I am working on an assignment where I have to subtract two very large integers. How can I write it's code provided that I have both numbers in a character array with each index holding a fraction of the original number. Like if I have a number 123456789 in an array then
arr[0]='1';
arr[1]='2';
arr[2]='3';
arr[3]='4';
and so on. n
nNw if i have to subtract this number from an other number, how can I do that?
1.What would regex pattern look like for addition of integers?
2.What would regex pattern look like for subtraction of complex numbers?
I am looking for simple code that subtract two time interval. I have time t1=5hour 30 minute and other time in 24 hour format. This code i written but it not working as expected
main() {
intTime1;
intTime2;
int hour=10;
int minute=5;
int second=13;
int h;int m;
[Code] ....
Is there any easy way of doing above code. Above two code section not working....
I'm working on a matrix class and I've hit a few snags. Here's what I've got so far:
Matrix.h
#include <iostream>
#include <conio.h>
using namespace std;
class Matrix {
private:
int matrix[50][50];
[Code] ....
Where I have questions is in implementing the addition and subtraction bits into the class itself. I understand that I'm going to have to do a copy operation (this from reading in C++ Primer Plus 5th Edition). Right now I'm just after adding/subtracting as the rest will be variations on the same theme.
So, here it goes:
As I understand the problem, I need to pass my two matrices as arguments to an addition function. This is going to involve having to copy the values of the two existing matrices into temporary matrices within the addition function, then I'll add them, and store them in a new matrix which will be my return value. So...something like this:
int Matrix::matrixAdd(int R, int C, const Matrix & matrix1, const Matrix & matrix2) {
int sum;
Matrix matrix;
for (int i = 0; i < R; i++)
[Code] ....
I do end up with errors there...C2240, and C2662. Again, I'm new to working through this, but that's what I've got. My idea is that I'm passing the maximum size of the array as defined by the user, in this case a 2x2 array, it'll cycle through and add up to that imposed limit...I went 2x2 because it's small enough that testing doesn't drive me up a wall.
On a controlled buffer of unsigned char it is possible to do subtraction faster than if you followed standard mathematical rules, here is an example:
typedef unsigned char uchr;
uchr num1 = 5; //00000101
uchr num2 = 3; //00000011
num2 = ~num2; // 11111100
++num2; // 11111101
uchr num3 = num1 + num2; // 00000010(2) - computer truncates result to fit char
Since you will be working with a buffer you don't even need to worry about truncating the final bit because the add function will not be able to reach it - unless it is given the ability to grow the buffer in which case you just set the bit to 0 yourself
I'm writing an addition and subtraction calculator that takes input as: 5+6-3+2. You should be able to add or sub as many numbers as you want. I want the while loop to stop when the user hits enter. I put the getchar() function to catch the and break the loop but it is also swallowing the '-' sign, which I want to use to subtract and is instead adding the numbers with "sum+=number". How can I get around that?
Code:
#include <stdio.h>
int main(int argc, char *argv[]){
int number, sum = 0;
[Code]....
trying to understand operator overloading, and i wrote some code just to define a "-" operator to do a simple subtraction. SO, i wrote a program that can perform a subtraction between two objects and put the result in the third object. now I Just cant show the result on the console. And also can anyone define the meaning of [b1.x], like I want to know am I assigning the value to the "b1"object or the x variable? This is a very concept that I need to understand.
#include<iostream>
using namespace std;
struct Ok
{
int x;
int y;
};
Ok operator-(const Ok& a , const Ok& b)
{
Ok result;
result = (a - b);
return result;
}
int main()
[Code]...
I need to create a binary calculator that outputs the operation of subtraction whenever you input 2 4 bit binary numbers. For example:
If I enter
1000
- 0111
I have a templated container that defines a forward iterator.
Calling std::distance on these iterators will generate code that will count the number of iterations it takes to get from the first parameter to the second, by repetitively incrementing.
