C# :: Regex For Addition Of Integers And Subtraction Of Complex Numbers
Jan 12, 20151.What would regex pattern look like for addition of integers?
2.What would regex pattern look like for subtraction of complex numbers?
1.What would regex pattern look like for addition of integers?
2.What would regex pattern look like for subtraction of complex numbers?
Below is a code that is used to calculate complex numbers (a+bi, where i = sqroot (-1)) through multiplication and addition.
However, on my output file, no Header is being printed; the only thing that is being printed is "8 + 7i + = "
"complex.h" is included at the end of the code.
Code:
// Trey Brumley// CMPS
// Dr. Tina Johnson
// March 1, 2013
// Program 2: Classes
// This program will demonstrate the use of classes by using a custom "complex-number" (a+bi) class.
[Code] ......
I'm working on a matrix class and I've hit a few snags. Here's what I've got so far:
Matrix.h
#include <iostream>
#include <conio.h>
using namespace std;
class Matrix {
private:
int matrix[50][50];
[Code] ....
Where I have questions is in implementing the addition and subtraction bits into the class itself. I understand that I'm going to have to do a copy operation (this from reading in C++ Primer Plus 5th Edition). Right now I'm just after adding/subtracting as the rest will be variations on the same theme.
So, here it goes:
As I understand the problem, I need to pass my two matrices as arguments to an addition function. This is going to involve having to copy the values of the two existing matrices into temporary matrices within the addition function, then I'll add them, and store them in a new matrix which will be my return value. So...something like this:
int Matrix::matrixAdd(int R, int C, const Matrix & matrix1, const Matrix & matrix2) {
int sum;
Matrix matrix;
for (int i = 0; i < R; i++)
[Code] ....
I do end up with errors there...C2240, and C2662. Again, I'm new to working through this, but that's what I've got. My idea is that I'm passing the maximum size of the array as defined by the user, in this case a 2x2 array, it'll cycle through and add up to that imposed limit...I went 2x2 because it's small enough that testing doesn't drive me up a wall.
I'm writing an addition and subtraction calculator that takes input as: 5+6-3+2. You should be able to add or sub as many numbers as you want. I want the while loop to stop when the user hits enter. I put the getchar() function to catch the and break the loop but it is also swallowing the '-' sign, which I want to use to subtract and is instead adding the numbers with "sum+=number". How can I get around that?
Code:
#include <stdio.h>
int main(int argc, char *argv[]){
int number, sum = 0;
[Code]....
Below is a program that generates random Addition for Subtraction problems depending on the user's choice. The user is prompted to input an answer and then it keeps your score. If you want to quit you just press zero.
Code:
#include <iostream>
#include <stdio.h>
#include <stdlib.h>
#include <time.h>
#include <iomanip>
#include <string>
using namespace std;
int menu();
bool addition(int &reward); // function to return truth values
[Code] ....
I am working on an assignment where I have to subtract two very large integers. How can I write it's code provided that I have both numbers in a character array with each index holding a fraction of the original number. Like if I have a number 123456789 in an array then
arr[0]='1';
arr[1]='2';
arr[2]='3';
arr[3]='4';
and so on. n
nNw if i have to subtract this number from an other number, how can I do that?
I am trying to write a class that can multiply complex numbers but without overloading operators
View 1 Replies View RelatedHow exactly did u accept it as a string? i mean did u use ascii values or anything? and what was your code for keeping track of carry?
View 1 Replies View RelatedI have a program written to add 2 complex numbers. Everything is working, except when the sum gets written, it gives me a number that is way off.
#include <iostream>
#include <complex>
#include <fstream>
#include <cstdlib>
#include <math.h>
class complex {
public:
complex();
complex(double r, double i){
[Code] .....
And my output ends up being Enter a complex number (a+bi) :
1+2i
Enter a complex number (a+bi) :
2+3i
x 1+2i
y 2+3i
4.8784e-270+4.85593e-270i
I have to write a code in which the addition of prime number gives the number user input..
for example if user enters 10 then
7+3 = 10
2+3+5 = 10
I created an algorithm that uses imaginary numbers. It is fine on Dev C++, and now I am trying to port to VS2008. I figured out most things, including how to declare complex numbers. However, I've been having an incredible hard time trying to figure how to use the " i " number! For example:
In Dev C++:
Code:
z_cmplx = cexp(I * f1/Fs * 2 * PI);
Where "I" is a macro from the library!
In VS2008:
Code:
z_cmplx = std::exp(I * f1/Fs * 2 * PI);
Although I DID include <complex> library just like I did before, the compiler gives me: error C2065: 'I' : undeclared identifier.
I'm trying to make a C++ program that generate 6 random numbers ( from 100,000 to 999,999 ), okay, so I wrote a few lines..
Code:
srand(time(0));
for (int i = 0; i < 5; i++)
{
std::cout << 100000 + (rand() % 999999) << std::endl;
}
The problem is, that it generates numbers like this:
117,207
123,303
131,083
... etc etc..
They're all starts with 100K, i want them to be an actual random..
I am working on a program where the person enters their name and their gross pay. I had to validate that the gross was a number and contained no letters.
I also have to validate the persons name to see if it contains any numbers. The book I am using has an example with only an if statement that says if it is correct or incorrect. I was trying to use <cctype> and toalpha
I just was wondering if there was a way to put it into a while loop or how i would have it ask the user to input their name again. When i tried it just blew up.
Also in the book they use const int SIZE= 8, but I don't want to put a size on the name if I don't have to.
