotal = 0;
char txt[6] = ""
int keypadPort at PORTD;
sbit LCD_RS at RB4_bit;
sbit LCD_EN at RB5_bit;
}
[code]....
i think it has something to do with the format of the value. i read that the micro controller crash when dividing by zero.
How to write a simple function that will take 3 ints and find the sum of the higher 2? This is what i got so far:
int findsum(int a,int b,int c)// will find the highest int and return it to our main program {
int max,max2;// this sets our local variable max
// next we will find the larger of our first 2 variables
if( a>=b)
{ max=a;
[Code] ....
How to get the second highest number and add it to max
I am working on an assignment where I have to subtract two very large integers. How can I write it's code provided that I have both numbers in a character array with each index holding a fraction of the original number. Like if I have a number 123456789 in an array then
arr[0]='1';
arr[1]='2';
arr[2]='3';
arr[3]='4';
and so on. n
nNw if i have to subtract this number from an other number, how can I do that?