Write a program, sumit.c, that reads an integer value n from the user and then sums the integers between 0 and n. Your program should be able to handle both positive and negative values of n and should write the sum to the output file sumitout.txt. Note that your sum should not actually include 0, since that doesn't affect the sum. Your program should open the file sumitout.txt for appending so that the file can record a series of runs.
For marking purposes run your program twice with values n = −10 and n = 5.
Here is a sample run:
Enter n: -4 The sum of integers from -1 to -4 is -1
#include<stdio.h>
int main(void) {
//declare your variables
int n, i, term, total = 0;
//promt user to enter and read a value of n
printf("Enter n: ");
scanf("%d", &n);
//calculate the sum
I'm a beginner at c++ and I need to write a program that reads a set of integers and then finds and prints the sum of the even and odd integers. The program cannot tell the user how many integers to enter. I need to have separate totals for the even and odd numbers. what would I need to use so that I can read whatever number of values the user inputs and get the sum of even and odd?
i am relatively new to C programming so i run into problems on daily basis. But this time i have something i just cant figuer out and i was hoping you could point me towards the right track. I am trying to divide two integers.DevValue by KpTotal. for some reason my micro controller allways crashes.Y is a variable of a distance measuring sensor. i have a 4x4 keypad to enter a three digit number (e.i 123) so Kp1 = 1 Kp2 = 2 Kp3 =3.
Code:
int kp1, kp2, kp3, kpTotal = 0; char txt[6] = "" int keypadPort at PORTD; sbit LCD_RS at RB4_bit; sbit LCD_EN at RB5_bit; }
[code]....
i think it has something to do with the format of the value. i read that the micro controller crash when dividing by zero.
How to write a simple function that will take 3 ints and find the sum of the higher 2? This is what i got so far:
int findsum(int a,int b,int c)// will find the highest int and return it to our main program { int max,max2;// this sets our local variable max // next we will find the larger of our first 2 variables if( a>=b) { max=a;
[Code] ....
How to get the second highest number and add it to max
I am working on an assignment where I have to subtract two very large integers. How can I write it's code provided that I have both numbers in a character array with each index holding a fraction of the original number. Like if I have a number 123456789 in an array then
arr[0]='1'; arr[1]='2'; arr[2]='3'; arr[3]='4'; and so on. n
nNw if i have to subtract this number from an other number, how can I do that?
I am trying to create a program that reads my file filled with random words, it then compares the words after they are put into a 2d array and sees if there is any matching words.. unfortunately the count is not working for me (in function2 and function3) and I am not sure why..
Code:
#include<stdio.h> #include<string.h> char function1(char words_array[][17]); int function2(char words_array[][17]); void function3(int pairs, char words_array[][17]); int main( void ) { char words_array[20][17]; int x = 0;
How i can concatenate two integers into one integer. I have code that concatenate two integers but if the 2nd integer is zero it won't work. How can i modify it so that it can cater the case of y=0 too.
Code:
int concatenate(int x, int y) { int pow = 10; while(y >= pow) pow *= 10; return x * pow + y; }
I compiled a simple program using a function to add two integers, in order to understand the difference of calling by value vs by reference.
Code:
#include <stdio.h> int add(int a, int b, int sum); int main() { int a, b, sum; printf("Please enter two integers "); scanf("%d%d", &a, &b);
[Code]...
I used these two (one, two) pages I found in the net while studying the subject. So here are my questions...
(a) Do I understand correctly that in the above code all a, b and sum are passed by value? (b) If I wanted only sum to be passed by reference, how the above code would change? (c) If I wanted all (a, b, sum) to be passed by reference, how the above code would change?
"Write a program that prompts the user for an integer number from the keyboard, and store it in a variable num. After each number is typed in, add num to a total.
Do this six times, each time adding num to a total. (Be sure to reuse the same variable named num for each of the six numbers entered.) When all six numbers have been entered from the keyboard, calculate an average. Display the total and average calculated. "
Here is what I have so far:
Code: #include<stdio.h> int main() { int num, total1, total2, total3, total4, total5, total6, avg;
from k&r book (4.2 - functions retuning non integers) (doesnt compile - 1 error)
Code:
#include <stdio.h> #define MAXLINE 100 /* rudimentary calculator */ main() { double sum, atof(char []); char line[MAXLINE]; int getline(char line[], int max); sum = 0; while (getline(line, MAXLINE) > 0) printf(" %g ", sum += atof(line)); return 0; }
Code:
int getline(char line[], int max); is no different from:
Code:
getline(char line[], int max); ?
so, the int (return type) is optional when using a function. i assume return type is casted double? why the (char [])? just weird cuz i never seen it before
I am trying to make a game where you have a secret code that is coded with colors like ROYG (red,orange,yellow,green) and I am having trouble when it tells you when you have a right color in the right spot or a right color in the wrong spot when you guess a color. How can I change my code under the function int comparearray where it will compare pointers to pointers and not integers and give me the correct number of "almost" and "correct".