Internally, the iterators can easily find the distance by a simple subtraction.
What I want to do is overload std::distance for these iterators so that it will take advantage of the simple calculation rather than repetitive increments.
The simple solution of course would be to make the iterators random access, but this would require that they support functionality that is not 'logical' for the container. Access to the container only makes logical sense when iterating one item at a time in the forward direction.
Code:
#include <iterator>
template <typename T>
class Container {
public:
class iterator : public std::iterator<std::forward_iterator_tag, T> {
[Code] .....
Below is a program that generates random Addition for Subtraction problems depending on the user's choice. The user is prompted to input an answer and then it keeps your score. If you want to quit you just press zero.
Code:
#include <iostream>
#include <stdio.h>
#include <stdlib.h>
#include <time.h>
#include <iomanip>
#include <string>
using namespace std;
int menu();
bool addition(int &reward); // function to return truth values
[Code] ....
I'm a beginner at c++ and I need to write a program that reads a set of integers and then finds and prints the sum of the even and odd integers. The program cannot tell the user how many integers to enter. I need to have separate totals for the even and odd numbers. what would I need to use so that I can read whatever number of values the user inputs and get the sum of even and odd?
View 2 Replies View RelatedWrite a program, sumit.c, that reads an integer value n from the user and then sums the integers between 0 and n. Your program should be able to handle both positive and negative values of n and should write the sum to the output file sumitout.txt. Note that your sum should not actually include 0, since that doesn't affect the sum. Your program should open the file sumitout.txt for appending so that the file can record a series of runs.
For marking purposes run your program twice with values n = −10 and n = 5.
Here is a sample run:
Enter n: -4 The sum of integers from -1 to -4 is -1
#include<stdio.h>
int main(void) {
//declare your variables
int n, i, term, total = 0;
//promt user to enter and read a value of n
printf("Enter n: ");
scanf("%d", &n);
//calculate the sum
[Code] ....
i am relatively new to C programming so i run into problems on daily basis. But this time i have something i just cant figuer out and i was hoping you could point me towards the right track. I am trying to divide two integers.DevValue by KpTotal. for some reason my micro controller allways crashes.Y is a variable of a distance measuring sensor. i have a 4x4 keypad to enter a three digit number (e.i 123) so Kp1 = 1 Kp2 = 2 Kp3 =3.
Code:
int kp1, kp2, kp3, kpTotal = 0;
char txt[6] = ""
int keypadPort at PORTD;
sbit LCD_RS at RB4_bit;
sbit LCD_EN at RB5_bit;
}
[code]....
i think it has something to do with the format of the value. i read that the micro controller crash when dividing by zero.
How to write a simple function that will take 3 ints and find the sum of the higher 2? This is what i got so far:
int findsum(int a,int b,int c)// will find the highest int and return it to our main program {
int max,max2;// this sets our local variable max
// next we will find the larger of our first 2 variables
if( a>=b)
{ max=a;
[Code] ....
How to get the second highest number and add it to max
Code:
#include <iostream>
#include <string>
using namespace std;
int main()
[Code] ......
How do I link the strings to the integers?
I'm trying to make a C++ program that generate 6 random numbers ( from 100,000 to 999,999 ), okay, so I wrote a few lines..
Code:
srand(time(0));
for (int i = 0; i < 5; i++)
{
std::cout << 100000 + (rand() % 999999) << std::endl;
}
The problem is, that it generates numbers like this:
117,207
123,303
131,083
... etc etc..
They're all starts with 100K, i want them to be an actual random..
I am doing a program and i need to read integers that are in a string and i dont know if i am doing it correctly.
Code:
unsigned int j=0, h1;
char num[100] , str1[100], str2[100], a[100], b[100];
sscanf(str1, "%[^;] ; %[^;] ; %d ", a, b, &h1); the string is : "0048915433190;24/10/2013;13h 7m 47s;13h 8m 59s;0;1;"
And what i want to read with sscanf is the hours, minutes and seconds.
