I am looking for simple code that subtract two time interval. I have time t1=5hour 30 minute and other time in 24 hour format. This code i written but it not working as expected
main() {
intTime1;
intTime2;
int hour=10;
int minute=5;
int second=13;
int h;int m;
[Code] ....
Is there any easy way of doing above code. Above two code section not working....
I am looking for simple code that subtract two time interval. I have time t1=5hour 30 minute and other time in 24 hour format. This code i written but it not working as expected. it not printing 5:30 minute subtract
Code:
main() {
intTime1;
intTime2;
int hour=10;
int minute=5;
int second=13;
int h;int m;
doubleNtime;
[Code] ....
Its a code in module of my program, where I need to print current time (HH:MM:SS) at regular intervals.
Code:
#include<time.h>
#include<stdio.h>
//#include<windows.h>
void delay(unsigned int t){ // loop for some delay.
[Code] ....
But when I am running this code I expect this to print difference in time due to delay. But it doesn't enter the delay loop, why ?
Is there a way of knowing which indices a thread is assigned in a parallel openMP scope?
View 6 Replies View RelatedI have a piece of code which gets multiple objects to move randomly at a designated number of intervals. I want to create a function which calculates the distance between each pair of points after that number of steps. so the distance between object 1 and object 2, object 1 and object 3, ..., object 1 and object N. then object 2 and object 3, object 2 and object 4, ..., object 2 and object N. then then object 3 and object 4, object 3 and object 5, ..., object 3 and object N and so on until the distance between all the pairs of points have been calculated.
#include <ctime>
#include <cstdlib>
#include<iostream>
#include<cmath>
#include<iomanip>
#include<fstream>
#include<vector>
using namespace std;
double dist(int a, int b);
int X(int x1, int x2);
int Y(int y1, int y1);
[Code] ....
I am working on an assignment where I have to subtract two very large integers. How can I write it's code provided that I have both numbers in a character array with each index holding a fraction of the original number. Like if I have a number 123456789 in an array then
arr[0]='1';
arr[1]='2';
arr[2]='3';
arr[3]='4';
and so on. n
nNw if i have to subtract this number from an other number, how can I do that?
I'm working on a matrix class and I've hit a few snags. Here's what I've got so far:
Matrix.h
#include <iostream>
#include <conio.h>
using namespace std;
class Matrix {
private:
int matrix[50][50];
[Code] ....
Where I have questions is in implementing the addition and subtraction bits into the class itself. I understand that I'm going to have to do a copy operation (this from reading in C++ Primer Plus 5th Edition). Right now I'm just after adding/subtracting as the rest will be variations on the same theme.
So, here it goes:
As I understand the problem, I need to pass my two matrices as arguments to an addition function. This is going to involve having to copy the values of the two existing matrices into temporary matrices within the addition function, then I'll add them, and store them in a new matrix which will be my return value. So...something like this:
int Matrix::matrixAdd(int R, int C, const Matrix & matrix1, const Matrix & matrix2) {
int sum;
Matrix matrix;
for (int i = 0; i < R; i++)
[Code] ....
I do end up with errors there...C2240, and C2662. Again, I'm new to working through this, but that's what I've got. My idea is that I'm passing the maximum size of the array as defined by the user, in this case a 2x2 array, it'll cycle through and add up to that imposed limit...I went 2x2 because it's small enough that testing doesn't drive me up a wall.
On a controlled buffer of unsigned char it is possible to do subtraction faster than if you followed standard mathematical rules, here is an example:
typedef unsigned char uchr;
uchr num1 = 5; //00000101
uchr num2 = 3; //00000011
num2 = ~num2; // 11111100
++num2; // 11111101
uchr num3 = num1 + num2; // 00000010(2) - computer truncates result to fit char
Since you will be working with a buffer you don't even need to worry about truncating the final bit because the add function will not be able to reach it - unless it is given the ability to grow the buffer in which case you just set the bit to 0 yourself
I'm writing an addition and subtraction calculator that takes input as: 5+6-3+2. You should be able to add or sub as many numbers as you want. I want the while loop to stop when the user hits enter. I put the getchar() function to catch the and break the loop but it is also swallowing the '-' sign, which I want to use to subtract and is instead adding the numbers with "sum+=number". How can I get around that?
Code:
#include <stdio.h>
int main(int argc, char *argv[]){
int number, sum = 0;
[Code]....
trying to understand operator overloading, and i wrote some code just to define a "-" operator to do a simple subtraction. SO, i wrote a program that can perform a subtraction between two objects and put the result in the third object. now I Just cant show the result on the console. And also can anyone define the meaning of [b1.x], like I want to know am I assigning the value to the "b1"object or the x variable? This is a very concept that I need to understand.
#include<iostream>
using namespace std;
struct Ok
{
int x;
int y;
};
Ok operator-(const Ok& a , const Ok& b)
{
Ok result;
result = (a - b);
return result;
}
int main()
[Code]...
I need to create a binary calculator that outputs the operation of subtraction whenever you input 2 4 bit binary numbers. For example:
If I enter
1000
- 0111
1.What would regex pattern look like for addition of integers?
2.What would regex pattern look like for subtraction of complex numbers?
I have a templated container that defines a forward iterator.
Calling std::distance on these iterators will generate code that will count the number of iterations it takes to get from the first parameter to the second, by repetitively incrementing.
Internally, the iterators can easily find the distance by a simple subtraction.
What I want to do is overload std::distance for these iterators so that it will take advantage of the simple calculation rather than repetitive increments.