How do I do the operation of two integers that gives you the results?
I'm supposed to write a program that:
Asks the user for an integer Asks the user for one of '+', '-', '*', or '/' (as a character) Asks the user for another integer Performs the given operation on the two integers, and prints out the result of
Please enter an integer: 4 Please enter an operation (+, - , *, /): * Please enter another integer: 5
4 * 5 = 20
Code: #include <iostream> using namespace std; int main() { int x; int c; int d; char e;
I have been tasked with sorting a text file with some numbers in it. For example, there can be 5 numbers in it: 1,2,3, 4, and 5. However, they are out of order (3,2,4,1 and 5). I need the numbers in numerical order. How can you sort the numbers into a new file?
Bubblesorting? I can not use arrays in this program. I have already determined the minimum number in the file.
I'm trying to write an algorithm for a larger project that will take two strings which are both large integers (only using 10 digit numbers for the sake of this demo) and add them together to produce a final string that accurately represents the sum of the two original strings. I realize there are potentially better ways to have gone about this from the beginning but I am supposed to specifically use strings of large integers as opposed to a long integer.
My thinking was to take the two original strings, reverse them so their ones position, tens position, and so on all line up properly for adding. Then one position at a time, convert the characters from the strings to single integers and add them together and then use that sum as the ones position or otherwise for the final string, which once completed will also be reversed back to the correct order of characters.
Where I'm running into trouble I think is in preparing for the event in which the two integers from the corresponding positions in their strings add to a sum greater than 9, and I would then have carry over some remainder to the next position. For example, if I had 7 and 5 in my ones positions that would add to 12, so I would keep the 2 and add 1 to the tens position once it looped back around for the tens position operation.
I'm not getting results that are in any way accurate and after spending a large amount of time stumbling over myself trying to rectify my algorithm, I am not sure what I need to do to fix this.
I have 2 integers, both in 2 seperate classes in 2 seperate files. I have main.cpp, test_01.h, Test_01.cpp, Player.h and Player.cpp. I ahve a function which takes an integer (a) as a parameter (from Test_01.h and Test_01.cpp). a sets another integer (attackPower) from the same class equal to a. The integer (health) in the other class (Player.h and Player.cpp), is then equal to health -= attackPower. But instead of giving me the right answer 75 (health = 100 and a is set to 25 when i call the function) it gives me the answer.
main.cpp
#include <iostream> #include "Test_01.h" #include "Player.h" using namespace std; int main() { Player p; Test_01 t;
In C++, the largest int value is 2147483647. So, an integer larger than this cannot be stored and processed as an integer. Similarly, if the sum or product of two positive integers is greater than 2147483647, the result will be incorrect. One way to store and manipulate large integers is to store each individual digit of the number in an array. Write a program that inputs two positive integers of, at most, 20 digits and outputs the sum of the numbers. If the sum of the numbers has more than 20 digits, output the sum with an appropriate message. Your program must, at least, contain a function to read and store a number into an array and another function to output the sum of the numbers. (Hint: Read numbers as strings and store the digits of the number in the reverse order.)
I now know how to count integers with while loop but I'm not sure how to count the integers with array.
So the question is:
1. program should keep reading integers as long as the integers are within [0,9999] 2. when user typed the integer not between 0 to 9999, the program print out the numbers of integers that were typed.
Sample 3 3 3 9999 9999 -1 You entered 3 3 times. You entered 9999 2 times.
#include <iostream> using namespace std; int main() { int i=-1; int x; int numbers[10000];
I am trying to make a 5x3 2D-vector of integers, then set its i-capacity to be 5 and j-capacity to be 3, i.e:
vec2D[i][j] i = 1,2,3,4,5 j = 1,2,3
and then assign integer values to it.
#include <vector> #include <iostream> using namespace std; int main () { vector<vector<int> > vec2D;
[Code] ....
It compiles, but does not work properly:
Test.exe exited with code -1073741819
i-capacity before reserve: 0 i-capacity after reserve: 5
i = 0 j-capacity before reserve: 336043326 j-capacity after reserve: 336043326 i = 1 j-capacity before reserve: 4282929217 j-capacity after reserve: 4282929217 Press <RETURN> to close this window...
I am trying to convert a C code with dynamic 2D arrays, to a C++ code. I prefer to keep the vec2D[i][j] = ... way of assignment instead of using vec2D.push_back(...).
I am working on a program where the person enters their name and their gross pay. I had to validate that the gross was a number and contained no letters.
I also have to validate the persons name to see if it contains any numbers. The book I am using has an example with only an if statement that says if it is correct or incorrect. I was trying to use <cctype> and toalpha
I just was wondering if there was a way to put it into a while loop or how i would have it ask the user to input their name again. When i tried it just blew up.
Also in the book they use const int SIZE= 8, but I don't want to put a size on the name if I don't have to.