I am trying to find a way to do something like this:
input: 3 4 7 4 3 3 7
output: 3 4 7
So what I am trying to do is from an array of integers to take numbers that occur only once. If 3 is in that away I am trying to input it in a different array only once.
input: 8 3 2 9 8 9 2
output: 2 3 8 9
I cannot find a way to solve this, and I have been trying to solve it for a long time.
Let's say that in a txt file named hot.txt, I have this:
12,23,32
And with ifstream I want to take those number, adding one by one as integers in a linked list.
ifstream myList;
char* p= new char;
cin>>p;
myList.open(p);
if(myList.is_open()) {
char* x =new char;
[Code] ....
I know this part is quite wrong :
myList.get(x,256,','); // dafaq
int num=atoi(x);
list->addOrdered(num);
What I wanted to do is to stop before each comma and take that character and store it in the linked list and continue until the end of the file, but I couldnt.
Here`s the text:
You have to expect the following input : an arbitrary amount of lines, each line consists of 5 int32 numbers. The full input will be terminated by an EOF.
E.g.:
1 2 3 4 5
6 7 8 9 0
...
You`re then supposed to convert the numbers to integers and do some calculations. I would know how to parse a single line of 5 numbers via scanf(). That`s easy, and that`s exactly what they did in class.
But how do i go about splitting the lines? What about the EOF? Even if could hack something together, by using errno or something, it would be way beyond what they are doing atm. The input is received via user input, ie stdin.
I know strings are essentially just arrays of characters, so what would be the easiest way to take each individual digit and put it into a separate space in an array?
ex.) *str = "90210"
array[0] = 9
array[1] = 0
array[2] = 2
array[3] = 1
array[4] = 0
All my attempts at achieving this just result in an array full of garbage numbers. What I've done is
Code:
int *array;
array = malloc(sizeof(int)*(strlen(str));
for(i=0; i<strlen(str); i++) {
array[i] = str[i]
}
also, I should mention that the string will be defined in main, and its converted into an array in a separate function.
Write a function that raises an integer to a positive integer power. Call the function x_to_the_n taking two integer arguments x and n. Have the function return a long int, which represents the results of calculating x^n.Here's my code:
Code:
#include <stdio.h>
long int x_to_the_n(int x, int n)
{
int i;
long int acc = 1;
for(i = 1; i <= n; ++i)
acc *= x;
}
[code]...
It compiles OK, but when I run it the program stops after entering the number (x) and power (n).
In my program, I am fed a string that contains integers such as Code: *str = "45678" and my program is simply supposed to read the number in and store each given number in a separate spot in an integer array. So basically, when my program has finished running it should be stored like:
Code:
arr[0] = 4
arr[1] = 5
arr[2] = 6
arr[3] = 7
arr[4] = 8
The way I have been attempting to do this was just copying it to the array like so:
Code:
arr = malloc(sizeof(int) *(strlen(str));
for (i=0; i<strlen(str); i++) {
a->digits[i] = str[i];
}
however, this just seems to return an impossibly high garbage value when I do. I'm assuming the way I'm trying to store it is 'illegal', but I cant seem to find online a proper way to do it.
I am trying to Write a program that inputs three integers from the keyboard and prints the sum, average, product, smallest and largest of these numbers. How do i go about it. What i dont know is how to come up with smallest and largest number .
View 1 Replies View RelatedI want to write a program to read in 15 integers from the user, and then store them in a 5x3 array, and print out the numbers as a 3x5 array.
View 7 Replies View RelatedI tried to sort a large numbers of vector of random integers with std::sort(), but when the number increases over 10M, std::sort returns all zero in values. Does std::sort have a limitation of input numbers?
View 1 Replies View Relatedcreate a program that asks the user to input 10 integers of an array the program will add the numbers greater or equal to 10.
View 6 Replies View Relatedso basically my project goes like this:
Write a C++ program that reads in two positive integers that are 20 or fewer digits in length and outputs the sum of the two numbers.
Your program will read the digits as values of type char so that the number 1234 is read as four characters '1', '2', '3' and '4'. After they are read into the program, the characters are changed to values of type int. The digits will be read into a partially filled array and you might find it useful to reverse the order of the elements in the array after array is filled with data from the keyboard.
Your program will perform the addition by implementing the usual pencil and paper addition algorithm. The result of the addition is stored in an array of size 20 and the result is written to screen. if the result of the addition is an integer with more than maximum number of digits(that is more than 20 digits) then your program should issue a message saying that it has encountered "integer overflow".
You should be able to change the maximum length of the integers by changing only one globally defined constant. Include the loop that allows the user to continue to do more additions until the user says the program should end. What I have so far is
#include <iostream>
#include <cstdlib>
using namespace std;
void reverseArr(int a[], int liu);
void addLargeInt(int a1[], int liu1, int a2[], int liu2, int sum[], int& liu_sum);
int main() {
cin.get(next);
[Code]...
My C programming class wants us to write a program to read integers into an array, sort the numbers and print out the occurrence of each number. I've tried everything that I can think of but the core dump is still occurring.
void countValues ( FILE *inf, int list[], int size ); /* Function prototypes. */
void printFrequencies( const int list[], int size );
int main (void) {
int status = EXIT_SUCCESS; /* defaulting status to success. */
FILE *inf = fopen( "numbers.txt", "r" ); /* input data file */
[Code] .....
I am looking for simple code that subtract two time interval. I have time t1=5hour 30 minute and other time in 24 hour format. This code i written but it not working as expected
main() {
intTime1;
intTime2;
int hour=10;
int minute=5;
int second=13;
int h;int m;
[Code] ....
Is there any easy way of doing above code. Above two code section not working....