The simple solution of course would be to make the iterators random access, but this would require that they support functionality that is not 'logical' for the container. Access to the container only makes logical sense when iterating one item at a time in the forward direction.
Code:
#include <iterator>
template <typename T>
class Container {
public:
class iterator : public std::iterator<std::forward_iterator_tag, T> {
[Code] .....
Below is a program that generates random Addition for Subtraction problems depending on the user's choice. The user is prompted to input an answer and then it keeps your score. If you want to quit you just press zero.
Code:
#include <iostream>
#include <stdio.h>
#include <stdlib.h>
#include <time.h>
#include <iomanip>
#include <string>
using namespace std;
int menu();
bool addition(int &reward); // function to return truth values
[Code] ....
This is a round robin execution. with gantt chart. arrival time and burst time. I think there is an error in my formula to get the right answer,i cant resolve it but my program is running. What is the code or the right formula??
#include<stdio.h>
int main(){
int i,j=0,n,time,remain,flag=0,ts;
int sum_wait=0,sum_turnaround=0,at[10],bt[10],rt[10];
int ganttP[50],ganttStartTime[50];
printf("Enter no of Processes : ");
scanf("%d",&n);
remain=n;
[Code] ....
So I'm trying to learn how to use time for time based movement and what not. I did this only knowing the command time(&variable)
time_t timer;
int I, X;
void main() {
time(&timer);
X=timer;
while(I==5) {
[Code] ......
There's probably some other better way to do it... Obviously but for now I see it as putting current time in X.
start while
take in time constantly until I is 5
constantly asking is time>X(preset time 5 seconds ahead)
if it is
display message and add one to I
Why doesn't this display my message after 5 seconds?
make a time-in time-out fuction which extracts the no. of hours and minutes from a string entered by the user.
#include <iostream>
#include <fstream>
#include <string>
[Code].....
when we would use add items at design time and when we would add them at run time
does it have anything to do with the page load method? if so, can i type this in source code instead?
why nGrade comes out as 0 every time?
Its as if im not inputting the values into the dynamic arrays in int main.
#include <iostream>
using namespace std;
void Calc(int a_anScores[], int a_anPerc[], int a_nTotal){
for( int iii = 0; iii < a_nTotal; ++iii){
a_anScores[iii] = (a_anScores[iii] * (a_anPerc[iii]/100));
}
int nGrade=0;
[Code]...
I have created this code with the classes for time and message. Basically the point of this code is to give the information of the sender, recipient, time, and message and im having issues with the time part.
#include <iostream>
#include <string>
#include <ctime>
[Code].....
so when you run this you can see i left a spot for the time but I just cant figure out how to figure out the Time part of this.
I am trying to make this while loop cut out / self break after 3 seconds. It is part of a simple game I am creating that gives the users 3 seconds to react otherwise it moves on to the next part.
while(1) {
key=getch();
if(key=='a'||key=='k'||key=='g') {
break;
}
}
All I need is it to end after 3 seconds, the rest of the code is working fine.
This sort of thing:
long startTime = System.currentTimeMillis(); //fetch starting time
while(false||(System.currentTimeMillis()-startTime)<10000)
If it IS for C, then I implemented it wrong or something.
I want to convert time from est to utc. Is there any function for this.
View 3 Replies View RelatedI just spent 3 hours writing and debugging 37 lines of code. Is this normal or am I "below average" in coding abilities. I come from a C background and decided to write C++ code that I finally got right as shown below for the specific example:
Code: #include <iostream>
#include <fstream>
#include <string>
#define SPACE_SEARCH 10
using namespace std;
[code].....
I think it was more the learning along the way that consumed atleast 75% of my time for this specific case. But then again, I read that programming always entails learning along the way and so its somehow no excuse for the long time taken in this specific case.
So as a matter of interest, what pace do all of you operate on, on average? i.e. LOC/day, Debugs per day or any other indicator of productivity?
I tried to write a simple program to calculate monthly yield, APR, and principle in various directions. Anyway, here's some code to get the APR from the principle and monthly yield. When I run it though, it spits 0 at me every time! What the problem is; the other functions work just fine and the code line for the APR calculation is just what it ought to be - I see neither a math nor tech problem here.
Here is the offending function:
Code:
void calculateAPR() {
int principle, monthlyYield, apr;
cout<<"
Please input the principle:";
cin>>principle;
cin.ignore();
[code]....
The issue is that I am trying to run a code which can trigger different timers at the same time. That is, when 3 is typed by the user, the firstimer is triggered. If before expiration another 3 is introduced, the second timer will be launched, and the difference between both triggers will be shown. Under this circumstance, timer_gettime only works once. I tried all the things I could imagine but still, it_value_tv_sec and _nsec return zero after the first expiration.
-Theoretically, and following the manuals, once the timer is restarted the gettime function should work as it does the first time.
-I have also tried to removed the timer and start it again, but in this case the timers are still being triggered, but the gettime outputs(even the first time) are nonsense.
Here is the code I am testing: [CODE]#include<stdio.h>
Code:
#include<signal.h>
#include<time.h>
timer_t firstTimerID;
timer_t secondTimerID;
timer_t thirdTimerID;
[Code] ......
I created a program to display time continuously so it auto updates every sec but the issue is i cant integrate the code in the main program because to make time update continuously it needs a loop a infinite loop so none of the rest program gets to work. My q is : is it possible to display time continuously and make the rest of program continue normally? like a multi thread program because i want to display time every sec in the bottom of program. By the way this is console app not gui
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