I am trying to create a program that reads my file filled with random words, it then compares the words after they are put into a 2d array and sees if there is any matching words.. unfortunately the count is not working for me (in function2 and function3) and I am not sure why..
Code:
#include<stdio.h>
#include<string.h>
char function1(char words_array[][17]);
int function2(char words_array[][17]);
void function3(int pairs, char words_array[][17]);
int main( void )
{ char words_array[20][17];
int x = 0;
[Code]...
How i can concatenate two integers into one integer. I have code that concatenate two integers but if the 2nd integer is zero it won't work. How can i modify it so that it can cater the case of y=0 too.
Code:
int concatenate(int x, int y) {
int pow = 10;
while(y >= pow)
pow *= 10;
return x * pow + y;
}
I compiled a simple program using a function to add two integers, in order to understand the difference of calling by value vs by reference.
Code:
#include <stdio.h>
int add(int a, int b, int sum);
int main()
{
int a, b, sum;
printf("Please enter two integers
");
scanf("%d%d", &a, &b);
[Code]...
I used these two (one, two) pages I found in the net while studying the subject. So here are my questions...
(a) Do I understand correctly that in the above code all a, b and sum are passed by value?
(b) If I wanted only sum to be passed by reference, how the above code would change?
(c) If I wanted all (a, b, sum) to be passed by reference, how the above code would change?
"Write a program that prompts the user for an integer number from the keyboard, and store it in a variable num. After each number is typed in, add num to a total.
Do this six times, each time adding num to a total. (Be sure to reuse the same variable named num for each of the six numbers entered.) When all six numbers have been entered from the keyboard, calculate an average. Display the total and average calculated. "
Here is what I have so far:
Code:
#include<stdio.h>
int main() {
int num, total1, total2, total3, total4, total5, total6, avg;
printf("Enter first number:");
scanf("%2d",&num);
[Code] .....
from k&r book (4.2 - functions retuning non integers)
(doesnt compile - 1 error)
Code:
#include <stdio.h>
#define MAXLINE 100
/* rudimentary calculator */
main()
{
double sum, atof(char []);
char line[MAXLINE];
int getline(char line[], int max);
sum = 0;
while (getline(line, MAXLINE) > 0)
printf(" %g
", sum += atof(line));
return 0;
}
Code:
int getline(char line[], int max); is no different from:
Code:
getline(char line[], int max); ?
so, the int (return type) is optional when using a function. i assume return type is casted double? why the (char [])? just weird cuz i never seen it before
I am trying to make a game where you have a secret code that is coded with colors like ROYG (red,orange,yellow,green) and I am having trouble when it tells you when you have a right color in the right spot or a right color in the wrong spot when you guess a color. How can I change my code under the function int comparearray where it will compare pointers to pointers and not integers and give me the correct number of "almost" and "correct".
Code:
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#define ROWS 100
#define COLS 4
}
[code]....
How do I do the operation of two integers that gives you the results?
I'm supposed to write a program that:
Asks the user for an integer
Asks the user for one of '+', '-', '*', or '/' (as a character)
Asks the user for another integer
Performs the given operation on the two integers, and prints out the result of
Please enter an integer: 4
Please enter an operation (+, - , *, /): *
Please enter another integer: 5
4 * 5 = 20
Code:
#include <iostream>
using namespace std;
int main() {
int x;
int c;
int d;
char e;
[Code] ....
I have a file where the first column shows letters, second column shows numbers.
How could I make it to print everything exactly how it is in the file – a vector/array with strings and integers?
I took a month's break from programming, and got rusty. Here's the problem:
The character 'b' is char('a'+1), 'c' is char('a'+2), etc. Use a loop to write out a table of characters with their corresponding integer values:
a (tab) 97
b (tab) 98
...
z (tab) 122
